PHP: why i am getting this error ??? "syntax error, unexpected '{'" - php

Question

i wanted to arrange this arrays element in assending order and wrote the below code :
<?php
$a=array("z","s","a","j","t","b");
for($i=0;$i<=6;$i++)
{
if ($i[0]<$i[1]) { echo $i[1]; }
else if ($i[1]<$i[2]) { echo $i[2]; }
else if ($i[2]<$i[3]) { echo $i[3]; }
else if ($i[3]<$i[4]) { echo $i[4]; }
else if ($i[4]<$i[5]) { echo $i[5]; }
else if ($i[5]<$i[6]) { echo $i[6]; }
else if ($i[6]<$i[7]) { echo $i[7]; }
else if ($i[7]<$i[8]) { echo $i[8]; }
else if ($i[8]<$i[9]) { echo $i[9]; }
else if ($i[9]<$i[10]) { echo $i[10]; }
else if ($i[10]<$i[11]) { echo $i[11]; }
else ($i[11]<$i[12]) { echo $i[12]; }
}
?>
but i an getting the following error :
Parse error: syntax error, unexpected '{' in C:\wamp\www\arange.php on line 16
how can i rectify it

Answer 1

This snippet is the problem:
else ($i[11]<$i[12]) { echo $i[12]; }
Either edit it into elseif or remove the ($i[11]<$i[12]).

Answer 2

I'd do this differently. Consider using PHP's built in sort() function.
$a = array("z","s","a","j","t","b");
sort($a);
foreach ($a as $element) {
echo "$element\n";
}
Also read about the foreach statement.

Answer 3

$b = '';
$a=array("z","s","a","j","t","b");
foreach($a as $i) if($i > $b) $b = $i;
echo $b;

Answer 4

Check out the manual for a clear example of the elseif/else if syntax. The else part in your code is the problem.

Answer 5

if ($i[5]<$i[6]) { echo $i[6]; }
actually will output something like this;
if ( b < ) { echo ; }
That why you see kinda error...