I have a problem with nested select in MySQL.
This one works, but I need to get two of them.
Example:
SELECT `a`.`title` , `a`.`askprice` , `a`.`picture`
, `a`.`description` , `a`.`userid` , `a`.`id`
FROM (
`mm_ads_fields_values` AS afv
)
LEFT JOIN `mm_ads` AS a ON `a`.`id` = `afv`.`aid`
WHERE `afv`.`value` = '38'
AND `a`.`category` = '227'
AND `a`.`status` =1
AND a.id
IN (
SELECT a.id
FROM mm_ads AS a
LEFT JOIN mm_ads_fields_values AS afv ON afv.aid = a.id
WHERE afv.value = '2913'
)
ORDER BY `id` DESC
LIMIT 20
This one works. But I need SQL statement like this one:
SELECT `a`.`title` , `a`.`askprice` , `a`.`picture`
, `a`.`description` , `a`.`userid` , `a`.`id`
FROM (
`mm_ads_fields_values` AS afv
)
LEFT JOIN `mm_ads` AS a ON `a`.`id` = `afv`.`aid`
WHERE `afv`.`value` = '38'
AND `a`.`category` = '227'
AND `a`.`status` =1
AND a.id
IN (
SELECT a.id
FROM mm_ads AS a
LEFT JOIN mm_ads_fields_values AS afv ON afv.aid = a.id
WHERE afv.value = '2913'
)
AND a.id
IN (
SELECT a.id
FROM mm_ads AS a
LEFT JOIN mm_ads_fields_values AS afv ON afv.aid = a.id
WHERE afv.value = '51'
)
ORDER BY `id` DESC
LIMIT 20
And this one, last one, won't work. Its loading, loading and never nothing happen..
What am I doing wrong?
Regards, Mario
Sorry for my bad English..
Glib answer: shouldn't the second IN statement use OR instead of AND? (edit: and use correct operator precedence.)
...
AND
( a.id
IN (
SELECT a.id
FROM mm_ads AS a
LEFT JOIN mm_ads_fields_values AS afv ON afv.aid = a.id
WHERE afv.value = '2913'
)
OR a.id
IN (
SELECT a.id
FROM mm_ads AS a
LEFT JOIN mm_ads_fields_values AS afv ON afv.aid = a.id
WHERE afv.value = '51'
)
)
...
Related
I'm struggling to convert this below MySQL query into laravel query builder. It has a lot of joins and subqueries inside. Can someone please help me?
MYSQL query:
SELECT a.id , b.*, a.agent_id, td.contacts, td.addresses
FROM teams a
left join team_details as td on td.team_id = a.id
LEFT OUTER JOIN
(
SELECT m.id, m.due_date, t.team_id, m.department, m.assigned_to , cm.title, u.name
FROM (
SELECT team_id, MAX(due_date) AS due_date
FROM campaign_activities where task_status=false and due_date is not null
GROUP BY team_id
) t JOIN campaign_activities m ON m.team_id = t.team_id AND t.due_date = m.due_date
left join campaign_activity_masters cm on cm.id = m.camp_activity_id
left join users u on u.id = m.assigned_to
) b ON a.id = b.team_id
order by a.id
I'm trying something like below but got stuck with LEFT OUTER JOIN as it has sub query inside :).
DB::table('teams as a')
->leftjoin('team_details as td', 'td.team_id','=','a.id')
->select('a.id', 'b.*', 'a.agent_id','td.contacts','td.addresses')
->leftouterjoin(DB::select(DB::raw('SELECT m.id, m.due_date, t.team_id, m.department, m.assigned_to , cm.title, u.name
FROM (
SELECT team_id, MAX(due_date) AS due_date
FROM campaign_activities where task_status=false and due_date is not null
GROUP BY team_id
) t JOIN campaign_activities m ON m.team_id = t.team_id AND t.due_date = m.due_date
left join campaign_activity_masters cm on cm.id = m.camp_activity_id
left join users u on u.id = m.assigned_to')))
->get();
Any suggestions, please? I want to apply paginate function paginate() instead of get() for this query builder.
I think you should try.
$cards = DB::select("SELECT a.id , b.*, a.agent_id, td.contacts, td.addresses
FROM teams a
left join team_details as td on td.team_id = a.id
LEFT OUTER JOIN
(
SELECT m.id, m.due_date, t.team_id, m.department, m.assigned_to , cm.title, u.name
FROM (
SELECT team_id, MAX(due_date) AS due_date
FROM campaign_activities where task_status=false and due_date is not null
GROUP BY team_id
) t JOIN campaign_activities m ON m.team_id = t.team_id AND t.due_date = m.due_date
left join campaign_activity_masters cm on cm.id = m.camp_activity_id
left join users u on u.id = m.assigned_to
) b ON a.id = b.team_id
order by a.id");
Hope it help you.
I have this sql request :
SELECT pl.*, l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
from locations sl
LEFT JOIN
(
SELECT * FROM paiement_loyer
union
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
WHERE usl.id not in (SELECT location_id FROM paiement_loyer) ||
(select count(*) FROM paiement_loyer
WHERE location_id = usl.id AND annee = YEAR(NOW())
AND mois=(MONTH(NOW())-1) ) = 0
) spl ON sl.id = spl.location_id
where sl.date_debut <= CURDATE() && CURDATE() <= sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY trim(upper(m.titre_crm)), c.numero, annee, mois
I would like to simplify it, do you have any idea please ?
An attempt at cleaning it up. Note that I think the first LEFT OUTER JOIN could probably be swapped to an INNER JOIN.
I have swapped the 2nd UNIONed query to 2 queries, and for those I have changed them to use LEFT OUTER JOINs which then check that there isn't a match
SELECT pl.id, pl.location_id, pl.mois, pl.annee, pl.loyer_paye,
l.loyer, l.charges, l.locataire_id, laire.nom, laire.prenom,
l.chambre_id, c.numero, c.etage, c.maison_id, m.titre_crm
FROM
(
SELECT spl.id, spl.location_id, spl.mois, spl.annee, spl.loyer_paye
FROM locations sl
LEFT OUTER JOIN
(
SELECT id, location_id, mois, annee, loyer_paye
FROM paiement_loyer
UNION
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl1
ON usl.id = pl1.location_id
WHERE pl1.location_id IS NULL
SELECT 9999, usl.id, (MONTH(NOW())-1), YEAR(NOW()), 0
FROM locations usl
LEFT OUTER JOIN paiement_loyer pl2
ON usl.id = pl1.location_id
AND pl2.annee = YEAR(NOW())
AND pl2.mois=(MONTH(NOW())-1)
WHERE pl2.location_id IS NULL
) spl ON sl.id = spl.location_id
WHERE CURDATE() BETWEEN sl.date_debut AND sl.date_fin
) pl
JOIN locations l ON pl.location_id = l.id
JOIN locataires laire ON l.locataire_id = laire.id
JOIN chambres c ON l.chambre_id = c.id
JOIN maisons m ON c.maison_id = m.id
ORDER BY TRIM(UPPER(m.titre_crm)), c.numero, pl.annee, pl.mois
I am using this mysql query
SELECT `p`.`id` AS product_id, `p`.`title` , `i`.`image` , `u`.`user_username` , `m`.`id` AS message_id, `m`.`date` , `m`.`from` , `m`.`to` , `m`.`message` , `m`.`read`
FROM (`messages` AS m)
JOIN `products` AS p ON `m`.`product_id` = `p`.`id`
JOIN `users` AS u ON `m`.`from` = `u`.`user_id`
JOIN `product_images` AS i ON `p`.`id` = `i`.`product_id`
WHERE `i`.`type` = 'FRONT'
AND (m.to = '1171' OR m.from = '1171)
GROUP BY `m`.`therad_user` , `m`.`product_id`
ORDER BY `m`.`id` DESC
In message table it shows message with oldest message id, I want to return latest message. but it show oldest message. how I solve this.
Try ORDER BY first, then only GROUP BY
SELECT * FROM
(
SELECT `p`.`id` AS product_id, `p`.`title` , `i`.`image` , `u`.`user_username` , `m`.`id` AS message_id, `m`.`date` , `m`.`from` , `m`.`to` , `m`.`message` , `m`.`read`
FROM (`messages` AS m)
JOIN `products` AS p ON `m`.`product_id` = `p`.`id`
JOIN `users` AS u ON `m`.`from` = `u`.`user_id`
JOIN `product_images` AS i ON `p`.`id` = `i`.`product_id`
WHERE `i`.`type` = 'FRONT'
AND (m.to = '1171' OR m.from = '1171)
ORDER BY `m`.`id` DESC
) tmp
GROUP BY `m`.`therad_user` , `m`.`product_id`
I am trying to run the following query, and I keep getting a syntax error. The query works fine without the LEFT JOIN. How can I implement the LEFT JOIN without error?
SELECT
m.mid,
m.seq,
m.created_on,
m.created_by,
m.body,
r.status,
u.username_clean
FROM message_recipient r
INNER JOIN message m
ON m.mid = r.mid AND m.seq = r.seq
WHERE r.uid = ".$logged_in_id."
AND r.status in ('A', 'N')
AND r.seq = (
SELECT
MAX(rr.seq)
FROM message_recipient rr
WHERE rr.mid = m.mid
AND rr.status in ('A', 'N')
)
AND IF (m.seq=1 and m.created_by = ".$logged_in_id." , 1=0, 1=1)
ORDER BY created_on DESC
LEFT JOIN users u
ON u.user_id = m.created_by
The LEFT JOIN is in the wrong place. All of the JOINs need to be before the WHERE clause:
SELECT
m.mid,
m.seq,
m.created_on,
m.created_by,
m.body,
r.status,
u.username_clean
FROM message_recipient r
INNER JOIN message m
ON m.mid = r.mid AND m.seq = r.seq
LEFT JOIN users u
ON u.user_id = m.created_by
WHERE r.uid = ".$logged_in_id."
AND r.status in ('A', 'N')
AND r.seq = (
SELECT
MAX(rr.seq)
FROM message_recipient rr
WHERE rr.mid = m.mid
AND rr.status in ('A', 'N')
)
AND IF (m.seq=1 and m.created_by = ".$logged_in_id." , 1=0, 1=1)
ORDER BY created_on DESC
The SQL clauses go in the following order:
SELECT
FROM
JOIN
WHERE
GROUP BY
ORDER BY
Even if you have multiple joins they will all appear before the WHERE
I'm trying to perform a query in Yii with CDbCommandBuilder so I can have the resultset in an array.
Problem is that I don't understand how to convert my SQL (pgsql) to the Yii CDbCommandBuilder syntax. Mainly my problem is with nested joins.
The query:
SELECT p.id
up.id as fid,
sum(CASE
WHEN v1.count>v2.count THEN v2.count
ELSE v1.count
END
) as res
FROM product as v1
INNER JOIN (
SELECT p_id, count
FROM product
WHERE user_id = {$user_id}) as v2 on v1.p_id = v2.p_id and v1.user_id <> {$user_id}
RIGHT JOIN users as p on p.id = v1.user_id
INNER JOIN uf on uf.friend_id = p.id and uf.user_id = {$user_id} and is_active = true
INNER JOIN up on up.user_id = p.id and is_active = true
GROUP BY p.id, up.id
ORDER BY res desc
Can anyone help?
Thanks
$sql = "SELECT p.id
up.id as fid,
sum(CASE
WHEN v1.count>v2.count THEN v2.count
ELSE v1.count
END
) as res
FROM product as v1
INNER JOIN (
SELECT p_id, count
FROM product
WHERE user_id = :user_id) as v2 on v1.p_id = v2.p_id and v1.user_id <> :user_id
RIGHT JOIN users as p on p.id = v1.user_id
INNER JOIN uf on uf.friend_id = p.id and uf.user_id = :user_id and is_active = true
INNER JOIN up on up.user_id = p.id and is_active = true
GROUP BY p.id, up.id
ORDER BY res desc";
$params = array(':user_id' => $user_id);
$aArrayOfRows = Yii::app()->db->createCommand($sql)->queryAll(true, $params);