Removing elements from an array whose value matches a specified string - php

Question

I have an array that looks like this:
Array ( [0] => Vice President [1] => [2] => other [3] => Treasurer )
and I want delete the value with other in the value.
I try to use array_filter to filter this word, but array_filter will delete all the empty values, too.
I want the result to be like this:
Array ( [0] => Vice President [1] => [2] => Treasurer )
This is my PHP filter code:
function filter($element) {
$bad_words = array('other');
list($name, $extension) = explode(".", $element);
if(in_array($name, $bad_words))
return;
return $element;
}
$sport_level_new_arr = array_filter($sport_level_name_arr, "filter");
$sport_level_new_arr = array_values($sport_level_new_arr);
$sport_level_name = serialize($sport_level_new_arr);
Can I use another method to filter this word?

Answer 1

array_filter() is the right function. Ensure your callback function has the correct logic.
Try the following:
function other_test($var) {
// returns whether the value is 'other'
return ($var != 'other');
}
$new_arr = array_filter($arr, 'other_test');
Note: if you want to reindex the array, then you could call $new_arr = array_values($new_arr); after the above.

Answer 2

foreach($sport_level_name_arr as $key => $value) {
if(in_array($value, $bad_words)) {
unset($sport_level_name_arr[$key])
}
}

Answer 3

This will create two arrays and will find the difference. In the second array we will put the elements to exclude:
array_values(array_diff($arr,array("other")));

Answer 4

If the callback function returns true, the current value from input is returned into the result array. PHP Manual
So you need to do return true; in your filter(); function instead of return $element; to make sure that no empty values are removed.