I am trying to print the duplicate records of the table but only the single row is getting
echoed.However in mysql this query results all the duplicate records. Here is the query:
$q = mysql_query("SELECT * FROM add WHERE cust_id = '144' GROUP BY cust_id");
$r = mysql_fetch_array($q);
$s = mysql_num_rows($q);
while($s !=0)
{
echo $r;
$s=$s-1;
}
Whats wrong with the code?
$q = mysql_query("SELECT * FROM add WHERE cust_id = '144' GROUP BY cust_id");
while($r = mysql_fetch_array($q))
{
print_r($r);
}
You need to loop through the entire record set... you are only grabbing the first row:
$resultset = mysql_query("select * from add where cust_id = '144' group by cust_id");
while($row = mysql_fetch_assoc($resultset))
{
echo $row['column_name'];
}
Your SQL query will in practice only ever return 0 or 1 rows, due to the GROUP BY clause. Are you absolutely sure that that's the query you were executing in mysql?
well, if you want to get duplicate values, then this query will serve you well:
T = the table
f = the field to check for duplicates
id = the rows id
select id,f from T group by f having count(f)= 2;
or >2 if you want every value in f that occurs in more than one row.
having is like where but evaluated after group by.
Try the following:
$q = mysql_query("SELECT * FROM add WHERE cust_id = '144'");
while($r = mysql_fetch_array($q))
{
echo $r;
}
Related
To select the previous row in MySQL I use the following script, which works perfect:
<?php
$previous = $row['id'] - 1;
$stmt = $db->query("SELECT * FROM data WHERE id = $previous");
while($row =$stmt->fetch()){echo ''.$row['title'].'';}
?>
In order to select the next row I want to use this script:
<?php
$next = $row['id'] + 1;
$stmt = $db->query("SELECT * FROM data WHERE id = $next");
while($row =$stmt->fetch()){echo ''.$row['title'].'';}
?>
This fetch the first record of the database and not the next row.
When you retrieve the previous row values, you write the data to $row, so when trying to fetch the next row, the value of $row['id'] is in fact the previous row id.
So store the value...
$currentID = $row['id'];
$previous = $currentID - 1;
// Other code
$next = $currentID + 1;
that is not the way you use mysql queries, you only want to run one query and then you loop on your results
either someting like
<?php
$stmt = $db->query("SELECT * FROM data ORDER BY id");
while($row =$stmt->fetch()){
echo ''.$row['title'].'';
}
?>
or
<?php
$stmt = $db->query("SELECT * FROM data ORDER BY id");
$results = $stmt->fetch_all(MYSQLI_ASSOC);
foreach ( $results as $key => $row ) {
echo ''.$row['title'].'';
}
?>
There is not need to add '1' in id and get the data. Its a bad idea. Accordingly if you want a next record then you should check a greater then, else use a lesser then for previous record. Simply...
$id=$row['id'];
next:
select * from <yout_table> where id = (select min(id) from <yout_table> where id > '$id')
previous:
select * from <yout_table> where id = (select max(id) from <yout_table> where id < '$id')
Its is work definitely....
I'm designing a website and I wrote some webpage that display the list of users.
I used to do a
$query = SELECT * FROM `table_users` WHERE `id`='.$id.'
and then increment the ID with a "while" so I can grab all the users. But it's too slow now, and it glitches when there is a gap between IDs.
So I tried something like
$query = SELECT `name` FROM `tbl_user`ORDER BY `id`
and displaying the userlist with a
while ($i < sizeof(mysql_fetch_array(mysql_query($query)))){
<code to display an user>
$i++
}
But the mysql_fetch_array only returnes one user, the first one (the one with the littliest ID). I want it to return all users in an array. How do I do ?
Try This
$query = "SELECT `name` FROM `tbl_user` ORDER BY `id`";
$user_query = mysql_query($query);
$i=1;
while ($row = mysql_fetch_array($user_query)){
echo $i." : ".$row['name']."<br>";
$i++;
}
Try it like this:
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
//$row is the row which was just gathered
}
And please, use PDO or MySQLi instead of deprecated mysql.
How to display only one row at random at the same time from DB. Everything works fine, but all rows are displayed. thanks
<?php
$sql = "SELECT id,name FROM table ";
$rows = array();
$result = $objCon->query($sql);
while($row = $result->fetch_assoc())
{
$rows[] = $row;
}
shuffle($rows);
echo '<ol>';
foreach($rows as $row)
{
echo '<li><h3>'.$row['id'].' = '.$row['name'].'</h3></li>';
}
echo '</ol>';
?>
Change your SQL request:
SELECT id,name FROM table ORDER BY RAND() LIMIT 1;
You can do it using PHP:
....
shuffle($rows);
$randomRow = reset($rows);
....
But the better way is to change your SQL query:
$query = "SELECT id, name FROM table ORDER BY RAND() LIMIT 1;"
<?php
$sql = "
SELECT id, name
FROM table
ORDER BY RAND()
LIMIT 1 ";
$result = mysql_query($sql);
// As you are only return a single row you do you require the while()
$row = mysql_fetch_array($result);
echo '<ol>';
echo '<li><h3>'.$row['id'].' = '.$row['name'].'</h3></li>';
echo '</ol>';
?>
By adding an ORDER BY RAND() in your sql query you are asking MySQL to randomly order the results then at a LIMIT to restrict the number of rows you would like returned.
The example code is written based on selecting a single row. If you would like more, e.g. 5, you will need to add a while loop.
I am trying to perform a query inside a while loop that is getting values from a column. I am trying to query first to get all my values from a column in my DB and then get the count of how many times that value is in that column.
Examples of output trying to get
myValue is in the column 3 times
myOtherValue is in the column 10 times
myOtherOtherValue is in the column 22 times
Example of code
$sql = "SELECT DISTINCT id, columnName FROM tableName";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
$id = $row['id'];
function myCount($id)
{
$query = "SELECT COUNT(*) FROM tableName WHERE name = '$id'";
$result = mysql_query($query);
$count = mysql_fetch_array($result);
}
echo "$id is in the column $count[0] times";
}
You can't define a function inside the while loop.
Using COUNT(*) with a GROUP BY name clause, then you could solve the problem with only one query.
I am using the following MySQL query to generate a table for users in a database. The query is designed to just return one row for each user, even though there are multiple rows for each user. This works fine, however I also need to calculate the number of unique entries for each user, to enter into the table where it states HERE. Do I need to use another query to return the count for all entries, and if so how do I integrate this with the code I already have?
$query="SELECT from_user, COUNT(*) AS num FROM tracks GROUP BY from_user ORDER BY COUNT(*) DESC";
$result=mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
$user = $row['from_user'];
echo "<tr>";
echo "<td>".$user."</td>";
echo "<td>uploads (**HERE**)</td>";
echo "<td>favourites (count)</td>";
echo "</tr>";
}
?>
</table>
Because you've already created the custom field 'num', you can use that to get the count!
Add the following line after user = ...
$count = $row['num'];
Then you can
echo "<td>uploads ($count)</td>";
It miss your table stucture to know your field name, but, if i well understand your question you can use count + distinct in mysql.
You can check this answer too.
SELECT DISTINCT(from_user) AS user,
COUNT(from_user) AS num
FROM tracks
GROUP BY from_user
ORDER BY num DESC";
For the second problem you can doing a second query, or do a join tracks .
I think, in your case it's easier to you to do se second query inside the loop to get all detail from 'user' result.
$query1="SELECT DISTINCT(from_user), COUNT(*) AS num
FROM tracks
GROUP BY from_user
ORDER BY COUNT(*) DESC";
$query2="SELECT * FROM tracks";
$result1=mysql_query($query1) or die(mysql_error());
$result2=mysql_query($query2) or die(mysql_error());
$user_array = array();
while ($row = mysql_fetch_array($result1)) {
$user = $row['from_user'];
$num = $row['num'];
$uploads_array = array();
while ($sub_row = mysql_fetch_array($result2)) {
if( $sub_row['from_user'] == $user ) {
//for example only due to the unknown structure of your table
$uploads_array[] = array(
"file_name" => $sub_row['file_name'],
"file_url" => $sub_row['file_url']
);
}
}
$user_array[] = array(
"name" => $user,
"num_entry" => $num,
"actions" => $uploads_array
);
}
// now the table with all data is stuctured and you can parse it
foreach($user_array as $result) {
$upload_html_link_arr = array();
$user = $result['name'];
$num_entry = $result['num_entry'];
$all_actions_from_user_array = $result['actions'];
foreach($all_actions_from_user_array as $upload) {
$upload_html_link_arr[] = sprintf('%s', $upload["file_url"],$upload["file_name"]);
}
$upload_html_link = implode(', ',$upload_html_link_arr);
$full_row = sprintf("<tr><td>%s</td><td>uploads : %s</td><td>favourites (%d)</td></tr>", $user, $upload_html_link, $num_entry);
// now just echo the full row or store it to a table for the final echo.
echo $full_row;
}
I hope this help, mike