GET request not returning data on success - php

Ok this problem is starting to get annoying!
I have this jquery ajax request code:
$.ajax({
type: "GET",
url: "/nameCheck.php",
data: {addressName: ""+addressName+"", customer: customer},
success: TEST,
error: reportProblem
});
the nameCheck.php looks like this:
include_once("db_connect.php3");
$addressName = $_GET["addressName"];
$customer = $_GET["customer"];
$search = mysql_query("select count(*) from Address where AddressName=".quote_correct($addressName)." and CustomerNumber=$customer",$database);
$rows=mysql_fetch_array($search);
$number_of_rows = $rows[0];
// note quote_correct is just a function to clean up the users input
if ($number_of_rows>1)
{
$message ="NO";
}
else
{
$message ="OK";
}
echo $message;
?>
and on success the TEST function looks like this
function TEST(data,status){
alert(data+" - "+ status);
}
Through a log file I set up in the php code - I see the process of checking to see if the customer name exists is working and I get the proper response of OK or NO.
The ajax call is a success too - and the TEST function is called - but no data is present..
Does anyone know why this isn't working?

Try having your ajax call look like this:
$.ajax({
type: "GET",
url: "/nameCheck.php",
data: { addressName: "" + addressName + "", customer: customer },
success: function (data) {
alert(data);
},
error: function(xhr, status, error) {
}
});

I usually also state in my get/post calls the return type. (json,html...) and does the returning php function know what to return?

You need to set the content-type header in your PHP. The default response is txt/html, jQuery wants JSON.
header('Content-type: application/json');

Related

Can't receive POST data through AJAX

So what I'm trying to do, is send some jQuery variables to my PHP script using Ajax post. However, for some reason, I cannot set the PHP variables to contain the values of the jQuery variables.
I have tried multiple types of Ajax data, like forms (new FormData();) and arrays.
script.js
$.ajax({
url: 'file.php',
type: 'POST',
data: {
'document_id': document_id,
'section_id': section_id,
'active_state': active_state
},
beforeSend: function () {
console.log('the data is: ' + document_id + section_id + active_state + '...');
},
success: function (response) {
console.log(response + ' is locked!');
},
fail: function (error) {
console.log(error + ' could not be locked');
});
file.php
print_r($_POST);
However, in the success function of the Ajax request, I DO receive an array back with the proper variables. When I check the output of the PHP file, it just returns a blank array.
This is what I eventually need to do:
if(isset($_POST['document_id'])){
$document_id = $_POST['document_id'];
$section_id = $_POST['section_id'];
$active_state = $_POST['active_state'];
// echo back the data to the success function
// proceed with insert into database
} else {
echo 'the data has not been set';
}
Any insights on what I may be doing wrong?
Try to use this to get the response from ajax request
<?php
extract($_POST);
print_r($_POST);
?>

AJAX call not returning values from PHP

I am making an AJAX call but its not returning a value in the success handler. This is my AJAX call. I have checked that it's hitting the PHP file correctly
var msj;
$.ajax({
type: "POST",
url: "ajaxFile.php",
data: {
name: name,
status: status,
description: description,
action: 1
},
sucess: function(data){
msj = data;
alert(data);
}
});
alert(msj);
My PHP code is as follow:
if (isset($_POST['action']))
{
if ($_POST['action'] == 1)
{
$obj = new project($_POST['name'], $_POST['active'], $_POST['description']);
$obj = testInput($obj);
$check = validateName($obj->getName());
if ($check == 1)
{
echo $nameError;
}
else
{
print "asdasdasd";
}
}
}
Please help me tracking the mistake.
As far as I can see there's a syntax error in your code. There's sucess instead of success.
You are only providing a "success" callback function. You should also provide an "error" callback so you can debug and see what is wrong. You can also provide a "complete" callback that will be used in both alternatives.
var msj;
$.ajax({
type:"POST",
url:"ajaxFile.php",
data:{name:name,status:status,description:description,action:1},
complete:function(data){
msj=data;
alert(data);
}
});
alert(msj);
In your PHP, you could add
header('Content-Type: application/json');
to make sure JQuery identify well your web service.

jQuery Ajax(post), data not being received by PHP

The Ajax function below sends data from a page to the same page where it is interpreted by PHP.
Using Firebug we can see that the data is sent, however it is not received by the PHP page. If we change it to a $.get function and $_GET the data in PHP then it works.
Why does it not work with $.post and $_POST
$.ajax({
type: "POST",
url: 'http://www.example.com/page-in-question',
data: obj,
success: function(data){ alert(data)},
dataType: 'json'
});
if there is a problem, it probably in your php page.
Try to browse the php page directly in the browser and check what is your output.
If you need some inputs from post just change it to the GET in order to debug
try this
var sname = $("#sname").val();
var lname = $("#lname").val();
var html = $.ajax({
type: "POST",
url: "ajax.class.php",
data: "sname=" + sname +"&lname="+ lname ,
async: false
}).responseText;
if(html)
{
alert(html);
return false;
}
else
{
alert(html);
return true;
}
alax.class.php
<php
echo $_REQUEST['sname'];
echo $_REQUEST['sname'];
?>
Ajax on same page will not work to show data via POST etc because, PHP has already run that's why you would typically use the external page to process your data and then use ajax to grab the response.
example
success: function(){
$('#responseDiv').text(data);
}
You are posting the data... Check if the target is returning some data or not.
if it returns some data then only you can see the data otherwise not.
add both success and error.. so that you can get what exactly
success: function( data,textStatus,jqXHR ){
console.log(data);//if it returns any data
console.log(textStatus);//or alert(textStatus);
}
error: function( jqXHR,textStatus,errorThrown ){
console.log("There is some error");
console.log(errorThrown);
}

Send data from Javascript to PHP and use PHP's response as variable in JS

I have checked around, but can't seem to figure out how this is done.
I would like to send form data to PHP to have it processed and inserted into a database (this is working).
Then I would like to send a variable ($selected_moid) back from PHP to a JavaScript function (the same one if possible) so that it can be used again.
function submit_data() {
"use strict";
$.post('insert.php', $('#formName').formSerialize());
$.get('add_host.cgi?moid='.$selected_moid.');
}
Here is my latest attempt, but still getting errors:
PHP:
$get_moid = "
SELECT ID FROM nagios.view_all_monitored_objects
WHERE CoID='$company'
AND MoTypeID='$type'
AND MoName='$name'
AND DNS='$name.$selected_shortname.mon'
AND IP='$ip'
";
while($MonitoredObjectID = mysql_fetch_row($get_moid)){
//Sets MonitoredObjectID for added/edited device.
$Response = $MonitoredObjectID;
if ($logon_choice = '1') {
$Response = $Response'&'$logon_id;
$Response = $Response'&'$logon_pwd;
}
}
echo json_encode($response);
JS:
function submit_data(action, formName) {
"use strict";
$.ajax({
cache: false,
type: 'POST',
url: 'library/plugins/' + action + '.php',
data: $('#' + formName).serialize(),
success: function (response) {
// PROCESS DATA HERE
var resp = $.parseJSON(response);
$.get('/nagios/cgi-bin/add_host.cgi', {moid: resp });
alert('success!');
},
error: function (response) {
//PROCESS HERE FOR FAILURE
alert('failure 'response);
}
});
}
I am going out on a limb on this since your question is not 100% clear. First of all, Javascript AJAX calls are asynchronous, meaning both the $.get and $.post will be call almost simultaneously.
If you are trying to get the response from one and using it in a second call, then you need to nest them in the success function. Since you are using jQuery, take a look at their API to see the arguments your AJAX call can handle (http://api.jquery.com/jQuery.post/)
$.post('insert.php', $('#formName').formSerialize(),function(data){
$.get('add_host.cgi?moid='+data);
});
In your PHP script, after you have updated the database and everything, just echo the data want. Javascript will take the text and put it in the data variable in the success function.
You need to use a callback function to get the returned value.
function submit_data(action, formName) {
"use strict";
$.post('insert.php', $('#' + formName).formSerialize(), function (selected_moid) {
$.get('add_host.cgi', {moid: selected_moid });
});
}
$("ID OF THE SUBMIT BUTTON").click(function() {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data: $("ID HERE OF THE FORM").serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
return false; //This stops the Button from Actually Preforming
});
Now for the Php
<?php
start_session(); <-- This will make it share the same Session Princables
//error check and soforth use $_POST[] to get everything
$Response = array('success'=>true, 'VAR'=>'DATA'); <--- Success
$Response = array('success'=>false, 'VAR'=>'DATA'); <--- fails
echo json_encode($Response);
?>
I forgot to Mention, this is using JavaScript/jQuery, and ajax to do this.
Example of this as a Function
Var Form_Data = THIS IS THE DATA OF THE FORM;
function YOUR FUNCTION HERE(VARS HERE) {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data:Form_Data.serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
}
Now you could use this as the Button Click which would also function :3

Wordpress - fetch user info using jQuery ajax POST request

I am working in Wordpress trying to use an ajax request to fetch user data by passing the user id.
I can see that the user id sends correctly via AJAX POST but I am getting an internal error message and I don't know why.
At first I thought it was because I was trying to fetch some custom fields that I had added to the user profile but even when I simplified my script I am still getting the error message.
Any help is much appreciated!
Front End
$('.author').click(function() {
var id = $(this).attr('id');
var temp = id.split('-');
id = temp[1];
$.ajax({
type: 'POST',
url: 'wp-content/themes/twentyeleven/author_info.php',
data: {id: id},
dataType: 'html',
success: function(data) {
$('#author-bio').html(data);
}
});
return false;
});
author_info.php
$user_id = $_POST['id'];
$forename = get_the_author_meta('user_firstname', $user_id);
$output = $user_id;
echo $output;
Error Message
500 (Internal Server Error) jquery.min.js:4
Mathieu added a hackable approach to intercepting a request and redirecting it, which is fine. I prefer to build out AJAX responses that return json_encoded arrays.
$('.author').click(function() {
var id = $(this).attr('id');
var temp = id.split('-');
id = temp[1];
$.ajax({
url: 'http://absolute.path/wp-admin/admin-ajax.php',
data: {'action' : 'ajax_request', 'fn': 'getAuthorMeta', 'id': id},
dataType: 'json',
success: function(data) {
//We expect a JSON encoded array here, not an HTML template.
}
});
return false;
});
Now we build out the function to handle our ajax requests.
First, we need to define our ajax add_action method ->
add_action('wp_ajax_nopriv_ajax_request', 'ajax_handle_request');
add_action('wp_ajax_ajax_request', 'ajax_handle_request');
We need to use both add_action lines here. I won't get into why. You'll notice the _ajax_request here. This is the 'action' that we sent over in our AJAX function data: {'action' : 'ajax_request'}. We use this hook to validate our AJAX request, it can be anything you'd like.
Next, we'll need to build out or function ajax_handle_request.
function ajax_handle_request(){
switch($_REQUEST['fn']){
case 'getAuthorMeta':
$output = ajax_get_author_meta($_REQUEST['id']);
break;
default:
$output = 'That is not a valid FN parameter. Please check your string and try again';
break;
}
$output = json_encode($output);
if(is_array($output)){
return $output;
}else{
echo $output;
}
}
Now let's build our function to actually get the author meta.
function ajax_get_author_meta($id){
$theMeta = get_the_author_meta([meta_option], $id);
return $theMeta;
}
Where [meta_option] is a field provided by WP's native get_the_author_meta function.
At this point, we'll now go back to our success:function(data) and (data) is a reference to the json_encoded array we've returned. We can now iterate over the object to get our fields and output them into the page as you'd like.
You are not in a POST at that moment because you are calling a specific page of your template that probably doesn't correspond to any article in your blog.
Instead, create a pluggin that will do this:
add_action('template_redirect', 'my_author_meta_intercept');
function my_author_meta_intercept(){
if(isset($_POST['getAuthorMeta'])){
echo get_the_author_meta('user_firstname', $_POST['getAuthorMeta']);
exit();
}
}
This will short circuit the request to the same page as before when you call it using:
http://mysite/mycurrenturl?getAuthorMeta=testMetaKey
So calling that post normally will return the article as usual, but if you pass in ?getAuthorMeta, it will stop the template from being selected and simply return the exact content you want it to return.
In your page, you just have to change your javascript to:
$('.author').click(function() {
var id = $(this).attr('id');
var temp = id.split('-');
id = temp[1];
$.ajax({
type: 'POST',
url: window.location.href,
data: {getAuthorMeta: id},
success: function(data) {
$('#author-bio').html(data);
}
});
return false;
});
Just make sure you adapt the concept to what you need!
I would rather recommend you to use WP AJAX action method.
As in your case, add the following to your functions.php file.
add_action('wp_ajax_get_user_info', 'ajax_get_user_info');
add_action('wp_ajax_nopriv_get_user_info', 'ajax_get_user_info');
function ajax_get_user_info() {
//Handle request then generate response using WP_Ajax_Response or your html.
}
then in javascript tag.
$('.author').click(function() {
var id = $(this).attr('id');
var temp = id.split('-');
id = temp[1];
jQuery.post(
ajaxurl, /* if you get error of undefined ajaxurl. set it to "http://example.com/wordpress/wp-admin/admin-ajax.php"*/
{
'action':'get_user_info',
'user_id':id
},
function(response){
alert('The server responded: ' + response);
}
);
});
I would recommend you to read the 5 tips for using AJAX in WordPress.
p.s; Code above is not tested, it may have errors. but you get the idea.

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