Fetch a single row of data from mysqli prepared statement [duplicate] - php

This question already has answers here:
Single result from database using mysqli
(6 answers)
Closed 2 years ago.
I have the following code and where if 1 row is found I would like to set the result to $aPrds, how can I do this?
$stmt = $db->prepare("select * from products where id=?");
$stmt->bind_param("s", $_GET['id']);
if($stmt->execute())
{
$stmt->store_result();
echo $stmt->num_rows;
if($stmt->num_rows==1)
{
//SET RETURNED ROW TO aPrds
}
else
{
echo "no results or too many found";
}
}
else
{
echo "sql invalid";
}
I have also tried the following code which has been unsuccessful (returns (null):
$stmt = $db->prepare("select productid, product_name, description from product where productid=?");
$a=1;
$stmt->bind_param("i", $a);
if($stmt->execute()){
$stmt->store_result();
if($stmt->num_rows==1){
$stmt->bind_result($b, $c, $d);
print_r($b);
print_r($c);
print_r($aPrds);
}else{
echo "no result or more than 1 returned";
}
}else{
echo "invalid sql";
}
Please note that I have tested the SQL and it works, also the $db mysqli connection is definitely working.

I think you are looking for the get_result and fetch_assoc methods:
// ....
$result = $stmt->get_result();
$aPrds = $result->fetch_assoc();
// ....
Edit:
Apparently these functions are not yet available (should have tested this, sorry). So this is tested:
function bind_array($stmt, &$row) {
$md = $stmt->result_metadata();
$params = array();
while($field = $md->fetch_field()) {
$params[] = &$row[$field->name];
}
call_user_func_array(array($stmt, 'bind_result'), $params);
}
// ....
if($stmt->execute()) {
bind_array($stmt, $row);
$stmt->fetch();
print_r($row);
// ....
And you second solution should also work if you added $stmt->fetch() after $stmt->bind_result($b, $c, $d);

Related

How can I collect result from prepare statement PHP? [duplicate]

This question already has an answer here:
What to do with mysqli problems? Errors like mysqli_fetch_array(): Argument #1 must be of type mysqli_result and such
(1 answer)
Closed 2 years ago.
I can't collect the results of my query in this function :
<?php
function getBestScore()
{
require_once ('connection.php');
$idJoueur = session_id();
if ($stmt = $conn->prepare('SELECT bestScore FROM Player WHERE ID = ?'))
{
$stmt->bind_param('i', $idJoueur);
$stmt->execute();
$result = $stmt->get_result();
$data = $result->fetch_assoc();
$bestScore = $data;
if (!(empty($bestScore)))
{
header("Location: ../index.php");
}
return $bestScore;
}
else
{
$error = $conn->errno . ' ' . $conn->error;
echo $error;
}
}
My connection works, I tried fetch_assoc(), store_result() but I failed every time.
If you want to select data then try the following
if ($stmt = $conn->prepare('SELECT bestScore FROM Player WHERE ID = ?')) {
$stmt->bind_param('i',$idJoueur);
$stmt->execute();
/* bind result variables */
$stmt->bind_result($result);
/* fetch value */
$stmt->fetch();
if (!(empty($result))) {
header("Location: ../index.php");
}
return $result;
}
Hope this helps.

mysqli prepared statement while fetch doesn't work

This method is part of a larger class, and am trying to get it to return an array of objects containing the same classes. However, it doesn't seem to be entering the while loop, and I can't figure out why. Any suggestions?
The expected result would be an array of objects containing this data http://sqlfiddle.com/#!9/b6e23/1.
public static function getAllFacts($groupID)
{
$factTable = array();
$conn = new mysqli($GLOBALS['hostName'], $GLOBALS['userName'], $GLOBALS['password'], $GLOBALS['database']);
if ($conn->connect_error)
{
echo "Database connection error (source table)<br>";
}
$query = "SELECT factID, sourceID, factTXT, citationID, noteGroupID, factCreated, factsGroupID FROM facts WHERE factsGroupID = ?";
$stmt = $conn->prepare($query);
if ($stmt)
{
$stmt->bind_param("i", $groupID);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result(
$factID,
$sourceID,
$factTXT,
$citaitionID,
$noteGroupID,
$factCreated,
$factsGroupID
);
$row = 0;
while ($stmt->fetch())
{
$numRows = $stmt->num_rows;
echo "numRows: " . $numRows . "<br>";
$factTable[$row] = new self($factID, $sourceID, $factTxt, $citationTxt, $noteGroupID, $factCreated, $factsGroupID, $numRows);
$row++;
}
$stmt->close();
}
else
{
echo "Statement failed. (source table) <br>";
}
return $factTable;
}

mysqli: PHP Fatal error: Call to a member function fetch_array()

I am having some trouble with prepared statements. Basically, this query is returning no rows, even though I know for a fact that this query should return multiple rows. I thought this was just a problem due to SQL injections, but maybe I'm doing something else wrong here, I don't know. If I take out the check for how many rows there are, I get an error:
PHP Fatal error: Call to a member function fetch_array()
Any help would be appreciated!
$stmt = $mysqli->prepare("SELECT sid from SDS WHERE uid=? AND dst=?");
$stmt->bind_param('ss',$username,$structureType);
$stmt->execute();
$stmt->bind_result($results);
$stmt->fetch();
if ($results) {
if($results->num_rows == 0) {
print("No results here.");
return 0;
}
$recordnames = array();
while ($next_row = $results->fetch_array()) {
$recordnames[] = $next_row['sid'];
}
return $recordnames;
}
When you use $stmt->bind_result($result); you are binding the sid from the database to the variable $results. So you cannot perform operations like :
if($results->num_rows == 0) { //... }
or
$results->fetch_array();
This is how I would do it :
<?php
$stmt = $mysqli->prepare("SELECT sid from SDS WHERE uid=? AND dst=?");
$stmt->bind_param('ss', $username, $structureType);
$stmt->execute();
$stmt->bind_result($sid);
$stmt->store_result();
if ($stmt->num_rows == 0)
{
print("No results here.");
$stmt->close();
return 0;
}
else
{
$recordnames = array();
while($stmt->fetch())
{
$recordnames[] = $sid;
}
return $recordnames;
}
?>
This way uses a different logic, check if the row count is 0, if so display "No results here", if not put results into the array.

$stmt-num_rows ( Return 0 ) [duplicate]

This question already has an answer here:
$stmt->num_rows returning 0 even after calling store_result
(1 answer)
Closed 9 years ago.
i am just trying to learn prepared statement and i am following the PHP manual to guide me through, i have checked the answers regarding this problem on stackoverflow but, i can't find any solutions, the $stmt->num_rows always ( Return 0 )
there is a post on stackoverflow discussed the problem and they advised to use
$stmt->store_result() just before the $stmt-num_rows, but the $stmt->num_rows return 0
some one please can tell me what i am doing wrong here.... i am just sick of the procedural style coding and i want to enhance my skills with prepared statement
here is the function down below
function get_all()
{
// ** Initializing the Connection
$mysqli = Connect();
$sql = ( ' SELECT * FROM `users` ' );
$stmt = $mysqli->prepare($sql);
$stmt->execute();
$res = $stmt->get_result();
echo $num_count = $stmt->num_rows();
$user = array();
for ($counter = 0; $row = $res->fetch_assoc(); $counter++)
{
$user[$counter] = $row;
}
return $user;
}
// This is the second update
function get_all()
{
// ** Initializing the Connection
$mysqli = Connect();
$sql = ( ' SELECT * FROM `users` ' );
$stmt = $mysqli->prepare($sql);
$stmt->execute();
$res = $stmt->get_result();
echo $num_count = $stmt->num_rows;
$user = array();
while($row = $res->fetch_assoc())
{
$user[] = $row;
}
return $user;
}
// third update
function get_alll()
{
// ** Initializing the Connection
$mysqli = Connect();
// no need to use * character,
// need to write query this way
$sql = ( ' SELECT `id`,`fname`,`lname`,`uname`,`email` FROM `users` ' );
$stmt = $mysqli->prepare($sql);
// here need to use bind param
$stmt->bind_result( $id, $fname, $lname, $uname, $email);
$stmt->execute();
// it's important to store the result
// before using num rows
$res = $stmt->store_result();
echo $num_count = $stmt->num_rows;
//
while($stmt->fetch())
{
echo $fname;
}
}
num_rows is a property, not a method, try with $stmt->num_rows without brackets

Return mysqli query result as an array in PHP

I've been searching the internet for a while now, but since I'm new to MySQLi, I cannot solve this problem myself. This is my code so far. I want to return the result as an array.
function myFunction($u_id, $mysqli){
$userinfo = "SELECT email, name, street, placename FROM users WHERE u_id = ? LIMIT 1";
if($stmt = $mysqli->prepare($userinfo)) {
$stmt->bind_param('i', $u_id);
$stmt->execute();
if(!$stmt->execute()) {
echo $stmt->error.' in query: '.$userinfo;
} else {
//this is what i found somewhere on the internet, and it gives me an array with the right keys but empty values.
$meta = $stmt->result_metadata();
while ($field = $meta->fetch_field()) {
$var = $field->name;
$$var = null;
$parameters[$var] = &$$var;
}
return $parameters;
}
$stmt->close();
}}
Hopefully someone can help me get this code working, or help me find an alternative.
Have you looked at using fetch_array
http://php.net/manual/en/mysqli-result.fetch-array.php
Working from your code
function myFunction($u_id, $mysqli){
$userinfo = "SELECT email, name, street, placename FROM users WHERE u_id = ? LIMIT 1";
if($stmt = $mysqli->prepare($userinfo))
{
$stmt->bind_param('i', $u_id);
$stmt->execute();
if(!$stmt->execute())
{
echo $stmt->error.' in query: '.$userinfo;
}
else {
//this is what i found somewhere on the internet, and it gives me an array with the right keys but empty values.
$parameters = array();
while ($row = $stmt->fetch_assoc()) {
$parameters[] = $row;
}
$stmt->close();
return $parameters;
}
$stmt->close();
}
}

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