I have a list
Each row has a common input field "sort_order" that's stored in MySQL db.
<input name="sort_order" type="text" value="<?php echo $cat['sort_order']; ?>" size="3" />
I want to be able to change the sort order inline, without going into the edit form.
How do I get all the values into the database. I think I need to loop through each row adding the sort_order[row_id] and value to an array. But I am stuck on how to achieve this.
all the values are posting according to firePHP. sort_order[50] 1, sort_order[51] 2 etc.
New Attempt at explaining:
I have a list view with 2 input fields.
<input name="cat_id" type="hidden" value="<?php echo $cat['cat_id']; ?>" />
<input name="sort_order" type="text" value="<?php echo $cat['sort_order']; ?>" size="3" />
I have a function that's called on post in the controller:
public function sortOrderUpdate(){
//collect the values of cat_id and sort_order from each input into a array
//$this->request->post['sort_order']
//$this->request->post['cat_id']
//send to the model
$this->model_cat->updateCatSortOrder($sortorderarray);
}
And the database model file function:
public function updateCatSortOrder($sortorderarray){
foreach((int)$sortorderarray as $sort){
$this->db->query("UPDATE cat SET sort_order='" . (int)$sort['sort_order'] . "' WHERE cat_id = '" . (int)$sort['cat_id'] . "'");
}
}
Whats the best way to achieve this?
Just use empty square brackets:
<input type="text" name="sort_order[]" value"<?php echo $sort_order; ?>" />
You can then access the input as an array, saving you from building it yourself. It'll be stored as $_POST['sort_order'] (or $_GET, depending on the method attribute specified in your <form> tag).
On a related note, you should probably escape $sort_order when echoing it:
<input type="text" name="sort_order[]" value"<?php echo htmlspecialchars($sort_order); ?>" />
i would not recommend using [ ] in html names.
<input type="text" name="sort_order_<?php echo $row_id; ?>" value"<?php echo $sort_order; ?>" />
say, you have 50 input fields, when posted, you can build an array this way:
$sortorder = array();
for($i=0; $i<50; $i++){
$sortorder[] = $_REQUEST['sort_order_' . $i];
}
Ok this seems to work:
<input name="cat_id[]" type="hidden" value="<?php echo $cat['cat_id']; ?>" />
<input name="sort_order[]" type="text" value="<?php echo $cat['sort_order']; ?>" size="3" />
Controller:
public function updateCatSortOrder(){
$sortvals = $this->request->post['sort_order']; //$this->request->post same as $_POST
$row = $this->request->post['cat_id'];
$n = count($this->request->post['cat_id']);
$sortorder = array();
for($i=0; $i<$n; $i++){
$sortorder[] = array(
'cat_id' => $row[$i],
'sort_order' => $sortvals[$i]
);
}
$this->model_cat->updateCatSortOrder($sortorder);
}
Model:
//UPDATE CAT SORT ORDER
public function updateCatSortOrder($sortorder){
foreach($sortorder as $sort){
$this->db->query("UPDATE cat SET sort_order='" . $this->db->escape($sort['sort_order']) . "' WHERE cat_id = '" . $this->db->escape($sort['cat_id']). "'");
}
}
Related
I need some help with this code.
In my code, I have the following hidden form fields as array:
Code:
<form action='final.php' method = 'POST'>
<input type="hidden" name="employeename" value="<?php echo $employeename; ?>">
<input type="hidden" name="ttitle" value="<?php echo $ttitle; ?>">
<input type="hidden" name="sourcename[]" value="<?php echo $_POST['sourcename' . $id]; ?>">
<input type="hidden" name="sourceaddress[]" value="<?php echo $_POST['sourceaddress' . $id]; ?>">
<input type="hidden" name="income[]" value="<?php echo $_POST['income' . $id]; ?>">
<input type="hidden" name="spousename[]" value="<?php echo $_POST['spousename' . $id]; ?>">
<input type="hidden" name="spouseAddress[]" value="<?php echo $_POST['spouseAddress' . $id]; ?>">
<input type="hidden" name="spouseIncome[]" value="<?php echo $_POST['spouseIncome' . $id]; ?>">
</form>
These hidden form fields are on a page called reviewe.php passed from pervious page called order.php.
I am trying to insert the values of these form fields from a page called finel.php as the action on the form indicates.
Code:
$sql = 'INSERT INTO `myDB`.`wp_myTable` ( `employeeID`'
. ', `sourcename`, `sourceaddress`, `income`,`spousename`,`spouseAddress`,`spouseincome` )'
. ' VALUES ( ? , ? , ? , ? , ? , ? , ? )';
if( $sth = mysqli_prepare($conn,$sql) ) {
mysqli_stmt_bind_param($sth,'sssssss'
,$last_id
,$_POST["sourcename"]
,$_POST["sourceaddress"]
,$_POST["income"]
,$_POST["spousename"]
,$_POST["spouseAddress"]
,$_POST["spouseIncome"]
);
When this code is excuted, I get this error:
Notice: Array to string conversion in c:\xampp\folder\final.php
I know this error means that I have hidden form fields I am trying to pass as an array but I am trying to insert them as string.
However, I don't know how to modify the code to accept the variables as array.
Any advice ? Thankyou.
You can get the value of the hidden inputs, while they are in an array, by simply getting the first index of the array.
if( $sth = mysqli_prepare($conn,$sql) ) {
mysqli_stmt_bind_param($sth,'sssssss'
,$last_id
,$_POST["sourcename"][0]
,$_POST["sourceaddress"][0]
,$_POST["income"][0]
,$_POST["spousename"][0]
,$_POST["spouseAddress"][0]
,$_POST["spouseIncome"][0]
);
You can use implode function to write the array as string by doing something like this:
implode(",", $array);
and then use explode function to read it back in an array like this:
explode(",", $array);
I want to get three values separated by a comma when the form is submitted. The value from the checkbox, textbox 1 and textbox 2.
This is my code that retrieves values from mysql database and generates checkboxes and two corresponding textboxes.
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
<?php
$query = "SELECT * FROM subject";
$data = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($data)){
$s = $row['sub'];
echo $s;
?>
<input type="checkbox" name="req_sub[]" value= "<?php echo $s; ?>" />
<input type="text" name="<?php echo $s; ?>" placeholder="Total Number" />
<input type="text" name="<?php echo $s; ?>" placeholder="Pass Number" />
<?php
}
?>
<input type="submit" name="submit" value="Add">
</form>
Suppose the user checks the first three boxes , and enters the values like in this picture -
when I click add, I get the values --
Physics
Math
Chemistry
by using the code below:
<?php
if (isset($_POST['submit'])) {
if (!empty($_POST['req_sub'])) {
foreach ($_POST['req_sub'] as $selected) {
echo $selected."</br>";
}
}
}
?>
but how do I get the values like this-
Physics,40,30
Math,40,30
Chemistry,30,25
I want this output in a variable so that I can store it in my database table.
I have spent several hours behind this in last few days. Please help me with this one.
you need to assign unique names to the <input type="text" ... /> so you can recieve its values in the PHP.
Second, you need to write PHP code, that's concatenating those values.
For example, your HTML code might be:
<input type="checkbox" name="req_sub[]" value= "<?php echo $s; ?>" />
<input type="text" name="total[<?php echo $s; ?>]" placeholder="Total Number" />
<input type="text" name="pass[<?php echo $s; ?>]" placeholder="Pass Number" />
and your PHP code might be:
if (isset($_POST['submit'])) {
if (!empty($_POST['req_sub'])) {
foreach ($_POST['req_sub'] as $selected) {
$total = $_POST['total'][$selected];
$pass = $_POST['pass'][$selected];
$var = $selected . ',' . $total . ',' . $pass;
echo $var . '<br />';
}
}
}
Am looping products out from product table to add them to cart table. only the selected product by checking the checkbox should be added, but if you select, the selected ones do not correspond..
HERE IS THE HTML GETTING THE PRODUCTS OUT
<html>
<form action="#" id="" class="horizontal-form" method="post">
<?php
$LISTP = "SELECT * FROM products ORDER BY id";
$sn = 0;
$stmt = $pdo->prepare($LISTP);
$stmt->execute();
while($list = $stmt->fetch(PDO::FETCH_ASSOC)){
$sn = $sn + 1;
$ID = $list['id'];
$NAME = $list['name'];
?>
<input type="checkbox" name="slected[]" class="checkboxes" value="1" />
<input type="hidden" name="productid[]" class="" value="<?php echo $ID;?>" />
<input type="text" name="name[]" class="" value="<?php echo $NAME;?>" />
<?php }?> </form>
<?php
// now when we submot the form
$slected = $_POST['slected'];
$prod = $_POST['productid'];
$name = $_POST['name'];
foreach($prod as $key => $product){
if($slected[$key]>0){
echo $product.' '.$name[$key].' '.#$slected[#$key].'--<br>';
}
// the problem is here, if you check all product it will work well, but if you check the second one
// it would echo the second one giving it the name of the first one which was not checked at all
?>
I used to do this the same way in the past, and have discovered what I think is a better way. Rather than having a hidden input that stores the ID, just use the ID as the index for all of the form variable keys:
<input type="checkbox" name="slected[<?php echo $ID; ?>]" class="checkboxes" value="1" />
<input type="text" name="name[<?php echo $ID; ?>]" class="" value="<?php echo $NAME;?>" />
Then, your PHP can be simplified:
// now when we submot the form
$slected = $_POST['slected'];
$name = $_POST['name'];
foreach( (array)$slected as $ID => $on ) {
echo $product . ' ' . $name[$ID] . ' ' . $ID . '--<br>';
}
So - basically, your $slected variable will contain an array of only items that are selected, AND you have the product ID built in to the $slected array.
There are two values I want to get from user that is name and price. I have made an auto generating rows function that generate input boxes with same name. Now the thing is I want to store them in database. I using foreach but that only get one array. I want to store both name as well as price. How can I do that. Here is my code.
HTML Form
<form method="post">
<input type="text" name="name[]" /><input type="text" name="price[]" />
<input type="text" name="name[]" /><input type="text" name="price[]" />
<input type="text" name="name[]" /><input type="text" name="price[]" />
<input type="text" name="name[]" /><input type="text" name="price[]" />
<input type="submit" value="Submit" name="submit" />
</form>
PHP Code
if(isset($_POST['submit']))
{
foreach($_POST['name'] as $name)
{
echo $name;
}
}
Call the index in the loop as well and then select the corresponding value from the other array.
foreach($_POST['name'] as $id => $name)
{
echo $name;
echo $_POST['price'][$id]
}
How about this
if(isset($_POST['submit']))
{
$names = $_POST['name']; # array
$prices = $_POST['price']; # array
foreach($names as $id => $name)
{
echo $name;
echo "<br>";
echo $prices[$id]
}
}
Provided you know both arrays will be the same length, a simple for loop will do:
if(isset($_POST['submit']) && count($_POST['name']) == count($_POST['price']))
{
for($i=0; $i < count($_POST['name']); $i++)
{
echo $_POST['name'][$i] . ' ' . $_POST['price'][$i];
}
}
Try this
$names = array_combine($_POST['name'], $_POST['price']);
foreach($names as $firstname => $price) {
echo $firstname . ' ' . $price . '<br>';
}
I am having the hardest time figuring out something that I think should be simple. I need to update multiple rows in my database with one submit button. I have it working with a submit for each row now, but I need to combine it. Here's what I'm trying. Where have I gone wrong? (I've been going off of multiple tutorials I found online and I think I have things all mixed up).
Here's the form:
<?php foreach ($teams as $team):
$id[]=$team['id'];?>
<form action="?update" method="post">
<div class="team-box">
<h2><?php echo $team['name'] ?></h2>
<label for="name">Name:</label>
<input type="text" name="name" value="<?php echo $team['name'] ?>" />
<label for="name">Match Wins:</label>
<input type="text" name="mwins" value="<?php echo $team['mwins'] ?>" />
<label for="name">Match Losses:</label>
<input type="text" name="mlosses" value="<?php echo $team['mlosses'] ?>" />
<label for="name">Match Ties:</label>
<input type="text" name="mties" value="<?php echo $team['mties'] ?>" />
<label for="name">Game Wins:</label>
<input type="text" name="gwins" value="<?php echo $team['gwins'] ?>" />
<label for="name">Game Losses:</label>
<input type="text" name="glosses" value="<?php echo $team['glosses'] ?>" />
<input type="hidden" name="id" value="<?php echo $team['id'] ?>" />
</div>
Here's the PHP to handle the UPDATE:
try
{
foreach($_POST['id'] as $id) {
$sql = 'UPDATE teams SET
name = "' . $_POST['name'.$id] . '",
mwins = "' . $_POST['mwins'.$id] . '",
mlosses = "' . $_POST['mlosses'.$id] . '",
mties = "' . $_POST['mties'.$id] . '",
gwins = "' . $_POST['gwins'.$id] . '",
glosses = "' . $_POST['glosses'.$id] . '"
WHERE id = "' . $_POST['id'.$id] . '"';
$pdo->exec($sql);
}
}
catch (PDOException $e)
{
$error = 'Error adding submitted team: ' . $e->getMessage();
include 'error.html.php';
exit();
}
header('Location: .');
exit();
Thanks in advance!
There are a couple of things that need fixing.
The FORM must be outside the foreach.
The '...name="name" value="...', to agree with the _POST code, should read instead:
... name="name" value="...
This way, a single POST will submit, say,
name123="Rangers"
mwins174="123"
Then you need all IDs. You can do that by issuing, in the foreach, this:
<input type="hidden" name="id[]" value="<?php print $team['id']; ?>" />
This will result in HTML:
<input type="hidden" name="id[]" value="123" />
...
<input type="hidden" name="id[]" value="456" />
and in $_POST['id'] being an array containing 123, 456 and so on.
You could also put in HTML:
<input type="text" name="name[<?php print $team['id']; ?>]" value="...
so that $_POST['name'] would be a vector with the same keys as the values of id, and therefore:
foreach($id as $team_id)
{
// Pseudocode
UPDATE... SET name=$name[$team_id]... WHERE id = $team_id;
}
This way you have one SUBMIT, and multiple UPDATEs.
Since all your field names change for each UPDATE query, you will need to execute separate queries as you already do. I don't think you would be able to perform a single UPDATE query.
I don't understand, what's wrong with executing several update queries?