how to find date of last thursday of the month in php ?
it is for the payment thing. staffs needs to paid on last thursday of the month on which they have submitted invoices. I am having hard time finding out the date of last thursday of month
thanks
abhinab
PHP >= 5.3:
<?php
$date = strtotime('last thu of this month');
echo date('d.m.Y H:i:s', $date);
PHP < 5.3:
<?php
$date = strtotime(sprintf('+1 month %s %s', date('F'), date('Y')));
while (date('D', $date) !== 'Thu') {
$date -= 86400;
}
echo date('d.m.Y H:i:s', $date);
(didn't find a better way to do this)
Output:
30.06.2011 00:00:00
Find the first day of the month right after.
Walk backwards one day at a time until you hit a Thursday.
Related
I need to get yesterday's date to show the market close date. This only applies to Monday through Friday as the markets are not open on the weekend. Using this format how would I do that?
<?php
$yesterday = date("Y-m-d", mktime(0, 0, 0, date("m") , date("d")-1,date("Y")));
echo $yesterday;
?>
Here's one way to do it:
$date= new \DateTime();
$oneDay = new \DateInterval('P1D');
$date->sub($oneDay);
if ('Sunday' === $date->format('l')) {
$date->sub($oneDay);
}
if ('Saturday' === $date->format('l')) {
$date->sub($oneDay);
}
echo $date->format('Y-m-d');
I just get today's date, subtract one day, and check to see if it is a Sunday. If so, subtract a day. Then I do the same thing for a Saturday. Ultimately you end up with the last weekday.
Keep in mind this is different then business day's as that Friday may be a holiday and the markets may be closed.
You could check what day the current week day is with date('w').
Note that Sunday is 0, and Saturday is 6.
And with that information, you can do:
$yesterday = strtotime(date('w') == 0 || date('w') == 6 ? 'last friday' : 'yesterday');
echo date('Y-m-d', $yesterday);
Basically, if it's a weekend, you ask for the last friday, otherwise, you ask PHP for yesterday.
If you don't like it in one line:
$w = date('w');
if($w == 0 || $w == 6)
$yesterday = strtotime('last friday');
else
$yesterday = strtotime('yesterday');
$yesterday = date('Y-m-d', $yesterday);
In our case today, Tuesday, June 14th 2016, it will return 2016-06-13.
For more information about the date function: http://php.net/manual/en/function.date.php
Why does
echo date("j/m/Y", strtotime("2015/01/31 00:00 next month"));
gives
3/03/2015
and not
28/02/2015
All I'm looking for is a todays date next month and if todays date is not valid then it'll give me the last day of next month.
$thisMonth = "2015-01-31 00:00";
$thisMonthDate = strtotime($thisMonth);
$nextMonthDate = strtotime($thisMonth . ' next month');
if (date('j', $thisMonthDate) !== date('j', $nextMonthDate)) {
$nextMonthDate = strtotime(date('Y-m-d H:i:s', $nextMonthDate) . ' last day of previous month');
}
echo date('Y-m-d H:i:s', $nextMonthDate), PHP_EOL;
What PHP is doing here is the following:
first it adds a month to your date, arriving to "2015/02/31"
then it realizes that this date does not exist, and that it is 3 days after "2015/02/28", which, translated in human terms, is "2015/03/03"
Look here for a solution to your problem, as #kingkero suggested
Here's a summary of the issue: On Sundays, strtotime('this week') returns the start of next week.
In PHP, the week seems to start on Monday. But, on any day except Sunday, this code
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
Outputs the date of this week's Monday, when it seems like it should be outputting last weeks Monday. It seems like, in this case, PHP is treating both Sunday and Monday as the the start of the week. It's now Monday, Dec 10, 2012, or 2012-12-10. date('Y-m-d', strtotime('sunday last week')) returns 2012-12-09 - yesterday.
Is this a bug, or am I missing something? It seems like a bug this obvious should be fairly well known, but I can't find anything about it. Is the only way to get the start of the week to use some special handling for Sundays?
$week_offset = (int) 'sunday' == date('l');
$week_start = strtotime("-$week_offset monday"); // 1 or 0 Mondays ago
As far as I can tell, this is a bug. I see no logical reason why strtotime('this week'); should return a future date. This is a pretty major bug. In my particular case, I had a leaderboard that showed the users with the most points since the beginning of the week. But on Sundays, it was empty because strtotime returned a timestamp for a future date. I was doubtful, because just I don't know how this could have gone unnoticed, but I couldn't find any other reports of this bug.
Thanks for all your time and help, folks.
This answer is late, but it's something that I've been struggling with. Every solution I've tried so far has malfunctioned for one reason or another. This is what I ended up with that worked for me. (though it may be look pretty, it at least works).
$thisMonday = strtotime('next Monday -1 week', strtotime('this sunday'));
Here is how you can get Monday of current week:
echo date("Y-m-d", strtotime(date('o-\\WW')));
It's not ideal but this is what I resorted to using:
if(date('N') == 7) {
$date = date('Y-m-d',strtotime('monday last week'));
} else {
$date = date('Y-m-d',strtotime('monday this week'));
}
I think the only problem with your coding is TimeZone.
Solution:
Set your own time Zone. Here is the example of my own time zone:
Example
date_default_timezone_set('Asia/Kolkata');
Set the above line before calling any time function.
Have a nice day.
I think instead of trying
echo date('Y-m-d', strtotime('monday this week', strtotime('last sunday')));
you should try
echo date('Y-m-d', strtotime('monday last week'));
Try this code
// set current date
$date = date("m/d/Y");
$ts = strtotime($date); // also $ts = time();
// find the year and the current week
$year = date('o', $ts);
$week = date('W', $ts);
// print week for the current date
$i = 1; // 1 denotes the first day of week
$ts = strtotime($year.'W'.$week.$i);
echo $day = date("l", $ts); // generate the name of day
echo "<br>";
echo $day = date("Y-m-d", $ts); // generate the date
You will get the the date of current week, whether you are on monday you will get the date of that monday.
If you want the most recent monday:
function mostRecentMonday(){
if(date("w") == 1){
return strtotime("midnight today");
} else {
return strtotime("last monday");
}
}
Easy to modify to use DateTime, or, to even specify a different date to use as the base.
Based on Bryant answer :
$first_week_date = date('d F Y', strtotime('next Monday -1 week', strtotime('this sunday')));
$last_week_date = date('d F Y', strtotime('next Monday -1 week + 6 days', strtotime('this sunday')));
This is for thos looking for a friendly solution that works with any day.
function getWeekStart($week_start_day = "Monday") {
$week_days = array("Sunday"=>0,"Monday"=>1,"Tuesday"=>2,"Wednesday"=>3,"Thursday"=>4,"Friday"=>5,"Saturday"=>6,);
if(!isset($week_days[$week_start_day])) {
return false;
} else {
$start_day = $week_days[$week_start_day];
$today = date("w");
$one_day = (60 * 60 * 24);
if($today < $start_day) {
$days_difference = 7 - ($start_day - $today);
} else {
$days_difference = ($today - $start_day);
}
$week_starts = strtotime(date("Y-m-d 00:00:00")) - ($one_day * $days_difference);
return $week_starts;
}
}
//Test: If today is Monday, it will return today's date
echo date("Y-m-d H:i:s", getWeekStart("Monday"));
I expected this functional to return 6/30/2005 instead of 7/1/2005.
print date("m/d/Y", strtotime("12/31/2004 +6 month"));
Similarly, print date("m/d/Y", strtotime("1/31/2011 +1 month")) returns 03/03/2011 while would like it to return 2/28/2011.
Does anyone know if there is a straight forward way to show the last day of the added month?
How about this?
echo date("m/d/Y", strtotime("last day of 12/31/2004 + 6 month")); // 6/30/2005
echo date("m/d/Y", strtotime("last day of 1/31/2011 + 1 month")); // 2/28/2011
Demo
Edit: For your reference, here is a link to the documentation for relative times.
as strtotime continue in to next month if there isn't enoghe days that month,
you can back 6 month and check if its end up on the start date
$date2 = date("Y-m-d", strtotime("{$date} +6 months"));
$date3 = date("Y-m-d", strtotime("{$date2} -6 months"));
if($date3 != $date)
{
$date2 = date("Y-m-t", strtotime("{$date2} -1 months"));
}
(or in your case "m/t/Y")
One simple way is to actually go one month ahead of the day you want and then make the day value zero. Also, mktime() might be easier
$mymonth = 2; // I want the last day of February
echo date('m/d/Y', mktime(0,0,0,$mymonth+1,0,2011));
This should return 2/28/2011.
strtotime does the best it can with conflicting information. Saying
1/31/2011 +1month
would mean advancing to
2/31/2011
but February only has 28 (sometimes 29) days. 2011 isn't a leap year, so the "31st of February" gets normalized to "March 3rd".
The same applies for '12/31/2004 +6month'. That takes you to June 31st, 2005. But June only has 30 days, so the date is normalized to July 1st instead.
A client wants a newsletter to be automatically generated every Monday, showing the schedule for the upcoming week. That's easy:
if(date('N', $time)==1) { /* Stuff */ }
Attach that to a crontab running nightly and I'm good to go.
However, if the newsletter is being generated in the last week of the month, it needs to show the schedule for the upcoming month. How would I determine when the monthly schedule needs to be generated?
date('m') == date('m', strtotime('+1 week'))
If the month a week from the date the report is running is different than the current month, show the report!
if(date('n', $time) !== date('n', $time+518400)){
// Six days from now it will be a new month
}
One way might be to see if next Monday is in a different month.
if (date('n', $time) != date('n', $time + 7*24*60*60)) { ... }
You could be fancier, but this seems consistent with your existing code.
You can use the t date format param to see how many days are in the particular month. Try
if ((date('t', $time) - date('j', $time)) > 6) {
// in the last week of the month
}
I know this a answered but this will help more:
PHP's built-in time functions make this even simple. http://php.net/manual/en/function.strtotime.php
// Get first Friday of next month.
$timestamp = strtotime('first fri of next month');
// Get second to last Friday of the current month.
$timestamp = strtotime('last fri of this month -7 days');
// Format a timestamp as a human-meaningful string.
$formattedDate = date('F j, Y', strtotime('first wed of last month'));