Unable to print a passed array in PHP - php

Question

I have 3 files:
DB.class.php - which handles all the databases.
Site.class.php - contains a function to return the latest entries in a database.
index.php - trying to print the array passed.
I am trying to pass an array into index.php from Site.class.php which is using a function from DB.class.php to put the mysql results into an associative array.
index.php:
<?php
// index.php
include 'classes/Site.class.php';
$site = new Site();
print_r($site->latestBookmarks());
?>
Site.class.php:
<?php
// Site.class.php
require_once 'DB.class.php';
class Site {
function latestBookmarks() {
$result = mysql_query("SELECT url, title FROM site ORDER BY id DESC");
$db = new DB();
return $db->processRowSet($result);
}
}
?>
DB.class.php:
<?php
// DB.class.php
class DB {
protected $db_name = "project";
protected $db_user = "root";
protected $db_pass = "root";
protected $db_host = "localhost";
// Open up a connection to the database.
public function connect() {
$connection = mysql_connect($this->db_host, $this->db_user, $this->db_pass);
mysql_select_db($this->db_name);
return true;
}
// Takes a MySQL row and returns an associative array where the keys in the array are the column names in the row set.
public function processRowSet($rowSet, $singleRow=false) {
$resultArray = array();
while ($row = mysql_fetch_assoc($rowSet)) {
array_push($resultArray, $row);
}
if ($singleRow === true)
return $resultArray[0];
return $resultArray;
}
// Select rows from the database.
public function select($table, $where) {
$sql = "SELECT * FROM $table WHERE $where";
$result = mysql_query($sql);
if (mysql_num_rows($result) == 1)
return $this->processRowSet($result, true);
return $this->processRowSet($result);
}
// Update a current row in the database.
public function update($data, $table, $where) {
foreach ($data as $column => $value) {
$sql = "UPDATE $table SET $column = $value WHERE $where";
mysql_query($sql) or die(mysql_error());
}
return true;
}
// Insert a new row into the database.
public function insert($data, $table) {
$columns = "";
$values = "";
foreach ($data as $column => $value) {
$columns .= ($columns == "") ? "" : ", ";
$columns .= $column;
$values .= ($values == "") ? "" : ", ";
$values .= $value;
}
$sql = "INSERT INTO $table ($columns) VALUES ($values)";
mysql_query($sql) or die(mysql_error());
return mysql_insert_id();
}
}
?>

Answer 1

A few problems I noticed:
You run a query in function latestBookmarks before you connect to the db;
In your function connect you connect to a database, but the result is discarded immediately, $connection is lost as soon as the function finishes.

Answer 2

You have no connection to the database when you run this line:
$result = mysql_query("SELECT url, title FROM site ORDER BY id DESC");
You will need to adjust your code to send the query string to the DB instance for processing. You can add a method to DB to execute mysql_query, and pass the query in like from Site:: latestBookmarks() like this:
$db = new DB();
$db->executeQuery("SELECT url, title FROM site ORDER BY id DESC");
return $db->processRowSet();