How to convert date into same format? - php

I want to get the $registratiedag and count a couple of days extra, but I always get stuck on the fact that it needs to be a UNIX timestamp? I did some google-ing, but I really don't get it.
I hope someone can help me figure this out. This is what I got so far.
$registratiedag = $oUser['UserRegisterDate'];
$today = strtotime('$registratiedag + 6 days');
echo $today;
echo $registratiedag;
echo date('Y-m-d', $today);
There's obviously something wrong with the strtotime('$registratiedag + 6 days'); part, because I always get 1970-01-01

You probably want this:
// Store as a timestamp
$registratiedag = strtotime($oUser['UserRegisterDate']);
$new_date = strtotime('+6 days', $registratiedag);
// You'll need to format for printing $new_date
echo date('Y-m-d', $new_date);
// I think you want to compare $new_date against
// today's date. I'd recommend a string comparison here,
// As time() includes the time as well
// time() is implied as the second argument to date,
// But we'll put it anyways just to be clearer
if( date('Y-m-d', $new_date) == date('Y-m-d', time()) ) {
// The dates are equal, do something here
}
else if($new_date < time()) {
// if the new date is earlier than today
}
// etc.
First it converts $registratiedag to a timestamp, then it adds 6 days
EDIT: You probably should change $today to something less misleading like $modified_date or something

try:
$today = strtorime($registratiedag);
$today += 86400 * 6; // seconds in 1 day * 6 days
at least one of your problems is that PHP does not expand variables in single quotes.

$today = strtotime("$registratiedag + 6 days");
//use double quotes and not single quotes when embedding a php variable in a string

If you want to include the value of variable $registratiedag right into the text passed as parameter of strtotime, you have to enclose that parameter with ", not with '.

Related

PHP, Date: A Dot appended to a month short representation

I have
date("M.", $datetime)
I want to get this output:
Jan.
Feb.
Mar.
Apr.
May (no dot necessary)
Jun.
Jul.
…
I dont like the idea of an if-statement to check the length/number of month every time a date is generated.
Is there a approach that is more simple? Like changing the month-name in general? Or hooking into the date function itself to implement an if-statement that runs every time the date function runs.
Thanks
If you don't want the dot to appear after May month, you will need a check of some sort - which normally is an if. You could do something like this, check if the month returned by date() isn't May, and add a dot after if it isn't.
$date = date("M", $datetime);
if (date("M") != "May")
$date .= ".";
Otherwise you'd need to implement a function of your own, but in the end - you will have to end up with this again, there's really no way around it - and this is by far the simplest and cleanest way.
You could wrap this into a function. You can't alter the date() function directly, but you can create one of your own.
function my_date($format, int $timestamp = null) {
if ($timestamp === null)
$timestamp = time();
$date = date($format, $timestamp);
if ($format == "M" && date("M", $timestamp) != "May")
$date .= ".";
return $date;
}
Then use it as
echo my_date("M", $datetime);
This seems to be a bit of a hammer to crack a nut, or to avoid an IF statement in this case, but you can create an array with your month names in it and use that to output different month names if you like
$m_arr = [0,'Jan.','Feb.','Mar.','Apr.','May','Jun.',
'Jul.', 'Aug.', 'Sep.','Oct.','Nov.','Dec.'];
$m = (int)date('n', $datetime);
echo $m_arr[$m];

php strtotime() values not working as expected

this code keeps telling me that $lasUpdate is always greater than $yesterday no matter the change i make to $yesterday result is (12/31/14 is greater than 01/19/15 no update needed). i feel like i'm missing something simple thank you in advance it is greatly appreciated.
$result['MAX(Date)']='12/31/14';
$lastUpdate = date('m/d/y', strtotime($result['MAX(Date)']));
$yesterday = date('m/d/y', strtotime('-1 day'));
if($lastUpdate<$yesterday){echo $lastUpdate.'is less '.$yesterday.'<br>'.'update needed';}
if($lastUpdate>=$yesterday){echo $lastUpdate.'is greater than '.$yesterday.'<br>'.'no update needed';
You have fallen victim to PHP type juggling with strings. A date function has a return value of a string. You cannot compare dates in their string format since PHP will juggle strings into integers in the context of a comparison. The only exception is if the string is a valid number. In essence, you are doing:
if ('12/31/14' < '01/19/15') { ... }
if ('12/31/14' >= '01/19/15') { ... }
Which PHP type juggles to:
if (12 < 1) { ... }
if (12 >= 1) { ... }
And returns false on the first instance, and true on the second instance.
Your solution is to not wrap date around the strtotime functions, and just use the returned timestamps from the strtotime functions themselves to compare UNIX timestamps directly:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
You will however want to use date when you do the echo back to the user so they have a meaningful date string to work with.
Try something like this:
$lastUpdate = strtotime($result['MAX(Date)']);
$yesterday = strtotime('-1 day');
if ($lastUpdate < $yesterday) { /* do Something */ }
12/31/14 is greater than 01/19/15
Because 1 is greater than 0. If you want to compare dates that way you will need to store them in a different format (from most to least significant digit), for example Ymd.
Or store the timestamps you are making in the different variables and compare them.

PHP Adding 15 minutes to Time value

I have a form that receives a time value:
$selectedTime = $_REQUEST['time'];
The time is in this format - 9:15:00 - which is 9:15am. I then need to add 15 minutes to this and store that in a separate variable but I'm stumped.
I'm trying to use strtotime without success, e.g.:
$endTime = strtotime("+15 minutes",strtotime($selectedTime)));
but that won't parse.
Your code doesn't work (parse) because you have an extra ) at the end that causes a Parse Error. Count, you have 2 ( and 3 ). It would work fine if you fix that, but strtotime() returns a timestamp, so to get a human readable time use date().
$selectedTime = "9:15:00";
$endTime = strtotime("+15 minutes", strtotime($selectedTime));
echo date('h:i:s', $endTime);
Get an editor that will syntax highlight and show unmatched parentheses, braces, etc.
To just do straight time without any TZ or DST and add 15 minutes (read zerkms comment):
$endTime = strtotime($selectedTime) + 900; //900 = 15 min X 60 sec
Still, the ) is the main issue here.
Though you can do this through PHP's time functions, let me introduce you to PHP's DateTime class, which along with it's related classes, really should be in any PHP developer's toolkit.
// note this will set to today's current date since you are not specifying it in your passed parameter. This probably doesn't matter if you are just going to add time to it.
$datetime = DateTime::createFromFormat('g:i:s', $selectedTime);
$datetime->modify('+15 minutes');
echo $datetime->format('g:i:s');
Note that if what you are looking to do is basically provide a 12 or 24 hours clock functionality to which you can add/subtract time and don't actually care about the date, so you want to eliminate possible problems around daylights saving times changes an such I would recommend one of the following formats:
!g:i:s 12-hour format without leading zeroes on hour
!G:i:s 12-hour format with leading zeroes
Note the ! item in format. This would set date component to first day in Linux epoch (1-1-1970)
strtotime returns the current timestamp and date is to format timestamp
$date=strtotime(date("h:i:sa"))+900;//15*60=900 seconds
$date=date("h:i:sa",$date);
This will add 15 mins to the current time
To expand on previous answers, a function to do this could work like this (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function here.)
// Return adjusted time.
function addMinutesToTime( $time, $plusMinutes ) {
$time = DateTime::createFromFormat( 'g:i:s', $time );
$time->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $time->format( 'g:i:s' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '9:15:00', 15 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
get After 20min time and date
function add_time($time,$plusMinutes){
$endTime = strtotime("+{$plusMinutes} minutes", strtotime($time));
return date('h:i:s', $endTime);
}
20 min ago Date and time
date_default_timezone_set("Asia/Kolkata");
echo add_time(date("Y-m-d h:i:sa"),20);
In one line
$date = date('h:i:s',strtotime("+10 minutes"));
You can use below code also.It quite simple.
$selectedTime = "9:15:00";
echo date('h:i:s',strtotime($selectedTime . ' +15 minutes'));
Current date and time
$current_date_time = date('Y-m-d H:i:s');
15 min ago Date and time
$newTime = date("Y-m-d H:i:s",strtotime("+15 minutes", strtotime($current_date)));
Quite easy
$timestring = '09:15:00';
echo date('h:i:s', strtotime($timestring) + (15 * 60));

PHP| arrays with times

I need to compare bentween a time taken from a database to the current time.
$DBtime = "2013-10-29 17:38:55";
this is the format of the arrays in the database.
How can I compare it with the current time?
Im not sure how, but maybe converting DBtime to Unixtime then:
(CurrentUnixTime - dbUnixTime) = x
Or maybe, we can take the 17:38 and compare it somehow with date("G:i");
Thank you! I hope you understand what I mean.
You can transform it into a UNIX timestamp using strtotime and then subtract the current timestamp by it.
$DBtime = "2013-10-29 17:38:55";
$db_timestamp = strtotime($DBtime);
$now = time();
$difference = $now - $db_timestamp;
echo $difference;
This will give you the difference in seconds.
You can convert the DBtime string to a unix timestamp in PHP using strtotime. In MySQL, you can use UNIX_TIMESTAMP when querying the column.
time() - strtotime($DBtime)
$date1 = new DateTime('2013-10-29 17:38:55');
$date2 = new DateTime('2013-11-29 18:28:21');
$diff = $date1->diff($date2);
echo $diff->format('%m month, %d days, %h hours, %i minutes');
$DBtime = "2013-10-29 17:38:55";
// Set whatever timezone was used to save the data originally
date_default_timezone_set('CST6CDT');
// Get the current date/time and format the same as your input date
$curdate=date("Y-m-d H:i:s", time());
if($DBtime == $curdate) {
// They match, do something
} else {
// They don't match
}

Adding months to timestamp in PHP

$bought_months = 6;
$currentDate = date('Y-m-d');
$expiring = strtotime('+'.$bought_months.' month', $currentDate);
This is what i tried.
I am trying to get a unix timestamp value of 6 months ahead from today.
How can i add months to my unix timestamp right? I tried above, since my other thought - calculating by seconds like one month in seconds: 2 629 743.83 * how many months + current timestamp, will not be precise.
(ofcourse because months have different number of days)
I get "A non well formed numeric value encountered" for the code above.
How can i do this?
Since you are using the current timestamp, you can omit the $currentDate variable altogether and it should make the notice go away too.
$bought_months = 6;
$expiring = strtotime('+'.$bought_months.' month');
To make the date correctly you'd need to use something like:
mktime( 0, 0, 0, ( $month + 6 ), $day, $year );
For maximum compatibility with post-2038 dates, use php's builtin DateTime class:
$d = new DateTime();
$d->modify("+6 months");
echo $d->format("U");

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