I have three database tables, question_set, question and answer.
question_set contains set_name and set_id
question contains question and also question_set_id
answer contains answer , question_id
I can not work out a way to show all the data in one view file,
I tried joins but then question data is repeating with it prints because every question has three or four answer.
Just thought I would point out.
Your database design is horrible.
It will not scale well, and infact I do not think it would actually. work.
The way I would do it is
Three tables
sets => id, name
questions => id, set_id, question
answers => id, set_id, question_id, answer, points
Note that in my above example I am taking it one step further, rather than each answer being true or false, it can have an assigned point value.
hence, an answer that you deemed half correct could be given 5 points, where as a correct answer could be given 10 points, it also works as a boolean true, just have a correct answer as 1 point, and an incorrect answer as 0 points
Anyway.
With the above table design in mind.
You could do
$this->db->select('s.id as set, s.name as name, q.id as qid, q.question as qu, a.id as aid, a.answer as an, a.points as p')
->from('sets s')
->join('questions q', 'q.set_id = s.id')
->join('answers a', 's.set_id = s.id')
->where('s.id', 'SET ID');
$questions = $this->db->get();
$set = array('questions' => array());
foreach($questions as $s){
$set['id'] = $s->set;
$set['name'] = $s->name;
$set['questions'][$s->qid]['id'] = $q->qid;
$set['questions'][$s->qid]['question'] = $q->qu;
if(!isset($set['questions'][$s->qid]['answers']))
$set['questions'][$s->qid]['answers'] = array();
$set['questions'][$s->qid]['answers'][] = array(
'id' => $q->aid,
'answer' => $q->an',
'points' => $q->p
);
}
So then you end up with an array that looks something like
array(
'id' => 1,
'name' => 'My first quiz',
'questions' = array(
array(
'id' => 1,
'question' => 'What is 1+1+1?',
'answers' => array(
array(
'id' => 1,
'answer' => 1,
'points' => 0
),
array(
'id' => 2,
'answer' => 2,
'points' => 0
),
array(
'id' => 3,
'answer' => 3,
'points' => 1
)
)
),
array(
'id' => 2,
'question' => 'What is 2+2+2?',
'answers' => array(
array(
'id' => 4,
'answer' => 6,
'points' => 1
),
array(
'id' => 5,
'answer' => 2,
'points' => 0
),
array(
'id' => 6,
'answer' => 3,
'points' => 0
)
)
)
)
);
Then you can do.
echo '<h2>'.$set['name'].'</h2>';
foreach($set['questions'] as $q){
echo '<div class="question">';
echo '<h3>'.$q['question'].'</h3>';
echo '<div class="answers">';
foreach($q['answers'] as $a){
echo '<label for="a'.$a['id'].'">'.$a['answer'].'<input type="checkbox value="'.$a['id'].'" name="q'.$q['id'].'" /></label><br />';
}
echo '</div>';
echo '</div>';
}
The easiest way, but which of course requires more SQL calls, is to use nested loops for this.
1) Join the question set and question tables
2) For each entry in the result set, retrieve the answers for that entry and put it in a separate array, nested in a bigger array where the key is the id of the question.
Your view would then look something like this:
foreach($questions as $question)
{
//Print question information
$answers = $answers_array[$question['id']];
foreach($answers as $answer)
{
//Print answers information
}
}
Might not be best practice but it will do the trick.
Related
I am new with coding and I just can't seem to get my head around this. A little help or tip is much appreciated.
Basically I want an array with Questionnaires, which consist of id, name and a sub array of questions. Questions also consist of id and name.(1 Questionnaire can have multiple questions)
Something like this is what I am looking for:
[{Questionnaires{id:x, name:x, questions:{id:x, name:x},{id:x2, name:x2}}]
This is my query
SELECT questionnaires.id QuestionnaireId, questionnaires.title QuestionnaireTitle, questions.id QuestionId, questions.text Question
FROM questionnaires INNER JOIN questionnaireshasquestions qa ON qa.idQuestionnaire = questionnaires.id
INNER JOIN questions ON questions.id = qa.idQuestion
And my PHP Code:
while ($row = $conn->fetch()) {
if (!isset($data['questionnaires'][$row['QuestionnaireId']])) {
$data['questionnaires'][] = array(
'id' => $row['QuestionnaireId'],
'title' => $row['QuestionnaireTitle'],
'questions' => array(
'id' => $row['QuestionId'],
'text' => $row['Question']
)
);
} else {
$data['questionnaires'][$row['QuestionnaireId']][] = array(
'questions' => array(
'id' => $row['QuestionId'],
'text' => $row['Question']
)
);
}
The JSON array I get with this is in a wrong/incorrect format:
{"questionnaires":[{"id":"1","title":"Are you hungry?","questions":{"id":"1","text":"How is your passion? "}},{"id":"1","title":"Are you hungry?","questions":{"id":"2","text":"Do you drink?"}},{"id":"2","title":"How are you feeling?","questions":{"id":"1","text":"How is your passion? "},"0":{"questions":{"id":"3","text":"Do you like fish?"}}},{"id":"5","title":"Is testing working?","questions":{"id":"4","text":"How is the testing?"}}]
As you can see, it repeats the same Questionnaire for each Question within...
I hope I explained well what I am trying to do here :)
Your collection method was a bit "broken".
This should work:
while ($row = $conn->fetch()) {
$id = $row['QuestionnaireId'];
if (!isset($data['questionnaires'][$id])) {
// First time we get this "QuestionnaireId" -
// define "container" that collects the related questions.
$data['questionnaires'][$id] = [
'id' => $row['QuestionnaireId'],
'title' => $row['QuestionnaireTitle'],
'questions' => [],
];
} else {
// Already got this "container" -
// put the question into the collection.
$data['questionnaires'][$id]['questions'][] = [
'id' => $row['QuestionId'],
'text' => $row['Question']
];
}
}
I'm working on trying to figure out how to show a search result from closest match to least closest.
Let's assume this is the multidimensional array of results. You will notice that there are arrays with the same "id", but have different "categories". I'm pretending this is a one-to-many relationship. So I'm assuming, for 1 "id", a user might have tagged it to 3 different relevant categories.
$results[] = array(
'id' => 1 ,
'text' => 'this is my first post',
'category' => 'blue'
);
$results[] = array(
'id' => 1 ,
'text' => 'this is my first post',
'category' => 'green'
);
$results[] = array(
'id' => 1 ,
'text' => 'this is my first post',
'category' => 'purple'
);
$results[] = array(
'id' => 2 ,
'text' => 'this is my second post',
'category' => 'blue'
);
$results[] = array(
'id' => 2 ,
'text' => 'this is my second post',
'category' => 'green'
);
Now, let's assume there are criteria that the user selected. I'll show it in array form:
$criterias = array('blue', 'green', 'purple');
Using this example, that means the $results "id" of 1 should show up first, and I want to show it's "text". This is because it scored 3 out of 3 (based on matching the criteria that was set in $criterias). Then following this logic the $results "id" of 2 should show up second because it only scored a 2 out of 3.
The final form what what I'm looking to do is be able to echo out the "text" value from highest score to lowest.
My level of programming in PHP is intermediate, so if you could please demonstrate a less complex solution that an intermediate could understand that would be great.
What I tried and didn't get to work was trying to first try to score it and put it into another multidimensional array and sort it, then echo it, but I couldn't get it to work.
Sorry for confusing title. But I don't know how to explain this.(I don't speak that good English)
Here is a picture to make it alittle bit more clear:
http://img823.imageshack.us/img823/8812/edxt.png
If pic_name=328.jpg AND user=myhrmans return value of 1
else if you cant find value user=myhrmans return 0 for example. Anyway I can pull this off?
Thank you :)
Not sure to understand precisely what you mean, but I'm going to make an attempt.
Your query should be written somehow like this one:
SELECT user, pic_name,
IF(user = 'myhrmans' AND pic_name = '328.jpg', 1, 0) AS value
FROM yourtable
WHERE user = myhrmans;
When executed from PHP (and after fetching the values), your query will return this array:
$result = array(
0 => array(
'user' => 'myhrmans',
'pic_name' => '326.jpg',
'value' => 0
),
1 => array(
'user' => 'myhrmans',
'pic_name' => '329.jpg',
'value' => 0
),
2 => array(
'user' => 'myhrmans',
'pic_name' => '328.jpg',
'value' => 1
),
3 => array(
'user' => 'myhrmans',
'pic_name' => '319.jpg',
'value' => 0
)
);
Which, if I understood, approaches what you want.
Here is the query string.
$query = "SELECT t.id, t.assignee, t.owner,
d.code, d.status, d.target_completion_date,
d.target_extension_date, d.submission_date, d.approval_date,
d.revision_start_date, d.revision_completion_date, d.message,
ty.name, f.orig_name, f.new_name,
b.payment_date, b.discount, b.total_cost, b.amount_payed, b.edit_level,
b.billing_type, b.pages, b.words
FROM tasks t
INNER JOIN details d ON t.detail_id = d.id
INNER JOIN billing b ON t.billing_id = b.id
INNER JOIN TYPE ty ON d.document_type_id = ty.id
INNER JOIN files f ON t.file_id = f.id
WHERE t.assignee = 'argie1234'";
And this is the array i would like the query result to turn into.
$user = array('allTask'=>array(array('taskid' => 1,
'assignee'=>'argie1234',
'owner'=>'austral1000',
'details' => array( 'code' => 'E',
'status'=>'TC',
'targetCompletionDateUTC'=>'1379401200',
'targetExtentionDateUTC'=>'1379401200',
'submissionDateUTC'=>'1379401200',
'approvalDateUTC'=>'1379401200',
'revisionStartDateUTC'=>'1379401200',
'revisionCompletionDateUTC'=>'1379401200',
'messageToEditor'=>'Please work on it asap.',
'documentType' => 'Thesis'),
'file' => array('orig_name' =>'originalname.docx',
'new_name' => 'newname.docx'),
'billing'=>array('paymentDate'=>'July 26,2013 12:40',
'discount' => '0',
'totalRevisionCharge' => '$20.00',
'totalAmountPayed' => '$20.00',
'revisionLevel' => '1',
'chargeType'=> '1',
'numPages' => '60',
'numWords' => '120,000' ) ),
array('taskid' => 12,
'assignee'=>'argie1234',
'owner'=>'usaroberto',
'details' => array( 'code' => 'E',
'status'=>'TC',
'targetCompletionDateUTC'=>'1379401200',
'targetExtentionDateUTC'=>'1379401200',
'submissionDateUTC'=>'1379401200',
'approvalDateUTC'=>'1379401200',
'revisionStartDateUTC'=>'1379401200',
'revisionCompletionDateUTC'=>'1379401200',
'messageToEditor'=>'Please work on it asap.',
'documentType' => 'Thesis'),
'file' => array('orig_name' => 'originalname.docx',
'new_name' => 'newname.docx'),
'billing'=>array('paymentDate'=>'July 26,2013 12:40',
'discount' => '0',
'totalRevisionCharge' => '$20.00',
'totalAmountPayed' => '$20.00',
'revisionLevel' => '1',
'chargeType'=> '1',
'numPages' => '60',
'numWords' => '120,000' ) ),
'account' => array( 'username' => 'marooon55',
'emailadd' => 'marooon#yahoo.com',
'firstname' => 'Maroon',
'initial' => 'E',
'lastname' => 'Young',
'country' => 'Australia',
'gender' => 'M',
'password' =>'360e2801190744a2af74ef6cbfdb963078b59709',
'activationDate' => '2013-09-13 14:30:34') );
How can i create the above array? I sure know how to define multi dimensional array, regretfully though i am having difficulty creating this complex array dynamically. As a beginner i don't even know where to begin.
Here is an example that might help you out. Try starting with simple multi dimensional arrays, once you get a hold of it, you can move onto building complex ones. You will then find that the array you want to build is not really difficult than you initially thought it to be.
$mycomplexarray = array('key1' => array('val1', 'val2'),
'key2' => array('val3', 'val4' => array('val5', 'val6')
)
);
You could create the array just as you have here. I'm not gonna write the whole thing out, but something like this...
$result = $mysqli->query($query); // however you query the db is up to you.
$row = $result->fetch_assoc(); //same as query use your prefered method to fetch
$user = array('allTask'=>array(array('taskid' => $row['id'],
'assignee'=>$row['assignee'],
'owner'=>$row['owner'],
'details' => array( 'code' => $row['code'],
'status'=>$row['status'],
...etc, Hope this makes sense for you.
Set up a structure array first that defines which columns will be stored in a sub array like
$struc=array('Id'->0, 'assignee'->0, 'owner'->0,
'code'->'detail', 'status'->'detail', 'target_completion_date'->'detail',
'target_extension_date'->'detail', 'submission_date'->'detail', 'approval_date'->'detail',
'revision_start_date'->'detail', 'revision_completion_date'->'detail', 'message'->'detail',
'name'->'file', 'orig_name'->'file', 'new_name'->'file',
'payment_date'->'billing', 'discount'->'billing', 'total_cost'->'billing', 'amount_payed'->'billing', 'edit_level'->'billing', 'billing_type'->'billing', 'words');
In your while ($a=mysqli_fetch_assoc($res)) loop you can now use this structure to decide whether you want to store an element directly in your target array or whether you want to place it in the subarray named in this structure array. Like
$res=mysqli_query($con,$sql);
$arr=array();
while($a=mysqli_fetch_assoc($res)) {
// within result loop: $a is result from mysqli_fetch_assoc()
$ta=array(); // temp array ...
foreach ($a as $k => $v){
if ($struc[$k]) $ta[struc[$k]][$k]=$v;
else $ta[$k]=$v;
}
$arr[]=$ta; // add to target array
}
This is the complete code, no more is needed. It was typed up on my iPod, so it is NOT tested yet.
The generated array should be equivalent to your $user['allTask'] array.
So, I have three tables. Movies, movies_genres and genres. I want to get a movie by its Id, and also join its genres in the result. I managed to join the results, but it doesn't display as i want it to. I'm not sure if what I'm asking is possible.
This is my query:
SELECT `movies`.*, GROUP_CONCAT(genres.id) AS genre_id, GROUP_CONCAT(genres.name) AS genre_name
FROM (`movies`)
INNER JOIN `movies_genres`
ON `movies_genres`.`movie_id` = `movies`.`id`
INNER JOIN `genres`
ON `genres`.`id` = `movies_genres`.`genre_id` WHERE `movies`.`id` = 19908
GROUP BY `movies`.`id`
The query was generated by Codeigniters Active Record class, here is the Codeigniter code if that helps:
$this->db->select('movies.*, GROUP_CONCAT(genres.id) AS genre_id, GROUP_CONCAT(genres.name) AS genre_name');
$this->db->from('movies');
$this->db->where('movies.id', $movie_id);
$this->db->join('movies_genres', 'movies_genres.movie_id = movies.id', 'inner');
$this->db->join('genres', 'genres.id = movies_genres.genre_id', 'inner');
$this->db->group_by('movies.id');
Here is the result i'm currently getting:
Array
(
[id] => 19908
[movie_title] => Zombieland
[overview] => An easily spooked guy...
[genre_id] => 28,12,35,27
[genre_name] => Action,Adventure,Comedy,Horror
)
And this is what I want:
Array
(
[id] => 19908
[movie_title] => Zombieland
[overview] => An easily spooked guy...
[genres] => array(
0 => array(
'id' => 28,
'name' => Action
),
1 => array(
'id' => 12,
'name' => Adventure
),
1 => array(
'id' => 35,
'name' => Comedy
),
1 => array(
'id' => 27,
'name' => Horror
)
)
)
Is this possible, and if so, how?
The query you listed will have n rows (where n = # of movies) whereas the query it seems you want will have many more rows (# of movie_genre's entries). You're probably better off leaving that query as it is, and doing some post processing.
Consider:
After you get it, just run your result (e.g. $result) array through something like:
foreach($result as &$row)
{
// Split over commas
$gi_elements = explode(',', $row['genre_id']);
$gn_elements = explode(',', $row['genre_name']);
// Build genre
$row['genre'] = array();
for($i=0; $i<count($gi_elements); $i++)
{
$row['genre'][] = array('id' => $gi_elements[$i], 'name' => $gn_elements[$i]);
}
// Cleanup
unset($row['genre_id']);
unset($row['genre_name']);
}
Afterwards, $results will look exactly as you wish without extra database work.
EDIT: Fixed some typos.