PHP - Database generates blank row when loading page - php

Question

I have a form which will submit information that inserts a row into a database (company details). The submission works ok but I also find that going to the page containing the form will insert a blank row in the database. Any idea why this may be? Code is as below:
<?php
echo "<form action='addnew.php' method='post'>";
echo "<input type='text' name='categoryAdd' value='Travel'/><br/>";
echo "<input type='text' name='EstablishmentNameAdd' value='EstablishmentName'/><br/>";
echo "<input type='text' name='Address1Add' value='Address1'/><br/>";
echo "<input type='text' name='Address2Add' value='Address2'/><br/>";
echo "<input type='text' name='Address3Add' value='Address3'/><br/>";
echo "<input type='text' name='Address4Add' value='Address4'/><br/>";
echo "<input type='text' name='PostcodeAdd' value='Postcode'/><br/>";
echo "<input type='text' name='NearestStationAdd' value='NearestStation'/><br/>";
echo "<input type='text' name='TelAdd' value='Tel'/><br/>";
echo "<input type='text' name='FaxAdd' value='Fax'/><br/>";
echo "<input type='text' name='EmailAdd' value='Email'/><br/>";
echo "<input type='text' name='WebsiteAdd' value='Website'/><br/>";
echo "<input type='text' name='DescriptionAdd' value='Description'/><br/>";
echo "<input type='submit' value='test'/>";
echo "</form>";
$EstablishmentNameAdd = mysql_real_escape_string($_POST['EstablishmentNameAdd']);
$CategoryAdd = $_POST['categoryAdd'];
$Address1Add = mysql_real_escape_string($_POST['Address1Add']);
$Address2Add = mysql_real_escape_string($_POST['Address2Add']);
$Address3Add = mysql_real_escape_string($_POST['Address3Add']);
$Address4Add = mysql_real_escape_string($_POST['Address4Add']);
$PostcodeAdd = $_POST['PostcodeAdd'];
$NearestStationAdd = mysql_real_escape_string($_POST['NearestStationAdd']);
$TelAdd = $_POST['TelAdd'];
$FaxAdd = $_POST['FaxAdd'];
$EmailAdd = mysql_real_escape_string($_POST['EmailAdd']);
$WebsiteAdd = mysql_real_escape_string($_POST['WebsiteAdd']);
$DescriptionAdd = mysql_real_escape_string($_POST['DescriptionAdd']);
$result1 = mysql_query("INSERT into establishment_id (EstablishmentName) values ('$EstablishmentNameAdd')");
$result2 = mysql_query("SELECT * from establishment_id where EstablishmentName = '$EstablishmentNameAdd'");
while($row = mysql_fetch_array($result2))
{
$ID = $row['EstablishmentID'];
$NAME = $row['EstablishmentName'];
};
$result3 = mysql_query("INSERT into establishmentdetails (EstablishmentID, EstablishmentName, category, Address1, Address2, Address3, Address4, Postcode, NearestStation, Tel, Fax,
Email, Website, Description) values('$ID', '$EstablishmentNameAdd', '$CategoryAdd', '$Address1Add', '$Address2Add', '$Address3Add', '$Address4Add', '$PostcodeAdd', '$NearestStationAdd', '$TelAdd', '$FaxAdd', '$EmailAdd',
'$WebsiteAdd', '$DescriptionAdd')");
?>

Answer 1

Add this after all the echos:
if(!empty($_POST)){
...
}
Wrap all the bottom code in that, so that way only if there is a post it will do the insert.

Answer 2

This is happening because you are echoing out the form.. and then immediately inserting things into your database that don't exist yet.
You can try this:
if(count($_POST) > 0 && in_array('EstablishmentNameAdd',$_POST)) {
$EstablishmentNameAdd = mysql_real_escape_string($_POST['EstablishmentNameAdd']);
$CategoryAdd = $_POST['categoryAdd'];
$Address1Add = mysql_real_escape_string($_POST['Address1Add']);
$Address2Add = mysql_real_escape_string($_POST['Address2Add']);
$Address3Add = mysql_real_escape_string($_POST['Address3Add']);
$Address4Add = mysql_real_escape_string($_POST['Address4Add']);
$PostcodeAdd = $_POST['PostcodeAdd'];
$NearestStationAdd = mysql_real_escape_string($_POST['NearestStationAdd']);
$TelAdd = $_POST['TelAdd'];
$FaxAdd = $_POST['FaxAdd'];
$EmailAdd = mysql_real_escape_string($_POST['EmailAdd']);
$WebsiteAdd = mysql_real_escape_string($_POST['WebsiteAdd']);
$DescriptionAdd = mysql_real_escape_string($_POST['DescriptionAdd']);
$result1 = mysql_query("INSERT into establishment_id (EstablishmentName) values ('$EstablishmentNameAdd')");
$result2 = mysql_query("SELECT * from establishment_id where EstablishmentName = '$EstablishmentNameAdd'");
while($row = mysql_fetch_array($result2))
{
$ID = $row['EstablishmentID'];
$NAME = $row['EstablishmentName'];
};
$result3 = mysql_query("INSERT into establishmentdetails (EstablishmentID, EstablishmentName, category, Address1, Address2, Address3, Address4, Postcode, NearestStation, Tel, Fax,
Email, Website, Description) values('$ID', '$EstablishmentNameAdd', '$CategoryAdd', '$Address1Add', '$Address2Add', '$Address3Add', '$Address4Add', '$PostcodeAdd', '$NearestStationAdd', '$TelAdd', '$FaxAdd', '$EmailAdd',
'$WebsiteAdd', '$DescriptionAdd')");
}