Want to delete array - php

Can anyone help me to improve this code? I want to delete array if it already exists. Thanks
if(count($cart['Item']) > 0) {
unset($cart['Item']);
$items['Item'] = array();
$cart = array_merge($cart, $items);
}

Apparently you want the $cart['Item'] variable to be an empty array after this step, no matter what it was before. So:
$cart['Item'] = array();
Done.

if(!empty($cart['Item'])) {
unset($cart['Item']);
}
!empty requires the array item to be both existent and not falsy (e.g. empty)
unset will delete the given key from $cart
However, if you want to replace it with a new, empty array:
$cart['Item'] = array();
No need to do anything else. PHP has a Garbage Collector.

If you just need to check if it exists. using isset() is faster in your case. Then you can just override it without any unsetting.
if( isset($cart['Item']))
{
$cart['Item'] = array();
}

you can try this,
if(isset($cart['Item']) && !empty($cart['Item'])) {
unset($cart['Item']);
}else{
$items['Item'] = array();
$cart = array_merge($cart, $items);
}
Thanks.

Related

how to limit access when one or more data on array have duplicate

i'm sorry if my english not good.
I have a problem in my code. how I can stop access when in my array have duplicate. I mean, when one or more data in array have duplicate, user must repeat input from first page. and when array have not duplicate, user can access next page.
this is my code I have try.
$no_id=array('100100','100200','100300','100200','100200','100100');
$array = array();
foreach ($no_id as $key => $value)
{
if(isset($array[$value]))
{
$array[$value] += 1;
} else
{
$array[$value] = 1;
}
}
foreach ($array as $alert => $n)
{
if($n >= 2)
{
header('location:../../home');
} else
{
header('location:../../questionnair');
}
}
but when found the duplicate data (in array 100100 have two data and 100200 three data), the system still bring user to access questionnair page, not home.
thanks for helping.
I think the main problem is that you should always use exit() after using header() with location, otherwise the page will continue to execute.
This would still cause a problem though if the first value was a unique value as the first loop would always exit;.
You could fix this (only ever call header() if the value is > 2, then the default of all are unique is after the loop), but an alternative is to use array_count_values() which counts how many each value exists in the list and then use max() to find the most occurring one, then test against that...
$no_id=array('100100','100200','100300','100200','100200','100100');
$n = max(array_count_values($no_id));
if($n >= 2)
{
header('location:../../home');
exit;
} else
{
header('location:../../questionnair');
exit;
}
Update:
An alternative and slightly quicker version would be to use your original first loop, but as soon as it detects the value is already set, then it can stop working and just return then...
$no_id=array('100100','100200','100300','100200','100200','100100');
$array = array();
foreach ($no_id as $key => $value)
{
if(isset($array[$value]))
{
header('location:../../home');
exit;
} else
{
$array[$value] = 1;
}
}
header('location:../../questionnair');
exit;
If you just need to check if the array does have dupliate, you can use array_unique and compare the new array with the old array. If the arrays are not the same, it means there are duplicates.
With code:
$no_id = array('100100','100200','100300','100200','100200','100100');
$new_array = array_unique($no_id);
if (count($no_id) == count($new_array)) {
// 2 arrays have same number of items => they are equal => no duplicates
$redirect = "questionnair.php";
} else {
// 2 arrays have different number of items => they are not equal => duplicates
$redirect = "home.php";
}
header("location: {$redirect}");
NOTE
You have to redirect to an another PHP page (ex. home.php and not just home).
First of all, it's simplier to use array_unique function, which will remove all duplicated values.
After that you can make checks, if nothing was changed, then there is no duplicated items.
Like this:
$no_id=array('100100','100200','100300','100200','100200','100100');
$no_id_unique = array_unique($no_id);
if(count($no_id)===count($no_id_unique)){
header('location:../../questionnair');
}else{
header('location:../../home');
}
exit();
Next thing that you using ../ in path which means go to parent directory.
I don't know your environment, but must likely it's a bad idea.
According to documentation it's better to specify full url of page where user must be forwarded:
header("Location: http://www.example.com/home/");
Also, please be aware, that you need to prevent all others output from a script, especcially before the header() call. Read more here.
you can use foreach (array_unique($no_id) as $key => $value)
You can use array_count_values for this, not tested, but could be like:
$counts = array_count_values($no_id);
$duplicate = false;
foreach ($no_id as $value) {
if ($counts[$value] > 1) {
$duplicate = true;
break; // found a duplicate, no need to check further.
}
}
if ($duplicate === true) {
header('location:../../home');
} else {
header('location:../../questionnair');
}
Using array_flip()
$no_id = array('100100','100200','100300','100200','100200','100100');
$no_id_unique = array_flip($no_id);
if(count($no_id) === count($no_id_unique)){
header('location:../../questionnair');
}else{
header('location:../../home');
}
exit();

Efficiency of using foreach loops to clear a PHP array's values

Which is more efficient for clearing all values in an array? The first one would require me to use that function each time in the loop of the second example.
foreach ($array as $i => $value) {
unset($array[$i]);
}
Or this
foreach($blah_blah as $blah) {
$foo = array();
//do something
$foo = null;
}
I don't want to use unset() because that deletes the variable.
Like Zack said in the comments below you are able to simply re-instantiate it using
$foo = array(); // $foo is still here
If you want something more powerful use unset since it also will clear $foo from the symbol table, if you need the array later on just instantiate it again.
unset($foo); // $foo is gone
$foo = array(); // $foo is here again
If we are talking about very large tables I'd probably recommend
$foo = null;
unset($foo);
since that also would clear the memory a bit better. That behavior (GC) is however not very constant and may change over PHP versions. Bear in mind that re-instantiating a structure is not the same as emptying it.
If you just want to reset a variable to an empty array, you can simply reinitialize it:
$foo = array();
Note that this will maintain any references to it:
$foo = array(1,2,3);
$bar = &$foo;
// ...
$foo = array(); // clear array
var_dump($bar); // array(0) { } -- bar was cleared too!
If you want to break any references to it, unset it first:
$foo = array(1,2,3);
$bar = &$foo;
// ...
unset($foo); // break references
$foo = array(); // re-initialize to empty array
var_dump($bar); // array(3) { 1, 2, 3 } -- $bar is unchanged
Unsetting the variable is a nice way, unless you need the reference of the original array!
To make clear what I mean:
If you have a function wich uses the reference of the array, for example a sorting function like
function special_sort_my_array(&$array)
{
$temporary_list = create_assoziative_special_list_out_of_array($array);
sort_my_list($temporary_list);
unset($array);
foreach($temporary_list as $k => $v)
{
$array[$k] = $v;
}
}
it is not working! Be careful here, unset deletes the reference, so the variable $array is created again and filled correctly, but the values are not accessable from outside the function.
So if you have references, you need to use $array = array() instead of unset, even if it is less clean and understandable.
I'd say the first, if the array is associative. If not, use a for loop:
for ($i = 0; $i < count($array); $i++) { unset($array[$i]); }
Although if possible, using
$array = array();
To reset the array to an empty array is preferable.
Isn't unset() good enough?
unset($array);
How about $array_name = array(); ?
Use array_splice to empty an array and retain the reference:
array_splice($myArray, 0);
i have used unset() to clear the array but i have come to realize that unset() will render the array null hence the need to re-declare the array like for example
<?php
$arr = array();
array_push($arr , "foo");
unset($arr); // this will set the array to null hence you need the line below or redeclaring it.
$arr = array();
// do what ever you want here
?>
Maybe simple, economic way (less signs to use)...
$array = [];
We can read in php manual :
As of PHP 5.4 you can also use the short array syntax, which replaces array() with [].
I see this questions is realla old, but for that problem I wrote a recursive function to unset all values in an array. Recursive because its possible that values from the given array are also an array. So that works for me:
function empty_array(& $complete_array) {
foreach($complete_array as $ckey => $cvalue)
{
if (!is_array($cvalue)) {
$complete_array[$ckey] = "";
} else {
empty_array( $complete_array[$ckey]);
}
}
return $complete_array;
}
So with that i get the array with all keys and sub-arrays, but empty values.
The unset function is useful when the garbage collector is doing its rounds while not having a lunch break;
however unset function simply destroys the variable reference to the data, the data still exists in memory and PHP sees the memory as in use despite no longer having a pointer to it.
Solution:
Assign null to your variables to clear the data, at least until the garbage collector gets a hold of it.
$var = null;
and then unset it in similar way!
unset($var);
The question is not really answered by the posts. Keeping the keys and clearing the values is the focus of the question.
foreach($resultMasterCleaned['header'] as $ekey => $eval) {
$resultMasterCleaned[$key][$eval] = "";
}
As in the case of a two dimensional array holding CSV values and to blank out a particular row. Looping through seems the only way.
[] is nearly 30% faster then as array()
similar as pushing new element to array
$array[] = $newElement then array_push($array, $newElement)
(keep in mind array_push is slower only for single or 2 new elements)
Reason is we skip overhead function to call those
PHP array vs [ ] in method and variable declaration

Items in Arrays, are they references?

look at the code below:
$index = GetIndexForId($itemid);
$item = null;
if( $index == -1 )
{
$item = array();
$this->items[] = $item;
$index = count($this->items)-1;
}
else
$item = $this->items[$index];
$item['id'] = $itemid;
$item['qty'] = $qty;
$item['options'] = $options;
$this->items[$index] = $item; // This line is my question
The last line, is it necessary? I really dont know how php handles array assignment.
P.S. GetIndexForId just searches for if the current ID already exists in the array, and the other "undeclared" variables are parameters.
From the documentation:
Array assignment always involves value copying. Use the reference operator to copy an array by reference.
So yes, given your code, the last line is necessary, but $this->items[] = $item; is superfluous.
If you want to update your Object, yes you need this last line
Any value type like boolean, int... will not be passed by reference. But if your array is filled with objects, it WILL be passed by reference. In your exemple, you need the last line. But as I said, if $item were an object you wouldn't need the last line. It is possible to pass a value type by reference with the reference operator.
Learn how to use the reference operator
HERE

PHP what is the best way to handle a variable that may not be set?

I have a foreach loop, that will loop through an array, but the array may not exist depending on the logic of this particular application.
My question relates to I guess best practices, for example, is it ok to do this:
if (isset($array))
{
foreach($array as $something)
{
//do something
}
}
It seems messy to me, but in this instance if I dont do it, it errors on the foreach. should I pass an empty array?? I haven't posted specific code because its a general question about handling variables that may or may not be set.
Just to note: here is the 'safest' way.
if (isset($array) && is_array($array)) {
foreach ($array as $item) {
// ...
}
}
Try:
if(!empty($array))
{
foreach($array as $row)
{
// do something
}
}
That's not messy at all. In fact, it's best practice. If I had to point out anything messy it would be the use of Allman brace style, but that's personal preference. (I'm a 1TBS kind of guy) ;)
I'll usually do this in all of my class methods:
public function do_stuff ($param = NULL) {
if (!empty($param)) {
// do stuff
}
}
A word on empty(). There are cases where isset is preferable, but empty works if the variable is not set, OR if it contains an "empty" value like an empty string or the number 0.
If you pass an empty array to foreach then it is fine but if you pass a array variable that is not initialized then it will produce error.
It will work when array is empty or even not initialized.
if( !empty($array) && is_array($array) ) {
foreach(...)
}
I would say it is good practice to have a 'boolean' other value that is set as 0 (PHP's false) to start, and any time some function adds to this array, add +1 to the boolean, so you'll have a definite way to know if you should mess with the array or not?
That's the approach I would take in an object oriented language, in PHP it could be messier, but still I find it best to have a deliberate variable keeping track, rather than try to analyze the array itself. Ideally if this variable is always an array, set the first value as 0, and use it as the flag:
<?PHP
//somewhere in initialization
$myArray[0] = 0;
...
//somewhere inside an if statement that fills up the array
$myArray[0]++;
$myArray[1] = someValue;
//somewhere later in the game:
if($myArray[0] > 0){ //check if this array should be processed or not
foreach($myArray as $row){ //start up the for loop
if(! $skippedFirstRow){ //$skippedFirstRow will be false the first try
$skippedFirstRow++; //now $skippedFirstRow will be true
continue; //this will skip to the next iteration of the loop
}
//process remaining rows - nothing will happen here for that first placeholder row
}
}
?>

PHP: A better way of getting the first value in an array if it's present

Here's my code:
$quizId = '';
foreach ($module['QuizListing'] as $quizListing) {
if ($quizListing['id']) {
$quizId = $quizListing['id'];
break;
}
}
Is there a better way of doing this?
What you're doing is reasonable assuming that:
multiple quiz listings appear; and
not all of them have an ID.
I assume from your question that one of both of these is not true. If you want the first quiz listing then do this:
$listing = reset($module['quizListing']);
$quizId = $listing['id'];
The reset() function returns the first element in the array (or false if there isn't one).
This assumes every quiz listing has an ID. If that's not the case then you can't get much better than what you're doing.
Slight change:
$quizId = '';
foreach ($module['QuizListing'] as $quizListing) {
if (isset($quizListing['id'])) {
$quizId = $quizListing['id'];
break;
}
}
to answer if this array is coming from a database you probably have to better to filter your query not to include those row at first place
something like
SELECT * from Quiz WHERE id <> 0
this would give you an array usable without any other processing.
$quiz = array_shift($module['QuizListing']);
if (null != $quiz) {
echo "let's go";
}
Using array_key_exists you can check if the key exists for your array. If it exists, then assign it to whatever you want.
if (array_key_exists('id', $quizListing)) {
$quizId = $quizListing['id'];
}

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