For starters, I am using the following:
php 5.3
PHPmailer - to send stmp email with google apps
GD to create the iamge
I am able to take a previously existing file, add text to that file and output to a browser.
I am able to send email with an existing embedded image using simple functions within phpmailer
I am NOT able to dynamically modify the first file, have it saved in memory, then embed THAT image in my email.
When creating my image, I am using a very basic sample script:
EDIT
I modified my code to the following: seems to run faster as well as easier to read. An actual file is created however whereas I would prefer a temporary file I could destroy after or simply use binary data. Is there a binary output function similar to imagegif()?
$photo = imagecreatefromgif('sample.gif');
imagealphablending($photo, true);
$fontsize = 20;
$font = '../times.ttf';
$fontcolor = imagecolorallocate($photo, 0, 0, 0);
$angle = 0;
$x = 100;
$y = 100;
$text = 'THIS IS A BLOB OF TEXT YO!';
imagettftext($photo, $fontsize, $angle, $x, $y, $fontcolor, $font, $text);
imagegif($photo, 'test.gif');
unfortunately, this wants to output my file to the browser, then proceed with the remainder of the script and send the email (without embedded image).
I know I am probably missing something simple but has anybody run into this issue before?
Firstly you need to a) save the image to temporary file using second argument of imagegif function; b) use PHP output buffering to capture the result sent to output and clean it from the response (see http://php.net/ob).
Afterwards you need to know how to embed the image as attachment to the email letter or copy it as real file with http address available and point the <img href=""/> to it.
Related
I have a site which displays a dynamically generated GD image (data pulled from SQL). I need to view this image to pinpoint inconsistencies in my coding. These aren't errors, but rather just simple variables that are out of place that I must isolate. The easiest way I've found to do this is to simply echo the variables at different points in the code.
The problem is that the GD Image will overlay the page and so nothing is displayed from echo/print. The only way I can call the variables/functions the way I want to is by clicking on unique spots on this image. So the image must be there to echo the correct php variables. Both must be present at the same time. The only way I can echo/print is to turn off the image, but then these variables tell me nothing without being able to look at the image.
I don't want to use breakpoints/debugging etc as I'm on a shared host and don't have access to the extensions required for this, and I don't want to run a server locally for development.
I'm pulling the image in an img src="image.php" tag, and the PHP is stored in an external file called functions.php. The index.html which brings it all together is just jquery/javascript.
How can I echo the outputs with the GD image still displayed?
Output your debugging to the log.
error_log('Your message here...');
http://php.net/manual/en/function.error-log.php
You could buffer the output of the script using ob_start()/ob_get_contents() and then use imagestring to draw those logs on the image like so:
ob_start();
echo("Foo");
$out = ob_get_contents();
imagestring($image, 5, 0, 0, $out, imagecolorallocate($image, 255, 255, 255));
ob_end_clean();
I'm fairly new to php but I'm trying to send an image to a buffer or some sort of temporary place where I can access later. The script I'm calling merges a bunch of images into one, then displays that image (see it in action here - change query parameters to change image). Here's a piece of my code so you have an idea of how that's happening:
$dest = imagecreatefrompng($img0);
$src12 = imagecreatefrompng($img12);
imagecolortransparent($src12, imagecolorat($src12, 0, 0));
//copy and merge
$src12_x = imagesx($src12);
$src12_y = imagesy($src12);
imagecopymerge($dest, $src12, 0, 0, 0, 0, $src12_x, $src12_y, 100);
// Output and free from memory
header('Content-Type: image/png');
imagepng($dest);
imagedestroy($dest);
imagedestroy($src);
However, this is an external script so I'd like to be able to pull that image from another page. I'm not sure what the best way to do it is... temporarily store it or pass the image back through. The one constraint is that the image has to exist before the content of the parent page is loaded. How can I make this happen?
If I understand correctly what you mean;
1) You want to pull the image from another website and save it to disk, you can do this;
file_put_contents("img.png", file_get_contents("URL-TO-IMAGE"));
2) You want to just display it? As the URL aboves headers are to display an image, you can put it right into an IMG tag.
<img src="URL-TO-IMAGE">
I am trying to generate a PDF with an image that is also generated by php.
Sounds simple enough and I am sure I'm just screwing up the header but I can't seem to find a solution here.
first I generate a PDF:
define('FPDF_FONTPATH','fonts/');
require('scpt/fpdf.php');
class PDF extends FPDF {}
$pdf = new FPDF('P','in',array(8.5,11));
$pdf->SetAutoPageBreak(false,0);
$pdf->SetTextColor(0,0,0);
$pdf->SetDrawColor(0,0,0);
$pdf->SetFont('Helvetica','',12);
$pdf->Image('label.php?imgid=17',0,0,0,0,'PNG');
$pdf->Output('label.pdf','D');
then I generate the PNG in label.php:
if(isset($_GET["imgid"])) {
header("Content-Type: image/png");
$im = #imagecreate(110, 20)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 0, 0, 0);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
}
This will output: FPDF error: Not a PNG file:....
calling label.php?imgid=17 in the browser however will show me the image just fine...
What am I missing?
EDIT
In document:
Example
// Insert a logo in the top-left corner at 300 dpi
$pdf->Image('logo.png',10,10,-300);
// Insert a dynamic image from a URL
$pdf->Image('http://chart.googleapis.com/chart?cht=p3&chd=t:60,40&chs=250x100&chl=Hello|World',60,30,90,0,'PNG');
so it SHOULD be possible to include a dynamically generated image without saving it first?!
EDIT #2
I made it work with the library mem_image but the problem remains that this should not throw an error IMO?! So I leave this question open to see if there is indeed something wrong with my script of this turning out to be a bug.
You almost had it, you're missing only a couple things. First you need the full server address in the URL for your Image() call, so instead of
$pdf->Image('label.php?imgid=17',0,0,0,0,'PNG');
You need:
$pdf->Image('http://www.yourserver.com/label.php?imgid=17',0,0,0,0,'PNG');
That will eliminate the FPDF error you were encountering. Then to get FPDF to render your output correctly, you need to add a call to AddPage(), so your PDF generation script would become:
require('scpt/fpdf.php');
$pdf = new FPDF('P','in',array(8.5,11));
$pdf->AddPage();
$pdf->Image('http://www.yourserver.com/label.php?imgid=17',0,0,0,0,'PNG');
$pdf->Output('label.pdf','D');
Of course you don't need the SetTextColor(), SetFont(), etc if you're only including the single image. You didn't need the custom class definition either (I removed the unneeded lines).
Don't forget to substitute www.yourserver.com for the appropriate domain and path for your script.
The argument to the Image function needs to be a file, not a URL or another script. Since you already have your label script, the easiest work around would be to download the image to a temp location and then call $pdf->Image() with that temporary file.
This problem occurred With your file name,Make sure your passing file name is valid
function _parsepngstream($f, $file)
{
// Check signature
if($this->_readstream($f,8)!=chr(137).'PNG'.chr(13).chr(10).chr(26).chr(10))
$this->Error('Not a PNG file: '.$file);
...
}
View allow_url_fopen directive
http://www.php.net/manual/en/filesystem.configuration.php#ini.allow-url-fopen
You need to do only changes that
require('fpdf.php');
and do the
$pdf->Image('http://www.yourserver.com/label.php?imgid=17',0,0,0,0,'PNG');
and run your code...
First, try to check your url with this code
$handle = fopen("http://www.yourserver.com/label.php?imgid=17", "rb");
print_r(fread($handle, 8192));
you with see what the contain in your url
**) make sure your url is not redirect to the login page
much more easy, only put .png in the final of dinamic chain and its all
example:
$pdf->Image('http://www.yourserver.com/label.php? imgid=17.png',0,0,0,0,'PNG');
or
$pdf->Image('../label.php?imgid=17.png',0,0,0,0,'PNG');
the mime type is not recognized in the url why does not appear png, if it's a stupid mistake but it is proven, google does the same by adding the extension with the url & PNG
I am doing an assignment for school where we are to make two php files. First file invokes session, generates a random 5 char string, and saves the string to the session array. The second script generates an image, and takes the string from the first file and incorporates it over the image to make a captcha.
I am having an issue passing the value to the second script. The session variable 'captcha_string' is fully visible in the first script, but is not passed to the second page. I am brand new at this, and frustrated. My understanding is, that as long as I start session, the entire $_SESSION array should be available. When I run the first script, I get a broken image tag, not the captcha i am hoping for. Hope this clears up my problem.
This is what I have done for the first file:
<?php
session_start();
$possible_chars = array_merge(range('A','Z'),range('0','9'));
shuffle($possible_chars);
$string = substr(implode($possible_chars),0,5);
$_SESSION['captcha_string']=$string;
?>
<img src="captcha_generator.php" alt="Weinerdog!" />
and this is the bit from the second file where I try to grab the $string (captcha_string), which is named "captcha_generator.php:
<?php
session_start();
putenv('GDFONTPATH=' . realpath('.'));
header("Content-type: image/png");
//import string for the captcha from $_SESSION
$string = $_SESSION['captcha_string'];
// Build an image resource using an existing image as a starting point.
$backgroundimage = "captcha_wiener.jpg";
$im=imagecreatefromjpeg($backgroundimage);
$colour = imagecolorallocate($im, rand(0,255), rand(0,255), rand(0,255));
// Output the string of characters using a true type font.
// Above we set the font path to the current directory, this
// means that arial.ttf font file must be in this directory.
$font = 'arial.ttf';
$angle = rand(-5,5);
imagettftext($im, 120, $angle, 50, 250, $colour, $font, $string);
// Draw some annoying lines across the image.
imagesetthickness($im, 10);
for ($i = 0; $i <3; $i++) {
imageline($im, rand(100,50), rand(150,200), rand(450,550), rand(200,250), $colour);
}
// Output the image as a PNG and the free the used memory.
imagejpeg($im);
imagedestroy($im);
?>
This is, of course, strictly an exercise to make sure we can pass values using session. There is no problem with the rest of the code making the captcha, it has been tested and works.
You're echo-ing some values with a content-type set to image/png, hence either you'll have the error of headers already sent, or, if the text wasn't sent yet (because cached by PHP), you'll have a broken image and you won't be able to see the text.
Don't worry, it has happened to everyone including me :-)
$imageurl = "kaptka.gif";
$im = imagecreatefromgif($imageurl);
$b = imagecolorallocate($im, 0, 0, 0);
imagesetpixel($im, 5, 5, $b);
header('Content-Type: image/gif');
imagegif($im, "asd.gif");
kaptka.gif is normal gif image. I want to draw some pixels anywhere on the image. Asd.gif looks normal, but when i open the file it should show me both like asd.gif, but it shows just "IMAGE" text.
You are calling the function imagegif() with a filename. This will write the image to disc. To display the contents, simply call it without the filename: this will pass the contents to the output stream, which means it will be sent to the client's browser. One way to do both is to call it twice, once to save the file, and once to display it.
When saving the file, you can assign the result to a variable $foo=imagegif($im, 'bar.gif') and then check the result to see if the save was successful. A FALSE means it failed.
You say the image saved to the server is OK, so the reason you are getting an "IMAGE text" in your browser is probably because you are sending a PNG header, but no data (because of the way you called imagefig()).