I have a price "0,10" or "00000,10"
Now when i try
number_format($price, 2, ',', '')
I get 0,00.
How can i fix this? I want 0,10 $.
I don't want rounding.
Or when i have 5,678, i get 5,68. But i want 5,67.
Several people have mentioned rounding it to 3 and then dropping the last character. This actually does not work. Say you have 2.9999 and round it to 3 it's 3.000.
This is still not accurate, the best solution is this:
$price = '5.678';
$dec = 2;
$price = number_format(floor($price*pow(10,$dec))/pow(10,$dec),$dec);
What this does is takes the price and multiplies it by 100 (10^decimal) which gives 567.8, then we use floor to get it to 567, and then we divide it back by 100 to get 5.67
You can increase the size of the number before rounding down with floor:
$price = floor($price * 100) / 100;
$formatted = number_format($price, 2, ',', '');
Another solution, which may give better precision since it avoids floating-point arithmetic, is to format it with three decimals and throw away the last digit after formatting:
$formatted = substr(number_format($price, 3, ',', ''), 0, -1);
you should convert comma-filled number back to normal decimal before with str_replace.
$number = str_replace(",", ".", $number);
and then you can use number_format
"00000,10" is a string. You should a decimal point. To get the desired behaviour, you could use:
echo substr(number_format(str_replace(',', '.', $price), 3, ',', ''), 0, -1);
Use this (needs activated intl PHP extension)
$numberFmtCurrency = new NumberFormatter('de_AT', NumberFormatter::CURRENCY);
$numberFmtCurrency->setAttribute(NumberFormatter::ROUNDING_INCREMENT, 0);
$numberFmtCurrency->formatCurrency(328.13, 'EUR'); // prints € 328.13 (and not 328.15)
If you are literally just wanting to clear leading zeroes and just limit the length, rather than round to a certain amount of decimal places, a more generalised solution could be this function:
function cutafter($string,$cutpoint,$length)
{
$temp = explode($cutpoint,$string);
$int = $temp[0];
$sub = $temp[1];
return number_format($int,0).','.substr($sub,0,$length);
}
Example:
$number = "005,678";
$answer = cutafter($number,",",2);
$answer now equals "5,67"
Just before number_format is executed the string "0,10" is converted by php to an number. because php always uses the engish notation the it won't look after the comma.
echo "4 apples" + 2;
output: 6
The " apples" part is ignored just as your ",10" is ignored.
Converting the "," to a "." allows php to see the other digits.
$price = str_replace(',', '.', '0,10');
number_format($price, 2, ',', '');
My problem was that html validator error messege thar number_format() argument is not double.
I solved this error message by placing floatval for that argument like number_format(floatval($var),2,'.',' ') and that is working good.
function format_numeric($value) {
if (is_numeric($value)) { // is number
if (strstr($value, ".")) { // is decimal
$tmp = explode(".", $value);
$int = empty($tmp[0]) ? '0' : $tmp[0];
$dec = $tmp[1];
$value = number_format($int, 0) . "." . $dec;
return $value;
}
$value = number_format($value);
return $value;
}
return $value; // is string
}
Unit Testing:
Passed / 1100000 => 1,100,000
Passed / ".9987" => .9987
Passed / 1100.22 => 1,100.22
Passed / 0.9987 => 0.9987
Passed / .9987 => 0.9987
Passed / 11 => 11
Passed / 11.1 => 11.1
Passed / 11.1111 => 11.1111
Passed / "abc" => "abc"
See this answer for more details.
function numberFormat($number, $decimals = 0, $decPoint = '.' , $thousandsSep = ',')
{
$negation = ($number < 0) ? (-1) : 1;
$coefficient = pow(10, $decimals);
$number = $negation * floor((string)(abs($number) * $coefficient)) / $coefficient;
return number_format($number, $decimals, $decPoint, $thousandsSep);
}
Related
I have a calculation that returns this double: 6.4971508379888. If I cast it to a float and echo it, it's the same number. I want to display (not round) the number with only two decimals, so I tried:
number_format((float)$number, 2, '.', '')
and
sprintf('%0.2f', (float)$number)
but in both cases I see 6.50 instead of 6.49. Why is this happening?
PHP automatically round the value based on given precision
If you want your expected results then follow the following code.
$precision = 2;
$number = floor($number * pow(10,$precision))/pow(10,$precision);
echo number_format((float)$number, $precision, '.', '');
This is a slight modification to the accepted answer because the solution provided wasn't giving an accurate result. It was causing the last digit to get rounded (down).
$digits = 2;
$number = floor($number * pow(10, ($digits + 1)) / pow(10, ($digits + 1));
echo number_format($number, $digits, '.', '');
Also, there should be no need to type-cast to a float when passing the number to number_format(). The calculation (and the function itself) will automatically set the type accordingly.
I need help converting a string that contains a number in scientific notation to a double.
Example strings:
"1.8281e-009"
"2.3562e-007"
"0.911348"
I was thinking about just breaking the number into the number on the left and the exponent and than just do the math to generate the number; but is there a better/standard way to do this?
PHP is typeless dynamically typed, meaning it has to parse values to determine their types (recent versions of PHP have type declarations).
In your case, you may simply perform a numerical operation to force PHP to consider the values as numbers (and it understands the scientific notation x.yE-z).
Try for instance
foreach (array("1.8281e-009","2.3562e-007","0.911348") as $a)
{
echo "String $a: Number: " . ($a + 1) . "\n";
}
just adding 1 (you could also subtract zero) will make the strings become numbers, with the right amount of decimals.
Result:
String 1.8281e-009: Number: 1.0000000018281
String 2.3562e-007: Number: 1.00000023562
String 0.911348: Number: 1.911348
You might also cast the result using (float)
$real = (float) "3.141592e-007";
$f = (float) "1.8281e-009";
var_dump($f); // float(1.8281E-9)
Following line of code can help you to display bigint value,
$token= sprintf("%.0f",$scienticNotationNum );
refer with this link.
$float = sprintf('%f', $scientific_notation);
$integer = sprintf('%d', $scientific_notation);
if ($float == $integer)
{
// this is a whole number, so remove all decimals
$output = $integer;
}
else
{
// remove trailing zeroes from the decimal portion
$output = rtrim($float,'0');
$output = rtrim($output,'.');
}
I found a post that used number_format to convert the value from a float scientific notation number to a non-scientific notation number:
Example from the post:
$big_integer = 1202400000;
$formatted_int = number_format($big_integer, 0, '.', '');
echo $formatted_int; //outputs 1202400000 as expected
Use number_format() and rtrim() functions together. Eg
//eg $sciNotation = 2.3649E-8
$number = number_format($sciNotation, 10); //Use $dec_point large enough
echo rtrim($number, '0'); //Remove trailing zeros
I created a function, with more functions (pun not intended)
function decimalNotation($num){
$parts = explode('E', $num);
if(count($parts) != 2){
return $num;
}
$exp = abs(end($parts)) + 3;
$decimal = number_format($num, $exp);
$decimal = rtrim($decimal, '0');
return rtrim($decimal, '.');
}
function decimal_notation($float) {
$parts = explode('E', $float);
if(count($parts) === 2){
$exp = abs(end($parts)) + strlen($parts[0]);
$decimal = number_format($float, $exp);
return rtrim($decimal, '.0');
}
else{
return $float;
}
}
work with 0.000077240388
I tried the +1,-1,/1 solution but that was not sufficient without rounding the number afterwards using round($a,4) or similar
I have these value stored in a decimal 10,2 field
1052730
956700
How do i print this using php so that the value is like
$10,527.30
$9,567.00
basically i am trying to avoid the value as
$1,052,730 <--- this i dont want
You can use the
money_format($format, $value)
function in php. The details of the formatting is given here.
Well, assuming that 1052730 is really 10527.30 as alluded to in your question:
$number = 1052730;
$decimals = $number % 100; //30 in this case
$digits = floor($number / 100);
$paddedDecimals = str_pad($digits, 2, '0', STR_PAD_LEFT);
$out = '$' . number_format($digits, 0).'.'.$paddedDecimals;
echo $out; // $10,527.30
There are no floating point calculations used for the decimal part, so there's no need to worry about precision issues (although at this precision it would likely be hard to get a float error in there)...
Just divide by 100:
<?php
echo number_format(1052730/100, 2, '.', ',') . PHP_EOL;
echo number_format(956700/100, 2, '.', ',') . PHP_EOL;
printf ("$%01.2f", ($input / 100));
I'd like to know if exists some function to automatically format a number by it's decimal, so if I have:
<?php
// $sql_result["col_number"] == 1,455.75
number_format ($sql_result["col_number"], 2, ".", "");
// will return 1455.75
// $sql_result["col_number"] == 1,455.00
number_format ($sql_result["col_number"], 2, ".", "");
// could I get 1455 instead of 1455.00?
?>
so my answer is if does exist some way to remove the decimals if I have DECIMAL data forma in my DB only when it's round?
Or shoud I do something like that?
<?php
// $sql_result["col_number"] == 1,455.00
str_replace(".00", "", (string)number_format ($sql_result["col_number"], 2, ".", ""));
// will return 1455
?>
floatval or simply casting to float
php > echo floatval(7.00);
7
php > echo floatval(2.30);
2.3
php > echo floatval(1.25);
1.25
php > echo floatval(1.125);
1.125
php > echo (float) 7.00;
7
php > echo (float) 2.30;
2.3
php > echo (float) 1.25;
1.25
php > echo (float) 1.125;
1.125
I actually think that your workaround is as good as any. It's simple and clear, and there's really no point talking about performance here, so just go for it.
As Emil says yours are good. But if you want to remove 0 from e.g. 7.50 too, I've got a suggestion, rtrim():
<?php
// if $sql_result["col_number"] == 1,455.50
rtrim(rtrim(number_format($sql_result["col_number"], 2, ".", ""), '0'), '.');
// will return 1455.5
?>
You could also use rtrim(), which would remove excess 0s, in the case where you might want to keep one decimal place but not the excess zeros. (For example, 4.50 becomes 4.5.) Also allows you to change the number of decimal places from 2 to any other number.
rtrim(rtrim((string)number_format($value, 2, ".", ""),"0"),".");
// 4.00 -> 4
// 4.50 -> 4.5
// 4.54000000 -> 4.54 (if you're doing more decimal places)
Actually I think the cleanest way I can think of to do this for someone that just did a search looking for this sort of thing is to do this:
( number_format ($sql_result["col_number"], 2) * 100 ) / 100;
I've been accused of doing something like this:
floatval($foo) == intval($foo) ? number_format($foo) : number_format($foo,2);
If you are targeting US currency I like to use this method:
function moneyform($number, $symbol = true) {
return str_replace(".00", "", money_format(($symbol? '%.2n' : "%!n"), $number));
}
moneyform(1300999);
-->$1,300,999
moneyform(2500.99);
-->$2,500.99
moneyform(2500.99, false);
-->2,500.99
Mine since most quantity or pieces do not require decimal, this function will only show decimal when needed.
str_replace(".00", "", number_format($this->pieces, 2));
Warren.S answer helped me out. I didn't need the number_format function, so I just did this
$value=$value-0;
But in the OP's case, he needs number_format to remove the commas. So this would work for him
$value=number_format ($sql_result["col_number"], 2, ".", "")-0;
Since I could not find a flexible solution I wrote a simple function to get the best result:
function getValueFormattedWithMinimalDecimals($value, $max_decimals = 2, $dec_point = ',', $thousands_sep = '') {
$bestNumberOfDecimals = -1;
$decimal = 0;
while ($decimal <= $max_decimals) {
$bestNumberOfDecimals = $decimal;
$valueDecimals = number_format($value, $decimal);
if (floatval($value) == $valueDecimals) {
break;
}
$decimal++;
}
if($bestNumberOfDecimals > 0 && number_format($value, $bestNumberOfDecimals) == number_format($value, 0)) {
$bestNumberOfDecimals = 0;
}
return number_format($value, $bestNumberOfDecimals, $dec_point, $thousands_sep);
}
What about
number_format($value,2) - 0;
I want that real numbers would be for example 12.92, but not 12.9241. Is it possible to do like that?
In PHP, try number_format:
$n = 1234.5678;
// Two decimal places, using '.' for the decimal separator
// and ',' for the thousands separator.
$formatted = number_format($n, 2, '.', ',');
// 1,234.57
For PHP you can use number_format(), for MySQL use the FORMAT() function.
MySQL: http://dev.mysql.com/doc/refman/5.1/en/string-functions.html#function_format
FORMAT(number, 2)
Example:
mysql> SELECT FORMAT(12332.123456, 4);
-> '12,332.1235
PHP: http://php.net/manual/en/function.number-format.php
$number = 1234.5678;
$formatted_number = number_format($number, 2, '.', '');
// 1234.56
$number = 1234.5678;
$teX = explode('.', $number);
if(isset($teX[1])){
$de = substr($teX[1], 0, 2);
$final = $teX[0].'.'.$de;
$final = (float) $final;
}else{
$final = $number;
}
final will be 1234.56
You can multiply your number by 100, do a rounding of the result and then divide back by 100.
Or in php use the round function round function
$result=round(12.9241, 2);