Hey, so I am trying to learn some string functions in PHP and came across a senario I cannot figure out. I want to take a string like such: /var/www/html and remove everything after the last forward slash (including the forward slash) so I end up with /var/www
What would be the best way to go about this? Many thanks.
Try using dirname. It may handle special cases for you that you may not have anticipated if you went with a string manipulation route.
This should work:
$str = substr($str, 0, strrpos($str, '/') - 1);
...but see icktoofay's solution if you're only planning on using this to handle file paths.
Related
Regex is my bete noire, can anyone help me isolate a string from a URL?
I want to get the page name from a URL which could appear in any of the following ways from an input form:
https://www.facebook.com/PAGENAME?sk=wall&filter=2
http://www.facebook.com/PAGENAME?sk=wall&filter=2
www.facebook.com/PAGENAME
facebook.com/PAGENAME?sk=wall
... and so on.
I can't seem to find a way to isolate the string after .com/ but before ? (if present at all). Is it preg_match, replace or split?
If anyone can recommend a particularly clear and introductory regex guide they found useful, it'd be appreciated.
You can use the parse_url function and then get the last segment from the path of the url:
$parts=parse_url($url);
$path_parts=explode("/", $parts["path"]);
$page=$path_parts[count($path_parts)-1];
For learning and testing regexes I found RegExr, an online tool, very useful: http://gskinner.com/RegExr/
But as others mentioned, parsing the url with appropriate functions might be better in this case.
I think you can use this php function (parse_url) directly instead of using regex.
Use smth like:
substr(parse_url('https://www.facebook.com/PAGENAME?sk=wall&filter=2', PHP_URL_PATH), 1);
I have this url (several similar ones)..
images/image1/image1.jpg
images/images1/images2/image2.jpg
images/images2/images3/images4/image4.jpg
I have this regex: but I want it to strip away the image name from the string:
<?php $imageurlfolder = $pagename1;
$imageurlfolder = preg_replace('/[A-Za-z0-9]+.asp/', '', $pagename1);?>
the string would look like the url's above images/images2/images3/images4/ but without the image4.jpg
hope you can help
Thanks
For this particular purpose function dirname() would be sufficient:
<?php echo dirname('images/images2/images3/images4/image4.jpg'); ?>
Would return:
images/images2/images3/images4
I think you can use the dirname function
for instance (from that page)
dirname("/etc/passwd")
would print
/etc
A quite straightforward way to do it:
preg_replace("#(?<=/)[^/]+$#","",$your_string);
It will remove everything between the last / and the end of the string.
Edit: as many peopole pointed out, you can also use dirname which might proof faster…
Hi all i know preg_replace can be used for formatting string but
i need help in that concerned area
my url will be like this
www.example.com/en/index.php
or
www.example.com/fr/index.php
what i want is to get
result as
www.example.com/index.php
i need it in php code so as to set in a session
can anyone please explain how ?
preg_replace('/www.example.com\/(.+)\/index.php/i', "www.example.com/index.php?lang=$1", $url); will do the thing
This is one way to do it:-
$newurl = preg_replace('/\/[a-z][a-z]\//', '/', $url);
Note that the search string appears with quotes and forward slashes ('/.../') and that the forward slashes in the URL then have to be escaped (\/). The language code is then matched with '[a-z][a-z]', but there are several other ways to do this and you may want something more liberal in case there are ever 3 letter codes, or caps. Equally you may need to do something tighter depending on what other URL schemes might appear.
I suspect in this instance it would be faster simply to use str_replace as follows:
$cleanedData = str_replace(array('www.example.com/en/', 'www.example.com/fr/'), '', $sourceData);
Finally i got a method my thanks to Purpletoucan
$newurl = preg_replace('/\/(en|esp|fr)\//', '/', $url);
it's working now i think!
I am trying to get the page or last directory name from a url
for example if the url is: http://www.example.com/dir/ i want it to return dir or if the passed url is http://www.example.com/page.php I want it to return page Notice I do not want the trailing slash or file extension.
I tried this:
$regex = "/.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*/i";
$name = strtolower(preg_replace($regex,"$2",$url));
I ran this regex in PHP and it returned nothing. (however I tested the same regex in ActionScript and it worked!)
So what am I doing wrong here, how do I get what I want?
Thanks!!!
Don't use / as the regex delimiter if it also contains slashes. Try this:
$regex = "#^.*\.(com|gov|org|net|mil|edu)/([a-z_\-]+).*$#i";
You may try tho escape the "/" in the middle. That simply closes your regex. So this may work:
$regex = "/.*\.(com|gov|org|net|mil|edu)\/([a-z_\-]+).*/i";
You may also make the regex somewhat more general, but that's another problem.
You can use this
array_pop(explode('/', $url));
Then apply a simple regex to remove any file extension
Assuming you want to match the entire address after the domain portion:
$regex = "%://[^/]+/([^?#]+)%i";
The above assumes a URL of the format extension://domainpart/everythingelse.
Then again, it seems that the problem here isn't that your RegEx isn't powerful enough, just mistyped (closing delimiter in the middle of the string). I'll leave this up for posterity, but I strongly recommend you check out PHP's parse_url() method.
This should adequately deliver:
substr($s = basename($_SERVER['REQUEST_URI']), 0, strrpos($s,'.') ?: strlen($s))
But this is better:
preg_replace('/[#\.\?].*/','',basename($path));
Although, your example is short, so I cannot tell if you want to preserve the entire path or just the last element of it. The preceding example will only preserve the last piece, but this should save the whole path while being generic enough to work with just about anything that can be thrown at you:
preg_replace('~(?:/$|[#\.\?].*)~','',substr(parse_url($path, PHP_URL_PATH),1));
As much as I personally love using regular expressions, more 'crude' (for want of a better word) string functions might be a good alternative for you. The snippet below uses sscanf to parse the path part of the URL for the first bunch of letters.
$url = "http://www.example.com/page.php";
$path = parse_url($url, PHP_URL_PATH);
sscanf($path, '/%[a-z]', $part);
// $part = "page";
This expression:
(?<=^[^:]+://[^.]+(?:\.[^.]+)*/)[^/]*(?=\.[^.]+$|/$)
Gives the following results:
http://www.example.com/dir/ dir
http://www.example.com/foo/dir/ dir
http://www.example.com/page.php page
http://www.example.com/foo/page.php page
Apologies in advance if this is not valid PHP regex - I tested it using RegexBuddy.
Save yourself the regular expression and make PHP's other functions feel more loved.
$url = "http://www.example.com/page.php";
$filename = pathinfo(parse_url($url, PHP_URL_PATH), PATHINFO_FILENAME);
Warning: for PHP 5.2 and up.
I have a full path which I would like to remove certain levels of it. So for instance,
/home/john/smith/web/test/testing/nothing/
I would like to get rid of 4 levels, so I get
/test/testing/nothing/
What would be a good of doing this?
Thanks
A simple solution is to slice the path up into parts, and then manipulate the array before sticking it back together again:
join("/", array_slice(explode("/", $path), 5));
Of course, if you wanted to remove that specific path, you could also use a regular expression:
preg_replace('~^/home/john/smith/web/~', '', $path);
One word of advice though. If your application is juggling around with paths a lot, it may be a good idea to create a class to represent paths, so as to encapsulate the logic, rather than have a lot of string manipulations all over the place. This is especially a good idea, if you mix absolute and relative paths.
Why are you all using regular expressions for something that requires absolutely no matching; CPU cycles are valuable!
str_replace would be more efficient:
$s_path = '/home/john/smith/web/test/testing/nothing/';
$s_path = str_replace('john/smith/web/test/', '', $s_path);
And use realpath() to resolve any '../../' paths.
And remember dirname(__FILE__) gets the CWD and rtrim() is extremely useful for removing trailing slashes..