How to retrieve an array of each date within two epochs - php

Question

I have two epochs. I want to figure out all the dates that are valid within the two epochs.
For example, if I have the epochs 946684800 (Sat, 01 Jan 2000 00:00:00 GMT) and 947203200 (Fri, 07 Jan 2000 00:00:00 GMT), I want to be able to get: 01/01/2000, 02/01/2000, 03/01/2000, 04/01/2000, etc.

Answer 1

If you have PHP 5.3 or newer, you could do this:
$date1 = new DateTime;
$date1->setTimestamp(946684800);
$date2 = new DateTime;
$date2->setTimestamp(947203200);
$interval = new DateInterval('P1D');
while ( $date1 <= $date2 )
{
$dates_in_between[] = $date1->getTimestamp();
$date1->add($interval);
}
Alternatively, you could use this:
// 1 day = 60 seconds * 60 minutes * 24 hours = 86400
for ($date = 946684800; $date <= 947203200; $date += 86400)
$dates_in_beteween[] = $date;
$dates_in_between will contain a list of "dates" in between.

Answer 2

PHP time values are just Unix timestamps - seconds since Jan 1/1970. Going off PHP 5's datetime object:
$start = strtotime('01 Jan 2000');
$end = strtotime('07 Jan 2000');
for ($d = $start; $d <= $end; $d += 86400) { // increment by 86,400 seconds, aka 1 day
echo date('d/m/Y', $d);
}
There's better ways of going about it, using the DateTime / DateInterval objects, but this is just to show the basics.

Answer 3

Given that your epoch is in seconds you could always add the number of seconds found in a day to the first epoch:
946684800 + 86400 = 946771200 -> Sun, 02 Jan 2000 00:00:00 GMT
And go on like this, I explain better:
947203200 - 946684800 = 518400 / 86400 = 6 (exactly 6 days)
so (PSEUDOCODE):
for(int i = 946684800; i<946684800 ;i+=86400){
day = getDate(i);
}

Answer 4

$epoch1 = '946684800';
$epoch2 = '947203200';
$i = 0;
while($time < $epoch2) {
$time = mktime(0, 0, 0, date("m", $epoch1) , date("d", $epoch1)+$i, date("Y",$epoch1));
echo date('d/m/Y', $time)."<br>";
$i++;
}

Answer 5

If understanding the question right, you want every DAY within the 2 epochs (2000-01-01 and 2000-01-07)..
Can be done like so:
<?php
$epoch1 = 946684800;
$epoch2 = 947203200;
$difference = $epoch1 - $epoch2;
..
//count days
$amountOfDays = round(($epoch2-$epoch1)/86400);
//looping all days
for($i=1; $i<=$amountOfDays; $i++) {
echo date('d/m/Y', $epoch1+($i*86400);
}
?>

Answer 6

$start = strtotime('2011-06-01');
$end = strtotime('2011-06-15');
$date = $start;
$anArray = array();
while ($date <= $end) {
$date = strtotime("+1 DAY", $date);
$anArray[] = $date;
}