I'm coding a listing system and I'm trying to get the posts ORDER by number of comments and votes FROM 2 tables.
Table1 : Lists => id, title, detail
Table2 : Votes => voteid, listid
Table3 : Comments => commentid, listid
WHERE MY Current query is
$q = mysql_query("SELECT * FROM zoo_leads
LEFT JOIN Votes ON Lists.id=Votes.listid
LEFT JOIN Comments ON Lists.id=Comments.listid
GROUP BY Lists.id ORDER BY Comments.listid DESC LIMIT 10
it is showing me results perfectly but ORDER BY is Lists.id Instead of number of votes and comments
Try:
SELECT *
FROM zoo_leads
LEFT JOIN votes
ON lists.id = votes.listid
LEFT JOIN comments
ON lists.id = comments.listid
GROUP BY lists.id
ORDER BY COUNT(votes.id) DESC,
COUNT(comments.id) DESC
LIMIT 10
That is because you have ORDER BY Comments.listid in your SQL statement.
Related
I'm trying to create a leaderboard but i'm not sure how to do the mysql query.
I would like to count all the levels from a player in the skills table and get the total Level and count all the experience from a player in the experience table and get the Total Exp along with displaying the persons name from the users column.
There is 3 tables factions_mcmmo_users, factions_mcmmo_experience, factions_mcmmo_skills.
This is what i have so far but it doesn't work:
$sql = ("SELECT a.id,
(SELECT COUNT(*) FROM factions_mcmmo_experience WHERE user_id = a.id) as TotalXP,
(SELECT COUNT(*) FROM factions_mcmmo_skills WHERE user_id = a.id) as TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a LIMIT 10;");
Any help would be very appreciated
EDIT: I have it working now but i'm unsure if its the most efficient way to do things so if anyone could help me out if theres a better way, it would mean a lot.
I would also like to know if it's possible to display the total exp and level with commas if the number is in the thousands for example: total level 5,882 and total xp 582,882
EDIT 2:
I have figured out how to format the numbers but still don't know if my code is efficient
$sql = ("SELECT id, user,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_skills b WHERE b.user_id = a.id) as TotalLevel,
(SELECT FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy),0) FROM factions_mcmmo_experience c WHERE c.user_id = a.id) as TotalXP
FROM (SELECT id, user FROM factions_mcmmo_users) a group by id ORDER BY TotalLevel DESC, TotalXP DESC LIMIT 10;");
EDIT 3
Updated code from scaisEdge but was displaying everyones level as 1 and XP as 1, so i changed count(*) changed to sum, added an order By TotalLevel in Descending order and that seems to have worked but i can't get it to display the persons name (user column) in the user table? not sure if i was supposed to change to sum because it didn't work the other way.
$sql = ("SELECT a.id, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC
LIMIT 10;");
EDIT 4
Everything working but when i try to format the totals using "FORMAT(Sum(Columns), 0) on the inner joins, the EXP Total appears to work but the main Total Level is not displaying results that are over 1,000 and it breaks the leaderboard positioning, it should be sorting them on total level but it appears to be random, when u remove the format,0 it goes back to working
I would like it to display commas if the number number is the thousands for example: Total Level: 5,532 and Total EXP 5882,882
See live demo: http://mcbuffalo.com/playground/leaderboards/server/factions-mcmmo.php
Updated Code trying to use Format:
$sql = ("SELECT a.id, a.user, b.TotalXP, c.TotalLevel
FROM (SELECT id, user FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, FORMAT(Sum(taming)+Sum(mining)+Sum(woodcutting)+Sum(repair)+Sum(unarmed)+Sum(herbalism)+Sum(excavation)+Sum(archery)+Sum(swords)+Sum(axes)+Sum(acrobatics)+Sum(fishing)+Sum(alchemy), 0) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
ORDER BY TotalLevel DESC;");
EDIT 5
Changed number with PHP, everything works
Original Images
you could use an couple of inner join
$sql = ("SELECT a.id, a.name, b.TotalXP, c.TotalLevel
FROM (SELECT DISTINCT id, name FROM factions_mcmmo_users) a
INNER JOIN (
SELECT user_id, COUNT(*) as TotalXP
FROM factions_mcmmo_experience
GROUP By user_id
) b on b.user_id = a.id
INNER JOIN (
SELECT user_id, COUNT(*) as TotalLevel
FROM factions_mcmmo_skills
GROUP by user_id
) c on c.user_id = a.id
LIMIT 10
I have a problem putting a limit on the number of rows from my Jokes table.
This is my query working, getting all rows:
SELECT Jokes.ID, Categories.CategoryName, Jokes.CategoryID, Jokes.JokeText
FROM Jokes
LEFT JOIN Categories
ON Jokes.CategoryID = Categories.ID
ORDER BY Jokes.ID DESC
Would it be something like?
SELECT Jokes.ID, Categories.CategoryName, Jokes.CategoryID, Jokes.JokeText
FROM (
SELECT * FROM Jokes ORDER BY ID DESC Limit 0,40)
AS a
LEFT JOIN Categories
AS b
ON a.CategoryID = b.ID
why not using
SELECT Jokes.ID, Categories.CategoryName, Jokes.CategoryID, Jokes.JokeText
FROM Jokes
LEFT JOIN Categories
ON Jokes.CategoryID = Categories.ID
ORDER BY Jokes.ID DESC
Limit 0,40
I have 2 tables.
First:
TABLE Articles
ID
Second:
TABLE Viewcount
DATE DATE PK
ARTICLE_ID INT PK (MATCHES ID IN TABLE Articles)
NUMVIEWS INT
How do I select all IDs from table Articles and then order by NUMVIEWS (DESC) of Viewcount according to dates?
I then need to append the IDs from Articles that were not found in viewcount to the End of the results in no particular order.
I know it has to be some sort of Join but I can't figure it out..
try this
SELECT id from Articles a
LEFT JOIN Viewcount v
ON a.id = v.article_id
AND v.date = 'some date here'
ORDER BY v.numviews ,v.date desc
A simple join will suffice, yes:
SELECT a.id FROm Articles a LEFT JOIN Viewcount v
ON v.article_id = a.id
ORDER BY v.numviews desc, v.date
This should work:
SELECT * FROM `Articles` `a`, `Viewcount` `v`
WHERE `v`.`ARTICLE_ID`=`a`.`ID`
ORDER BY `v`.`NUMVIEWS` DESC
Replace SELECT * by SELECT `a`.`ID` to get only the Article IDs.
SELECT ID from (Articles JOIN Viewcount on Articles.ID = Viewcount.ID) ORDER BY Viewcount.NUMVIEWS, Viewcount.date
I have tables tbl_posts and tbl_comments with primary keys post_id and comment_id respectively. I tried this code:
$allPosts=mysql_query("
select c.comment_id, post_id, count(*)
from post u,
comments c
where u.comment_id = c.comment_id
group by comment_id, post_id
LIMIT 10
");
but I have no clue what it does. How do I combine two tables so that the total comments determines the order of the listed posts from tbl_posts?
Try this, it's more readable if you separate per lines and work with joins
select c.comment_id, post_id, count(*)
from post u join comments c
on u.comment_id = c.comment_id
group by comment_id, post_id LIMIT 10
It looks like you have tables named tbl_comment and tbl_post but your query has them listed as just comment and post.
select c.comment_id, post_id, count(*)
from tbl_post u, tbl_comments c
where u.comment_id = c.comment_id
group by comment_id, post_id LIMIT 10
$allPosts=mysql_query("select c.comment_id, post_id, count(*) from tbl_post u, tbl_comments c where u.comment_id = c.comment_id group by comment_id, post_id LIMIT 10");
This just fixes the query so it runs, and does not address any content issues you may have, namely the group by on both (what I am guessing) are primary keys.
** EDIT **
To fix the sorting try:
SELECT tbl_post.comment_id, count(*)
FROM tbl_post, tbl_comments
WHERE tbl_post.comment_id = tbl_comment.comment_id
GROUP BY comment_id LIMIT 10
ORDER BY count(*)
Explanation of your SQL:
You are selecting column comment_id from table comments, column post_id from table post using a inner join, grouping by comment_id, post_id, with a limit of 10 results.
I would try:
$allPosts = mysql_query("SELECT * FROM
(SELECT c.comment_id, u.post_id, COUNT(*) AS 'count' FROM post u
LEFT JOIN comments c ON c.comment_id = u.comment_id
GROUP BY c.comment_id, u.post_id)
ORDER BY count DESC LIMIT 10");
SELECT
links.id,
links.url,
links.user_id,
links.title,
links.description,
links.nsfw,
links.posted,
links.category_id,
votes.vote
votes.vote_date
FROM links
INNER JOIN votes
ON votes.link_id = links.id
ORDER BY (I want to sort by the count of votes on the links) DESC
If I want to sort my links/posts by votes, how can I then do it with this SQL?
The link with the highest vote count shows first.
You want grouping. Try this:
SELECT
links.id,
links.url,
links.user_id,
links.title,
links.description,
links.nsfw,
links.posted,
links.category_id
FROM
links
INNER JOIN votes ON votes.link_id = links.id
GROUP BY links.id
ORDER BY COUNT(votes.id) DESC
I didn't test it (because I don't have your dataset), but it should be more or less correct.
Group by link id and select thee vot count
SELECT
count(*) as votecount,
links.id,
links.url,
links.user_id,
links.title,
links.description,
links.nsfw,
links.posted,
links.category_id,
votes.vote
votes.vote_date
FROM links
INNER JOIN votes
ON votes.link_id = links.id
GROUP BY links.id
2.) Wrap this in a superquery for sorting
SELECT * FROM (
<as above>
) AS baseview
ORDER BY votecount DESC
You can use a subquery:
SELECT links.id, links.url, votes.vote, votes.vote_date
FROM links
INNER JOIN votes ON votes.link_id = links.id
INNER JOIN (
SELECT links.id AS link_id, COUNT(votes.id) AS num_votes
FROM links
INNER JOIN votes ON votes.link_id = links.id
GROUP BY links.id
) AS votes_per_link ON links.id=votes_per_link.link_id
ORDER BY votes_per_link.num_votes DESC
Since I didn't understand which of these behaviors you are asking for, I post solutions to different cases here:
Get links, order by highest vote:
SELECT votes.link_id, links.url, MAX(votes.vote) AS maxvote
FROM votes INNER JOIN links ON links.id = votes.link_id
GROUP BY votes.link_id ORDER BY `maxvote` DESC;
Get links, order by average vote:
SELECT votes.link_id, links.url, AVG(votes.vote) AS avgvote
FROM votes INNER JOIN links ON links.id = votes.link_id
GROUP BY votes.link_id ORDER BY `avgvote` DESC;
Get links, order by votes count:
SELECT votes.link_id, links.url, COUNT(votes.vote) AS cntvotes
FROM votes INNER JOIN links ON links.id = votes.link_id
GROUP BY votes.link_id ORDER BY `cntvotes` DESC;
Get votes, by highest vote:
SELECT links.id, links.url, votes.vote
FROM links INNER JOIN votes ON links.id = votes.link_id
ORDER BY votes.vote DESC;
(I omitted some fields to shorten queries, of course feel free to add them back again).