I'm trying to echo the variable $theurl inside of $image_all but it's not working.
$theurl = OF_DIRECTORY;
$image_all = $theurl.$image_path;
This should be simple, right? It's only showing what $image_path equals, even though it will echo $theurl if I simply do <?php echo $theurl; ?>.
What am I missing?
Lets make a very very simple example:
define(OF_DIRECTORY, 'blabla/test/');
$image_path = 'file.php';
$theurl = OF_DIRECTORY;
$image_all = $theurl.$image_path;
echo $image_all;
Works great by the way! However, why use the $theurl at all? Why not $image_all = OF_DIRECTORY . $image_path;. You need provide us more information or code, but as far as your specifications goes, everything should be OKAY.
Related
PHP CODE:
$video1="welcome.mp4";
$video2="movie.mp4";
$video3="ends.mp4";
$num_id="1";
$get = '$' . "video" . $num_id;
$file = $get;
echo "<a href=Player.php?file=$file'>Play</a>";
html code results:
Play
HTML - expectancy:
Play
I would do something like this.
$videos = ['welcome.mp4','movie.mp4','ends.mp4'];
foreach($videos as $video){
echo "<a href=Player.php?file=$video'>Play</a><br>";
}
I would do this (If I wanted to be Kool, or confuse a junior developer .. lol )
$video1="welcome.mp4";
$video2="movie.mp4";
$video3="ends.mp4";
$num_id="1";
$get = ${"video".$num_id};
$file = $get;
echo "<a href=Player.php?file=$file'>Play</a>";
Output
<a href=Player.php?file=welcome.mp4'>Play</a>
But I am not sure you are ready to have access to that much power...
Sandbox
I am working on a script with templates. So I have this PHP code:
<?php
$string = "TEST";
echo(file_get_contents('themes/default/test.html'));
?>
And I have this HTML (the test.html file):
<html>
<p>{$string}</p>
</html>
How can I make PHP actually display the variable inside the curly brackets? At the moment it displays {$string}.
P.S:
The string might also be an object with many many variables, and I will display them like that: {$object->variable}.
P.S 2: The HTML must stay as it is. This works:
$string = "I'm working!"
echo("The string is {$string}");
I need to use the same principle to display the value.
You can use the following code to achieve the desired result:
<?php
$string = "TEST";
$doc = file_get_contents('themes/default/test.html'));
echo preg_replace('/\{([A-Z]+)\}/', "$$1", $doc);
?>
P.S. Please note that it will assume that every string wrapped in { }
has a variable defined. So No error checking is implemented in the code above. furthermore it assumes that all variables have only alpha characters.
If it is possible to save your replacees in an array instead of normal variables you could use code below. I'm using it with a similar use case.
function loadFile($path) {
$vars = array();
$vars['string'] = "value";
$patterns = array_map("maskPattern", array_keys($vars));
$result = str_replace($patterns, $vars, file_get_contents($path));
return $result;
}
function maskPattern($value) {
return "{$" . $value . "}";
}
All you PHP must be in a <?php ?> block like this:
<html>
<p><?php echo "{" . $string . "}";?></p>
</html>
If you know the variable to replace in the html you can use the PHP function 'str_replace'. For your script,
$string = "TEST";
$content = file_get_contents('test.html');
$content = str_replace('{$string}', $string, $content);
echo($content);
It's simple to use echo.
<html>
<p>{<?php echo $string;?>}</p>
</html>
UPDATE 1:
After reading so many comments, found a solution, try this:
$string = "TEST";
$template = file_get_contents('themes/default/test.html', FILE_USE_INCLUDE_PATH);
$page = str_replace('{$string}',$string,$template);
echo $page;
Ok, so I have literally never been so confused. As you can see I have pretty much the same function twice here (I know that may seem stupid but it is just easier for me to read for my page when it's like this - but that isn't the point of this)
The first one goes to the link it's given (http://www.blade-edge.com/images/KSA/Flights/craft.asp?db=dunai) then follows the path to get the img src of http://i.imgur.com/8t5rwWh.png
But the second function doesn't get the src of the image it's pointing to (which would be http://i.imgur.com/jWWUEqt.png) but instead gets the src for a completely different image on the page http://www.blade-edge.com/images/KSA/Flights/prev.png.
I am sure this is a really stupid mistake that I have just overlooked but I can't work it out.
Anyone?
function getImage(){
$page = file_get_html(getPageURL());
$element = $page->find("html/body/div/div[1]/center/table/tbody/tr[1]/td/table/tbody/tr/td[1]/div/div/img");
$imgLink = $element[0]->getAttribute("src");
echo "<img id='shipImage' src='".$imgLink."'></img>";
}
function getMap(){
$page = file_get_html(getPageURL());
$element = $page->find("/html/body/div/div[1]/center/table/tbody/tr[2]/td/center/img");
$imgLink = $element[0]->getAttribute("src");
echo "<img id='shipMap' src='".$imgLink."'></img>";
}
The following works for me:
function getImage($imageType){
$page = file_get_html(getPageURL());
$element = $page->find("/html/body/div/div[1]/center/table/tbody", 0)->children($imageType)->find("img");
$imgLink = $element[0]->getAttribute("src");
return $imgLink;
}
echo "<img id='shipImage' src='" . getImage(0) . "'></img>"; // Spacecraft image
echo "<img id='shipMap' src='" . getImage(1) . "'></img>"; // Map image
I won't try to guess the reason behind the problem, as I do not know the innards of the library.
I'm trying to change a value in a string that's holding my current URL. I'm trying to get something like
http://myurl.com/test/begin.php?req=&srclang=english&destlang=english&service=MyMemory
to look like
http://myurl.com/test/end.php?req=&srclang=english&destlang=english&service=MyMemory
replacing begin.php for end.php.
I need the end.php to be stored in a variable so it can change, but begin.php can be a static string.
I tried this, but it didn't work:
$endURL = 'end.php';
$beginURL = 'begin.php';
$newURL = str_ireplace($beginURL,$endURL,$url);
EDIT:
Also, if I wanted to replace
http://myurl.com/begin.php?req=&srclang=english&destlang=english&service=MyMemory
with
http://newsite.com/end.php?req=&srclang=english&destlang=english&service=MyMemory
then how would I go about doing that?
Assuming that you want to replace the script filename of the url, you can use something like this :
<?php
$endURL = 'end.php';
$url ="http://myurl.com/test/begin.php?req=&srclang=english&destlang=english&service=MyMemory";
$pattern = '/(.+)\/([^?\/]+)\?(.+)/';
$replacement = '${1}/'.$endURL.'?${3}';
$newURL = preg_replace($pattern , $replacement, $url);
echo "url : $url <br>";
echo "newURL : $newURL <br>";
?>
How do you want them to get to end.php from beigin.php? Seems like you can just to a FORM submit to end.php and pass in the variables via POST or GET variables.
The only way to change what page (end.php, begin.php) a user is on is to link them to another page from that page, this requires a page refresh.
I recently made a PHP-file for this, it ended up looking like this:
$vars = $_SERVER["QUERY_STRING"];
$filename = $_SERVER["PHP_SELF"];
$filename = substr($filename, 4);
// for me substr removed 'abc/' in the beginning of the string, you can of course adjust this variable, this is the "end.php"-variable for you.
if (strlen($vars) > 0) $vars = '?' . $vars;
$resultURL = "http://somewhere.com" . $filename . $vars;
I am trying to link a tumblr feed to a website. I found this code (As you can see, something must be broken with it as it doesnt even format correctly in this post):
<?php
$request_url = “http://thewalkingtree.tumblr.com/api/read?type=post&start=0&num=1”;
$xml = simplexml_load_file($request_url);
$title = $xml->posts->post->{‘regular-title’};
$post = $xml->posts->post->{‘regular-body’};
$link = $xml->posts->post[‘url’];
$small_post = substr($post,0,320);
echo ‘<h1>’.$title.’</h1>’;
echo ‘<p>’.$small_post.’</p>’;
echo “…”;
echo “</br><a target=frame2 href=’”.$link.”’>Read More</a>”;
?>
And i inserted the tumblr link that I will be using. When I try to preview my HTML, i get a bunch of messed up code that reads as follows:
posts->post->{'regular-title'}; $post = $xml->posts->post->{'regular-body'}; $link = $xml->posts->post['url']; $small_post = substr($post,0,320); echo '
'.$title.'
'; echo '
'.$small_post.'
'; echo "…"; echo "Read More"; ?>
Any help would be appreciated. Thank you!
That is PHP, not HTML. You need to process it with a PHP parser before delivering it to a web browser.
… it should also be rewritten so it can cache the remote data, and escape special characters before injecting the data into an HTML document.