update with combo box - php

Question

I have job insert page which is working fine.
I just build an update page in admin panel.
I'm not able to show screen short :(
I need to show the category as selected which is already in the job table.
let me show you the table details.This is the job table
CREATE TABLE IF NOT EXISTS `jobs` (
`job_id` int(11) NOT NULL AUTO_INCREMENT,
`job_title` varchar(99) NOT NULL,
`job_category` int(3) NOT NULL,
`job_location` varchar(33) NOT NULL,
`job_country` varchar(33) NOT NULL,
`job_salary` int(12) NOT NULL,
`job_reference` varchar(9) NOT NULL,
`job_contact_name` varchar(9) NOT NULL,
`job_description` text NOT NULL,
`job_requirments` text NOT NULL,
`job_companydetails` text NOT NULL,
`status` int(2) NOT NULL,
`date` date NOT NULL,
`featured` int(1) NOT NULL,
PRIMARY KEY (`job_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1091 ;
and this is the category table
CREATE TABLE IF NOT EXISTS `job_category` (
`category_id` int(11) NOT NULL AUTO_INCREMENT,
`category_name` varchar(25) NOT NULL,
PRIMARY KEY (`category_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=16 ;
I'm just showing data from job table for update.
but the thing is that I need to show JOB CATEGORY in the Combobox.
I think it is easy through like this
<select name="job_category">
<?php
$result = mysql_query("SELECT * FROM $category_tbl");
while($row = mysql_fetch_array($result))
{
echo "<option value=$row[category_id]> $row[category_name] </option>";
}
?>
</select>
but the thing is that I need to show selected category name which is in the job table

Answer 1

In the while loop you can have something like:
while($row = mysql_fetch_array($result)) {
echo "<option value='$row[category_id]'";
if($row['category_id'] === $rows['job_category']){
echo "selected='selected'";
}
echo "> $row[category_name] </option>";
}
job['job_category'] would contain the category id of the job you are currently displaying.
Hope this helps.

Answer 2

It is has some bug
I just fixed it
look the changes
$result = mysql_query("SELECT * FROM $category_tbl");
while($row = mysql_fetch_array($result))
{
echo "<option value='$row[category_id]'";
if($row['category_id'] === $rows['job_category'])
{
echo "selected='selected'";
}
echo "> $row[category_name] </option>";
}
thanks for your clue