I have a basic php script that calls system("netstat -l") and the reads what services are online. I got it all working exept that system() sends the whole return to the client... So my question is how do i run system() whiteout having it sending the command output to the client?
Im running this on ubuntu server.
You can do:
$output = shell_exec('netstat -l');
$output will now contain the output of the command.
shell_exec
Use shell_exec(). It will return the output of the command, instead of printing it like system().
Related
I am using XAMPP on Windows 7 to run a localhost, and I'm trying to use the PHP exec function to execute a Node.js script.
I am able to successfully use the exec function to run PhantomJS scripts, but when I try to do the same thing for Node.js, it doesn't work.
He's an example of a PHP script that properly runs a PhantomJS script:
<?php
exec('/phantomjs/bin/phantomjs /phantomjs/scripts/test.js', $output);
print_r($output);
And here's a similar example of a Node.js script that outputs an empty array every time:
<?php
exec('/Program Files (x86)/nodejs/node /Program Files (x86)/nodejs/test.js', $output);
print_r($output);
I'm sure that all of my paths are correct and that the Node.js script executes correctly whenever I execute it directly from the command line, but I can't get anything to return from the Node.js script when I run it from the PHP exec command. I also tried the following script, but I still get nothing:
<?php
exec('/Program Files (x86)/nodejs/node -v', $output);
print_r($output);
Any advice on what I'm missing would be greatly appreciated. Thank you.
I am making an android application in which I am first uploading the image to the server and on the server side, I want to execute a Python script from PHP. But I am not getting any output. When I access the Python script from the command prompt and run python TestCode.py it runs successfully and gives the desired output. I'm running Python script from PHP using the following command:
$result = exec('/usr/bin/python /var/www/html/Source/TestCode.py');
echo $result
However, if I run a simple Python program from PHP it works.
PHP has the permissions to access and execute the file.
Is there something which I am missing here?
exec('/usr/bin/python /var/www/html/Source/TestCode.py', $output);
var_dump($output);
2nd Parameter of exec will give output
EDIT:
exec('/usr/bin/python /var/www/html/Source/TestCode.py 2>&1', $output);
2>&1 - redirecting stderr to stdout. Now in case of any error too, $output will be populated.
First Check your python PATH using "which python" command and check result is /usr/bin/python.
Check your "TestCode.py" if you have written #!/usr/bin/sh than replace it with #!/usr/bin/bash.
Than run these commands
exec('/usr/bin/python /var/www/html/Source/TestCode.py', $result);
echo $result
i have 2 shell commands and i want to exec in php the first command that act like an application and stay into it and exec another command there (in this application).
i write in my shell: wpa_cli
and get the result:
Interactive mode
>
now i can write commands in that software, like:
Interactive mode
> status
and get the result:
wpa_state=DISCONNECTED
p2p_device_address=34:b1:f7:1f:2d:bb
address=34:b1:f7:1f:2d:bb
>
my problem is that i want to do that outside the shell by php.
how can i do that?
Your requirement is similar to this interactive shell using PHP, but it requires execution of PHP script in terminal, which you don't want.
So, in this case, you can use any of these php functions: shell_exec, exec, system or passthru and run both wpa_cli status commands together, you will get the required result.
e.g. run the following script in your php file and see the output,
echo '<pre>'. shell_exec('wpa_cli status') .'</pre>';
You can also use PHP Ajax Shell or similar scripts to execute your commands and get response on the same page without reloading it.
I'm working on using tesseract with PHP and this is my first time using such things as exec.
/usr/local/bin/tesseract /images/hello.png stdout works perfectly via SSH but nothing happens when I try and run this via PHP;
echo exec('/usr/local/bin/tesseract images/hello.png result');
But if I try;
echo exec('/usr/local/bin/tesseract images/hello.png result 2>&1');
Then the page writes Tesseract Open Source OCR Engine v3.03 with Leptonica So I feel like I must close.
Any ideas?
Got it working using the following
exec('/usr/local/bin/tesseract /images/hello.png stdout', $msg);
print_r($msg);
http://php.net/manual/en/function.exec.php
Return Values
The last line from the result of the command. If you need to execute a command and have all the data from the command passed directly back without any interference, use the passthru() function.
To get the output of the executed command, be sure to set and use the output parameter.
I am trying to invoke a script which takes several seconds (web services with 3rd party) using the PHP exec call. After much struggling, I reduced this to the classic hello world example. The calling script looks like:
exec('/usr/bin/php /home/quote2bi/tmp/helloworld.php > /tmp/execoutput.txt 2>&1 &');
When I run this, the output execoutput.txt contains a copy of the invoking script page, not hello world as I expected.
Why can't I get this PHP script to execute using exec? Note that when I change the command to something like ls -l, the output is a directory listing as expected. btw, in case it matters, I did chmod the called script to 755...
Update - I moved the exec call to the end of the calling script and at least now I don't see the calling script executed in the output. Thx to posters and I will try some of these ideas.
Help!
Thanks
Steve
I had this issue also and it turns out this is a bug in php (#11430). The fix is to use php-cli when calling another php script within a php script. So you can still use exec but rather than use php use php-cli when calling it in the browser:
exec("php-cli somescript.php");
This worked for me.
What exec is doing is taking the rightmost command and appending it to your destination. If you have the shebang line in your php script, you shouldn't need to include the binary directive of the php interpreter.
if you just want the script's output, try:
exec('/home/quote2bi/tmp/helloworld.php > /tmp/execoutput.txt 2>&1 &')
however if you do not want the errors to be in the file, you should redirect the STDERR prior to outputting to the file. Like so:
exec('/home/quote2bi/tmp/helloworld.php 2> /dev/null > /tmp/execoutput.txt')
the above should only output the "Hello World" to the execoutput.
Edit:
Interesting you are getting this behaviour. You stated the command "ls" worked. Try making an alias for this and forward it to a file like so:
alias pexec='php /home/quote2bi/tmp/helloworld.php'
then
exec('pexec > /tmp/execoutput.txt 2>&1 &')
it seems to be a problem with the way exec handles input as opposed to the shell itself.
-John
The problem is with PHP itself, it treats everything as $argv in the script. It doesn´t redirect the output to a file ou to /dev/null.
I faced the same problem some time ago. What I did is to create a runscript.php in /opt/php-bin and then inside this script run what It should be running. Something like this:
$script = $argv[1]
$params = implode(' ', array_slice($argv, 2));
$cmd = "{$script} {$params} > /dev/null &";
$output = array();
$return = 0;
exec("php {$cmd}", $output, $return);
exit((int)$return);
And then you call it using:
exec('/opt/php-bin/runscript.php /path/to/your/script.php arg1 arg2')
It´s the only way I managed to get this working.
To avoid the stated problems of PHP in this area, why not put this in inside a shell script? PHP can then execute the shell script which has all the redirections handled internally.
If you need to dynamically change things, then why not write the shell script and then execute it (and of course, clean up afterwards)?
if you are just simply running a php script one possible way to execute the entire code is to use the include() that will run the php file and output any results. You cannot direct the output to a text file but it should appear in the browser window if you're Hello World php script looks like
<?php echo "Hello World!"; ?>
then it will spit that out in the browser. So your second code would look like
<?php include("helloWorld.php"); echo " PHP ROCKS";?>
resulting in a page that would look like,
Hello world! PHP ROCKS
This runs as if you run the script from browser.
This came across while working on a project on linux platform.
exec('wget http://<url to the php script>)
Hope this helps!!