Can I echo in single quotes with a variable?
example
echo 'I love my $variable.';
I need to do this because I have lots of HTML to echo too.
You must either use:
echo 'I love my ' . $variable . '.';
This method appends the variable to the string.
Or you could use:
echo "I love my $variable.";
Notice the double quotes used here!
If there's a lot of text, have a look at the Heredoc syntax.
$var = <<<EOT
<div style="">Some 'text' {$variable}</div>
EOT;
The documentation says:
Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.
So the answer is no, not in this way.
The solution is simple:
Don't echo HTML.
As long you are not creating like partial views or stuff †, there is no reason to echo HTML. Embed PHP into HTML instead:
<div class="foo">
<span><?php echo $value; ?></span>
</div>
The benefits are:
Don't have to remember escaping of quotes.
Easier to maintain HTML code.
†: In this case heredoc [docs] is the least worse alternative.
No. Variables (and special characters) only expand in strings delimited with double quotes. If you want to include a variable in a single-quote delimited string, you have to concatenate it instead:
echo 'I love my '.$variable.'.';
You could also escape the double quotes of your HTML if you'd rather use strings delimited by doble quotes:
echo "$text";
See the PHP manual on strings, especially the part on string parsing, for more information.
No. ' will not parse variables. use
echo 'I love my '.$variable.'.';
or
echo "I love my {$variable}. And I have \" some characters escaped";
not within the string, but you can exit the string and concatenate the variable in.
echo 'I love my '.$variable.'.';
The other option would just be to escape the double quotes.
echo "I love my \"$variable\".";
Or just go in and out of php to echo variables (although ugly).
I love my <?php echo $variable; ?>.
With short tags enabled, I love my <?=$variable?>.
Lastly there is heredoc format that allows both single and double quotes along with variables.
echo <<<HTML
I love my $variable. '"...
HTML;
Taken from php.net:
"Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings."
So the answer is no you can't. But you can do it like this :
echo 'I love my' . $variable . '.';
It will be cleaner this way.
Beside the solutions mentioned by other users such as string concatenation, you can use placeholders as follows;
Note the %s is for string.
$variable = 'what ever';
printf('The $variable is %s', $variable);
Try this
<php echo 'I love my '. $variable . ' .'; ?>
In my case, I have changed my command as follows and it worked for me:Added double quotes twice("") beside every single quote(')
PVALUE='1,2,3'
echo "variable='""${PVALUE},repmgr'""" >>postgresql.conf
Output:
variable='1,2,3,repmgr'
#How to print a variable in echo within a single quote bash shell script
use the escape sing-quote to surround the text string as:
variable='my dog'
echo \''I love ' $variable\'
=>
'I love my dog'
Related
Can I echo in single quotes with a variable?
example
echo 'I love my $variable.';
I need to do this because I have lots of HTML to echo too.
You must either use:
echo 'I love my ' . $variable . '.';
This method appends the variable to the string.
Or you could use:
echo "I love my $variable.";
Notice the double quotes used here!
If there's a lot of text, have a look at the Heredoc syntax.
$var = <<<EOT
<div style="">Some 'text' {$variable}</div>
EOT;
The documentation says:
Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.
So the answer is no, not in this way.
The solution is simple:
Don't echo HTML.
As long you are not creating like partial views or stuff †, there is no reason to echo HTML. Embed PHP into HTML instead:
<div class="foo">
<span><?php echo $value; ?></span>
</div>
The benefits are:
Don't have to remember escaping of quotes.
Easier to maintain HTML code.
†: In this case heredoc [docs] is the least worse alternative.
No. Variables (and special characters) only expand in strings delimited with double quotes. If you want to include a variable in a single-quote delimited string, you have to concatenate it instead:
echo 'I love my '.$variable.'.';
You could also escape the double quotes of your HTML if you'd rather use strings delimited by doble quotes:
echo "$text";
See the PHP manual on strings, especially the part on string parsing, for more information.
No. ' will not parse variables. use
echo 'I love my '.$variable.'.';
or
echo "I love my {$variable}. And I have \" some characters escaped";
not within the string, but you can exit the string and concatenate the variable in.
echo 'I love my '.$variable.'.';
The other option would just be to escape the double quotes.
echo "I love my \"$variable\".";
Or just go in and out of php to echo variables (although ugly).
I love my <?php echo $variable; ?>.
With short tags enabled, I love my <?=$variable?>.
Lastly there is heredoc format that allows both single and double quotes along with variables.
echo <<<HTML
I love my $variable. '"...
HTML;
Taken from php.net:
"Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings."
So the answer is no you can't. But you can do it like this :
echo 'I love my' . $variable . '.';
It will be cleaner this way.
Beside the solutions mentioned by other users such as string concatenation, you can use placeholders as follows;
Note the %s is for string.
$variable = 'what ever';
printf('The $variable is %s', $variable);
Try this
<php echo 'I love my '. $variable . ' .'; ?>
In my case, I have changed my command as follows and it worked for me:Added double quotes twice("") beside every single quote(')
PVALUE='1,2,3'
echo "variable='""${PVALUE},repmgr'""" >>postgresql.conf
Output:
variable='1,2,3,repmgr'
#How to print a variable in echo within a single quote bash shell script
use the escape sing-quote to surround the text string as:
variable='my dog'
echo \''I love ' $variable\'
=>
'I love my dog'
PHP Code:
$name = 'click here';
echo '$name';
Here I am Expecting 'Click here' but my Output is:
$name
The PHP Manual addresses this accurately:
Note: Unlike the double-quoted and heredoc syntaxes, variables and escape sequences for special characters will not be expanded when they occur in single quoted strings.
To solve the issue, use either one of these solutions:
echo "$name";
echo ''.$name.'';
<?php echo $name; ?>
Either use double quotes around your entire echo statement and escape the quotes in your HTML, or use the concantination operator .
Using double quotes:
"$name";
Using the concantination operator
''.$name.'';
Using double quotes causes PHP to evaluate all variables (replace them with their contents) within the string. However to do this you also have to escape the inner double quotes by making them \" so that PHP doesn't confuse them with the end of the string.
Using the concantination operator you are actually creating 3 different strings, the open tag, the contents of the variable, and the closing tag and then gluing them together using the . to make one complete string which is sent to echo.
Manual reference on strings
http://php.net/manual/en/language.types.string.php
The basics are anything within " (double quotes) is evaluated, anything within ' (single quotes) is not.
So for your code there are a few options
Replace single quotes with double quotes and escape embedded double quotes with \
echo "$name";
You can also replace the embedded double quotes with single quotes (i don't think html minds, not sure about html5)
echo "<a href='http://example.net/some.php' class='menu'>$name</a>";
You could also do a printf, this replace %s = string, with your value $name
printf('%s", $name);
I am confused about using single and double quotes and back slash while using java script and html tags in php can any one please clarify i googled it but still not clear about it. i am confused for this small thing.i am new to programming
- here is my code
<?php
if(isset($_GET['id'])) {
echo '<div id="d2">';
include "test2.php";
echo '</div>'; }
else
{
echo '<div id="d1">';
include "insert.php";
print "<script type=javascript>"
print "document.getEelementById('alertdiv1').innerHTML='hi' ;"
print "</script>"
echo '</div>';
}
?>
In PHP, you can enclose a string in either single quotes or double quotes. Both are valid:
$var = "this is a string";
$var2 = 'this is also a string';
The main difference is that if your string contains a variable, and you want the variable content to be treated as part of the string, you need to use double quotes:
echo "$var which I made";
will return:
this is a string which I made
When you are manipulating html, css and JavaScript strings, you need to make sure that you don't accidentally close your PHP string. For example:
echo "<h1 class='myheading'>Heading Text</h1>";
Notice how I used double quotes to enclose my string? Because I did that, I was able to use single quotes in the html, without escaping them.
If I'd wanted to use double quotes in my string, I would have had to escape them, like this:
echo "<h1 class=\"myheading\">Heading Text</h1>";
The \ tells PHP that the double quote which immediately follows is to be treated as a literal, and not used to terminate the string.
I can't see any problems relating to quotes in your code.
<script type=javascript> — That is not a valid value of the type attribute (which is optional anyway now). Get rid of the type attribute.
document.getEelementById — Element only has 3 es in it, not 4.
alertdiv1 — There is no element with that id in your code
hi as far as concerned single quotes and double quotes doesnt matters when its a string.but when you use any variable inside
$a = 'hi';
echo '$a' ;
will output
$a
but when you use " "
$a = 'hi';
echo "$a" ;
it will print
hi
Basically, if you're using "" (quotation marks) as your delimiter and you then use a quotation mark as part of the string you must escape it by putting a backslash in front of it.
For example:
$string = "This is my string"; // This is fine as the value of the string doesn't contain any quotation marks (")
$string = "I am including a quote in my string \"To Be Or Not To Be\"."; // This is also fine, as I have escaped the quotation marks inside the string
The same applies if you're using '' (apostrophes) as your delimiter and you then want to use them as part of the string, you must escape them using back slash ().
Hope that helps.
$var = "AAA";
echo 'This costs a lot of $var.'; // This costs a lot of $s.
echo "This costs a lot of $var."; // This costs a lot of AAA.
Getting very confused with echoing an HTML anchor with a variable inside.
<?php
echo ' Next';
?>
I've tried so many variations of lost which ones I've tried. One of the attempts was with curly brackets { but still nothing. I know I'm getting my single and double quotes muddled up!
Could somebody please put me straight on this one. Also, what is the rules for apostrophes and quotes in PHP. If I want to echo something, what shall I start it with, an apostrophe or a quote.
<?php
echo ' Next';
?>
If you want to do some math of other trickery inside an echo, you will need to surround it in brackets.
Edit: #DaveRandom points out that the exception to the trickery clause is $var++ and ++$var.
If you use ' when printing string, everything inside is treated as a text.
If you use ", variables passed inside are converted to the their values.
However it's impossible to do a math operations inside ". You have to escape it and do it in 'PHP way'.
<?php
echo ' Next';
?>
Use double quotes "something" and surround the variables with curly brackets when they are inside the quotes.
echo " <a href='?p={$current_page+1}'>Next</a>";
You can also use string concatenation, which basically means joining a few strings together:
echo 'something' . 'something else' . $my_variable;
As for escaping, if anywhere inside some quotes you want to insert a quote of the same type (e.g. if you surround your script with double quotes and you want to insert a double quote), you need to escape these quotes by prepending them with a backslash - \.
For example you want to output Text and you have surrounded it in double quotes, you need to escape these double quotes in the HREF attribute by prepending them with a backslash \, so the result should be Text.
The following are valid ways of escaping and displaying characters:
echo "it\" so nice to be here";
echo 'it\'s so nice to be here';
echo "it's so nice to be here"; // Different quotes, no need to escape
echo 'it"s so nice to be here'; // Different quotes, no need to escape
The following will result in an error:
echo 'it's so nice the be here';
Because the PHP interpreter will assume the expression to be ended with the quote found in it's, resulting in the rest of the line being treated is invalid code.
For more information you can read the PHP documentation on the echo() function and this wonderful article on Quotes and Strings as well.
I assume you want to do this:
echo ' Next';
You can try This
$link = ' %s';
printf($link, $current_page - 1, "Prev");
printf($link, $current_page + 1, "Next");
I try to use single quotes as much as possible and I've noticed that I can't use \n in single quotes. I know I can just enter a newline literally by pressing return, but that screws up the indentation of my code.
Is there some ASCII character or something that I can type that will produce newline when I'm using single quotes?
No, because single-quotes even inhibit hex code replacement.
echo 'Hello, world!' . "\xA";
echo 'hollow world' . PHP_EOL;
Use the constant PHP_EOL then it is OS independent too.
If you are echoing to a browser, you can use <br/> with your statement:
echo 'Will print a newline<br/>';
echo 'But this wont!';
FYI it is possible to get newlines into strings without double quotes:
printf('Please%1$sgive%1$sme%1$snewlines%1$s', PHP_EOL);
Which may be useful If your irrational fear of double quotes knows no bounds. Though I fear this cure may be worse than the disease.
I wonder why no one added the alternative of using the function chr():
echo 'Hello World!' . chr(10);
or, more efficient if you're going to repeat it a million times:
define('C_NewLine', chr(10));
...
echo 'Hello World!' . C_NewLine;
This avoids the silly-looking notation of concatenating a single- and double-quoted string.
The only escape sequence you can use in single quotes is for the single quote itself.
$foo = 'That\'s great';
The only way you could insert a new line into a string created with single quotes is to insert a literal newline
$bar = 'That\'s
cheating';
There IS a difference on using single VS double quotes in PHP
e.g:
1. echo '$var\n';
2. echo "$var\n";
in 1, PHP will print literally: $var\n
in 2, PHP will have to search the location in memory for $var, and return the value in that location, also, it will have to parse the \n as a new line character and print that result
We're in the range of millionths of a second, but there IS a difference in performance. I would recommend you to use single quotes whenever possible, even knowing you won't be able to perceive this performance increase. But I'm a paranoid developer when it comes to performance.
You may want to consider using <<<
e.g.
<<<VARIABLE
this is some
random text
that I'm typing
here and I will end it with the
same word I started it with
VARIABLE
More info at: http://php.net/manual/en/language.types.string.php
Btw - Some Coding environments don't know how to handle the above syntax.
You can use this:
echo 'Hello World' . "\n";
This worked well for me:
print_r('Hello world'.PHP_EOL);
No, according to documentation, PHP recognize no special symbol in single quotes. And there is no single reason to use single quotes as much as possible
in case you have a variable :
$your_var = 'declare your var';
echo 'i want to show my var here'.$your_var.'<br>';