how would you convert a date stored as
2011-01-18 11:51:41
into
18-01-2011 11:51:41
using PHP?
many thanks in advance!
date('d-m-Y H:i:s', strtotime('2011-01-18 11:51:41'));
More reliable than using strtotime(), assuming you're on PHP 5.3+
$oldtime = date_parse_from_format('Y-m-d h:i:s', '2011-01-18 11:51:41');
$newtime = date('d-m-Y h:i:s', $time);
However, the date format you're converting FROM suggests it's coming from a MySQL datetime field, in which case you could also do:
SELECT DATE_FORMAT(yourfield, '%d-%m-%Y %H:%i:%s')
and save yourself a full roundtrip in PHP.
Convert the old date to UNIX time with strtotime(), then output it in the new format with date()
$olddate = "2011-01-18 11:51:41";
$newdate = date('d-m-Y H:i:s', strtotime($olddate));
echo $newdate;
// 18-01-2011 11:51:41
$your_date = "2011-01-18 11:51:41";
echo date('d-m-Y H:i:s', strtotime($your_date));
demo
Related
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";
Im trying to add a certain amount of days to a timestmp using this in PHP:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo $endDate2;
but its displaying: 1216526400
any ideas?
Try:
echo date("Y-m-d H:i:s",$endDate2);
Or (for just the date):
echo date("Y-m-d",$endDate2);
You can find documentation about how to format your string here: http://php.net/manual/en/function.date.php
You should be using DateTime for working with dates. It's timezone friendly.
$datetime = new DateTime('2008-06-20');
$datetime->modify('+1 day');
echo $datetime->getTimestamp();
strtotime() converts the date into a unix timestamp which is the number of seconds since January 1st 1970. If you want a date output you have to run the finished timestamp through date() first.
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate.' +1 day');
echo date("Y-m-d", $endDate);
strtotime creates a Unix timestamp so if you want to be presented with a formatted date, you need to pass the timestamp as an argument to the date function as follows:
$capturedDate = '2008-06-20';
$endDate = strtotime($capturedDate);
$endDate2 = strtotime('+1 day',$endDate);
echo date('Y-m-d', $endDate2);
Additionally, there are a wide variety of parameters you can use in the date function if you want to display additional information.
e.g.: echo date('Y-m-d H:i:s', $endDate2); or echo date('Y-m-d h:i:s a', $endDate2);, etc.
Sooooo close, just take your timestamp and convert it back into date format using date("desired format",$endDate2);
DateTime is a very nice way to deal with dates. You can try like this:
$capturedDate = '2008-06-20';
$date = DateTime::createFromFormat('Y-m-d', $capturedDate)->modify('+1 day');
echo $date->getTimestamp();
I have a forum in PHP which takes a date like in the form
dd/mm/yyyy hh:mm:ss. However, I need to insert it for SQL as a DATETIME in the format as yyyy-mm-dd hh:mm:ss. How can I convert this data?
Your date time format is wrong: dd/mm/yyyy hh:mm:ss. Probably you mean d/m/Y H:i:s
If you have 5.3+ version there is safe way to convert the date time into another format. Here's an example:
$timestamp = '31/05/2001 12:22:56';
$timestamp = DateTime::createFromFormat('d/m/Y H:i:s', $timestamp);
echo $timestamp->format('Y-m-d H:i:s');
or if you like more procedural way:
$timestamp = '31/05/2001 12:22:56';
$timestamp = date_create_from_format('d/m/Y H:i:s', $timestamp);
echo date_format($timestamp, 'Y-m-d H:i:s');
Be careful with previous suggestions. Some are completely wrong and others could lead to errors.
You can use the strtotime and date to rework the format.
$new_date = date( "Y-m-d H:i:s", strtotime( $old_date ) );
What this does is take your old date (dd/mm/yyyy hh:mm:ss), converts it to a unix timestamp that can then be used with the php date function to format the date to the desired format.
Two of several possible ways:
Convert in code and then pass the converted value to mysql: $mysqldate = date( 'Y-m-d H:i:s', $phpdate );
Let mysql do the work by using its built-in functions:
$query = "UPDATE table SET datetimefield = FROM_UNIXTIME($phpdate) ...";
if you have datetime avaialable from a from like above format then u just need to use following function.
function localToMysql($dateTime){
$date_chunks = explode('/', $dateTime);
$time_chunks = explode(' ', $date_chunks[2]);
$final_format = $time_chunks[0] . "-" . $date_chunks[1] . "-" . $date_chunks[0] . " " . $time_chunks[1];
return $final_format;
}
Ho do I convert:
2010-12-24 11:39:43
to:
24/12 11:39
Thanks.
This should to the trick:
$newFormat = Date ( 'd/m H:i', StrToTime ( '2010-12-24 11:39:43' ) );
You use StrToTime to convert a string representation of a date to timestamp. You then feed that timestamp to the Date function that takes the format of the date as the first parameter.
Try:
$unixtime = strtotime("2010-12-24 11:39:43");
$newFormat = date("d/m H:i", $unixtime);
echo date("d/m H:i", strtotime("2010-12-24 11:39:43"));
$date = DateTime::createFromFormat('Y-m-d G:i:s', 2010-12-24 11:39:43); //You can simply tell DateTime accept your timestamp as is since PHP 5.3
echo $date->format('d/m G:i T'); //Will output what you wanted + Timezone Abbreviation (because of the T)
I have a datetime column in MySQL.
How can I convert it to the display as mm/dd/yy H:M (AM/PM) using PHP?
If you're looking for a way to normalize a date into MySQL format, use the following
$phpdate = strtotime( $mysqldate );
$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
The line $phpdate = strtotime( $mysqldate ) accepts a string and performs a series of heuristics to turn that string into a unix timestamp.
The line $mysqldate = date( 'Y-m-d H:i:s', $phpdate ) uses that timestamp and PHP's date function to turn that timestamp back into MySQL's standard date format.
(Editor Note: This answer is here because of an original question with confusing wording, and the general Google usefulness this answer provided even if it didnt' directly answer the question that now exists)
To convert a date retrieved from MySQL into the format requested (mm/dd/yy H:M (AM/PM)):
// $datetime is something like: 2014-01-31 13:05:59
$time = strtotime($datetimeFromMysql);
$myFormatForView = date("m/d/y g:i A", $time);
// $myFormatForView is something like: 01/31/14 1:05 PM
Refer to the PHP date formatting options to adjust the format.
If you are using PHP 5, you can also try
$oDate = new DateTime($row->createdate);
$sDate = $oDate->format("Y-m-d H:i:s");
$valid_date = date( 'm/d/y g:i A', strtotime($date));
Reference: http://php.net/manual/en/function.date.php
Finally the right solution for PHP 5.3 and above:
(added optional Timezone to the Example like mentioned in the comments)
without time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date);
echo $date->format('m/d/y h:i a');
with time zone:
$date = \DateTime::createFromFormat('Y-m-d H:i:s', $mysql_source_date, new \DateTimeZone('UTC'));
$date->setTimezone(new \DateTimeZone('Europe/Berlin'));
echo $date->format('m/d/y h:i a');
An easier way would be to format the date directly in the MySQL query, instead of PHP. See the MySQL manual entry for DATE_FORMAT.
If you'd rather do it in PHP, then you need the date function, but you'll have to convert your database value into a timestamp first.
Forget all. Just use:
$date = date("Y-m-d H:i:s",strtotime(str_replace('/','-',$date)))
To correctly format a DateTime object in PHP for storing in MySQL use the standardised format that MySQL uses, which is ISO 8601.
PHP has had this format stored as a constant since version 5.1.1, and I highly recommend using it rather than manually typing the string each time.
$dtNow = new DateTime();
$mysqlDateTime = $dtNow->format(DateTime::ISO8601);
This, and a list of other PHP DateTime constants are available at http://php.net/manual/en/class.datetime.php#datetime.constants.types
This should format a field in an SQL query:
SELECT DATE_FORMAT( `fieldname` , '%d-%m-%Y' ) FROM tablename
Use the date function:
<?php
echo date("m/d/y g:i (A)", $DB_Date_Field);
?>
Depending on your MySQL datetime configuration. Typically: 2011-12-31 07:55:13 format. This very simple function should do the magic:
function datetime()
{
return date( 'Y-m-d H:i:s', time());
}
echo datetime(); // display example: 2011-12-31 07:55:13
Or a bit more advance to match the question.
function datetime($date_string = false)
{
if (!$date_string)
{
$date_string = time();
}
return date("Y-m-d H:i:s", strtotime($date_string));
}
SELECT
DATE_FORMAT(demo.dateFrom, '%e.%M.%Y') as dateFrom,
DATE_FORMAT(demo.dateUntil, '%e.%M.%Y') as dateUntil
FROM demo
If you dont want to change every function in your PHP code, to show the expected date format, change it at the source - your database.
It is important to name the rows with the as operator as in the example above (as dateFrom, as dateUntil). The names you write there are the names, the rows will be called in your result.
The output of this example will be
[Day of the month, numeric (0..31)].[Month name (January..December)].[Year, numeric, four digits]
Example: 5.August.2015
Change the dots with the separator of choice and check the DATE_FORMAT(date,format) function for more date formats.
You can also have your query return the time as a Unix timestamp. That would get rid of the need to call strtotime() and make things a bit less intensive on the PHP side...
select UNIX_TIMESTAMP(timsstamp) as unixtime from the_table where id = 1234;
Then in PHP just use the date() function to format it whichever way you'd like.
<?php
echo date('l jS \of F Y h:i:s A', $row->unixtime);
?>
or
<?php
echo date('F j, Y, g:i a', $row->unixtime);
?>
I like this approach as opposed to using MySQL's DATE_FORMAT function, because it allows you to reuse the same query to grab the data and allows you to alter the formatting in PHP.
It's annoying to have two different queries just to change the way the date looks in the UI.
You can have trouble with dates not returned in Unix Timestamp, so this works for me...
return date("F j, Y g:i a", strtotime(substr($datestring, 0, 15)))
This will work...
echo date('m/d/y H:i (A)',strtotime($data_from_mysql));
Using PHP version 4.4.9 & MySQL 5.0, this worked for me:
$oDate = strtotime($row['PubDate']);
$sDate = date("m/d/y",$oDate);
echo $sDate
PubDate is the column in MySQL.
Direct output e.g. in German format:
echo(date('d.m.Y H:i:s', strtotime($row["date_added"])));
$date = "'".date('Y-m-d H:i:s', strtotime(str_replace('-', '/', $_POST['date'])))."'";