Insert row to MySQL Table using PHP Form - php

Question

I would like a user to be able to insert a "bid" into a MySQL table using a php form - this is only for demo, not live purpose. I get the following error message,
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''90','2011-07-13'' at line 3 (Line 3 refers to my tag?) I figure it doesnt like the form inputs just being "text" type, but no idea how to fix it - all advice very welcome, this is my form & php code below;
<form action="insert.php" method="post">
<div><label for="commodity">Commodity</label><input type="text" name="commodity"/></div>
<div><label for="region">Region</label><input type="text" name="region"/></div>
<div><label for="member">Member</label><input type="text" name="member" /></div>
<div><label for="size">Size</label><input type="int" name="size" /></div>
<div><label for="price">Post Bid</label><input type="decimal" name="price" /></div>
<div><label for="posted">Date Posted</label><input type="text" name="posted"/></div>
<P><label for="submit">Submit Bid</label><input type="submit" /></P>
</form>
& php
<?php
$con = mysql_connect("localhost","","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("palegall_newTrader", $con);
$sql="INSERT INTO `buy` (commodity, region, member, size, price, posted)
VALUES
('$_POST[commodity]','$_POST[region]','$_POST[member]','$_POST[size]','$_POST[price]','$_POST[posted]'";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
mysql_close($con)
?>
Many thanks in advance, scotia

Answer 1

You're vulnerable to SQL injection, and your POST probably contains a ', which is causing the syntax error. Try the following:
$commodity = mysql_real_escape_string($_POST['commodity']);
$region = mysql_real_escape_string($_POST['region']);
etc...
$sql = "INSERT INTO ... VALUES ('$commodity', '$region', etc...)";
the escape function will ensure that any SQL metacharacters in the data are escaped, so they can't "break" your query. Never EVER directly insert user-provided data into an SQL query, even if it's a simple script that only you will ever use. Get into the habit of escaping everything (or better yet, using PDO prepared statements), because at some point, you'll get burned if you don't.

Answer 2

Your closing parenthesis need to go after the last value to be inserted, now it's after the 4th element. Put it at the and of the statement.
$sql="INSERT INTO `buy` (commodity, region, member, size, price, posted)
VALUES
('$_POST[commodity]','$_POST[region]','$_POST[member]','$_POST[size]','$_POST[price]','$_POST[posted]')"
Also, follow #Marc's advice and sanatize your input.

Answer 3

Shouldn't it be
$sql="INSERT INTO `buy` (commodity, region, member, size, price, posted) VALUES ('$_POST[commodity]','$_POST[region]','$_POST[member]','$_POST[size]','$_POST[price]','$_POST[posted]')";

Answer 4

There is a misplaced parenthesis after $_POST['size'] that should be after $_POST[posted]
The SQL should look like this:
$sql="INSERT INTO `buy` (commodity, region, member, size, price, posted)
VALUES
('$_POST[commodity]','$_POST[region]','$_POST[member]','$_POST[size]','$_POST[price]','$_POST[posted]')";