tablesorter.pager plugin - php

The number of returned results is 2 which is correct and it comes up with 2 for the number of pages which is also correct but instead of showing 1 on the first page it shows both records. I'm not sure hwy the tablesorter.pager plugin is doing that.
<?php
session_start();
require("../inc/dbconfig.php");
require("../inc/global_functions.php");
require("../inc/variables.php");
// find out how many rows are in the table
$query = "SELECT CONCAT_WS(' ',firstName,lastName) AS name, username, emailAddress, userID FROM manager_users WHERE statusID != 4";
$result = mysqli_query($dbc,$query);
$rows = mysqli_num_rows($result);
$itemsPerPage = 1;
$totalPages = ceil($rows/$itemsPerPage);
$fileName = basename($_SERVER[PHP_SELF]);
$pageName = "User Accounts";
$userData = $_SESSION['user_data'];
$userID = $userData['userID'];
?>
<script type="text/javascript">
$(document).ready(function() {
$('#usersPageList').tablesorter().tablesorterPager({sortlist: [0,0], container:$('#usersPageList .pagination'),cssPageLinks:'a.pageLink'});
$('a.bt_green').click(function(e) {
e.preventDefault();
$('div.right_content').load('forms/addnew/' + $(this).attr('id'));
});
$('.ask').jConfirmAction();
});
</script>
<h2>User Accounts</h2>
<table id="usersPageList" class="rounded-corner">
<thead>
<tr>
<th scope="col" class="rounded-first"></th>
<th scope="col" class="rounded">Name</th>
<th scope="col" class="rounded">Email Address</th>
<th scope="col" class="rounded">Username</th>
<th scope="col" class="rounded">Edit</th>
<th scope="col" class="rounded-last">Delete</th>
</tr>
</thead>
<tfoot>
<tr>
<td colspan="5" class="rounded-foot-left"><em>Displays all of the registered and verified users!</em></td>
<td class="rounded-foot-right"> </td>
</tr>
</tfoot>
<tbody>
<?php
while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) {
echo "<tr>";
echo "<td><input type=\"checkbox\" name=\"\" /></td>";
echo "<td>".$row['name']."</td>";
echo "<td>".$row['emailAddress']."</td>";
echo "<td>".$row['username']."</td>";
echo "<td><img src=\"images/user_edit.png\" alt=\"\" title=\"\" border=\"0\" /></td>";
echo "<td>";
if (($row['userID'] !== '10000') && ($row['userID'] !== $userID)){
echo "<img src=\"images/trash.png\" class=\"delete\" alt=\"\" title=\"\" border=\"0\" id=\"".$row['userID']."\" />";
}
echo "</td>";
echo "</tr>";
}
?>
</tbody>
</table>
<?php
addRemove($fileName,$pageName);
pagination($totalPages);
?>
<input type="hidden" name="myhiddenPageToken" id="myhiddenPageToken" value="useraccounts" />

Maybe I'm misunderstanding what you want, but I think you want just one record at a time to show on the page? I have no idea why you would do that, but you can use the pager's size option:
$("table").tablesorter({
widthFixed: true,
widgets: ['zebra']
}).tablesorterPager({
container: $("#pager"),
size: 1 // only show one record
});
Also, if you are using the select to change the number of records showing, you'll need to include a "1" (demo).

Related

Bootstrap 4 table td width size customize

I need to increase the rating column width but my w-9 doesn't work.. I want to expand the rating column.
Here's my table code:
<table class="table table-bordered stick-top">
<thead class="text-center" id="data">
<tr>
<th></th>
<th>Questions</th>
<th id="try">Rating</th>
</tr>
</thead>
<tbody class="body_data">
<?php
$jio=mysqli_query($conn,"SELECT * FROM question")or die ("error");
while(list($Question_ID,$Question_Description)=mysqli_fetch_array($jio))
{ ?>
<tr>
<td><?php echo $Question_ID; ?></td>
<td><?php echo $Question_Description; ?> </td>
<?php
$q1 = "SELECT * FROM rating ORDER BY Rating_ID ASC";
$r1 = $conn -> query($q1);
echo "<td class='w-9'";
while($row = $r1 -> fetch_object()){
echo "<input id='radio' type='radio' name='radio$Question_ID' value='" . $row -> Rating_ID . "' required>". $row -> Rating_ID;"";
}
echo "</td>";
?>
</tr>
<?php } ?>
</tbody>
</table>
if you check Bootstrap Doc at Sizing doc you will they have included support for 25%, 50%, 75%, 100% and auto so basically when you are using w-9 the class is empty
so if you can't modify css file you need to place the following attribute inside your td tag :
<td style="width:9%">

Search Results display

i have a website project, where customers will need to search and the results will display, so i have done all that, but the problem is when a search results comes up,if there's more than 1 row,it dublicate the results on the same row,here are the code.
<h1 style="font-family:calibri;color:#13CC0D;text-align:center;">BODABODA SEARCH RESULTS</h1>
<table cellpadding="1" cellspacing="1" id="resultTable">
<thead>
<tr>
<th style="border-left: 1px solid #C1DAD7"> Region</th>
<th> District </th>
<th> Ward </th>
<th> Street</th>
<th> Driver Name </th>
<th>Identification Type</th>
<th>Identification Number</th>
<th>Motorcycle Type</th>
<th>Motorcycle Reg No</th>
<th>Phone Number</th>
</tr>
</thead>
<?php
$conn = mysqli_connect('localhost', 'efalococ_calcia', '*ad4#zNQ=nfN') or die('can not connect to the server'.mysqli_error);
mysqli_select_db($conn, 'efalococ_safirii');
if(isset($_POST['search'])){
$query = $_POST['region'];
$query1 = $_POST['district'];
$query2 = $_POST['ward'];
$query3 = $_POST['street'];
$results = mysqli_query($conn,"SELECT * FROM bodaboda WHERE (`region` LIKE '%".$query."%') && (`district` LIKE '%".$query1."%') && (`ward` LIKE '%".$query2."%') && (`street` LIKE '%".$query3."%')") or die(mysql_error());
if(mysqli_num_rows($results) >0){
while($row = mysqli_fetch_array($results)){
echo "<td>".$row['Region']."</td>" ;
echo "<td>".$row['District']."</td>";
echo "<td>".$row['Ward']."</td>";
echo "<td>".$row['Street']."</td>";
echo "<td>".$row['DriverName']."</td>";
echo "<td>".$row['IdentificationType']."</td>";
echo "<td>".$row['IdentificationNumber']."</td>";
echo "<td>".$row['MotorcycleType']."</td>";
echo "<td>".$row['MotorcycleRegNo']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
}
}else{
echo '<span style="color:red;font-family:cursive;font-size:14px;">No results found, Please Modify your search </span> Click here'.mysqli_error($conn);
}
}
?>
</table>
And the results shows like this!
Can you please help on that? any idea?
You just need to use the <tr> for every row.
The tag defines a row in an HTML table.
Learn more about HTML tr tag
while($row = mysqli_fetch_array($results)) {
echo "<tr>";
echo "<td>".$row['Region']."</td>" ;
echo "<td>".$row['District']."</td>";
echo "<td>".$row['Ward']."</td>";
echo "<td>".$row['Street']."</td>";
echo "<td>".$row['DriverName']."</td>";
echo "<td>".$row['IdentificationType']."</td>";
echo "<td>".$row['IdentificationNumber']."</td>";
echo "<td>".$row['MotorcycleType']."</td>";
echo "<td>".$row['MotorcycleRegNo']."</td>";
echo "<td>".$row['PhoneNumber']."</td>";
echo "</tr>";
}

DataTables warning (table id = 'My Table'): Requested unknown parameter '0' from the data source

I have a datatable to show fields from a MYSQL database however I keep getting the error:
DataTables warning (table id = 'My Table'): Requested unknown
parameter '0' from the data source
Here is my code:
<table class="table table-striped table-bordered" id="sample_1">
<thead>
<tr>
<th style="width:8px;"><input type="checkbox" class="group-checkable" data-set="#sample_1 .checkboxes" /></th>
<th>Username</th>
<th class="hidden-phone">Email</th>
<th class="hidden-phone">Points</th>
<th class="hidden-phone">Joined</th>
<th class="hidden-phone"></th>
</tr>
</thead>
<tbody>
<?php
$con = mysql_connect("localhost","cl49-XXX","XXX");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("cl49-XXX", $con)or die( "Unable to select database");
$result=mysql_query("SELECT * FROM products ")or die('You need enter a catagory ' );
echo "<tr>"; // first row beginning
for ($i = 1; $i <= mysql_num_rows($result); $i++)
{
$row = mysql_fetch_array($result);
$prodname = $row['prodname'];
$prodID = $row['prodID'];
$catagory = $row['catagory'];
echo "<tr class='odd gradeX'>
<td><input type='checkbox' class='checkboxes' value='1'/></td>
<td class='hidden-phone'>$prodID</td>
<td class='hidden-phone'>$prodname</td>
<td class='hidden-phone'>$catagory</td>
<td class='hidden-phone'><a href='deleteproduct.php?q=$prodID'><button class='btn btn-danger'type='submit'><font color='white'>Delete</font> </a>
";
echo "</tr><tr>"; // it's time no move to next row
}
echo "</tr>"; // last row ending
?>
</tbody>
</table>
Does anyone know what this error means?
The number of td's should match what you have given while calling out the datatable();
Quick fix(if you do not want to customize the default functionalities) would be :
$('#sample_1').dataTable();
If you have given anything inside datatable({/configs/}) just remove it completely and it should work well.

mysql query to display results in repeating columns

I am trying to build a comparison table using mysql query and php.
I would like the result to be displayed in a columns, like this:
<table border="1" cellspacing="0" cellpadding="0">
<tr>
<td width="151" scope="col">product</td>
<td width="89" scope="col">product1</td>
<td width="78" scope="col">product2</td>
<td width="77" scope="col">product3</td>
</tr>
<tr>
<td>type</td>
<td>type2</td>
<td>type3</td>
<td>type5</td>
</tr>
<tr>
<td>size</td>
<td>size2</td>
<td>size1</td>
<td>size4</td>
</tr>
<tr>
<td>price</td>
<td>4.99</td>
<td>3.99</td>
<td>3.59</td>
</tr>
</table>
but I can only get the table to show the results - not a row title too (i.e. I want the first column to show 'product', 'type', 'size', 'price'.
The code I have so far is
<?php
// query the database
$result = mysql_query($query_getproducts);
// cols we are interested in (from the SQL query)
$cols = array(
'product',
'type',
'size',
'price',
);
// initialize rotated result using cols
$rotated = array();
foreach($cols as $col) {
$rotated[$col] = array();
}
// fill rotated array
while(($row = mysql_fetch_assoc($result)) !== false) {
foreach($cols as $col) {
$rotated[$col][] = $row[$col];
}
}
// echo html
echo "<table border=1 width=473>";
echo "<tr>";
echo "</tr>";
foreach($rotated as $col => $values) {
echo "<tr>";
foreach($values as $value) {
echo "<td> " . htmlentities($value) . "</td>";
}
echo "</tr>";
}
echo "</table>";
?>
hope someone can help.
First of all mysql_* functions are deprecated. You should use PDO or Mysqli.
If you want table headers static ie you want to show table header as "Product,Type,Size, Price"
Then use
<tr>
<th>Product</th>
<th>Type</th>
<th>Size</th>
<th>Price</th>
</tr>
Then if your should use mysql_fetch_assoc which returns associative array with column name as there key. You can use that array and print the result using loop.
eg:
<?php
$rs=mysql_query($query);
while($row=mysql_fetch_assoc($rs) ){
?>
<tr>
<td><?php echo $row['keyname']?></td>
.....
.....
</tr>
<?php
}
?>
try like this ,
echo "<table border=1 width=473>";
echo " <tr>
<th>Product Name</th>
<th>Description</th>
<th>Product Size</th>
<th>Price</th>
</tr>";
foreach($rotated as $col => $values) {
echo "<tr>";
foreach($values as $value) {
echo "<td> " . htmlentities($value) . "</td>";
}
echo "</tr>";
}
echo "</table>";

retrieve id of table rows?

i have this script bellow to open table2 when clicking on the buttom 'more details'
<script>
$(document).ready(function() {
$('#Table1 tr').click(function(event){
$('#Table2').show();
alert($(this).attr('id'));
});
});
</script>
and this my code
<table id= "Table1" width='100%' border='1' cellspacing='0' cellpadding='0'>
$sql2=..
$sql3 = blabla ;
while($row3 =mysql_fetch_array($sql3)){
$sql4 = mysql_query (" SELECT $ww as place FROM data WHERE $ww =".$row3[$ww]." and id_user = ".$userid." ");
$row4 = mysql_fetch_array($sql4) ;
$string = "<blink > here </blink>" ;
$wnumber = $row3[$ww] ;
echo "<tr id= '".$wnumber."'><td style= 'text-align : center ;'>Week ".$row3[$ww]."
</td>" ;
echo "<td >".(int) $row3["percent"] ."% </td>";
echo "<td > "?><?php if($row4['place'] ==
$row3[$ww] and $row2['id'] == $userid ){ echo $string ; } else { echo "";} ;?><?php
"</td>";
echo "<td ><button class='showr'>More Details</button> </td></tr>";
//More Details when clicking on this buttom it open the table2
}
</tr>
</table>
this is second table
<?php
echo "<div id= 'Table2' style= 'display:none;'>";
echo "<table width='100%' border='1' cellspacing='0' cellpadding='0'>";
echo "<th> Week ".$wnumber."</th>";
echo "<th>try2</th>";
echo "<tr ><td>day</td>";
echo "<td>fff</td></tr>";
echo "</table></div>";
?>
*what i have now 5 rows with 5 buttoms .
*what it happen now is when clicking on every bottom it echo same '$wnumber' lets say 6.
however it defers from row to row ,
- script works good with alert of the id of which row is clicked.
- only the last buttom who works with the last id of row.
*what i want is every bottom works with its row id which echo the right '$wnumber'
* what i have tried is (make variable in the div)
echo "<div id= '".$wnumber."' style= 'display:none;'>";
instead of
echo "<div id= 'Table2' style= 'display:none;'>";
but didnt work.
hope its clear and there is solution of it.
EDIT : this source code
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function() {
$('#Table1 tr').click(function(event){
$('#Table2').show();
alert($(this).attr('id'));
});
});
</script>
<br />
<table id= "Table1" width='100%' border='1' cellspacing='0' cellpadding='0'>
<th >Weeks</th>
<th ><p></p></th>
<th > Your place</th>
<th > More Details</th>
<tr>
<tr id= '1'><td style= 'text-align : center ;'>Week 1</td><td style= 'text-align :
center ;'>33% </td><td style= 'text-align : center ;'> <td style= 'text-align :
center ;'><button class='showr'>More Details</button></td></tr><tr id= '6'><td
style= 'text-align : center ;'>Week 6</td><td style= 'text-align : center ;'>33%
</td><td style= 'text-align : center ;'> <td style= 'text-align : center
;'><button
class='showr'>More Details</button></td></tr><tr id= '13'><td style= 'text-align:
center ;'>Week 13</td><td style= 'text-align : center ;'>33% </td><td style=
'text-align : center ;'> <blink style= 'color:#990000 ;font-weight: bolder;' > 69
here </blink><td style= 'text-align : center ;'><button class='showr'>More
Details</button></td></tr></tr>
</table>
<br />
<div id= 'Table2' style= 'display:none;'><table width='100%' border='1'
cellspacing='0' cellpadding='0'><th> Week 13</th><th>try2</th><tr ><td>day</td>
<td>fff</td></tr></table></div>
<br /><br /> <br />
I tried your html code after correcting the missing td, tr.
And then clicking on each row / button displays the div.
Ensure you form proper html code in your php echo
Try something like this:
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(document).ready(function() {
$('#Table1 tr').click(function(event){
$('#details').find('#week' + $(this).attr('id')).show();
// alert($(this).attr('id'));
});
});
</script>
<?php
$result = mysql_query($sql);
// save the results to an array so you can loop them twice
while($row = mysql_fetch_array($result)) :
$rows[] = $row;
endwhile;
?>
<table id="table1">
<tr>
<th>heading</th>
<th>heading</th>
<th>heading</th>
<th>heading</th>
</tr>
<?php foreach ($rows as $row) : // loop #1 to output the main table ?>
<tr id="<?php echo $row['ww'] ?>">
<td>value</td>
<td>value</td>
<td>value</td>
<td><button type="button">More details</button></td>
</tr>
<?php endforeach; ?>
</table> <!-- end table 1 -->
<div id="details">
<?php foreach ($rows as $row) : // loop #2 to output a table for each set of details ?>
<table id="week<?php echo $row['ww'] ?>" style="display: none">
<tr>
<th>Week <?php echo $row['ww'] ?></th>
<th>try2</th>
</tr>
<tr>
<td>value</td>
<td>value</td>
</tr>
</table>
<?php endforeach; ?>
</div> <!-- end details -->
I copy / pasted your code into a jsFiddle and it seems to work as expected. Clicking on the row sends an alert with the correct ID.
http://jsfiddle.net/JeeNN/
Is there something I'm missing in your intent here?
Note : Best practice would be to skip the inline CSS and add external styling for your tables. Also, valid HTML is a must.
Update:
I went ahead and formatted the php code you posted so it's a bit easier to read. There's some variables that aren't defined and a couple other issues, but I'm sure you have it correct in your php file.
I think that you're going to want to run the loop a second time to create the second table. In this second loop, echo out the second table once per loop - you'll end up with a bunch of tables (one per row plus the first table). Then simply swap the visibility of the tables as user's click each id.
Is that what you're looking for? If not, perhaps try to rephrase your question.
Here's that formatted code:
<table id="Table1" width='100%' border='1' cellspacing='0' cellpadding='0'>
<?php
$sql2 = [..];
$sql3 = [..];
$ww = ?;
while($row3 = mysql_fetch_array($sql3)){
$sql4 = mysql_query ("SELECT $ww as place FROM data WHERE $ww =".$row3[$ww]." and id_user = ".$userid." ");
$row4 = mysql_fetch_array($sql4) ;
$string = "<blink> here </blink>" ;
$wnumber = $row3[$ww];
echo "<tr id='".$wnumber."'>";
echo "<td style='text-align:center;'>Week ".$row3[$ww]."</td>";
echo "<td>".(int) $row3["percent"] ."% </td>";
echo "<td>":
if($row4['place'] == $row3[$ww] and $row2['id'] == $userid ){
echo $string;
} else {
echo " ";
}
echo "</td>";
//More Details when clicking on this buttom it open the table2
echo "<td ><button class='showr'>More Details</button></td>";
echo "</tr>";
} ?>
</table>
<div id= 'Table2' style= 'display:none;'>
<table width='100%' border='1' cellspacing='0' cellpadding='0'>
<tr>
<th> Week <?php echo $wnumber; ?></th>
<th>try2</th>
</tr>
<tr>
<td>day</td>
<td>fff</td>
</tr>
</table>
</div>

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