PHP dynamic alphabetical list with headers - php

Question

So what I am trying to produce is something like this:
Except, I do not want duplicates, when there is more than one sign, it becomes duplicated as well as re creating the "C" list view header. My SQL query is creating a column known as first_char which is holding the first character of one of the other columns.......below is my code:
<?php foreach ($data as $name=>$signs): ?>
<!-- If name is not empty, create the header -->
<?php if (isset($name) && !empty($signs)): ?>
<div data-role='collapsible-set' data-theme='d'>
<h2>Username: <strong id="headerName"><?=$name?></strong></h2>
<?php endif; ?>
<?php endforeach; ?>
<!-- for every sign, take the first char and create a list view -->
<?php foreach ($signs as $char):
$current_char = '';
if ($char['first_char'] != $current_char){
$current_char = $char['first_char'];
echo '<ul data-role="listview" data-dividertheme="d" style="margin-top: 0;"><li data-role="list-divider">'.$current_char.'</li></ul><br>';
}
foreach ($signs as $sign):
if($current_char == $sign['first_char'] and !empty($signs)):
?>
<div data-role='collapsible' data-collapsed='true' data-icon='arrow-l'>
<h3><?=$sign['sign_name']?></h3>
<div class='ui-grid-a'>
<div class="ui-block-a">
<div class="ui-bar ui-bar-d" style="height:25px;">
<strong>Last Seen:</strong><strong id="text"><?=$sign['last_connected']?></strong>
</div>
</div>
<div class="ui-block-a">
<div class="ui-bar ui-bar-d" style="height:25px;">
<strong>Resolution:</strong><strong id="text"><?=$sign['resolution_x'].'x'.$sign['resolution_y']?></strong>
</div>
</div>
<div class="ui-block-a">
<div class="ui-bar ui-bar-d" style="height:25px;">
<strong>Group Name:</strong><strong id="text"><?=$sign['group_name']?></strong>
</div>
</div>
<div class="ui-block-a">
<div class="ui-bar ui-bar-d" style="height:25px;">
<strong>Sign Number:</strong><strong id="text"><?=$sign['sign_id']?></strong>
</div>
</div>
</div>
</div>
<?php endif; ?>
<?php endforeach; ?>
<?php endforeach; ?>
Thanks in advance

Answer 1

This fixes the previous error and gets rid of the duplication. $current_char needed to be outside the foreach loop, and removed the 2nd foreach.
<?php $current_char = '';?>
<?php foreach ($signs as $sign):?>
<?php
if ($sign['first_char'] != $current_char){
$current_char = $sign['first_char'];
echo '<ul data-role="listview" data-dividertheme="b" style="margin-top: 0;padding-top: 3px;"><li data-role="list-divider">'.$current_char.'</li></ul><br>';
}
?>
The query used above for SQL was this:
SELECT
user.username,
groups.group_id, groups.group_name,
sign.last_connected, sign.sign_id, sign.sign_name, sign.resolution_x, sign.resolution_y, LEFT(sign.sign_name, 1) AS first_char
FROM
user
LEFT JOIN(
groups, sign
)ON(
user.user_id = groups.userID AND
groups.group_id = sign.groupID
)
WHERE
username = ? AND
UPPER(sign.sign_name) BETWEEN "A" AND "Z"
OR sign.sign_name BETWEEN "0" AND "9" ORDER BY sign.sign_name