For some reason I am unable to use query results in the same function that calls them. Please see controller below and model and let me know where my issue is.
What breaks down is line 2 of controller, trying to concatenate query result contact_name and description_computer and saving it as variable name. I get the following error "Undefined variable: query" for both query results.
Using codeigniter.
Controller
function get_quarter_info($data)
{
$data['query'] = $this->model->get_client_info($data);
$data['name'] = $query['contact_name'] . " " . $query['description_computer'] . ".pdf";
$html = $this->load->view('Quarter_info_view', $data, true);
$pdf = pdf_create($html, '', false);
write_file($data['name'], $pdf);
$this->index();
}
Model
function get_client_info($data)
{
$query = $this->db->get_where('subscriber_report', array('client_number'=> $data['client_number']));
return $query->row_array();
}
You should probably use $query instead of $data['query]. The data array is used to pass data to your view.
You're not assigning a value to $query in get_quater_info. Instead, you're assigning the value to $data['query'];
Try this instead:
$query = $data['query'] = $this->model->get_client_info($data);
Related
I am facing problem to join these tables and also know how to make controller code to view data in view file with text boxes.
public function get_order_return_info()
{
$this->db->select('tbl_order_details.*', false);
$this->db->select('tbl_order_details.order_details_id', false);
$this->db->select('tbl_order.order_id', false);
$this->db->select('tbl_product.product_id', false);
$this->db->select('tbl_inventory.product_quantity', false);
$this->db->from('tbl_order_details');
$this->db->join('tbl_order', 'tbl_order_details.order_id = tbl_order.order_id ', 'left');
$this->db->join('tbl_product', 'tbl_order_details.product_code = tbl_product.product_id ', 'left');
$this->db->join('tbl_inventory', 'tbl_product.product_id = tbl_inventory.product_id ', 'left');
$query_result = $this->db->get();
$result = $query_result->result();
return $result;
}
You can use MVC to solve this
//Controller
function get_data() {
$data['list'] = $this->your_model->get_data();
$this->load->view('your_view/location',$data);
}
//Model
function get_data() {
$sql = "your_query";
$list = $this->db->query($sql)->result_array();
return $list;
}
//View
foreach($list as $data) {
echo $data['your_selected_field']; // it could be table,text field,or just text
}
API Reference : https://www.codeigniter.com/user_guide/database/results.html#result-arrays
Hope this helps
First u can create OrderModel to work with order table. Then create function get_order_data.
//Order Model
public function get_orders() {
// your db query to get orders
return $result;
}
Then u can load model in controller using $this->load->model('OrderModel'); Best place is __construct to load model
And call your get_orders() function
// Your controller
// Create data array to store front data
$data = [];
$data['orders'] = $this->OrderModel->get_orders();
After getting $orders pass it to view using following codes
$this->load->view('path/to/view', $data);
Finally u can call your order data in view using $orders
I hope this will help u
You need to set alias to the table to function it properly like this.
$this->db->select('a.*,a.order_details_id, b.order_id ', false);
$this->db->from('tbl_order_details as a');
$this->db->join('tbl_order as b', 'a.order_id = b.order_id ', 'left');
If you want select 1 row only you need to use this function.
$this->db->get('tbl_order_details')->row_array();
or if you want all result row you need to use this.
$this->db->get('tbl_order_details')->result_array();
On your controller you should add this lines to pass your result on your view page.
public function index()
{
$data['orderDetails'] = $this->your_model->get_order_return_info();
$this->load->view('pages/yourview/index',$data);
}
And finally to set your order details to the text boxes. You need to echo it inside the text boxes like this.
<input type="Text" name="orderID" value="<?php echo $orderDetails['order_id'];?>" >
If you use result_array() you need to use foreach loop to echo it.
I want to display a value in view in CodeIgniter but I am getting several errors like trying to get the property on non-object. I think my code is correct but I am getting errors. Below is my code.
controller:
public function trainer($id)
{
$user_record = $this->db->query("select * from usr_data where usr_id=$id")->result();
$data['title'] = 'trainer Dashboard';
$data['user_record'] = null;
$data['active_courses'] = [];
$data['inprogress'] = [];
if(count($user_record)) {
$user_record = $user_record[0];
$data['title'] = ucwords($user_record->firstname).' Dashboard';
$data['user_record'] = $user_record;
$active_courses = $this->base_model->getTrainercourseAll($id);
$data['active_courses'] = $active_courses;
$inprogress = $this->base_model->getstaffinprogress($id);
$data['inprogress'] = $inprogress;
}
$this->load->view('trainer-dashboard', $data);
}
model:
public function getstaffinprogress($user_id) {
$result=$this->executeSelectQuery("select AVG(m.percentage) from object_data o, ut_lp_marks m where o.obj_id=m.obj_id and o.type='crs' and m.status=1 ");
return $result;
}
view:
<h3>Avg inprogress:<?php echo "<span style='color:#ff00ff;font-family:verdana;'>".$inprogress->percentage."</span>";?></h3>
I want to display the column percentage which is coming from database.above code is in the controller, model and view.i thought my controller code is wrong.
Anyone help me to get rid of this error. I want to display a value in view in CodeIgniter but I am getting several errors like trying to get the property on non-object. I think my code is correct but I am getting errors. Below is my code.
Try this in your view file,
if(isset($inprogress)){
echo $inprogress->percentage;
}
Then your code look like this,
<h3>Avg inprogress:<?php if(isset($inprogress)){ echo "<span style='color:#ff00ff;font-family:verdana;'>".$inprogress->percentage."</span>";}?></h3>
Then call the controller function. I think inprogress is not set at the first time.
If it doesn't work, try to var_dump($inprogress) in controller and check value and type.
And try this code in your model. Query also seems not correct
public function getstaffinprogress($user_id) {
$this->db->select_avg('ut_lp_marks.percentage');
$this->db->where('ut_lp_marks.obj_id', $user_id);
$this->db->where('object_data.type', 'crs');
$this->db->where('ut_lp_marks.status', 1);
$this->db->join('object_data', 'object_data.obj_id = ut_lp_marks.obj_id');
$query = $this->db->get('ut_lp_marks');
return $query->result_array();
}
I assume that your db is ut_lp_marks. Then var_dump array and check data is correct first. Then access array element.
public function getstaffinprogress($user_id) {
$result = array();
$query=$this->db->query("select AVG(m.percentage) from object_data o, ut_lp_marks m where o.obj_id=m.obj_id and o.type='crs' and m.status=1 ");
foreach($query->result() as $row){
$result = $row;
}
return $result;
}
Also check $inprogress->percentage exists before print in view.
I am fetching data from mysql database table in codeigniter using following code
$result = $this->db->get("shipping");
$data = $result->result_array();
But returns no data.
When I apply the limit as
$this->db->get("shipping",1,30)
The code works.
But I want to fetch all result and not by limiting it.
Could anyone please let me know how do I resolve this issue.
Thanks in advance.
have you tried using query rather than get?
$sql = "
SELECT
*
FROM
shipping
";
$query = $this->db->query($sql);
$data = $query->result();
You have not put a return
https://www.codeigniter.com/user_guide/database/results.html
// This will get every result from shipping
public function somefunction() {
$result = $this->db->get("shipping");
return $result->result_array();
}
Controller function
public function somecontrollerfunction() {
$this->load->model('some_model');
$data['shipping'] = array();
$data['shipping'] = $this->some_model->somefunction();
// var_dump($data['shipping']);
$this->load->view('your_view', $data);
}
I do not want to be asking a question that has already been answered, however I have done a ton of research and I am stuck. Any help would be appreciated.
I am trying to query and add database results to OpenCart's addproduct.tpl
In the MODEL file I have:
public function units() { //function that gets database info and returns it
$unit_variables = $this->db->query("SELECT unit FROM ". DB_PREFIX ."
weight_class_description");
if (!$unit_variables) {
die(mysql_error());
}
else {
foreach ($unit_variables->rows as $temp_var) {
print_r($temp_var['unit'], true);
}
}
}
In the CONTROLLER file I have:
$this->load->model('catalog/product'); //where my function is located
$this->model_catalog_product->units();
$weight_variables = units();
if (isset($this->request->post['weight_variables'])){
$this->data['weight_variables'] = $this->request->post['weight_variables'];
}
In the VIEW I have:
<?php echo $weight_variables ?>
I get the following error:
Call to undefined function units() in /path/to/controller/file on line etc.
Note: When I print_r($temp_var); instead of returning print_R($temp_var, true) and delete these lines of code $weight_variables = units(); if (isset($this->request->post['weight_variables'])){ $this->data['weight_variables'] = $this->request->post['weight_variables'] } in the controller file my model file will display the query results on the addproduct.tpl
units() is a METHOD of your object, yet you're calling it as a standalone regular function:
$weight_variables = units();
^^^^^^^
Shouldn't it be:
$weight_variables = $this->model_catalog_product->units();
instead? And note that as-written, your method doesn't actually return anything, so $weight_variables will simply get assigned null..
I have to extract two separate pieces of information from my mysql database. I'm having a hard time trying to figure out how to extract two different sets of information via function(s) I'm writing. I'm trying to figure out a solution but I'm not getting it. Below is my syntax so far. My goal here is to get both of the functions (getPrice and getOtherPrice) all within the same function working. If I // one, the other one works. If both are active, just one is working. How would you guys go about correcting this issue, what do you think I'm doing wrong? Thanks Everyone.
function getJoinInformation($year,$make,$model)
{
$data = $this->getPrice($year,$make,$model);
$data = $this->getOtherPrice($year,$make,$model);
return $data;
}
function getPrice($year,$make,$model)
{
$this->db->select('*');
$this->db->from('tbl_car_description d');
$this->db->join('tbl_car_prices p', 'd.id = p.cardescription_id');
$this->db->where('d.year', $year);
$this->db->where('d.make', $make);
$this->db->where('d.model', $model);
$query = $this->db->get();
return $query->result();
}
function getOtherPrice($year,$make,$model)
{
$this->db->select('*');
$this->db->from('tbl_car_description d');
$this->db->where('d.year', $year);
$this->db->where('d.make', $make);
$this->db->where('d.model', $model);
$query = $this->db->get();
return $query->result();
}
you are returning only last function result you should put the the result of both function by making an array of $data
function getJoinInformation($year,$make,$model)
{
$data['getPrice'] = $this->getPrice($year,$make,$model);
$data['getOtherPrice'] = $this->getOtherPrice($year,$make,$model);
return $data;
}
You're replacing the result in the variable $data.
$data = $this->getPrice($year,$make,$model);
$data = $this->getOtherPrice($year,$make,$odel);
$data will always just contain the result of the last function.