Is is possible to display (via php) the main menu of a Drupal 6.20 site in a WordPress theme template file located in a subdirectory on the same domain?
Right now, I'm displaying the menu by copying the static html from the Drupal site and adding it to header.php in the WordPress template in the site located in mydomain.com/blog/. But of course that's not going to work when another menu item is added to the Drupal site, or the Drupal menu is changed in any way.
So is there a Drupal php function that will pull the menu into the WP file?
Failing that, is there a way with php to parse a Drupal page for the html of the menu (yes, this would be ugly) and display it in WP?
The first part of the challenge is to output only the menu, with as little (or none) of the surrounding HTML as possible, so you have as little work to do in parsing the HTML as possible.
The second part is to take that output from Drupal and actually display it on your WordPress site.
You could add the Drupal database as a secondary database in WordPress using the a new instance of the $wpdb object, write the query to get the right content from the tables, and format the results. That could work, but might be overkill.
An alternative workable option may be to use JSON to format the output of the primary links, using the drupal_json function in Drupal, then consume the JSON feed in Wordpress.
I'm assuming:
you have admin access to login to the Drupal site, which you'll need to create nodes, and clear the theme cache
you want to output the Primary Links menu, which 90%+ of Drupal sites use. This is probably true, but it is possible your site uses custom menus. If so, this is still possible, you'd just write slightly different code in step 3.
The steps would be:
Create a Drupal node (you can call it anything, it's just a placeholder)
Get the node id of your dummy page (ie., node/234). From the node id, create a one-off page template in your Drupal site's themes folder. It should be called page-node-xxxx.tpl.php, with xxxx being your node id
Add this code to page-node-xxxx.tpl.php:
<?php
drupal_json(menu_navigation_links(variable_get('menu_primary_links_source', 'primary-links')));
?>
This will create a JSON feed of your menu items.
Clear the theme cache of your Drupal site by visiting http://yoursite.com/admin/build/themes and visit http://yoursite.com/node/xxxx to see the raw JSON feed.
You should now be able to use a jQuery method like $.getJSON or $.ajax in your Wordpress theme to consume and display the JSON feed, or possibly use json_decode and curl to output your array as HTML.
A good thing about Drupal's drupal_json function is that it already sends the correct JSON headers, so now all you have to do is write the jQuery or PHP that does what you need.
I'm assumed you are more of a Wordpress specialist and have a working knowledge of Drupal but maybe not a lot of familiarity with its inner workings. So, sorry if it seemed too basic (or not basic enough :).
The Drupal theming engine is very modular - you may be able to make an appropriate PHP call into Drupal to get just the menu rendered, then emit that HTML as a part of your WordPress page.
g_thom's answer is very good and if you wish to create a very simple module to output the main navigation you can write something like this:
<?php
function getmenus_help($path, $arg) {
// implementing the help hook ... well, not doing anything with it just now actually
}
function getmenus_all() {
$page_content = '';
$page_content = json_encode(menu_navigation_links(variable_get('menu_primary_links_source', 'primary-links')));
// fill $page_content with the menu html
print $page_content;
return NULL;
}
function getmenus_menu() {
$items = array();
$items['getmenus'] = array(
'title' => 'Get Menus',
'page callback' => 'getmenus_all',
'access arguments' => array('access getmenus'),
'type' => MENU_CALLBACK,
);
return $items;
}
// permissions
function getmenus_perm() {
return array('access getmenus');
}
In your PHP code you can then write something like:
function primary_links() {
$primary_links = file_get_contents(SITE_URL . '/getmenus');
$primary_links = json_decode($primary_links);
$primary_links = (array)$primary_links;
$i = 0;
$last = count($primary_links);
$output = '';
foreach ($primary_links as $pm) {
$href = $pm->href;
if (strpos($pm->href, 'http://') === FALSE) {
if ($pm->href == '<front>') {
$href = SITE_URL . '/';
} else {
$href = SITE_URL . '/' . $pm->href;
}
}
$output .= '
<li>
'.$pm->title.'</li>';
$i++;
}
return $output;
}
I hope this helps!
PS: Make sure you update the module's permissions to allow anonymous users to have access to the path you set in your module - otherwise you will get a 403 Permission Denied.
Related
I'm finding that the resources for doing this are sparse. I'm using MODX as a CMS and want to take my existing blogs from Wordpress and use them in the new CMS. The resources are abundant for going from MODX to WP, but there's only one published method for WP to MODX, using the Articles method, which unfortunately doesn't work anymore. Whether that is because Articles hasn't been updated or the XML file from WP is incompatible.
Anyway, I'm left now with trying to do this the old fashioned way and I will not be able to bring each article over one-by-one. I want to learn how to take the exported XML file from WP and parse it into MODX, probably using PHP. But I'm unsure where to start.
Any suggestions would be helpful...yes I tried Google already. I'm not sure what to start with.
Thanks!
getFeed snippet code can be helpful for you here. You can take it's code, modify a bit and process WP feed items, something like the next:
if (!empty($url) && $modx->getService('rss', 'xmlrss.modRSSParser')) {
$rss = $modx->rss->parse($url);
if (!empty($rss) && isset($rss->items)) {
while (list($itemKey, $item) = each($rss->items)) {
foreach ($item as $k => $v) {
$item[$k] = str_replace(array('[',']'),array('[',']'),$item[$k]);
}
/// process rss items here
// f.e. add new modx resources
$newArticle = $this->modx->newObject('modResource'); //new article
$newArticle->set( 'template', ARTICLE_TEMPLATE_ID ); // replace ARTICLE_TEMPLATE_ID with actual article template id
$newArticle->set( 'pagetitle', $item['title'] ); // pagetitle
$newArticle->set( 'parent', ARTICLE_CONTAINTER_ID);
$newArticle->set( 'content', $item['description'] );
//add other valuable fields
if(!$newArticle->save()){
// modx error
}
}
}
Iam new in drupal. I want to create a page and want to add data in page directly with out using backend content. I have created a page like this, page-test.tpl.php. How can I call this newly created page in browser?
First you have to create your own custom module.Let the module name be test.Create 2 files namely test.info and test.module.Declare a hook_menu function inside the test.module file.Since your module name is test your hook_menu will be named as test_menu.
Hook_menu enables modules to register paths in order to define how URL requests are handled. Paths may be registered for URL handling only, or they can register a link to be placed in a menu.
Test.module
function test_menu() {
$items = array();
$items['test'] = array(
'title' => 'My Page',
'description' => 'Study Hard',
'page callback' => 'test_simple', //Calls the function
'access arguments' => array('access content'),
);
return $items;
}
function test_simple() {
return array('#markup' => '<p>' . t('My Simple page') . '</p>');
}
Test.info
name = Test
description = Provides a sample page.
core = 7.x
After adding this try clearing the drupal cache and then navigate to /test.Try this link if you are a beginner.Try reading hook_theme which allows you to use your custom template.More about hook_theme here.Hope it might help u mate.. :)
Pages in drupal are stored in the database, not in actual code files like old websites used to. The template files (.tpl.php) are exactly that - templates. So for example, lets say you have blog content. You'd have to create a content type of 'Blog'. you could then create a template file (ex. node--blog.tpl.php) which would format the way the blog pages would look. But you would still need to add new pages through the drupal interface in order to add them to the site. You could always use an input type of PHP if you'd like to include php in the body of the page.
If you simply want to display a php file in your browser from your site, you can just upload a php file of your choice to your sites/default/files directory and access it directly via the file path.
Ok, here's the deal: I am constructing a Drupal website that has several different sections. Each section is a view that displays a content type. (Each section has it's own content type) For example, I have a view that points to ?q=blog which displays content type blog.
All the sections look a little different than each other. Not like 'website-within-a-website' different but different enough that they can't all use the same template file and each be modified with CSS. Each section needs it's own page.tpl.php.
Unfortunately, AFAIK Drupal theme's .info files can only either assign one page.tpl.php for the entire theme or assign a page-node-####.tpl.php for each node. There is going to be lots of content on this website so setting Drupal to make a new identical page-node-####.tpl.php for every created node would get unmanagable very fast.
To solve this problem, I am going to use pathauto to create an alias for each content type. For example, all nodes of content type blog are given an alias ?q=blog/[post title]. Modify template.php to use page-blog.tpl.php for any page who's alias starts with the word 'blog'.
Other people have tried doing this sort of thing and have created functions such as the one described. Unfortunately, all the ones I have seen are for Drupal 6 or below. I have tried modifying existing ones with no success. So far, though, I think this is on the right track:
function basic_preprocess_page(&$vars, $hook) {
...
if( module_exists('path') ) {
$alias = drupal_get_path_alias( $_GET['q'] );
$site_section = "blog";
if( strpos( $alias, $site_section ) === 0 ) {
$VARIABLE_THAT_TELLS_THE_PAGE_WHAT_TEMPLATE_TO_USE = "/path/to/page-blog.php";
}
}
}
I cannot find $VARIABLE_THAT_TELLS_THE_PAGE_WHAT_TEMPLATE_TO_USE does anyone know what it is?
Maybe my site is structured badly. If anyone knows how to restructure my site so I can more easily make a theme with seperate sections please share how!
Thanks a million! (c:
EDIT: Perhaps I need to use template suggestions instead. Does anyone know the function or variable to use to set this?
They changed the name of this array key in D7 and I haven't seen it documented anywhere. I finally figured this out after a good bit of debugging. You can override the theme template in template.php with a hook_preprocess_page() like so:
function myTheme_preprocess_page(&$vars) {
global $node;
if ($node->type == 'blog') {
$vars['theme_hook_suggestions'] = array('my__blog_template'); // use my--blog-template.tpl.php, note '-' = '_'
}
elseif ($node->type == 'articles') {
$vars['theme_hook_suggestions'] = array('article__node_template'); // use article--node-template.tpl.php
}
}
Oh and don't forget to flush the Drupal caches after making changes to your template.php.
Ok, I found it:
http://drupal.org/node/223440#comment-991840
$alias = drupal_get_path_alias($_GET['q']);
if ($alias != $_GET['q']) {
$template_filename = 'page';
foreach (explode('/', $alias) as $path_part) {
$template_filename = $template_filename . '-' . $path_part;
$variables['template_files'][] = $template_filename;
}
}
Credit to this function goes to user mfb.
I had a lot of trouble with this so I will explain it here in case anyone finds it useful.
This function goes in your template.php. It needs to be part of the <theme name>_preprocess_page function. What it does is it takes the alias and then explodes it into a bunch of different components. For example if you are on a page with the alias ?q=blog/blog-post-title it would be exploded into blog and blog-post-title. It then turns each component into a name for a template suggestion. It puts each template suggestion into the template_files[] array (inside the $variables[] array) so that the page now has two new template suggestions:
page-blog, and page-blog-blog-post-title
Template suggestions are alternate template files. In this case they are for pages, but they don't necessarily have to be. You can have template suggestions for anything you can think of including blocks, nodes and the like. Don't let the name 'template suggestion' fool you. Template suggestions will be used over default templates as long as they exist. I don't know why it was named like that. I think it should be renamed.
What you do, then, now that you've set up Drupal to look for a template suggestion that points to your alias, is create a new template file where all the rest are in your theme. In this case, let's say I want to theme my entire blog section. In the templates folder I should create a file named page--blog.tpl.php (note the --double hyphens--) with the layout I want.
Drupal will use the most specific template suggestion it can find so if you wanted you could make one blog post to look completely different than the rest of the site long as you make a template for it named page--blog--blog-post-title and put it in your theme's templates directory. (again, note the double hyphens.)
I have been trying to load fivestar module and show the rating widget of the selected node in an external php file. I have gotten the rating widget displayed on the page but it only displays degraded version of the widget (non-JavaScript, dropdown widget and "Rate" button) I looked into the source code of the page but the javascript for fivestar module was not loaded. I have tried to load javascript using following functions but had no luck:
fivestar_add_js();
$path = drupal_get_path('module','fivestar');
drupal_add_js($path.'/js/fivestar.js', 'inline', 'footer');
The following is the code in the php file:
//require the bootstrap include
require_once 'includes/bootstrap.inc';
//Load Drupal
drupal_bootstrap(DRUPAL_BOOTSTRAP_FULL);
fivestar_add_css();
// I have used one of the following two functions one at a time to test.
fivestar_add_js();
$path = drupal_get_path('module','fivestar');
drupal_add_js($path.'/js/fivestar.js', 'inline', 'footer');
$book = $_GET["book"];
$chap = $_GET["chap"];
$prob = $_GET["prob"];
$string = $book.'/'.$chap.'/'.$prob;
$query = "SELECT ctcr.nid FROM content_type_comments_ratings AS ctcr WHERE ctcr.field_problem_value = '".$string."'";
$result=db_query($query);
$row = db_fetch_array($result);
if(isset($row['nid']))
{
$nid = $row['nid'];
node_load(FALSE, NULL, TRUE);
$fivestar = node_load($nid, NULL, TRUE);
if (function_exists('fivestar_widget_form')) print fivestar_widget_form($fivestar);
}
If you could give me a hint or direct me to some reading on the web, I would appreciate it. Thank you very much in advance.
By doing all this on an 'external' page/file, you circumvent the Drupal theming system - drupal_add_js() (and fivestar_add_js(), as it is just using that in the end) do not output the script tags themselves, but simply ensure that they will be included in the $scripts variable in page.tpl.php, which is then responsible to print that variables content. As you do not go through the page template, you get no script tags.
You could do a print drupal_get_js(); in your external file to output the scripts added via drupal_add_js() as a quick fix, but note that this will output all the default drupal js files as well, which might be more than you need (but might as well contain other scripts needed by fivestar, e.g. jquery). Alternatively, you'll have to create the needed script tags yourself.
As for hints on what to read, it is difficult to point you to something particular, but you might want to read up on the theming system in general.
I have a website where drupal manage the contents, but another application handle the e-commerce (my customer doesnt like to change his own e-commerce)
I dont like to have the e-commerce to looks differently from the rest of the websites, so i've made a drupal Page node with php code in the body, that simply include the external app and initialize it.
It works well, but the problem is the other link the e-commerce generate:
http://example.com/shop #The Page node i've created, this work
http://example.com/shop/catalog/fruit/ #here comes the trouble!
The external app handle the url by its own, so what i need is to tell drupal to redirect all the url that begin with shop to his shop Page node... something like
http://example.com/shop/* => load http://example.com/shop
What is the best practices to do that?
If you create a module rather than a node this will be quite easy.
use hook_menu() to match the URL string
function example_menu() {
$menu = array()
$menu['shop'] = array(
'page callback' = 'example_callback';
)
}
function example_callback() {
// use arg() to get arguments.
return shop_php();
}
Creating a callback with hook menu allows you to call your own code, the value returned by the callback will be displayed in the page. When drupal sees a URL which matches shop* it will call the function example_callback. In this function you can put the code you currently have in your page node. And return the content you wish to display in the page.
After googlin around, i found the Drupal custom_url_rewrite_inbound that does exactly what i need.
I inserted the function in my /sites/default/settings.php:
function custom_url_rewrite_inbound(&$result, $path, $path_language) {
if(preg_match("/^shop(\/)/", $path, $matches)) {
$result = 'node/XX'; //XX is the ID of my Page Node with the ecommerce code.
}
}
It works like a charm!