Could you please help me to a string inside a string when start and end are given. Actually I want to delete all the contents between //[langStart-en] and //[langEnd-en] in the following example
//[langStart-en] This is a test //[langEnd-en]
using preg_replace. I used the following code
$string = '//[langStart-en] This is a test //[langEnd-en]';
$pattern = '/\/\/\[langStart-en\][^n]*\/\/\[langEnd-en\]/';
$replacement = '//[langStart-en]//[langEnd-en]';
$my_string = preg_replace($pattern, $replacement, $string);
echo $my_string;
It is showing the following error
Warning: preg_replace() [function.preg-replace]: Unknown modifier '/' : eval()'d code on line 4"
Please help
Why remove the string between the given strings if you can concatenate the strings you are given. They will give you the same result.
string c = a + b;
Here you go:
//[langStart-en]//[langEnd-en]
For those of you with less sense of humour - shame on you. But here's an answer.
var str = '//[langStart-en] This is a test //[langEnd-en]';
str.replace(/\/\/\[langStart-en\].+\/\/\[langEnd-en\]/g, '//[langStart-en]//[langEnd-en]');
Yah, I don't mean to be sarcastic.
$my_string = '//[langStart-en]//[langEnd-en]';
Or
$string = '//[langStart-en] This is a test //[langEnd-en]';
$pattern = '/\/\/\[langStart-en\][^n]*\/\/\[langEnd-en\]/';
$replacement = '//[langStart-en]//[langEnd-en]';
$my_string = preg_replace($pattern, $replacement, $string);
echo $my_string;
Not sure what language your using to do this.
But most languages have an indexof function.
var mystring - "cccctestoooabcccc";
var i = mystring.indexof("test");
var x = mystring.indexof("abc");
With those indexs you can use a function like substring(startindex, endindex);
Although, you will have to add or subtract the length of your string (test or abc)
Because the the index is of the first character location.
So
i = 4 and x = 11
you'd would want to pull the substring between ((i + "test".length), x)
Hopefully pull the substring "ooo"
This is rough, but should give you the general idea.
$string = '//[langStart-en] This is a test //[langEnd-en]';
$string = preg_replace(
'/\/\/\[langStart-en\][\s\S]+?\/\/\[langEnd-en\]/',
'//[langStart-en]//[langEnd-en]',
$string
);
Related
I have a doubt, it may be something simple but I have no knowledge to solve it.
I get a string in php
$ string = "[link = someUrl] Text [link]"
And I would like to turn this string into:
"<a href='someUrl'> Text <a/>"
How do I change the URL? and How Can I do the opposite?
Remember that the string belongs to a text with more strings of these gifts.
Short preg_replace solution:
$s = "[link=someUrl] Text [/link]";
$result = preg_replace('#\[[^=]+=([^]]+)\]([^[]+).*#', '<a href=\'$1\'>$2</a>', $s);
print_r($result);
The output (as web page source code):
<a href='someUrl'> Text </a>
You can use the following code
function transformText($string) {
preg_match("/\[link\=([^\]]*)\](.*?)\[\/link]/", $string, $matches);
$someUrl = $matches[1];
$text = $matches[2];
$newString = "<a href='$someUrl'>$text</a>";
return $newString;
}
$string = "[link=someUrl] Text [/link]"; // Test string
echo (transformText($string));
Live demo for the regex used : https://regex101.com/r/tzVfmH/4
Note : The above code works only if there's a single [link], [/link] pair.
If multiple occurrences are to be handled then its better to use regex search and replace, using php's preg_replace as suggested in RomanPerekhrest's answer.
I'm trying to get all numeric before space/alpha in PHP string.
Example:
<?php
//string
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
//result I need
firstStr = 12
SecondStr = 412
thirdStr = 100
How do I can get all the number of a string just like example above?
I've an idea to get the position of first Alpha, then get all numeric before that position.
I've successfully get the position using
preg_match('~[a-z]~i', $value, $match, PREG_OFFSET_CAPTURE);
But I'm not done yet to get the numeric before the posisition.
How do I can do that, or anybody know how to fix my idea?
Anyhelp will be appreciated.
You don't need to use regex for strings like the examples you've shown, or any functions at all for that matter. You can just cast them to ints.
$number = (int) $firstStr; // etc.
The PHP rules for string conversion to number will handle it for you.
However, because of those rules, there are some other types of strings that this won't work for. For example, '-12 Car' or '412e2 8all'.
If you do use a regex, be sure to anchor it to the beginning of the string with ^ or it will match digits anywhere in the string as the other regex answers here do.
preg_match('/^\d+/', $string, $match);
$number = $match[0] ?? '';
Here's an extremely hackish approach that will work in most situations:
$s = "1001BigHairyCamels";
$n = intval($s);
$my_number = str_replace($n, '', $s);
$input = '100Pen';
if (preg_match('~(\d+)[ a-zA-Z]~', $input, $m)) {
echo $m[1];
}
This function will do the job!
<?php
function getInt($str){
preg_match_all('!\d+!', $str, $matches);
return $matches[0][0];
}
$firstStr = '12 Car';
$secondStr = '412 8all';
$thirdStr = '100Pen';
echo 'firstStr = '.getInt($firstStr).'<br>';
echo 'secondStr = '.getInt($secondStr).'<br>';
echo 'thirdStr = '.getInt($thirdStr);
?>
How can I do the following with php?
This is my example:
http://www.example.com/index.php?&xx=okok&yy=no&bb=525252
I want remove this part: &yy=no&bb=525252
I just want this result:
http://www.example.com/index.php?&xx=okok
I tried this :
$str = 'bla_string_bla_bla_bla';
echo preg_replace('/bla_/', '', $str, 1); ;
but this not what I want.
Going for preg_replace was a good start. But you need to learn about regexes.
This will work:
$str = 'http://www.example.com/index.php?&xx=okok&yy=no&bb=525252';
echo preg_replace ('/&yy.+$/', '', $str);
Here the regex is &yy.+$
Let's see how this works:
&yy matches &yy obviously
.+ matches everything ...
$ ... until the end of the string.
So here, my replacement says : Replace whatever begins by &yy until the end of the string by nothing, which is actually simply deleting this part.
You can do this:
$a = 'http://www.example.com/index.php?&xx=okok&yy=no&bb=525252';
$b = substr($a,0,strpos($a,'&yy')); // Set in '&yy' the string to identify the beginning of the string to remove
echo $b; // Will print http://www.example.com/index.php?&xx=okok
Are you always expecting the end part to have the 'yy' variable name? You could try this:
$str = 'http://www.example.com/index.php?&xx=okok&yy=no&bb=525252';
$ex = explode('&yy=', $str, 2);
$firstPart = $ex[0];
I have a small problem. I am tryng to convert a string like "1 234" to a number:1234
I cant't get there. The string is scraped fro a website. It is possible not to be a space there? Because I've tried methods like str_replace and preg_split for space and nothing. Also (int)$abc takes only the first digit(1).
If anyone has an ideea, I'd be greatefull! Thank you!
This is how I would handle it...
<?php
$string = "Here! is some text, and numbers 12 345, and symbols !£$%^&";
$new_string = preg_replace("/[^0-9]/", "", $string);
echo $new_string // Returns 12345
?>
intval(preg_replace('/[^0-9]/', '', $input))
Scraping websites always requires specific code, you know how you receive the input - and you write code that is required to make it usable.
That is why first answer is still str_replace.
$iInt = (int)str_replace(array(" ", ".", ","), "", $iInt);
$str = "1 234";
$int = intval(str_replace(' ', '', $str)); //1234
I've just came into the same issue, however the answer that was provided wasn't covering all the different cases I had...
So I made this function (the idea popped in my mind thanks to Dan) :
function customCastStringToNumber($stringContainingNumbers, $decimalSeparator = ".", $thousandsSeparator = " "){
$numericValues = $matches = $result = array();
$regExp = null;
$decimalSeparator = preg_quote($decimalSeparator);
$regExp = "/[^0-9$decimalSeparator]/";
preg_match_all("/[0-9]([0-9$thousandsSeparator]*)[0-9]($decimalSeparator)?([0-9]*)/", $stringContainingNumbers, $matches);
if(!empty($matches))
$matches = $matches[0];
foreach($matches as $match):
$numericValues[] = (float)str_replace(",", ".", preg_replace($regExp, "", $match));
endforeach;
$result = $numericValues;
if(count($numericValues) === 1)
$result = $numericValues[0];
return $result;
}
So, basically, this function extracts all the numbers contained inside of a string, no matter how many text there is, identifies the decimal separator and returns every extracted number as a float.
One can specify what decimal separator is used in one's country with the $decimalSeparator parameter.
Use this code for removing any other characters like .,:"'\/, !##$%^&*(), a-z, A-Z :
$string = "This string involves numbers like 12 3435 and 12.356 and other symbols like !## then the output will be just an integer number!";
$output = intval(preg_replace('/[^0-9]/', '', $string));
var_dump($output);
I have a string, "Chicago-Illinos1" and I want to add one to the end of it, so it would be "Chicago-Illinos2".
Note: it could also be Chicago-Illinos10 and I want it to go to Chicago-Illinos11 so I can't do substr.
Any suggested solutions?
Complex solutions for a really simple problem...
$str = 'Chicago-Illinos1';
echo $str++; //Chicago-Illinos2
If the string ends with a number, it will increment the number (eg: 'abc123'++ = 'abc124').
If the string ends with a letter, the letter will be incremeted (eg: '123abc'++ = '123abd')
Try this
preg_match("/(.*?)(\d+)$/","Chicago-Illinos1",$matches);
$newstring = $matches[1].($matches[2]+1);
(can't try it now but it should work)
$string = 'Chicago-Illinois1';
preg_match('/^([^\d]+)([\d]*?)$/', $string, $match);
$string = $match[1];
$number = $match[2] + 1;
$string .= $number;
Tested, works.
explode could do the job aswell
<?php
$str="Chicago-Illinos1"; //our original string
$temp=explode("Chicago-Illinos",$str); //making an array of it
$str="Chicago-Illinos".($temp[1]+1); //the text and the number+1
?>
I would use a regular expression to get the number at the end of a string (for Java it would be [0-9]+$), increase it (int number = Integer.parse(yourNumberAsString) + 1), and concatenate with Chicago-Illinos (the rest not matched by the regular expression used for finding the number).
You can use preg_match to accomplish this:
$name = 'Chicago-Illinos10';
preg_match('/(.*?)(\d+)$/', $name, $match);
$base = $match[1];
$num = $match[2]+1;
print $base.$num;
The following will output:
Chicago-Illinos11
However, if it's possible, I'd suggest placing another delimiting character between the text and number. For example, if you placed a pipe, you could simply do an explode and grab the second part of the array. It would be much simpler.
$name = 'Chicago-Illinos|1';
$parts = explode('|', $name);
print $parts[0].($parts[1]+1);
If string length is a concern (thus the misspelling of Illinois), you could switch to the state abbreviations. (i.e. Chicago-IL|1)
$str = 'Chicago-Illinos1';
echo ++$str;
http://php.net/manual/en/language.operators.increment.php