Grouping by date in php/mysql - php

Question

I have a an array:
Array
(
[0] => Array
(
[id] => 53
[product] => something
[price] => £78
[quantity] => 23
[time] => 2011-07-15 20:29:21
)
[1] => Array
(
[id] => 52
[product] => product
[price] => £89
[quantity] => 1
[time] => 2011-07-14 00:51:57
)
[2] => Array
(
[id] => 51
[product] => product
[price] => £89
[quantity] => 1
[time] => 2011-07-14 00:51:37
))
I got this using the following sql statement:
select * from some_table GROUP BY time DESC
I want to display the results ordered by date, with the date as a heading:
e.g.
**2011-07-15**
all array elements for above date go here
**2011-07-15**
all array elements for above date go here
I thought about doing a seperate statement for each seperate day, but that sounds wrong. Is there a better way?

Answer 1

ORDER BY Time in your query, like this:
select * from some_table ORDER BY time DESC
Then loop in PHP:
$last_date = 0;
while($row = mysql_fetch_assoc($result)){
$date = date('Y-m-d', strtotime($row['time']));
if($date != $last_date)
echo '**'.$date.'**';
$last_date = $date;
echo '<br />';
echo 'Id: '.$row['Id'];
echo 'Product: '.$row['product'];
echo 'Price: '.$row['price'];
echo 'Quantity: '.$row['quantity'];
echo '<br /><br />';
}
If you're ouputting to a console instead of an HTML page then replace the '<br \>' with "\n"

Answer 2

<?
$arrDate = Array
(
[0] => Array
(
[id] => 53
[product] => something
[price] => £78
[quantity] => 23
[time] => 2011-07-15 20:29:21
);
$currentDate = null;
foreach ($arrDate as $item) {
if ($item["time"] == $currentDate) {
// print details
}
else {
$currentDate = $arrDate["time"];
// print date header.
// print details
}
}
?>