How to split search results into pages? - php

Question

How to split the search results into pages? (like page 1, page 2, page 3...)
When the user searches for products on my e-commerce website, I want results to be split into several pages showing around 20 products per page. The search results are the outcome of database query.
For example: If the user searches for Samsung mobiles so my query will be:
SELECT * FROM PRODUCTS WHERE BRAND='SAMSUNG';
Suppose the above query returns 55 results, how to show them into pages (1,2 and 3)?
I am using PHP, MySQL, Apache on Windows machine.

Answer 1

The appropriate SQL would be adding:
LIMIT start, amount
You can navigate like
search.php?start=20
and then code like:
LIMIT $start, $amount
with
$start = intval($_GET['start']);
and
$amount = 20;
That will result in max 20 records a page.

Answer 2

Use SQL's LIMIT keyword to limit the amount of results from your query; for example:
SELECT * FROM PRODUCTS WHERE BRAND='SAMSUNG' LIMIT 20, 40;
This would select 20 elements, starting at the 40th

Answer 3

Here is the complete code:
<?php
// Requested page
$requested_page = isset($_GET['page']) ? intval($_GET['page']) : 1;
// Get the product count
$r = mysql_query("SELECT COUNT(*) FROM PRODUCTS WHERE BRAND='SAMSUNG'");
$d = mysql_fetch_row($r);
$product_count = $d[0];
$products_per_page = 20;
// 55 products => $page_count = 3
$page_count = ceil($product_count / $products_per_page);
// You can check if $requested_page is > to $page_count OR < 1,
// and redirect to the page one.
$first_product_shown = ($requested_page - 1) * $products_per_page;
// Ok, we write the page links
echo '<p>';
for($i=1; $i<=$page_count; $i++) {
if($i == $requested_page) {
echo $i;
} else {
echo ''.$i.' ';
}
}
echo '</p>';
// Then we retrieve the data for this requested page
$r = mysql_query("SELECT * FROM PRODUCTS WHERE BRAND='SAMSUNG' LIMIT $first_product_shown, $products_per_page");
while($d = mysql_fetch_assoc($r)) {
var_dump($d);
}
?>
Hope its help.

Answer 4

Yes you can run a query to get total record count and than use query using limit
exampe:
select count(id) from table_name
This will return total record count in database

Answer 5

In my php learning books, it provides a solution using a PHP class
it looks like this
<!-- language: php -->
<?php
error_reporting(0); // disable the annoying error report
class page_class
{
// Properties
var $current_page;
var $amount_of_data;
var $page_total;
var $row_per_page;
// Constructor
function page_class($rows_per_page)
{
$this->row_per_page = $rows_per_page;
$this->current_page = $_GET['page'];
if (empty($this->current_page))
$this->current_page = 1;
}
function specify_row_counts($amount)
{
$this->amount_of_data = $amount;
$this->page_total=
ceil($amount / $this->row_per_page);
}
function get_starting_record()
{
$starting_record = ($this->current_page - 1) *
$this->row_per_page;
return $starting_record;
}
function show_pages_link()
{
if ($this->page_total > 1)
{
print("<center><div class=\"notice\"><span class=\"note\">Halaman: ");
for ($hal = 1; $hal <= $this->page_total; $hal++)
{
if ($hal == $this->current_page)
echo "$hal | ";
else
{
$script_name = $_SERVER['PHP_SELF'];
echo "$hal |\n";
}
}
}
}
}
?>
then we call it on the script that require paging
<!-- language: php -->
<?php $per_page = 5;
$page = new Page_class($per_page);
error_reporting(0); // disable the annoying error report
$sql="SELECT * FROM table WHERE condition GROUP BY group";
$result=mysql_query($sql) or die('error'.mysql_error());
// paging start
$row_counts = mysql_num_rows($result);
$page->specify_row_counts($row_counts);
$starting_record = $page->get_starting_record();
$sql="SELECT * FROM table WHERE condition GROUP BY group LIMIT $starting_record, $per_page";
$result=mysql_query($sql) or die('error'.mysql_error());
$number = $starting_record; //numbering
$num_rows = mysql_num_rows($result);
if ($num_rows == 0 )
{ // if no result is found
echo "<div class=\"notice\">
<center><span class=note>NO DATA</span></center>
</div>";
}
else {
// while goes here ...
}
?>
// call the page link
<?php
$page->show_pages_link();
?>
hope it helps, just tried it hours ago to my search script page (learning from books)