i'm still asking the same question regarding my drop downs.i have these two drop downs that sets the month and year respectively. the first drop down would allow the user to choose a month.if user would not choose any of the options the display would be the current month.same with the year drop down.i have already done it with a single drop down but i can't do it for two drop downs.scenario would be user could use from the month and let the year drop down to be in default and vice versa.
$(document).ready(function()
{
$("#months").change(function(event)
{
var m= $(this).val();
if(m!='00' || m!='NULL')
{
$("#memcount").load('../crd_reports/month.php', {"m":m});
$("#top10").load('../crd_reports/top10_monthly.php', {"m":m});
}
});
$("#years").change(function(event)
{
var y=$(this).val();
if( y == '10')
{
}
else if(y!='10' || y!='NULL')
{
$("#display").load('../crd_reports/month.php', {"y":y});
$("#top10").load('../crd_reports/top10_monthly.php', {"m":m});
}
});
});
this is my month.php. this file has the same content as the top10_monthly.php
if (isset($_REQUEST['m']))
{
$m = $_REQUEST['m'];
include '../../include/dbconnect.php';
$sql = "SELECT * FROM tbl_user WHERE admin_level LIKE 'CRD' ORDER BY id";
$result =mysql_query($sql);
It seems you want to set the date from the db to the page.Is it right?
If so , I think there is no need to do that , for you can just transfer the date value includes yeaer,month and day to the js by write php code in the js .
for example:
<script language="javascript">
var y=<?php echo $d['year']?>;
var m=<?php echo $d['month']?>;
var d=<?php echo $d['day']?>;
</script>
the $d is an array from the db. then you can use the jquery set the value to the drop down in the front html . But attenstion you should put the code in the $(function(){}).
Related
i want to filter the data according selection of option from three drop down.
$(document).ready(function(){
var institute = $("#institute_wise").val();
var library_type = $("#library_type_wise").val();
var state = $("#state_wise").val();
if(institute=='Select' && library_type=='Select' && state=='Select')
{
$("#load-a").load("get-filter-values.php?url=all");
//$('#load-a').html("");
}
using any method . can anyone solve this problem.
I have a problem with updating the data I display from my db. Initially, when the page opens I display the date corresponding to the current date but then the user can change the date by entering it in a text box and when he clicks update all the data displayed should be deleted and the data corresponding to the new date should be displayed. Right now I have a javascript function which deleted all the data in the div when the button is clicked. The div holds the data I want to change. But I don't know how to add new data into the div. I tried to add php code to look up the database for the data in the javascript function but I don't know how to add it to the text box.
function changedate()
{
document.getElementById("label1").innerText=document.getElementById("datepicker").valu e;
document.getElementById("selecteddate").innerText=document.getElementById("datepicker" ).value;
document.getElementById("teammembers").innerHTML = "";//empties the div(teammembers)
<?php
$con=mysqli_connect("localhost","*****","*****","*****");
$result = mysqli_query($con,"SELECT * FROM users");
while($row = mysqli_fetch_array($result))
{
if(trim($user_data['email'])!=trim($row['email']))
{
$email_users = $row['email'];
//I want to first show this email but I don't know how to add it to the div.
}
}
?>
}
You can use a combination of jQuery and AJAX to do this. Much simpler than it sounds. To see that this is the right answer for you, just view this example.
In the below example, there are two .PHP files: test86a.php and test86b.php.
The first file, 86A, has a simple selection (dropdown) box and some jQuery code that watches for that selection box to change. To trigger the jQuery code, you could use the jQuery .blur() function to watch for the user to leave the date field, or you could use the jQueryUI API:
$('#date_start').datepicker({
onSelect: function(dateText, instance) {
// Split date_finish into 3 input fields
var arrSplit = dateText.split("-");
$('#date_start-y').val(arrSplit[0]);
$('#date_start-m').val(arrSplit[1]);
$('#date_start-d').val(arrSplit[2]);
// Populate date_start field (adds 14 days and plunks result in date_finish field)
var nextDayDate = $('#date_start').datepicker('getDate', '+14d');
nextDayDate.setDate(nextDayDate.getDate() + 14);
$('#date_finish').datepicker('setDate', nextDayDate);
splitDateStart($("#date_finish").val());
},
onClose: function() {
//$("#date_finish").datepicker("show");
}
});
At any rate, when the jQuery is triggered, an AJAX request is sent to the second file, 86B. This file automatically looks stuff up from the database, gets the answers, creates some formatted HTML content, and echo's it back to the first file. This is all happening through Javascript, initiated on the browser - just like you want.
These two files are an independent, fully working example. Just replace the MYSQL logins and content with your own fieldnames, etc and watch the magic happen.
TEST86A.PHP
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
//alert('Document is ready');
$('#stSelect').change(function() {
var sel_stud = $(this).val();
//alert('You picked: ' + sel_stud);
$.ajax({
type: "POST",
url: "test86b.php", // "another_php_file.php",
data: 'theOption=' + sel_stud,
success: function(whatigot) {
//alert('Server-side response: ' + whatigot);
$('#LaDIV').html(whatigot);
$('#theButton').click(function() {
alert('You clicked the button');
});
} //END success fn
}); //END $.ajax
}); //END dropdown change event
}); //END document.ready
</script>
</head>
<body>
<select name="students" id="stSelect">
<option value="">Please Select</option>
<option value="John">John Doe</option>
<option value="Mike">Mike Williams</option>
<option value="Chris">Chris Edwards</option>
</select>
<div id="LaDIV"></div>
</body>
</html>
TEST86B.PHP
<?php
//Login to database (usually this is stored in a separate php file and included in each file where required)
$server = 'localhost'; //localhost is the usual name of the server if apache/Linux.
$login = 'abcd1234';
$pword = 'verySecret';
$dbname = 'abcd1234_mydb';
mysql_connect($server,$login,$pword) or die($connect_error); //or die(mysql_error());
mysql_select_db($dbname) or die($connect_error);
//Get value posted in by ajax
$selStudent = $_POST['theOption'];
//die('You sent: ' . $selStudent);
//Run DB query
$query = "SELECT `user_id`, `first_name`, `last_name` FROM `users` WHERE `first_name` = '$selStudent' AND `user_type` = 'staff'";
$result = mysql_query($query) or die('Fn test86.php ERROR: ' . mysql_error());
$num_rows_returned = mysql_num_rows($result);
//die('Query returned ' . $num_rows_returned . ' rows.');
//Prepare response html markup
$r = '
<h1>Found in Database:</h1>
<ul style="list-style-type:disc;">
';
//Parse mysql results and create response string. Response can be an html table, a full page, or just a few characters
if ($num_rows_returned > 0) {
while ($row = mysql_fetch_assoc($result)) {
$r = $r . '<li> ' . $row['first_name'] . ' ' . $row['last_name'] . ' -- UserID [' .$row['user_id']. ']</li>';
}
} else {
$r = '<p>No student by that name on staff</p>';
}
//Add this extra button for fun
$r = $r . '</ul><button id="theButton">Click Me</button>';
//The response echoed below will be inserted into the
echo $r;
Here is a more simple AJAX example and yet another example for you to check out.
In all examples, note how the user supplies the HTML content (whether by typing something or selecting a new date value or choosing a dropdown selection). The user-supplied data is:
1) GRABBED via jQuery: var sel_stud = $('#stSelect').val();
2) then SENT via AJAX to the second script. (The $.ajax({}) stuff)
The second script uses the values it receives to look up the answer, then ECHOES that answer back to the first script: echo $r;
The first script RECEIVES the answer in the AJAX success function, and then (still inside the success function) INJECTS the answer onto the page: $('#LaDIV').html(whatigot);
Please experiment with these simple examples -- the first (simpler) linked example doesn't require a database lookup, so it should run with no changes.
You want to output a literal JS statement with whatever you get back from php, basically:
document.getElementById("teammembers").innerHTML = // notice no erasing, we just
// overwrite it directly with the result
"<?php
$con=mysqli_connect("localhost","*****","*****","*****");
$result = mysqli_query($con,"SELECT * FROM users");
while($row = mysqli_fetch_array($result))
{
if(trim($user_data['email'])!=trim($row['email']))
{
$email_users = $row['email'];
//I want to first show this email but I don't know how to add it to the div.
// so just show it!
echo $email_users; // think about this for a second though
// what are you trying to achieve?
}
}
?>"
This is a vast question, not very specific. Checkout more about AJAX requests - basically from javascript you will have a call to the server that retrieves your data.
This is a snippet from the javascript library jQuery :
$.ajax({
type: "POST",
url: "emails.php",
data: { user: "John" }
}).done(function( msg ) {
$('teammembers').html(msg);
});
hope this will give you a starting point
just a quick one im looking to populate three drop down boxes to filter data and each one of them is going to affect the next.
what i want is for
Drop down 1 has company
once drop down 1 is selected the second drop down is populated with the branches for that company
once selected the third drop down is populated by the staff members for that company in that branch then when i press search it should pull the data for that 1 staff member. all of the information is in one table
the table i have is called "stafflist"
the columns are "company", "branch" and "staffname" each staff member has an autonumber id field which i use as a lookup called "staffID"
Thank you for any help
Regards
Slowie
Lets take an easy example, This is a javascript solution. I'm using this and it works perfectly fine. This script work in case if you select a country it populates its corresponding cities in the second dropdown. You can take some idea and use this for your case where you can deal with three dropdowns respectively.
This is the country dropdown:
<?php
$countrylist=mysql_query("SELECT * FROM country ORDER BY name ASC");
echo "<select name='country' id='country' onchange=\"reload(this.form)\" title='Country e:g; United Kingdom,Pakistan'><option value='0'>Select Country</option>";
while($clist=mysql_fetch_array($countrylist))
{
echo "<option value='$clist[Name]'>$clist[Name]</option>"."<br/>";
}
echo "</select>";
?>
This is the region dropdown:
<select name="region" id="region" ></select>
Now make a seperate file named crlist.js and include it in the page having above code like this:
<script type="text/javascript" src="crlist.js"> </script>
code for crlist.js:
var request = false;
/*#cc_on #*/
/*#if (#_jscript_version >= 5)
try {
request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e2) {
request = false;
}
}
#end #*/
function fillSelect(country,path) {
var url = path+"crlist.php?country=" + country;
request.open("GET", url, true);
request.onreadystatechange = go;
request.send(null);
}
function go() {
if (request.readyState == 4) {
//if (request.status == 200) {
var response = request.responseText;
var list=document.getElementById("region");
for (i = list.length - 1; i>=0; i--) {
list.remove(i);
}
var records=response.split('|');
for (i=1; i<records.length; i++) {
//alert("rcord="+records[i]);
var record=records[i].split('*');
var region=record[0];
//alert("region="+region);
var regionid=record[1];
//alert("regionid="+regionid);
var x=document.createElement('option');
//var y=document.createTextNode(region);
x.text=region;
//x.value=region;
//alert(x.text);
//x.appendChild(y);
//list.appendChild(x);
list.options.add(x);
}
//}
}
}
function initCs(path) {
if (!request && typeof XMLHttpRequest != 'undefined') {
request = new XMLHttpRequest();
}
var country=document.getElementById('country');
country.onchange=function() {
if(this.value!="Select") {
var list=document.getElementById("region");
for (i = list.length - 1; i>=0; i--) {
list.remove(i);
}
//while (list.childNodes[0]) {
//list.removeChild(list.childNodes[0]);
//}
}
fillSelect(this.value,path);
//alert(this.value);
}
//fillSelect(country.value);
}
Now make a seperate file named crlist.php.
Code for crlist.php:
<?php
require_once 'yourconfigfile.php';
$cname = $_GET['country'];
$query="select ID,Name from city where CountryCode=(select code from country where name='$cname') Order By Name ASC";
$res = mysql_query($query) or die(mysql_error());
while($region = mysql_fetch_array($res)){
echo "<option value='".$region['Name']."'>".$region['Name']."</option>";
}
?>
Now add following script on the page having dropdowns:
<script type="text/javascript" src="crlist.js"> </script>
<script>
$(document).ready(function() {
initCs("");
});
</script>
This is my own script, and i've assumed that you have created country and region tables. But you need to tweak the queries and above code according to your db structure. In your case you have to create tables for company, branches and employees.
Hope this helps.
Have you ever heard about AJAX() OR jQuery ? if not then refer those link first; actually for your task you need to use Ajax OR jquery based dropdown boxes. which can make your dream success. :)
refer below link for your solution.
If any help needed you can feel free to ask me..
EDIT As per your commnet :
Step-1:- "SELECT company_id,company_name from company_table WHERE $condition ";
Step-2:- Fill first drop down box with record of first query set.
Step-3:- call jquery.ajax function onchange event of first drop down box in which call one
php page i.e: getRecords.php.
Step-4:- In getRecords.php page you need to get all the Branches of that company by passing company id in ajax and return a record array as response.
Step-5:- Fill second drop down with these records and again onchange event call another jquery.ajax request for final drop down box and do all things same as Step-4.
I think its all steps what you need for. still have any issue let me inform.
Thanks.
I have two drop-down boxes. I want to populate second drop-down box on selection in the first drop-down box. My values are retrieving from database. Is this possible without using php or I need intermediate ajax and php file to get values from first drop-down and populate values file. Or this is possible without using php I mean only using Jquery. Please give me hint to do that.
Suppose I have 2 countries. First is INDIA and second is USA. ON first drop-down I am selecting countries and if first dropdown is selected than second dropdown populate its respective states.
if you encode your data into JSON format, then you can do something like this:
for HTML:
<select name='country' id='country'>
<option value='india'>India</option>
<option value='usa'>USA</option>
</select>
<select name='dates' id='dates'>
</select>
jQuery:
data = {
india: ['2011-03-11','2010-02-01'],
usa: ['2006-03-11','2009-02-01']
}
$('#country').change(function(){
var dateopts = ''
$.each(data[$(this).val()],function(i,v){
dateopts += "<option value='"+v+"'>"+v+"</option>"
})
$('#dates').html(dateopts)
})
Which when the country is changed, will build and populate the options for the second select box.
See the working example here: http://jsfiddle.net/xHxcD/
The above method requires all data to be sent to client side with the initial page request. If you have lots of data, it would be better to receive the data via AJAX. It would be simplest to do this by building an object in PHP with the same data structure as your client side, then use json_encode to convert it into as JSON string and echo it out.
Reading this into your client side would then be as simple as this:
$.ajax('myJsonData.php?country=india',function(jsonData){ data.india = jsonData })
You could do it either way. If you dont want to use ajax, just load every single option into an object. Then when you select something from select #1, populate #2 with the assoicated array of data from your object.
If I were doing it, I wouldn't do it with ajax unless there was a TON of data.
Yes you can do it without using php. For that you've to assign two different states list in Javascript array and base on the selection just change the options in the other select box. As simple as that.
You can assign the javascript array using your serverside scripting language while loading the page if you're using database to store the states.
But do not do this unless you've very small amount data. In your case you've only 2 countries so you can go ahead with it.
Lets take an easy example, I'm using this for the same purpose that you want and it works perfectly fine.
This is the country dropdown:
<?php
$countrylist=mysql_query("SELECT * FROM country ORDER BY name ASC");
echo "<select name='country' id='country' onchange=\"reload(this.form)\" title='Country e:g; United Kingdom,Pakistan'><option value='0'>Select Country</option>";
while($clist=mysql_fetch_array($countrylist))
{
echo "<option value='$clist[Name]'>$clist[Name]</option>"."<br/>";
}
echo "</select>";
?>
This is the region dropdown:
<select name="region" id="region" ></select>
Now make a seperate file named crlist.js and include it in the page having above code like this:
<script type="text/javascript" src="crlist.js"> </script>
code for crlist.js:
var request = false;
/*#cc_on #*/
/*#if (#_jscript_version >= 5)
try {
request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e2) {
request = false;
}
}
#end #*/
function fillSelect(country,path) {
var url = path+"crlist.php?country=" + country;
request.open("GET", url, true);
request.onreadystatechange = go;
request.send(null);
}
function go() {
if (request.readyState == 4) {
//if (request.status == 200) {
var response = request.responseText;
var list=document.getElementById("region");
for (i = list.length - 1; i>=0; i--) {
list.remove(i);
}
var records=response.split('|');
for (i=1; i<records.length; i++) {
//alert("rcord="+records[i]);
var record=records[i].split('*');
var region=record[0];
//alert("region="+region);
var regionid=record[1];
//alert("regionid="+regionid);
var x=document.createElement('option');
//var y=document.createTextNode(region);
x.text=region;
//x.value=region;
//alert(x.text);
//x.appendChild(y);
//list.appendChild(x);
list.options.add(x);
}
//}
}
}
function initCs(path) {
if (!request && typeof XMLHttpRequest != 'undefined') {
request = new XMLHttpRequest();
}
var country=document.getElementById('country');
country.onchange=function() {
if(this.value!="Select") {
var list=document.getElementById("region");
for (i = list.length - 1; i>=0; i--) {
list.remove(i);
}
//while (list.childNodes[0]) {
//list.removeChild(list.childNodes[0]);
//}
}
fillSelect(this.value,path);
//alert(this.value);
}
//fillSelect(country.value);
}
Now make a seperate file named crlist.php.
Code for crlist.php:
<?php
require_once 'yourconfigfile.php';
$cname = $_GET['country'];
$query="select ID,Name from city where CountryCode=(select code from country where name='$cname') Order By Name ASC";
$res = mysql_query($query) or die(mysql_error());
while($region = mysql_fetch_array($res)){
echo "<option value='".$region['Name']."'>".$region['Name']."</option>";
}
?>
Now add following script on the page having dropdowns:
<script type="text/javascript" src="crlist.js"> </script>
<script>
$(document).ready(function() {
initCs("");
});
</script>
This is my own script, and i've assumed that you have created country and region tables. But you need to tweak the queries and above code according to your db structure.
Reference to my answer: Cascade Dropdown List using jQuery/PHP
Hope this helps.
Very simply, I have one dropdown menu dynamically populated with data:
SQL Code
$querycourse = "SELECT course, COUNT(course) AS count FROM acme WHERE course IS NOT NULL GROUP BY course ";
$procc = mysqli_prepare($link, $querycourse);
$queryc = mysqli_query($link, $querycourse) or die(mysqli_error($link));
PHP Code
echo "<select name='course[]' value='' multiple='multiple' size=10>";
// printing the list box select command
echo "<option value=''>All</option>";
while($ntc=mysqli_fetch_array($queryc)){//Array or records stored in $nt
echo "<option value=\"$ntc[course]\">\"$ntc[course]\"</option>";
/* Option values are added by looping through the array */
}
echo "</select>";// Closing of list box
What I need is another dropdown that is populated with data based on a selection from the first dropdown box.
I am using MySQL, PHP, Javascript and can also (at a push) use jQuery. I have no experience in Ajax.
Would anyone be kind enough to point me in the right direction?!
Thanks in advance, as always,
Homer.
First and Best Method (If you have or may have enough option specific data)
Use AJAX. It is the easiest way, I think, compared to the other ways to implement the same. Use Jquery to implement AJAX. It makes AJAX a piece of cake! Here I share my piece of cake for you -
Following is roughly the complete code you need -
Call a javascript function populateSecondDropdown() on your first select like this -
echo "<select name='course[]' value='' multiple='multiple' size=10 onchange='populateSecondDropdown(this, 'http://yourprojectUrl','Any Subject');'>";
// printing the list box select command
echo "<option value=''>All</option>";
while($ntc=mysqli_fetch_array($queryc))
{//Array or records stored in $nt
echo "<option value=\"$ntc[course]\">\"$ntc[course]\"</option>";
/* Option values are added by looping through the array */
}
echo "</select>";// Closing of list box
Define an ajax call inside inside the populateSecondDropdown() function -
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script>
<script type="text/javascript">
function populateSecondDropdown(object,baseUrl)
{
$.ajax({
type: "POST",
url: baseUrl+"/ajax/fetchOptions.php",
data: { id_option: $(object).val(), operation: 'get_subjects' },
dataType: "json",
success: function(data)
{
//Clear options corresponding to earlier option of first dropdown
$('select#secondDropdown').empty();
$('select#secondDropdown').append('<option value="0">Select Option</option>');
//Populate options of the second dropdown
$.each( data.subjects, function()
{
$('select#secondDropdown').append('<option value="'+$(this).attr('option_id')+'">'+$(this).attr('option_name')+'</option>');
});
$('select#secondDropdown').focus();
},
beforeSend: function()
{
$('select#secondDropdown').empty();
$('select#secondDropdown').append('<option value="0">Loading...</option>');
},
error: function()
{
$('select#secondDropdown').attr('disabled', true);
$('select#secondDropdown').empty();
$('select#secondDropdown').append('<option value="0">No Options</option>');
}
});
}
</script>
And finally the query to fetch 2nd dropdown's options in the AJAX processor file fetchOptions.php. You can use $_POST['id_option'] here to fetch the options under it. The database query here should fetch the option_id and option_name fields for every option (as expected by the jquery code inside $.each) and return a json encoded array like this:-
return json_encode(array("subjects" => $resultOfQuery));
Second Method (Using only javascript)
Fetch all the data for the second dropdown grouped by the field of the first dropdown. E.g. let's take courses displayed in the first dropdown and subjects under courses displayed in the 2nd
Create all the options of the 2nd dropdown. Assign classes equal to the courses while creating the options like this:-
$querycourse = "SELECT course, subject FROM subjects WHERE subject IS NOT NULL GROUP BY course ";
$procc = mysqli_prepare($link, $querycourse);
$queryc = mysqli_query($link, $querycourse) or die(mysqli_error($link));
echo "<select name='subjects[]' value='' multiple='multiple' size=100>";
echo "<option value=''>All</option>";
while($ntc=mysqli_fetch_array($queryc))
{//Array or records stored in $nt
echo "<option value=\"$ntc[subject]\" class=\"$ntc[course]\">\"$ntc[subject]\"</option>";
}
echo "</select>";
Then define onchange="displaySubjectsUnderThisCourse(this);" for the first dropdown and write this javascript :-
function displaySubjectsUnderThisCourse(object)
{
var selectedCourse = $(object).val();
//Display the options with class = the selected option from first dropdown
$("."+selectedCourse).removeClass("hidden"); //define a class hidden with display:none;
$('option:not(.selectedCourse)').hide(); // hide all options whose class is other than selectedCourse - Not sure whether this will work or not, though
//Deselect any previous selections
//If single option selection is allowed
$('select#secondDropdown option').attr('selected', false);
// or following if multiple selection is allowed (needed for IE)
$('select#secondDropdown option').attr('selectedIndex', -1);
}
The basic idea here is to hide/display option groups but my code may have errors.
Finally, please note, the second method (fetching all the option values) would be better only if you have limited small amount of data and are very sure there will always be less data in future. But, since nobody can be so certain about the future, it is advisable to use the AJAX method always.
There are two methods:
First, you can load all choices for
the second select list into a
JavaScript array. When an option is
selected in the first select,
populate the second with the
appropriate options.
Second, you can use Ajax to make a
call to the server and fetch the
options for the second select based
on the choice of the first. The
server would then return a list of
options (one per line, tab delimited
is how I do it) that you parse and
use to populate the second select.
The first option is very fast and easy, but may take a while to load if you have a large list of options for the second select.
The second option is more complicated, but much more flexible.
Here's some Ajax code to get you started:
Create a request:
var HTTP_UNINITIALIZED = 0;
var HTTP_SETUP_NOTSENT = 1;
var HTTP_PROCESSING = 2;
var HTTP_PARTIAL_RESULT = 3;
var HTTP_COMPLETE = 4;
function createRequest()
{
var request = null;
try
{
request = new XMLHttpRequest();
}
catch( failed_once )
{
try
{
request = new ActiveXObject( "Msxml2.XMLHTTP" );
}
catch( failed_twice )
{
try
{
request = new ActiveXObject( "Microsoft.XMLHTTP" );
}
catch( failed_thrice )
{
request = null;
}
}
}
return( request );
}
Send the request:
var request = createRequest();
function doSearch( value )
{
getURL = "<url to get list>?Value=" + value;
request.open( "POST", getURL, true );
request.onreadystatechange = showResults;
request.send( null );
}
Use the results:
function showResults()
{
if( request.readyState == HTTP_COMPLETE && request.status == 200 )
{
if( request.responseText != "" )
{
var lines = request.responseText.split( "\n" );
for( i = 0 ; i < lines.length ; i++ )
{
var parts = lines[i].split( "\t" );
// populate the second select
}
}
}
}
How you handle the server side portion is up to you.