jQuery code causing conflict in results - php

Question

I would like to ask, is there a better way to run this code. I have a form with a select of #BA_customer which when selected populates a second menu with the address of the selected client. I also need to display a dept dropdown based on the customer selecetion. I think the code I have is causing a conflict where the customer is being passed twice in 2 seperate statements. What is the correct way to do this? Many thanks
<script language="javascript" type="text/javascript">
$(function() {
$("#BA_customer").live('change', function() { if ($(this).val()!="")
$.get("../../getOptions.php?BA_customer=" + $(this).val(), function(data) {
$("#BA_address").html(data); });
});
});
</script>
<script language="javascript" type="text/javascript">
$(function() {
$("#BA_customer").live('change', function() { if ($(this).val()!="")
$.get("../../getDept.php?BA_customer=" + $(this).val(), function(data) {
$("#BA_dept").html(data); });
});
});
</script>
+++++++ dept.php Code +++++++++++++++++++++
$customer = mysql_real_escape_string( $_GET["BA_customer"] ); // not used here, it's the customer choosen
$con = mysql_connect("localhost","root","");
$db = "sample";
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($db, $con);
$query_rs_select_dept = sprintf("SELECT * FROM departments where code = '$customer'");
$rs_select_dept = mysql_query($query_rs_select_dept, $con) or die(mysql_error());
$row_rs_select_dept = mysql_fetch_assoc($rs_select_dept);
$totalRows_rs_select_dept = mysql_num_rows($rs_select_dept);
echo '<label for="dept">Select a Department</label>'.'<select name="customerdept">';
echo '<option value="">Select a Department</option>';
while ($row_rs_select_dept = mysql_fetch_assoc($rs_select_dept))
{
$dept=$row_rs_select_dept['name'];
echo '<option value="dept">'.$dept.'</option>';
}
echo '</select>';
++++ SOLUTION +++++++++++++
mysql_select_db($db, $con);
$query_rs_dept = sprintf("SELECT * FROM departments where code = '$customer'");
$rs_dept = mysql_query($query_rs_dept, $con) or die(mysql_error());
$totalRows_rs_dept = mysql_num_rows($rs_dept);
echo '<label for="dept">Select a Department</label>'.'<select name="customerdept">';
echo '<option value="">Select a Department</option>';
while ($row_rs_dept = mysql_fetch_assoc($rs_dept))
{
$dept=$row_rs_dept['name'];
echo '<option value="dept">'.$dept.'</option>';
}
echo '</select>';
Remove the first $row_rs_select_dept = mysql_fetch_assoc($rs_select_dept); from the script and it works. Just posted solution in case some other soul needs help with problem like this.

Answer 1

Maybe you could send the two requests together?
$(function() {
$("#BA_customer").live('change', function() {
if($(this).val()!="")
$.get("../../getOptions.php?BA_customer=" + $(this).val(), function(data) {
$("#BA_address").html(data);
});
$.get("../../getDept.php?BA_customer=" + $(this).val(), function(data) {
$("#BA_dept").html(data);
});
});
});