Converting separate month, day and year values into a timestamp - php

I have a month value (1-12), day value (1-31), and a year value (2010,2011,2012). I also have a hour value and a minute value.
How can I give this to strtotime() in a way it can convert it to a timestamp?

why convert string to date when you already know year month and date.
use setDate funtion
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>

Given the variables $year $month $day $hour $minute you can do:
strtotime("$year-$month-$day $hour:$minute");
Be careful to enclose the variables with ", never in this case with '.
UPDATE (thanks to comments of #Clockwork and #Tadeck):
In case there is a variable $timeofday that represents the time of day (i.e. AM or PM),
then you can parse it this with:
strtotime("$year-$month-$day $hour:$minute$timeofday");
that is to say, just attach that variable to the end of the text.

Is strtotime the best tool for this job? What about mktime()?
$time = mktime($hour, $minute, 0, $month, $day, $year);

You can provide it to function strtotime() in many ways, as mentioned in documentation. Some examples include:
$your_time = strtotime('12/31/2011 9:59');
$your_time = strtotime('2011-12-31 9:59');
$your_time = strtotime('December 31, 2011 9:59');
etc. It really is very flexible.
You can find the list of valid formats in the documentation, and that is (from the "Compound Formats" list in the mentioned documentation) for example:
10/Oct/2000:13:55:36 -0700,
2008:08:07 18:11:31,
2008-08-07 18:11:31,
2008-07-01T22:35:17.02,
2008-07-01T22:35:17.03+08:00,
20080701T22:38:07,
20080701T9:38:07,
20080701t223807,
20080701T093807,
2008-7-1T9:3:37,
(this is really copy of the documentation)

Use it like this strtotime("YYYY-mm-DD HH:MM AM/PM"):
echo date("d F Y h:i:s A", strtotime("2011-06-01 11:15 PM")) . "\n";
OUTPUT
01 June 2011 11:15:00 PM

Y-m-d hh:mm will work
echo strtotime('2011-12-14 11:44 am');
cit #Pekka :)

strtotime($month."-".$day."-".$year)

Related

how do you convert the "exp" jwt to proper date format(YYYY-MM-DD T HH:MM+02 00) [duplicate]

I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>

How can i convert date("j/n/y") to epoch

I have some data that makes use of date("j/n/y") format i.e date for today is 23/1/15
I have tried
echo strtotime($today);
but this does not give me the timestamp i want.How would i convert a date in date("j/n/y") format to epoch?.
Use DateTime::createFromFormat() to read the date format and then use DateTime::getTimestamp() to format it as a timestamp.
$date = DateTime::createFromFormat('j/n/y', '23/1/15');
$epoch = $date->getTimestamp();
I think you're looking for the mktime function in PHP. It goes a little like this:
$timestamp = mktime(0,0,0,0,0,0);
Where, in order, the arguments are: hour, minute, second, month, day, year. So, in your case:
$today = mktime(0, 0, 0, 1, 23, 2015);
// Would return the timestamp for Jan. 23rd, 2015 at 12:00:00 am (I think)
If you're looking for a dynamic right now timestamp, you may use date() in each of the arguments of mktime. For example:
$rightnow = mktime(date("H"), date("i"), date("s"), date("m"), date("d"), date("Y"));
// Would return the timestamp for Jan. 23rd, 2015 at 10:57:25 am.
But, as John Conde says, it requires you break apart the date before you can use it, so it may not be as efficient.
Hope that helps!
Just to have another approach this one would be good for 85 more years.
$date = date('j/n/y', time());
list($day, $month, $year) = explode("/", $date);
$date = "20" . $year . "-" . $month . "-" . $day;
echo date('m/d/Y', strtotime($date));

PHP and or mysql: Make a date from some variables

Assume that i have two variables in php:
$year
$month
Then I want to make another variable:
$date
which:
$date=$year-$month-25
So, if I have 2012 in $year and 7 for $month, $date will be 2012-07-25.
Actually, I will compare it with some date in MySQL.
$year and $month are inputted by user.
anybody have a solution?
The solution either how to make $date or anything as long it can be comparred with a date in mysql.
Thanks before. ^^
You can make a unix timestamp through this:
$myDate = mktime(0, 0, 0, $month, 25, $year);
This is a pretty useful thing to have, as you can format it into all sorts of nice via:
echo date("Y-m-d", $myDate);
// Prints something like: 2012-07-25
or
echo date("l", $myDate);
// Prints something like: Monday
or
date('l jS \of F Y h:i:s A', $myDate);
// Prints something like: Monday 8th of August 2005 03:12:46 PM
You can do as follows
$complete_date = $year."-".$month."-25";
which gives you 2012-7-25
Please, read the "php manual" for concat your PHP string.
it's not
$date = $year-$month-25;
it is
$date = $year . '-' . $month . '- 25';
or
$date = $year . "-" . $month . "- 25";
but simple quote is more optimize for php string.
The solution either how to make $date or anything as long it can be
comparred with a date in mysql
The key here is use of strtotime to create and compare.
MySQL dates can be converted to integer through the use of strototime:
strtotime($mysql_date);
Then you can get time() and compare to two:
time()<>strtotime($mysql_date) // then the two dates are not equal.
You can use mktime function
$date = date('Y-m-d',mktime(0,0,0,$month,25,$year));
Well, I would use mktime to get the timestamp of the date ( http://php.net/manual/de/function.mktime.php ) and use the command unix_timestamp(date(yourfield)) in mysql to compare them.
(the date() withing unix_timestamp is only required when you save datetime values and not pure date values)
Since mysql dates are usually in this format Y-m-d by default, you can use $thedate = date('Y-m-d',mktime(0,0,0,$month,25,$year)); where $month and $year are based on the user input. Of course you have to make the user input it in the format you want by using select/lists.

Convert timestamp to readable date/time PHP

I have a timestamp stored in a session (1299446702).
How can I convert that to a readable date/time in PHP? I have tried srttotime, etc. to no avail.
Use PHP's date() function.
Example:
echo date('m/d/Y', 1299446702);
strtotime makes a date string into a timestamp. You want to do the opposite, which is date. The typical mysql date format is date('Y-m-d H:i:s'); Check the manual page for what other letters represent.
If you have a timestamp that you want to use (apparently you do), it is the second argument of date().
I just added H:i:s to Rocket's answer to get the time along with the date.
echo date('m/d/Y H:i:s', 1299446702);
Output: 03/06/2011 16:25:02
$timestamp = 1465298940;
$datetimeFormat = 'Y-m-d H:i:s';
$date = new \DateTime();
// If you must have use time zones
// $date = new \DateTime('now', new \DateTimeZone('Europe/Helsinki'));
$date->setTimestamp($timestamp);
echo $date->format($datetimeFormat);
result: 2016-06-07 14:29:00
Other time zones:
Africa
America
Antarctica
Arctic
Asia
Atlantic
Australia
Europe
Indian
Pacific
Others
If you are using PHP date(), you can use this code to get the date, time, second, etc.
$time = time(); // you have 1299446702 in time
$year = $time/31556926 % 12; // to get year
$week = $time / 604800 % 52; // to get weeks
$hour = $time / 3600 % 24; // to get hours
$minute = $time / 60 % 60; // to get minutes
$second = $time % 60; // to get seconds
If anyone wants timestamp conversion directly to a DateTime object, there's a simple one-liner:
$timestamp = 1299446702;
$date = DateTime::createFromFormat('U', $timestamp);
Following #sromero comment, timezone parameter (the 3rd param in DateTime::createFromFormat()) is ignored when unix timestamp is passed, so the below code is unnecessary.
$date = DateTime::createFromFormat('U', $timestamp, new DateTimeZone('UTC'); // not needed, 3rd parameter is ignored
You may check PHP's manual for DateTime::createFromFormat for more info and options.
Try this one:
echo date('m/d/Y H:i:s', 1541843467);
$epoch = 1483228800;
$dt = new DateTime("#$epoch"); // convert UNIX timestamp to PHP DateTime
echo $dt->format('Y-m-d H:i:s'); // output = 2017-01-01 00:00:00
In the examples above "r" and "Y-m-d H:i:s" are PHP date formats, other examples:
Format Output
r ----- Wed, 15 Mar 2017 12:00:00 +0100 (RFC 2822 date)
c ----- 2017-03-15T12:00:00+01:00 (ISO 8601 date)
M/d/Y ----- Mar/15/2017
d-m-Y ----- 15-03-2017
Y-m-d H:i:s ----- 2017-03-15 12:00:00
Try it.
<?php
$timestamp=1333342365;
echo gmdate("Y-m-d\TH:i:s\Z", $timestamp);
?>
You can try this:
$mytimestamp = 1465298940;
echo gmdate("m-d-Y", $mytimestamp);
Output :
06-07-2016
Unless you need a custom date and time format, it's easier, less error-prone, and more readable to use one of the built-in date time format constants:
echo date(DATE_RFC822, 1368496604);
echo date("l M j, Y",$res1['timep']);
This is really good for converting a unix timestamp to a readable date along with day. Example:
Thursday Jul 7, 2016
echo 'Le '.date('d/m/Y', 1234567890).' à '.date('H:i:s', 1234567890);
I have used this:
<?php echo date('d/m/Y H:i a', $row['start_time']); ?>

PHP get 31 days distance from starting date

How can I get what date it will be after 31 days starting with $startDate, where $startDate is a string of this format: YYYYMMDD.
Thank you.
strtotime will give you a Unix timestamp:
$date = '20101007';
$newDate = strtotime($date.' + 31 days');
you can then use date to format that into the same format, if that's what you need:
echo date('Ymd', $newDate);
If you're using PHP 5.3:
$date = new DateTime('20101007');
$date->add(new DateInterval('P31D'));
echo $date->format('Y-m-d');
The pre-5.3 date functions are lacking, to say the least. The DateTime stuff makes it much easier to deal with dates. http://us3.php.net/manual/en/book.datetime.php
Just a note that +1 month will also work if you want the same date on the next month and not 31 days exactly each time.
echo date('Y m d',strtotime('+31 Days'));

Categories