Okay so I'm learning about uploads and need to copy the tmp file to a specified directory so I use the copy command.
I use this inside my index.php of the main directory (learningupload/ folder)
copy($_FILES['photo']['tmp_name']['file'], './pics/'.$photoname.'.jpg');
Now I'm doing this on Xampp local host, and my uploads go to the tmp folder which is of course different from where I want the upload to go
so there's
C:\xampp\tmp
C:\xampp\htdocs\learningupload\pics\
My question is this: What is this ./ inside the destination string I need to have? Doesn't it usually mean you're moving UP a directory? Why not have it '/pics' no dot? I tried that and said it couldn't open the stream. Does the dot here mean it's referring to whatever directory index.php is in? Or am I thinking ../ moves up a directory? And single dot is different?
Thanks.
./ means "current working directory". Which directory is current working one you can see with echo getcwd();
The parent directory (the upper one) is ../
You can change your working directory using chdir() or you can just specify the full path instead.
Related
Main Folder1
- Submain1 folder
- filehere1.html
Main Folder2
- image.jpg
I currently working on filehere.html file, what I want to do is to locate image .jpg. How to locate this via path? Any idea?
To go folders back, you have to use ../ in the link. Spaces aren't recognised either, so you use %20 for them. Therefore, the path should be: ../Main%20Folder2/image.jpg
./ Is referring to current working directory
../ will refer to parent directory
In your case files are outside of current working directory
../ Main Folder2/image.jpg. Will give u the expected result
I work in responsivefilemanager and in config file I Have two line:
$upload_dir = '/user/uploads/files/'; // path from base_url to base of upload folder (with start and final /)
$current_path = '../../../../uploads/files/'; // relative path from filemanager folder to upload folder (with final /)
This wroked In xammp system (with sub folder. /user/ is sub folder). if i move in real server i need to edit this two line and remove sub folder and one ../ from two line.
Now, I need to auto detect url path. My mean is : if i install in sub folder Or root folder this two line worked in my script without manual editing.
How do can i create this?
There is no particular way to just autodetect what directory to upload to. The easiest is to solve this by just checking if the directory exists and use the other directory if it was not found.
However, I'd suggest having the same relative structure on both systems is the best solution. With the same relative structure this should work across all servers and systems without having to change anything.
I am trying to move my jpg image file from one directory to another using the rename() function. However it keeps on giving the error saying No such file or directory. I have changed it to the copy() function with the following error failed to open stream: No such file or directory.
I am trying this as following:
rename('/_upload/1.image.jpg', '/_accepted/test/1.image.jpg');
The file is orginally already in my htdocs/_upload folder. This PHP file is already in my htdocs folder. All permissions are set to 777 but giving the same error.
Instead of starting / in your path, use ./:
rename('./_upload/1.image.jpg', './_accepted/test/1.image.jpg');
/ means that you are giving path starting the server's root directory.
./ starts with your current directory.
In your example, the arguments to rename are file names. /_upload/1.image.jpg is an absolute file name. That means, it is relative to the root directory. It is not relative to your server root, document root or current dierctory.
try this to give complete abosolute path
rename($_SERVER['DOCUMENT_ROOT'].'/_upload/1.image.jpg', $_SERVER['DOCUMENT_ROOT'].'/_accepted/test/1.image.jpg');
I have a domain root which is a folder within the server root. How can I mkdir inside a different folder within the domain root?
ROOT > DOMAIN ROOT FOLDER > PHP MKDIR
ROOT > IMAGE FOLDER > MKDIR HERE
I need the php in the 'domain root folder' to create a directory within the 'image folder'. Any help?
You can usually do something like this:
mkdir('../images/newfolder');
You may have to add more ../../ on to the front of this, depending on where you are running the script from exactly. Each ../ moves you up another level, so it seems like just one would work here given your example, but you have to be sure you are where you think you are.
You could also use absolute path in your php-script.
mkdir('/root/images/new_folder');
Make sure that your web-server has permissions for writing to specific folder.
I usally work from the directory my current script is located in and maneuver my way to the desired location from there. Works fine as long as you don't move you script. In addition, it will be easier to keep track of where everything is relative to the script.
You can get the current path with:
$path = dirname(__FILE__);
Then appending ../ to go deeper etc.
Let’s say I have two folders in my PHP server root directory: x and y. There are two more directories inside the x folder: a and b. In the /x/a directory I have the index.php file and in the /y folder a stuff.php file.
From my /x/a/index.php file, I want to include the /y/stuff.php file. How do I do that?
My server doesn’t allow including files from other domains, so adding the full URL doesn’t work!
Also, I’d like to know how to start a path from the root in PHP. I use ./blabla from the index of my root and ../blabla from directories in the root, but, unfortunately, .../blabla doesn’t work from 2nd grade directories.
To access the root begin your path with "/".
If you want to go up one directory from where you are currently, e.g. from /x/a/ to /x/ you could use "../".
If you want to go back up two directories (e.g. from /x/a/ to /) you could use "../../" (rather than ".../" which you mentioned).
try:
include "../../y/stuff.php";