Multiple SQL Searches - OR Command - php

Question

My users can search for an order by an address right now. What I would like to do is let them be able to search with multiple criteria. Let them search by address, city, state, etc etc.
I have tried using the following code, but it doesn't seem to work.
$sql = ("SELECT order_number, sitestreet FROM `PropertyInfo` WHERE `sitestreet` LIKE '%$street%' OR `sitecity` LIKE '%$city%' AND `user` LIKE '$user'");
$result = mysql_query($sql);
I don't think it's reading the value in $user cause it displays all orders for all users.
How can I make it possible to search for an order using multiple serach values?
Thank you!

Answer 1

Wrap your OR statements in parenthesis so it forms one top-level condition, the user is the other top-level condition:
$sql = '
SELECT
`order_number`,
`sitestreet`
FROM
`PropertyInfo`
WHERE
(
`sitestreet` LIKE "%'.$street.'%" OR
`sitecity` LIKE "%'.$city.'%"
) AND
`user` = '.$user;
Also note, you want a direct match to the user column, use = instead of LIKE. I am assuming that $user is a numeric ID...

Answer 2

How about trying like
$sql = ("SELECT order_number, sitestreet FROM PropertyInfo WHERE (sitestreet LIKE
'%$street%' OR sitecity LIKE '%$city%') AND user LIKE '$user'");

Answer 3

AND has a higher order of precedence than OR (see http://dev.mysql.com/doc/refman/5.0/en/operator-precedence.html for details). You need to wrap your OR statement in parentheses so it get evaluated as one statement, before the AND statement.
SELECT order_number, sitestreet
FROM `PropertyInfo`
WHERE (`sitestreet` LIKE '%$street%' OR `sitecity` LIKE '%$city%')
AND `user` LIKE '$user'

Answer 4

Try:
$sql = ("
SELECT order_number, sitestreet
FROM `PropertyInfo`
WHERE (`sitestreet` LIKE '%$street%'
OR `sitecity` LIKE '%$city%')
AND `user` LIKE '$user'");
You should group the ORs together. The way it is written I believe it is reading it as 'if Street matches, ignore any other conditions (OR), otherwise both city and user must match.
Also G molvi's point is good, unless you're looking for a pattern match, go with =
HTH