Unexpected $end in php script? - php

Question

I have this bit of code that looks fine to me, but I keep getting the following error:
"Parse error: syntax error, unexpected $end in
/home/txclanco/public_html/hotmuze/addSong.php on line 21"
This is a script that takes in the input from a form, checks for duplicates and if there is a duplicate, it will not make a new row but just add 1 to the 'rating' row where the songname is the song typed in. If there isn't a duplicate, the script will add the data as a new row. The data types are:
id = A_I/int
songname = varchar
artist = varchar
rating = int
The script is below with the mysql data blanked out:
<?
mysql_connect("localhost", "***", "***") or die(mysql_error());
mysql_select_db("***") or die(mysql_error());
$songname = $_POST['songname'];
$artist = $_POST['by'];
$ratenum = 1;
$chkquery = "SELECT * FROM hotmuze WHERE songname='$songname'";
$plusOneQuery = "SELECT * FROM hotmuze WHERE songname='$songname'";
$updateQuery = "UPDATE hotmuze SET rating='$rating2' WHERE songname='$songname'";
$checkdata = mysql_query($chkquery);
$checkrows = mysql_num_rows($checkdata);
if($checkrows==0)
{
$insquery = "INSERT INTO hotmuze (id, songname, artist, rating) VALUES('', '$songname', '$artist', '$ratenum'";
$insdata = mysql_query($insquery);
}
if($checkrows!=0)
{
$plusData = mysql_query($plusOneQuery);
}
if(mysql_num_rows($plusData)!=0)
{
$result = mysql_fetch_assoc($plusData);
$rating = $result['ratng'];
$rating2 = $rating + 1;
mysql_query($updateQuery);
echo "Data Inserted";
}
?>
Line 21 being:
if($checkrows!=0)
{
// The brace is on line 21
$plusData = mysql_query($plusOneQuery);
}
Any ideas what could be wrong with the script? I know the Unexpected $end error usually means that there's a brace out of place, but this time, it's fine?

Answer 1

change this
$insquery = "INSERT INTO hotmuze (id, songname, artist, rating) VALUES('', '$songname', '$artist', '$ratenum'";
to
$insquery = "INSERT INTO hotmuze (id, songname, artist, rating) VALUES('', '$songname', '$artist', '$ratenum')";
you have missed the ) at end

Answer 2

VALUES open and close '()' is need
$insquery = "INSERT INTO hotmuze (id, songname, artist, rating)
VALUES('', '$songname', '$artist', '$ratenum')";

Answer 3

Count the number of opening brackets you have against the number of closing brackets.
$insquery = "INSERT INTO hotmuze (id, songname, artist, rating) VALUES('', '$songname', '$artist', '$ratenum')";