I have a simple checkbox, on click it sends XHR to PHP page , php processes correctly and I use json_encode($response) to return. But instead of a simple true or false I get the source code for the page and it is causing a "parsererror" of course.
ajax call as follows
$.ajax({
type: "post",
url: "myprocessor.php",
dataType: 'json',
data: { "id" : idnumber, "action": "makeLive", "isLive" : "1" },
beforeSend: function(data) {
$("#ajaxInProgress").addClass('progress');
},
success: function(data) {
$("#status").removeClass().addClass((data.error === true) ? 'error' : 'success').text('Success! Appraiser is NO LONGER Live ').slideDown('slow');
},
error: function(data) {
$("#status").removeClass().addClass('error').text(' - Changing the Live status for this appraiser to "Not Live" has failed - APPRAISER IS STILL LIVE IN SYSTEM, please try again').slideDown('slow');
},
complete: function(data) {
$("#ajaxInProgress").removeClass('progress');
setTimeout(function() {
$("#status").slideUp('slow').removeClass();
},2000);
}
});
The php I post to is as follows:
if (isset($_POST['action'])) {
if($_POST['action']=='makeLive') {
$checkappraiser=mysql_query("SELECT * FROM table WHERE id='".mysql_real_escape_string($_POST['id'])."'");
if (mysql_numrows($checkappraiser)>0) {
$livesetting=mysql_result($checkappraiser,0,"live");
$livesetting=!$livesetting;
$runSql = mysql_query("UPDATE table SET live='$livesetting' WHERE id='".mysql_real_escape_string($_POST['id'])."'");
if(!$runSql) {
$return['error'] = true;
} else {
$return['error'] = false;
}
}
}
echo json_encode($return);
}
Any suggestions would be great.
I am getting the proper data passed
I am getting the correct data updated in DB
My response is coming back as a parser error because it is trying to parse the source code as a json array.
Just a quick check, do you put <?php at the beginning of your php file?
That, or you're doing something wrong in your webserver, not passing files through to php correctly. Does hitting the php file directly load the source or the result?
If you hit page.php, does it load the same thing as if you hit page.phP or pHP, etc? It matters to web server filters, depending on the web server...
If you use tomcat for java, for example... you can turn off case sensitivity for finding files, but it does not turn off case sensitivity for mapping files to filters or servlets, so .jsp would load the jsp servlet, but .jsP would not.
Related
I have a chatting room with maximum of 2 users, when one user send a message to another, the second user should be notified that new message is received just like Facebook
I have done it with Ajax request like
$(document).ready(
function() {
setInterval(function() {
$.ajax({
url: 'incs/check_new_msg.php' ,
cache: false,
success: function(data)
{
$('#message').html(data);
},
});
}, 1000);
});
<div id="message"></div>
In check_new_msg.php I use the following code:
$new_msg = mysql_query("select * from inbox where status = '0' ");
echo mysql_num_rows($new_msg);
The above code work good but the problem is that it check inbox and new message each second , but it seems harmful for processor as it run a MySQL query each second, please help me how to to execute checking query only when a new message is received.
i will give you a concept then you should try to implement it.
create an external text file when inserting something from another computer and at client side check same file each second rather than checking database. if file exists then check database else continue checking text file
So your only concern is it runs the query every second right?
Here's my solution:
$(document).ready(
function() {
function check_message()
{
$.ajax({
url: 'incs/check_new_msg.php' ,
cache: false,
success: function(data)
{
$('#message').html(data);
},
complete: function(data)
{
check_message();
},
});
}
check_message();
});
<div id="message"></div>
What this does is it will call the ajax recursively once the last ajax request is completed.
One of the ways of implementing the feature you discussed is long polling method. In this method you leave the connection open for certain time and if the changes occur within that time, the response is returned back to user. and another connection is opened and so on.
You should google about longpolling as there are lots of tutorials available. Best of luck
I found a good solution for this problem , for this purpose i use a notepad file in same directory where the script exists.
when inserting a new record from any computer you have to create notepad file with insertion.
$insert = mysql_query("insert into inbox .....");
if(insert)
{
if(!file_exists(notepad_file_path))
{
fopen(notepad_file_path);
}
}
Then I call ajax request request
$(document).ready(
function() {
function check_message()
{
$.ajax({
url: 'incs/check_new_msg.php' ,
cache: false,
success: function(data)
{
$('#message').html(data);
},
complete: function(data)
{
check_message();
},
});
}
check_message();
});
<div id="message"></div>
After that in external ajax file check existence of notepad file, if file exists then give access to database, in that way it will not be harmful for processor.
if(file_exists(notepad_file_path))
{
$new_msg = mysql_query("select * from inbox where status = '0' ");
echo mysql_num_rows($new_msg);
if(mysql_num_rows($new_msg) == 0)
{
unlink(notepad_file_path);
}
}
I am currently migrating an already built web application to MVC, and I'm figuring out that I'm too newbie to do some kind of changes. There are some ajax calls that are freaking me out. I'll try to be as clear as possible, but due to my inexperience I'm not sure if I won't let some important information by the way.
The point is in the old application, things go this way:
In the php code:
if ($action_user == 'show_alerts') {
$list = array();
$query = "SELECT alert_type FROM alert_contact WHERE NOT
deleted AND user_email=" . typeFormat($email);
$result = mysqli_query($db, $query) or die('Error in query "'.$query . '": ' . mysqli_error($db));
while ($db_field = mysqli_fetch_assoc($result)) {
$list[] = $db_field['alert_type'];
}
echo json_encode($list);
In the jquery code:
$.ajax({
type: 'POST',
url: 'userpost.php',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json'
Here comes my problem, and since I don't have an userpost.php file anymore, I have to send it to the index.php and call my users component by a get petition, which I don't like, but I coudn't find another way to do it. And, what is even worse, I don't know at all how ajax is getting the variables that it needs. It must be a pretty basic mistake, but I recognize my skills at this point are't so good. That's what I'm doing in my version:
In the php code:
if ($action_user == 'show_alerts') {
$list = ModelUser::getAlertContact($act_email);
echo json_encode($list);//I predict that ajax don't reach this line, but not sure
}
In the jquery code:
$.ajax({
type: 'POST',
url: 'index.php?option=users',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json',
success: function(data) {
alert ('gotcha');
$.each(alertsarray, function(index, value) {
if ($.inArray(value, data) === -1) {
$("#sub" + value).prop("checked", false);
$('#alert' + value).removeClass("list_alert_sub");
}
else {
$("#sub" + value).prop("checked", true);
$('#alert' + value).addClass("list_alert_sub");
}
});
},
error: function(data) {
alert("¡Error (ajax)!");
}
});
Any help would be appreciated, and if there's some more information I've missed, please let me know. Thanks in advance.
UPDATE:
I've been making some progress but don't seem to find a real solution. Now I know that the url has to be the controller, so I'm using 'components/userpost/controller.php' as it, and it reaches the ajax call, cause the success alert is showing up. The problem is the MVC way, because I send ajax to the controller, but since I don't have a reload in the page, all the includes are failing so they are obviously not being loaded, and I'm getting errors like this:
PHP Warning: include(components/userpost/model.php): failed to open
stream: No such file or directory in
/var/www/html/viewer_mvc/components/userpost/controller.php on line 3,
referer: http://localhost/viewer_mvc/index.php
Really hope you guys can show me where am I failing, and if there's a special way to do these thing in MVC.
For the JQuery call it makes a POST request to index.php?option=users with JSON data. The form with the ID userForm is serialized using the Jquery serialize method.
The .serialize() method creates a text string in standard URL-encoded notation. It can act on a jQuery object that has selected individual form controls
$.ajax({
type: 'POST',
url: 'index.php?option=users',
data: $('#userForm').serialize(),
cache: false,
dataType: 'json'
Now for your PHP sample
if ($action_user == 'show_alerts') {
$list = ModelUser::getAlertContact($act_email);
echo json_encode($list);//I predict that ajax don't reach this line, but not sure
}
This code will be looking for variables that probably don't exist anymore if it is a different file i.e. is there an $action_user variable?
To start reimplementing it you will need to add the logic so that it checks the POST variable if your not using the framework code. So if you have a form element with the name 'name' then that will be available in your PHP script POST variable
$_POST['name']
[How to call a PHP function in MVC using AJAX]
$.ajax({
type: 'POST',
url: 'save-user.php',
data: { fname: "manish", email: "manishkp#com", role:"admin"},
success: function(data) {
console.log(data);
if(data == 'error')
{
$('#Register_error').text('Must Be filled...');
$('#Register_error').show();
}
else {
$('#Register_error').hide();
$('#Register_success').text('Successfully submit');
$('#Register_success').show();
}
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<?php
$fname = $_POST['fname'];
$email = $_POST['email'];
$role = $_POST['role'];
if(!empty($fname) && !empty($email) && !empty($role))
{
#MYSQL CONNECTION QUERY #
echo"success";
}
else{
echo "error";
}
?>
I'm trying to test an ajax call on post by doing the following just for testing purposes, but for some reason the call is never successful. I've been searching around and there isn't much that I could find that would explain why this isn't working.
$.ajax({
type: "POST",
url: "file.php",
success: function(data) {
if(data == 'true'){
alert("success!");
}
},
error: function(data) {
alert("Error!");
}});
file.php contains the following:
<?php
return true;
?>
Can someone please point me in the right direction. I realize that this may seem simple but I am stumped. Thank.
return true will make the script exit. You need:
echo 'true';
Firstly check your paths. Is file.php residing in the same folder as the file that your javascript is contained in?
If your path is incorrect, you will get a 404 error printed to your javascript console if you are using chrome.
Also you should change your php to:
<?php
echo 'true';
Once your path is correct and your php is amended you should be good to go.
Have you tried by accessing to the file directly and see if it outputs something?
return true shouldn't be use in that case (or any other, it's better to use exit or die), everything get by a AJAX call is hypertext generated by server side, you should use (as they pointed you before echo 'true';)
You could also try a traditional AJAX call XMLHttpRequest (without JQuery) if problem persists, and then check if there is any problem between the request and server..
EDIT: also, do not check by comparison, just make an alert to 'data' to see what it gets.
In addition to the echo 'true' suggestion, you can also try to alert the actual data that's returned to ajax. That way you can see if you have the proper value/type for your if statement.
success: function(data) {
alert(data);
}
try this, the new ajax syntax
$.ajax({ type: "POST", url: "file.php" }).done(function(resp){
alert(resp);
});
Here is correct way:
$.ajax({
type : "POST",
url : "file.php",
success : function (data) {
/* first thing, check your response length. If you are matching string
if you are using echo 'true'; then it will return 6 length,
Because '' or "" also considering as response. Always use trim function
before using string match.
*/
alert(data.length);
// trim white space from response
if ($.trim(data) == 'true') {
// now it's working :)
alert("success!");
}
},
error : function (data) {
alert("Error!");
}
});
PHP Code:
<?php
echo 'true';
// Not return true, Because ajax return visible things.
// if you will try to echo true; then it will convert client side as '1'
// then you have to match data == 1
?>
So, I am using jquery to make an ajax call to a php script on my server.
For some reason I cannot figure out, however, there is no querystring sent. Using var_dump() on the $_GET object shows that it is an empty string, and Chrome's network activity developer tool indicates no string is sent.
$.ajax({
"url":"../script/content.php",
"settings": {
"dataType":"html",
"type":"GET",
"data":{
"id":$(this).prop('id')
}
}
}).done( function(msg) {
//$('#debug').html(msg);
$('#dialog').html(msg);
$('#dialog').load(function() {
$('#close').click(function() {
$('#over').fadeOut(fadeTime);
});
if ($('#unique') > 0) {
$('#unique').load(function(){
$('#over').fadeIn(fadeTime);
});
}
else {
$('#over').fadeIn(fadeTime);
}
});
});
I had tried the ajax call without the quotes where they weren't necessary before hand, and the result was the same... I just put those in because I thought it might be the problem... though I think that in such notation the quotes don't make a difference unless one of the field values is supposed to be a string.
Is there anything clear in that code which might cause a querystring not to be sent? I guess there is a problem with my syntax... I just can't see it.
The #dialog load callback seems to never be called, either... but I guess that is another question.
Try this
$.ajax({
//The link we are accessing with params
url:'http://example.com/script/content.php'
+ '?id='
+ $(this).prop('id'),
// The type of request.
type: "get",
//The type of data that is getting returned.
dataType: "html",
error: function(){
//something here
},
success: function( strData ){
//something here
}
});
I am very new to ajax and jquery, but I came across a code on the web which I am manipulating to suit my needs.
The only problem is that I want to be able to respond to the ajax from PHP.
This ajax POSTS to a php page (email.php).
How can I make the email.php reply back if the message is sent or if message-limit is exceeded (I limit the nr of messages sent per each user)?
In other words, I want ajax to take a 1 or 0 from the php code, and for example:
if(response==1){ alert("message sent"); } else { alert("Limit exceeded"); }
Here is the last part of the code: (If you need the full code just let me know)
var data_string = $('form#ajax_form').serialize();
$.ajax({
type: "POST",
url: "email.php",
data: data_string,
success: function() {
$('form#ajax_form').slideUp('slow').before('');
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}//end success function
}) //end ajax call
return false;
})
Thanks
The success function of an $.ajax call receives a parameter, usually called data though that's up to you, containing the response, so:
success: function(data) {
// Use the data
}
(It also receives a couple of other parameters if you want them; more in the docs.)
The data parameter's type will vary depending on the content type of the response your PHP page sends. If it sends HTML, data will be a string containing the HTML markup; if your page sends JSON, the data parameter will be the decoded JSON object; if it's XML, data will be an XML document instance.
You can use 1 or 0 if you like (if you do, I'd probably set the content type to "text/plain"), so:
success: function(data) {
if (data === "1") {
// success
}
else if (data === "0") {
// failure
}
else {
// App error, expected "0" or "1"
}
}
...but when I'm responding to Ajax requests, nine times out of ten I send JSON back (so I set the Content-Type header to application/json), because then if I'm using a library like jQuery that understands JSON, I'll get back a nice orderly object that's easy to work with. I'm not a PHP guy, but I believe you'd set the content type via setContentType and use json_encode to encode the data to send back.
In your case, I'd probably reply with:
{"success": "true"}
or
{"success": "false", "errMessage": "You reached the limit."}
so that the server-side code can dictate what error message I show the user. Then your success function would look like this:
success: function(data) {
var msg;
if (typeof data !== "object") {
// Strange, we should have gotten back an object
msg = "Application error";
}
else if (!data.success) {
// `success` is false or missing, grab the error message
// or a fallback if it's missing
msg = data.errMessage || "Request failed, no error given";
}
if (msg) {
// Show the message -- you can use `alert` or whatever
}
}
You must pass an argument to your "success" function.
success: function(data)
{
if(data == '1')
{
$('form#ajax_form').slideUp('slow').before('');
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}
}
And in your php file, you should just echo the response you need
if(mail())
{
echo '1';
}
else
{
echo '0';
}
Anything you echo or return in the php file will be sent back to you jquery post. You should check out this page http://api.jquery.com/jQuery.post/ and think about using JSON formatted variables to return so like if you had this in your email script:
echo '{ "reposonse": "1" }';
This pass a variable called response with a value of 1 back to you jquery script. You could then use an if statement how you described.
just have email.php echo a 0 or 1, and then grab the data in the success event of the ajax object as follows...
$.ajax({
url: 'email.php',
success: function(data) {
if (data=="1"){
...
}else{
...
}
}
});
what you do is, you let your ajax file (email.php) print a 1 if successful and a 0 if not (or whatever else you want)
Then, in your success function, you do something like this:
function(data) {
$('form#ajax_form').slideUp('slow').before('');
if(data==1){ alert("message sent"); } else { alert("Limit exceeded"); }
$('#success').html('<h3>Success</h3>Your email is has been sent.');
}
So you capture the response in the data var of the function. If you a bigger variety in your output, you can set you dataType to "json" and have your php file print a json_encoded string so that you can access your different variables in your response via for example data.success etc.
PHP can only return to AJAX calls, by its output. An AJAX call to a PHP page is essentially the same as a browser requesting for the page.
If your PHP file was something like,
<?php
echo "1";
?>
You would receive the "1" in your JavaScript success callback,
that is,
success: function(data) {
// here data is "1"
}
As an added note, usually AJAX responses are usually done in JSON format. Therefore, you should format your PHP replies in JSON notation.