Php fiscal year report, trouble with selecting proper year - php

Question

I am building a report for a client using php and codeigniter.
This report is a financial report, as such, I must reflect money collected since the beginning of the fiscal year. In this case, July 31st.
I already query the user for the date of the report, but how would I get php to know which fiscal year to take?
I have a rough idea, something along the lines of
'If Month-Day is before July 31, use current year-1
Else use current year'
But I do not know how I would code that, or if it would work, or if there is a more elegant way of doing the same thing.

Answer 1

I think your best bet is the dateTime class.
http://us3.php.net/manual/en/class.datetime.php
I think something like this is what you will need
public function getCurrentYear(DateTime $dateToCheck)
{
$today = new DateTime();
$currentYear = (int)$today->format('Y');
$endFiscalYear = new DateTime('31 July'); //year left out, so will default to this year
if($dateToCheck < $endFiscalYear){ //you need PHP >= 5.2.2 for this to work
$currentYear--;
}
return $currentYear;
}
You can set $today by doing something like :-
$today = new DateTime('20 June 2011');
Read more in the link above
Here is a slightly different version which should be a bit more robust as it will return the fiscal year of any date you give it, not just dates in the current year.
function getFiscalYear(DateTime $dateToCheck)
{
$fiscalYearEnd = '31 July';
$year = (int)$dateToCheck->format('Y');
$fiscalyearEndDate = new DateTime($fiscalYearEnd . ' ' . $year);
if($dateToCheck <= $fiscalyearEndDate){
$year--;
}
return $year;
}
use it like this :-
$dateToCheck = new DateTime('1 jan 2009'); // for example
$fiscalYear = getFiscalYear($dateToCheck);
This will return 2008
This version should work if your PHP version is < 5.2
function getFiscalYear($timestamp)
{
$year = (int)date('Y', $timestamp);
$fiscalYearEndDate = strtotime('31 July ' . $year);
if($timestamp < $fiscalYearEndDate) $year--;
return $year;
}
Use like this:-
$date = strtotime('1 Jan 2009');
fiscalYear = getFiscalYear($date);
Will return 2008

Answer 2

function get_fiscal_year($format = 'Y-m-d', $cutoff_date = '31 July') {
$fiscal_year = strtotime($cutoff_date);
if(time() < $fiscal_year)
$fiscal_year = strtotime($cutoff_date .' last year');
return date($format, $fiscal_year);
}
$fisical_year = get_fiscal_year();
$now = date('Y-m-d');
You then could use the function to query database with statement condition
transcation_date between $fisical_year and $now

Answer 3

If user gives the date: #givenDate and you want to search in your dateField (which is of type date), you can use something like:
WHERE dateField BETWEEN
DATE( CONCAT( YEAR(#givenDate)-(MONTH(#givenDate)<8), '-08-01' ))
AND DATE( CONCAT( 1+YEAR(#givenDate)-(MONTH(#givenDate)<8), '-07-31' ))