I want to only display 5 results from my database with my PHP search script. How can I do this?
My PHP code is:
<?php
mysql_connect("localhost","username","password");
mysql_select_db("database");
if(!empty($_GET['q'])){
$query= mysql_real_escape_string(trim($_GET['q']));
}
$searchSQL = "SELECT * FROM links WHERE `title` LIKE '%{$query}%'";
$searchResult = mysql_query($searchSQL);
while ($row=mysql_fetch_assoc($searchResult)){
$results[] = "<div class='webresult'><div class='title'><a href='{$row['url']}'>{$row['title']}</a></div><div class='desc'>{$row['description']}</div><div class='url'>{$row['url']}</div></div>";
}
echo implode($results);
?>
<?php
$database=mysql_connect("localhost","username","password");
mysql_select_db("database");
if(!empty($_GET['q'])){
$query= mysql_real_escape_string(trim($_GET['q']));
$searchSQL = "SELECT * FROM links WHERE `title` LIKE '%{$query}%' LIMIT 0,5";
// .^.
// add a limit clause here. |
$searchResult = mysql_query($searchSQL);
while ($row=mysql_fetch_assoc($searchResult)){
$results[] = "<div class='webresult'><div class='title'><a href='{$row['url']}'>{$row['title']}</a></div><div class='desc'>{$row['description']}</div><div class='url'>{$row['url']}</div></div>";
}
echo implode($results);
}
?>
Solution: Add a LIMIT clause to your query, in order to limit the number of the returned results.
Suggestion: Place your database querying code inside the if clause, because this way you will avoid troubles of the GLOBAL variables kind.
where you have $searchSQL = "SELECT * FROM links WHEREtitleLIKE '%{$query}%'"; you can change this to using a LIMIT clause like so:
$searchSQL = "SELECT * FROM links WHERE `title` LIKE '%{$query}%' LIMIT 5";
For more information on using a LIMIT clause try the following links:
MySQL Reference guide
SELECT * FROM links WHERE `title` LIKE '%{$query}%' LIMIT 0,5"
that should display 5 results.
Related
I am using the following to fetch the latest articles from the database:
//Latest Article
$title_query1 = "SELECT title FROM articles ORDER BY id DESC LIMIT 1";
$description_query1 = "SELECT description FROM articles ORDER BY id DESC LIMIT 1";
$content_query1 = "SELECT content FROM articles ORDER BY id DESC LIMIT 1";
$image_query1 = "SELECT image FROM articles ORDER BY id DESC LIMIT 1";
$title_result1 = mysqli_query($con, $title_query1) or die(mysqli_error($con));
$description_result1 = mysqli_query($con, $description_query1) or die(mysqli_error($con));
$content_result1 = mysqli_query($con, $content_query1) or die(mysqli_error($con));
$image_result1 = mysqli_query($con, $image_query1) or die(mysqli_error($con));
//Second Latest Article
$title_query2 = "SELECT title FROM articles ORDER BY id DESC LIMIT 2,1";
$description_query2 = "SELECT description FROM articles ORDER BY id DESC LIMIT 2,1";
$content_query2 = "SELECT content FROM articles ORDER BY id DESC LIMIT 2,1";
$image_query2 = "SELECT image FROM articles ORDER BY id DESC LIMIT 2,1";
$title_result2 = mysqli_query($con, $title_query2) or die(mysqli_error($con));
$description_result2 = mysqli_query($con, $description_query2) or die(mysqli_error($con));
$content_result2 = mysqli_query($con, $content_query2) or die(mysqli_error($con));
$image_result2 = mysqli_query($con, $image_query2) or die(mysqli_error($con));
However, i'm not sure how I can then do something like this:
<h1>Here is the first article: <?php $title_result1 ?><h1>
<h2>Here is the first article description: <?php $description_result1 ?>
<h1>Here is the second article: <?php $title_result2 ?><h1>
<h2>Here is the second article description: <?php $description_result2 ?>
Also, is this method not good? If I am going to do this for 100+ articles, will it cause the web page to load slowly?
Thanks
You do not need to do a single query for each column. You can get all columns for a row by doing select * Also, as mentioned, you can fetch as many rows as you want, and loop through them.
I prefer the while method.. Example, show last 100 articles
// fetch latest 100
$sql = "SELECT * FROM articles ORDER BY id DESC LIMIT 100";
if ($result = mysqli_query($con, $sql)){
// got results, convert result object to array called $row
while ($row = mysqli_fetch_array($result)) {
// echo out $row array elements with
//the column names from the database as array index
echo '<h2>'. $row['title'] .'</h2>'; // example wrap results with HTML
echo '<b>' .$row['description'] .'</b>';
echo $row['content'];
echo <img src="'. $row['image'] .'" title="'.$row['description'].'">';
echo '<br>'; //so next result is on new line
} // end of while loop
} else {
//no result, error
}
I'm trying to order a list of items based on the amount of comments for each topic as shown below:
$page = $_GET['page'];
$query = mysql_query("SELECT * FROM topic WHERE cat_id='$page' LIMIT $start, $per_page");
if (mysql_num_rows($query)>=1)
{
while($rows = mysql_fetch_array($query))
{
$number = $rows['topic_id'];
$title = $rows['topic_title'];
$description = $rows['topic_description'];
//get topic total
$sqlcomment = mysql_query("SELECT * FROM comments WHERE topic_id='$number'");
$commentnumber = mysql_num_rows($sqlcomment);
// TRYING TO ORDER OUTPUT ECHO BY TOPIC TOTAL ASC OR DESC
echo "
<ul>
<li><h4>$number. $title</h4>
<p>$description</p>
<p>$topictime</p>
<p>$commentnumber</p>
</li>
</ul>
";
}
}
else
{
echo "<p>no records available.</p><br>";
}
What would be the best way to order each echo by $num_rows (ASC/DESC values)? NOTE: I've updated with the full code - I am trying to order the output by $commentnumber
The first query should be:
SELECT t.*, COUNT(c.topic_id) AS count
FROM topic AS t
LEFT JOIN comments AS c ON c.topic_id = t.topic_id
WHERE t.cat_id = '$page'
GROUP BY t.topic_id
ORDER BY count
LIMIT $start, $per_page
You can get $commentnumber with:
$commentnumber = $rows['count'];
You don't need the second query at all.
First of all you have error here
echo "divs in order from least to greatest "number = $num_rows"";
It should be
echo "divs in order from least to greatest number = " . $num_rows . "";
And about the most commented try with
$sql = "SELECT * FROM `table` WHERE `id` = '$id' ORDER BY column DESC/ASC";
Or if there is not count column try with
$sql = "SELECT * FROM `table` WHERE `id` = '$id' ORDER BY COUNT(column) DESC/ASC";
I have problem making this to work. I wannt to select row from database and render it to list. This is my code:
<ul class = "list">
<li>
<?php
$x = 'some_string';
$title = 'title';
$dbc = mysqli_connect('localhost', 'root', '', 'database') or die('Error connecting');
$query = "SELECT * FROM table WHERE column ==$x ORDER BY procenat DESC LIMIT 5";
$data = mysqli_query($dbc, $query);
?>
<div id = "listdiv">
<?php
while ($row = mysqli_fetch_array($data)) {
?>
<h4><?php echo $row[$title]; ?> </h4>
<?php
}
mysqli_close($dbc);
?>
</div> </li> </ul>
I tried with LIKE '%$x%' and that didn't work as well. And i tried ... column = $x
You need to use single equal sign along with quotes.
$query = "SELECT * FROM table WHERE column = '$x' ORDER BY procenat DESC LIMIT 5";
You should use LIKE operator like this
$query = "SELECT * FROM table WHERE column_name LIKE '%$x%' ORDER BY procenat DESC LIMIT 5
Change the query line as shown below
$query = "SELECT * FROM table WHERE column = '".$x."' ORDER BY procenat DESC LIMIT 5";
There are two mistake in your query just try this one.
replace $x with '$x'
replace == with =
run your query
$x = 'some_string';
$query = "SELECT * FROM table WHERE column ='$x' ORDER BY procenat DESC LIMIT 5";
i have a simple query who select me 3 news from table, but i wont to change this number from other file whith variable.
So this is query:
$query = 'SELECT * FROM news ORDER BY created_at DESC LIMIT 3';
I tried differently, but did not work...
Help please
My code(i can't answer on my question so i add it here)
$newsAmount = 3;
function get_news() {
$query = "SELECT * FROM news ORDER BY created_at DESC LIMIT $newsAmount";
$result = mysql_query($query);
$news = array();
while ($row = mysql_fetch_array($result)) {
$news[] = $row;
}
return $news;
if (!$result) {
trigger_error('Invalid query: ' . mysql_error() . " in " . $query);
}
}
This is this code.
Actually you can just do this:
$query = "SELECT * FROM news ORDER BY created_at DESC LIMIT $newsAmount";
But make sure to keep the string in double quotes so the variable can be evaluated, Single quotes will be printed out as it is.
Try to echo $query, you will notice that its being printed.
Try this:
$newsAmount = 3;
$query = 'SELECT * FROM news ORDER BY created_at DESC LIMIT ' + $newsAmount;
you cannot return an array like you did in your code.
I would suggest to do the query inside your main code instead of writing it in a function.
I am using LIKE to do my searching, i try it in phpMyAdmin and return the result but when i use it in php it return empty result.
$search = "ip";
$start = 0;
$query = "SELECT * FROM product WHERE product_name LIKE '%$search%' LIMIT $start,30";
$result = mysql_query($query);
if(empty($result))
$nrows = 0;
else
$nrows = mysql_num_rows($result);
It will return result when i using phpMyAdmin to run this query but when i use it in php, it return empty.
Update:
Sorry guys,
I just found out the problem is i didn't connect database as well. anyway, thanks for helping.
Try This
$query = "SELECT * FROM `product` WHERE `product_name` LIKE '%".$search."%' LIMIT 0, 30";
And if the sole purpose of your code is to get the number of products with the searched-for name, use SELECT COUNT(*) instead of doing a mysql_num_rows() on all your data. It will decrease your querytime and the amount of data that is (unnecessarily) fetched.
I am not sure why this is not working, as the query seems to be correct to me. I would like to suggest you writing query this way
$query = <<<SQL
SELECT * FROM product WHERE product_name LIKE "%$search%" LIMIT $start,30
SQL;
please note that there should not be any space or any character after SQL;
$query = "SELECT * FROM product WHERE product_name LIKE '%" . $search . "%' LIMIT " . (int) $start. ",30";
you can use directly mysql_num_rows()
but here is right code
$query = "SELECT * FROM product WHERE product_name LIKE '%".$search."%' LIMIT $start,30";
$search = "ip";
$start = '0';
$query = "SELECT * FROM product WHERE product_name LIKE '%".$search."%' LIMIT $start,30";
$result = mysql_query($query)or die(mysql_error());
if(mysql_num_rows($result) == 0){
$nrows = 0;
} else{
$nrows = mysql_num_rows($result);
}
//use mysql_num_rows($result) instead of empty($result) because in this situation $result is every time not empty so use inbuilt PHP function mysql_num_rows($result);