mysql: works ok in console, in php will not access data - php

connecting either as root or regular user, everything works fine from mysql console
on php, connects fine, set schema fine, but will not pull data from schema.
// connect and set schema
$_db = mysql_connect( '127.0.0.1', 'root', '*******' );
mysql_select_db( 'suangao' );
echo "schema = ".db_get_col("select database()");
// => schema = suangao
// non-table query
$result = mysql_query( "select 1" );
echo "rows 1 = ".mysql_num_rows($result);
// => rows 1 = 1
// simplest table query
$result = mysql_query( "select 1 from users" );
echo "rows 2 = ".mysql_num_rows($result);
// => rows 2 = 0
php does not even see users table, but in mysql created, inserted, etc
have same setup working fine on different machine, but cannot get this to fly
mea culpa! indeed the table users was empty! I had mistakenly believed that select 1 from table would always return 1 if the table existed - evidently I was incorrect!

As far as I know a mysql user has privileges depending on his host mask.
I don't know which host is used if you connect via mysql console and don't add a host while connecting. But it seems to be a different one than your script uses and so your permissions are insufficient.
Try changing 127.0.0.1 in your connection script into localhost. Although this is meant to be the same it isn't the same in detail. Then the connected user should have another host mask and hopefully the same for which you have granted the needed permissions.
Finally you could check the privileges by connection via console with root account and looking into the table user_privileges. The entries there should speak for themselves.

Related

mssql_connect will not connect different DB on same SQL Server

$conn_161 = "192.168.0.161"; //local serwer adress
$user_161 = "ME";
$pass_161 = "what_is_the_password?";
$connect_161 = mssql_connect($conn_161,$user_161,$pass_161);
mssql_select_db ( 'DUKENUKEN3D' , $connect_161 );
//as requested - 1st DB connection and 1st query
$q_duke = "select * from DUKE /*DB1*/";
$r_duke = mssql_query($q_wartownik,$connect_161); //result
$connect_different_db = mssql_connect($conn_161,$user_161,$pass_161);
mssql_select_db ( 'BIGMAN' , $connect_different_db );
//second db and query
$q_bigman = "select * from BIGPEOPLE /*DB2*/";
$r_bigman = mssql_query($q_bigman,$connect_different_db ); //result
Error:
Warning: mssql_query() [function.mssql-query]: message: Invalid object name 'DUKE'.
Yes I know mssql_select_db is old, but I need to use it in this project. As you see I try to connect to same server but select 2 different DB at the same time, and run queries in the same php page (to connect data from 2 different DB). It seems it is not valiable? I even tried to run mssql_select_db just before doing the query to second DB, and then changing it back to first DB.
I understand this is limitation of the library (I will run all queries from LAST selected DB).
Is there a workaroud? Because all I got is to create page inside invisible iframe and there run php page with different db connection - far from good solution.
I would expect that this will work the same as it would if you were running this in a SQL environment directly (e.g. you can try it in SSMS or from the command line).
You can specify the database name when you reference the table in the query: e.g.
select * from db1.dbo.DUKE
This is standard SQL Server behaviour whenever you want to refer to an object which is outside the context of the current database.

One website - multiple database

We have multiple masters that are synced into a slave. We have decided to create a database for each master (let say MDB0001; MDB0002; MDB0003, etc...). This will allow to not corrupt the entire database if one replication fails or has corrupted data... The slave is used to show information to the people that are on the web (the master is only available in the local network)
The purpose is: we want to have a website (in php) on the server (slave) that shows the content for each database depending who is logged in. So if the user MDB0001 is connected, we have to read the data from the database MDB0001.
How can this be done? Is it a good way to do that? Or, do I have to duplicate the website for each database?
I hope I'm clear in my explanation. Thanks
assuming you get a variable from the login you could put a key->value array together on your db.php page;
$userDBs = array('login1'=>'db1','login2'=>'db2');
$dbName = $userDBs[$loggedinID]; // if login1 logs in, db1 would be result.
$db = new PDO('mysql:host=localhost;dbname='.$dbName, 'someUser', 'somePass');
or have a seperate db for the associations:
$sel = "Select dbName from databases where userId='".$loggedInID."'";
$stmt = $db->query($sel);
while($r = $stmt->fetch()){
$dbName = $r['dbName'];
}
$db = new PDO('mysql:host=localhost;dbname='.$dbName, 'someUser', 'somePass');

Send database table from one server to another database table in different server PHP MySQL

I am trying to send database table from one server to another database table in different server. Here is the PHP code I have tried so far, but to no avail:
<?php
$dblink1=mysql_connect('server', 'user', 'pass'); // connect server 1
mysql_select_db('db1_name',$dblink1); // select database 1
$dblink1=mysql_connect('server', 'user', 'pass'); // connect server 2
mysql_select_db('db2_name',$dblink2); // select database 2
$table='output_table';#not sure if this is correct
$tableinfo = mysql_fetch_array(mysql_query("SHOW CREATE TABLE first_table ",$dblink1)); // get structure from table on server 1
echo $tableinfo;
mysql_query(" $tableinfo[1] ",$dblink2); // use found structure to make table on server 2
$result = mysql_query("SELECT * FROM first_table ",$dblink1); // select all content
while ($row = mysql_fetch_array($result, MYSQL_ASSOC) ) {
mysql_query("INSERT INTO output_table (".implode(", ",array_keys($row)).") VALUES ('".implode("', '",array_values($row))."')",$dblink2); // insert one row into new table
}
mysql_close($dblink1);
mysql_close($dblink2);
echo "complete";
?>
I have tried the output_table with and without the same column names/amount as first_table, but it does not seem to be working.
Again, any help would be appreciated.
The problem might be that $dblink2 is undefined.
$dblink2=mysql_connect('server', 'user', 'pass'); // connect server 2
mysql_select_db('db2_name',$dblink2); // select database 2
Also consider using pdo methods instead because mysql- methods are now less favored to the PDO way of working with database objects.
This is most likely a firewall issue. Most 3rd party hosts don't allow you to access MySQL from 'the outside'.
You can do this if you manage the MySQL server yourself or if you have a host that doesn't deny you to access the database from another machine, but in regular web hosting, this is not common.
o to your phpMyAdmin installation and look for the file config.inc.php. Open that file, and check which hostname / ip is being used

php connect to mysql db in cloud 9?

I usually connect php to mysql with localhost in my PC..
now i'm trying to put my project in cloud https://c9.io ,but i can't connect to mysql. i already have mysql database in cloud and put my project in same place...
mysql_connect("/lib/mysql/socket/mysql.sock","myUser","") or die(mysql_error());
i use script above to connect but i get Unknown MySQL server host '/lib/mysql/socket/mysql.sock' (1)
what shoul i do ?
Okay, so none of the above answers had worked for me, but fortunately I was able to setup a database and get it up and running my own way and I can now make queries and run them successfully, so I will share my method with you in hopes that anyone else scouring the internet can stumble across this and not have to go through the same head scratching that I did.
If you want the quick rundown, just scroll to Step 3 and read on from there. If you're a complete beginner, keep reading as I'll walk you through it in detail.
Couple things to mention:
You will have to setup a database via a Terminal in Cloud 9. I had no experience prior doing it in a Terminal before, but it's very simple to learn.
You can not use mysql functions, you have to use mysqli, since mysql functions are deprecated and Cloud 9 will not run them.
Step 1: Setup MySQL on Cloud 9 (in Terminal)
In your project, open up a New Terminal (click the plus-sign tab above the text editor space, select "New Terminal"). In the terminal, type mysql-ctl start and hit Enter. MySQL will start up in the back, but you won't get any response back in the terminal.
Next, type mysql-ctl cli and hit Enter. You should see some text that starts off as Welcome to the MySQL monitor.... Congrats, you've setup MySQL on your Cloud 9 project.
Step 2: Create a test database (in Terminal)
You can actually go ahead and create your official database if you like, but for this sake I'll just make a database that holds a table that holds an ID and a username. So here's the steps to setting up a database and a table. If you've used MySQL and databases before, then this should be cake, but I'll explain it in detail for those who might not fully understand MySQL .
Type SHOW DATABASES; and hit Enter. This will show a list of current databases within your project. You can enter this any time you want to see a list of your databases on the current project.
Type in CREATE DATABASE sample_db; and hit Enter. You should get a Query OK, 1 Row affected. which means the query was successful. You can name the database whatever you like, but for this little walk-through, I named it sample_db.
Type in USE sample_db; and hit Enter. This selects sample_db from the list of databases.
Type in CREATE TABLE users (id INT(11), username VARCHAR(20));, and hit Enter. This creates a table named users with two columns: id and username. The number in parentheses represents the character limit the column will store in the database. In this case for example, username won't hold a string longer than 20 characters in length.
Type in INSERT INTO users (id, username) VALUES (1, "graham12");, and hit Enter. This will add the id of 1 and a username graham12 in the table. Since the id column is an INT, we do not put quotes around it.
Type in SELECT * FROM users;, and hit Enter. This will show everything that is in the users table. The only entry in there should be what we inserted from the last step we just did.
Step 3: Get the credentials you'll need to connect to the database from PHP. (in Terminal)
Now we have some data in our table that we can test our mysqli connection with. But first, we have to get the credentials we will need to connect to the database in PHP. In Cloud 9, we will need 5 credentials to connect:
Host name
Username
Password
Database name
Port #
Username, password, database name, and port #, are practically already known to you by now. I'll explain:
Host name - Type in SHOW VARIABLES WHERE Variable_name = 'hostname';, and hit Enter. You'll get a table that has 2 columns: Variable_name and Value. In the Value column you should see something like yourUsername-yourProjectName-XXXXXXX, where the X's are a 7 digit number. Write this number down or save it some where. This is your host name. (If you're getting the quick rundown on this walkthrough, just start a new terminal and start up your mysql and select the database you want to use, then type in SHOW VARIABLES WHERE Variable_name = 'hostname';. Re-read this step from the beginning if you're confused.)
Username - Your username that you use to log in to Cloud 9.
Password - There is NO password for your database in Cloud 9.
Database name - This would be sample_db or whatever you named your database;
Port # - is 3306. In Cloud 9, all of your projects are wired to 3306. This is a universal constant of Cloud 9. It will not be anything else. Write this as you would an integer, not as a string. mysqli_connect() will interpret the port # as a long data type.
Last Step: Connect to the database with PHP! (using PHP)
Open up a PHP file and name it whatever you like.
I'll pretend that my host name is graham12-sample_db-1234567 for this example and that this is what my data looks like:
Host name: "graham12-sample_db-1234567"
Username: "graham12"
Password: ""
Database name: "sample_db"
Port #: 3306
So in PHP, insert your credentials accordingly:
<?php
//Connect to the database
$host = "grahamsutt12-sample_db-1234567"; //See Step 3 about how to get host name
$user = "grahamsutt12"; //Your Cloud 9 username
$pass = ""; //Remember, there is NO password!
$db = "sample_db"; //Your database name you want to connect to
$port = 3306; //The port #. It is always 3306
$connection = mysqli_connect($host, $user, $pass, $db, $port)or die(mysql_error());
//And now to perform a simple query to make sure it's working
$query = "SELECT * FROM users";
$result = mysqli_query($connection, $query);
while ($row = mysqli_fetch_assoc($result)) {
echo "The ID is: " . $row['id'] . " and the Username is: " . $row['username'];
}
?>
If you get a result and no error then you have successfully setup a database and formed a connection to it with PHP in Cloud 9. You should now be able to make all the queries you can normally make.
Note: I demonstrated the last part without using parameterized queries for the sake of being simple. You should always use parameterized queries when working with real web applications. You can get more info on that here: MySQLi Prepared Statements.
For starters, the mysql_* functions are deprecated so you shouldn't be using them. Look at PDO or mysqli instead. Next, you'll want to try this per the example docs:
$link = mysql_connect('localhost:/lib/mysql/socket/mysql.sock', 'myUser', '') or die(mysql_error());
To find the ip running you project, create a test file with the code below, run it and put the result as host.
<?php
$ip = getenv("REMOTE_ADDR") ;
Echo "Your IP is " . $ip;
?>
You are using Cloud9 so it's a little different to use. To connect to MySQL you have to first create the MySQL server in C9. Type this in C9's command line:
mysql-ctl start
C9 will create your mysql server.
MySQL 5.1 database added. Please make note of these credentials:
Root User: <username>
Database Name: c9
Next to find your IP address type:
echo $IP
Now use this code with your username, the ip address, no password and the 'c9' database to access MySQL:
mysql_connect("<$IP>","<username>","") or die(mysql_error());
mysql_select_db("c9")
Hope this helps
The documentation show how start, stop, and run the mysql environment.
Start the MySQL shell mysql-ctl start then in yor file.php:
$ip = getenv("REMOTE_ADDR");
$port = "3306";
$user = "YorUsername";
$DB = "c9";
$conn = mysql_connect('$ip', '$user', '', '$db', '$port')or die(mysql_error());
mysql_select_db('$db','$conn')or die(mysql_error());
mysql_query("select * from YourTableName",'$conn')or die(mysql_error());
The line getenv("REMOTE_ADDR") return the same local IP as the application you run on Cloud9.

MySQL DB opimise through php

Another little bit which I am missing (as a beginner) I have a Backup script between two DB and as a final step I should optimise the real DB to reduce the size of the overhead. I have a code which works when I use only one DB but I need to use two:
$actconn = mysql_connect($dbhost, $actdbuser, $actdbpass) or die ('act Error connecting to mysql');
$bckconn = mysql_connect($dbhost, $bckdbuser, $bckdbpass) or die (' back Error connecting to mysql');
$ressql="SHOW TABLE STATUS FROM $actdbname WHERE Data_free / Data_length > 0.1 AND Data_free > 102400";
- this should tell that bckuser is ignored, I believe...
$res = mysql_query( $ressql, $actconn);
echo mysql_error();
while($optrow = mysql_fetch_assoc($res)) {
mysql_query('OPTIMIZE TABLE ' . $optrow['Name'], $actconn);
}
actconn value: Resource id #1
bckconn value: Resource id #2
mysql_error says:
SELECT command denied to user 'bckuser'#'localhost' for table 'actual table'
any idea what I do wrong?
UPDATE:
bckuser should not do anything with it as actdbuser is the root of that DB, but some reason SHOW TABLE won't recognise $actconn...
UPDATE2:
I tried just the opt again and the only thing is changed is the $actdbname='db-name'; when working and $actdbname='db-name' with the spec apostrophe;
please note this is on sharedhost so I can't change the DB name.
thanks #Corbin interesting idea, I tried and didn't work, but how could I debug it? I can't even debug it properly some reason...
You need to have a proper grant permissions to user 'bckuser'#'localhost' for executing SHOW TABLE STATUS query.
Unfortunately in MySQL 5.5 there is no separate grant option for this operation. Alternatively you can grant ALL to this user or use root user login for doing this operation.
see Grants Manual

Categories