I am trying to count row numbers on an another table and use HAVING to select only rows greater than 0.
SELECT COUNT(t3.ID),t1.ID,t2.sell,t1.date
FROM `album` t1
INNER JOIN `members` t2 ON t2.aID = t1.ID
INNER JOIN `table` t3 ON t3.rID = t1.ID
WHERE t1.date <= '$dt' AND t2.sell = '1'
ORDER BY t1.date DESC
HAVING COUNT(t3.ID) > 0
It doesnt work. where am i wrong ?
Thanks
You need a GROUP BY clause so that MySQL knows how to group the data when you're using aggregate functions such as COUNT.
SELECT COUNT(t3.ID),t1.ID,t2.sell,t1.date
FROM `album` t1
INNER JOIN `members` t2 ON t2.aID = t1.ID
INNER JOIN `table` t3 ON t3.rID = t1.ID
WHERE t1.date <= '$dt' AND t2.sell = '1'
GROUP BY t1.ID,t2.sell,t1.date
HAVING COUNT(t3.ID) > 0
ORDER BY t1.date DESC
For more information, see this.
Related
I searched around and found a near example to what I'm looking for, but it doesn't work in my case.
I have a query that does an INNER JOIN on two tables and this join constrains my overall data set substantially. I then want to LEFT JOIN onto a third table but I only want one record from that third table. The reason for the left join is because not every result of the INNER JOIN has a match in the 3rd table. Something like this:
SELECT DISTINCT t1.code, t2.id, t2.code, t3.id, t3.source_title, t3.display_order
FROM table1 t1
INNER JOIN table2 t2 ON t2.code=t1.code AND t2.type=0
LEFT JOIN table3 t3 ON t3.code=t1.code
ORDER BY t1.code, t3.display_order
This query returns too many records because the third table contains multiple records with a matching code. I just want the first one that matches with the lowest display_order value and, unfortunately, I can't limit the records to have display_order=1 because the lowest display order is not always one.
IMPORTANT: The t3.id value (if any) returned by this query must correspond to the record with the lowest display_order value. I.e., it won't work if the query correctly returns the lowest display_order value but the t3.id value corresponds to some other record in table 3.
Is this even possible? Any help would be much appreciated.
EDIT: Per Nick's suggestion, I have tried this, which appears to be working. I'll do some verification and report back:
SELECT DISTINCT t1.code, t2.*, sq.id, sq.source_title, sq.display_order
FROM table1 t1
INNER JOIN table2 p ON t2.code=t1.code AND t2.type=0
LEFT JOIN (
SELECT t3.*
FROM table3 t3
WHERE t3.display_order=(
SELECT MIN(display_order)
FROM table3 t3a
WHERE t3a.code = t3.code
)
) sq ON sq.code=t1.code
ORDER BY t1.code, sq.display_order
You should be able to replace table3 in your LEFT JOIN with
(SELECT *
FROM table3 t3
WHERE display_order = (SELECT MIN(display_order)
FROM table3 t3a
WHERE t3a.code = t3.code)
) t3
In MySQL 8.0 you can try to use row_number() for each code and ordered by display_order in a subquery from table3. Then left join that result and check for the row_number() to be equal to 1.
SELECT DISTINCT
t1.code,
t2.id,
t2.code,
t3.id,
t3.source_title,
t3.display_order
FROM table1 t1
INNER JOIN table2 t2
ON t2.code = t1.code
LEFT JOIN (SELECT t3.id,
t3.source_title,
t3.display_order,
t3.code,
row_number() OVER (PARTITION BY t3.code
ORDER BY t3.display_order) rn
FROM table3 t3) t3
ON t3.code = t1.code
WHERE t2.type = 0
AND t3.rn = 1
ORDER BY t1.code,
t3.display_order;
In lower versions you can try correlated subqueries ordered by display_order and LIMIT 1 (to get only one record).
SELECT DISTINCT
t1.code,
t2.id,
t2.code,
(SELECT t3.id
FROM table3 t3
WHERE t3.code = t1.code
ORDER BY t3.display_order,
t3.id
LIMIT 1) id,
(SELECT t3.source_title
FROM table3 t3
WHERE t3.code = t1.code
ORDER BY t3.display_order,
t3.id
LIMIT 1) source_title,
(SELECT t3.display_order
FROM table3 t3
WHERE t3.code = t1.code
ORDER BY t3.display_order,
t3.id
LIMIT 1) display_order
FROM table1 t1
INNER JOIN table2 t2
ON t2.code = t1.code
WHERE t2.type = 0
ORDER BY t1.code,
(SELECT t3.display_order
FROM table3 t3
WHERE t3.code = t1.code
ORDER BY t3.display_order,
t3.id
LIMIT 1);
I assumed, that display_order in table3 isn't unique but id is. So I added id to the ORDER BY clauses in the subqueries to make sure the same record is selected in each of them. If display_order is unique, you can remove id FROM the ORDER BY clauses.
Edit:
If you don't want to repeat the subqueries in the (overall) ORDER BY clause, you can also order by the column ordinals. E.g.:
...
ORDER BY 1, 6;
$query = "SELECT * FROM table3 WHERE name_id = '(SELECT name_id FROM table2
WHERE salary < 1000 && name = '(SELECT name FROM table1
WHERE savings > 1000)')'";
Basically I want to get the data from the table1 based on the savings and use it to get the data from table 2 and use that data to get all the information from table 3. But this wont work. Is my code right or am I doing something wrong?
I also cannot create new tables, I simply want to display the data from table 3.
Use join
SELECT * FROM table3 t3 join table2 t2
on t3.name_id=t2.name_id
join table1 t1
on t3.name=t1.name
where salary < 1000 and savings > 1000
$query="SELECT * FROM table3 LEFT JOIN table2 ON table3.name_id=table2.name_id
LEFT JOIN table1 ON table3.name=table1.name
WHERE table2.salary < 1000 AND table1.savings > 1000 "
Another syntax of join is
SELECT * FROM table1 t1,table2 t2 ,table3 t3
where t1.name = t3.name and
t2.name_id = t3.name_id and
t1.savings > 1000 and t2.salary < 1000;
$query = "SELECT t3.* FROM table3 t3
INNER JOIN table2 t2 ON t2.name_id = t3.name_id AND t2.salary < 1000
INNER JOIN table1 t1 ON t1.name = t2.name AND t1.savings > 1000";
I want to get the id from first table, and the information in the second table but only if there is any related row in second table, AND where the greatest date of the related rows is smaller(earlier) than time right now...
This is what I have right now:
"SELECT t1.id as actID, t2.id AS eventsid, t2.controlled FROM `activites` t1
LEFT JOIN `events` t2 ON t2.activitesid = t1.id
WHERE t2.datum < UNIX_TIMESTAMP() GROUP BY t2.controlled"
And what I have been trying is something like
"SELECT t1.id as actID, t2.id AS eventsid, t2.controlled FROM `activites` t1
LEFT JOIN `events` t2 ON t2.activitesid = t1.id
WHERE (SELECT `datum` FROM `events` t3 WHERE t3.controlled = t2.controlled ORDER BY `datum` DESC LIMIT 1) < UNIX_TIMESTAMP() GROUP BY t2.controlled"
Is there anybody who can point me in wich direction to go or how to type this kind of query?
There is no need pointing out that I should use PDO, mysqli etc...
I have this table
What I want to do is to query/echo out those id with the same value for example id 1 and id 3 has the same value. Is that possible in the same table and column? Thanks!
You can use a self-join to get all pairs of IDs with the same weight
SELECT t1.weight, t1.id AS id1, t2.id AS id2
FROM YourTable AS t1
JOIN YourTable AS t2 ON t1.weight = t2.weight AND t1.id < t2.id
or GROUP_CONCAT to get all the IDs with the same weight in a single row:
SELECT weight, GROUP_CONCAT(id) AS ids
FROM YourTable
GROUP BY weight
HAVING COUNT(*) > 1
To get just one pair for each weight:
SELECT t1.weight, t1.id AS id1, t2.id AS id2
FROM YourTable AS t1
JOIN YourTable AS t2 ON t1.weight = t2.weight AND t1.id < t2.id
GROUP BY t1.weight
DEMO
here us the query
SELECT *
FROM Table1
WHERE complete='Y'
AND shipped='Y'
AND active='Y'
AND create_dttm > '2013-10-10 08:28:41'
AND order_id IN
(SELECT DISTINCT t1.order_id
FROM Table2 t1
INNER JOIN table3 t2 ON t1.prod_id = t2.prod_id
WHERE t2.prod_sku LIKE '%D-600%'
AND t1.create_dttm > '2013-02-15 08:28:41')
You are using a sub-query in WHERE clause, that could be the main reason behind slow execution of your query. Try using JOINS instead of sub query.
SELECT t1.*
FROM Table1 t1
INNER JOIN Table2 t2 ON T1.order_id = T2.order_id
AND t2.create_dttm > '2013-02-15 08:28:41'
INNER JOIN table3 t3 ON t2.prod_id = t3.prod_id
AND t3.prod_sku LIKE '%D-600%'
WHERE complete='Y'
AND shipped='Y'
AND active='Y'
AND create_dttm > '2013-10-10 08:28:41'
And also check for indexes on your tables.