Problem with a while loop - php

Question

My query does no return anything for my second index. It always sends me a message Notice: Undefined offset: 1. I tried doing with a for it is the same result, so I have read that my problem it is in the query, somebody told me let $stmt be null for freeing resources of my statement. I dont know what is wrong.
These are my methods. I dont know what to someone say use $database->setAttribute(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY,true);
Example: $arrayDirectory[] = {'user1', 'user2'};
It must echo 1 2 but just prints me 1
for($i=0;$i<sizeof($arrayDirectory;$i++){
$res[$i] = $obj->obtainID($arrayDirectory[$i]);
echo $res[$i];
}
This is my obtainID method:
public function obtainID($user){
$conexion = $this->objConexion->configuracion();
$query = "CALL sp_xxx('$user')";
$stmt = $conexion->prepare($query);
$stmt->execute();
$resultado = $stmt->fetchColumn();
return $resultado;
}
$stmi = null where?

Answer 1

For one,
$arrayDirectory[] = {'user1', 'user2'};
is a syntax error. { ... } does not work for arrays in PHP. Maybe it's just a typo and you're getting PHP confused with javascsript.
But the bigger issue is the []. That tells PHP to treat $arrayDirectory as an array (fine), but PUSH as a single value whatever you're assigning.
If your code was really:
$arrayDirectory[] = array('user1', 'user2');
This would create the following structure:
array(1) {
[0]=>
array(2) {
[0]=>
string(5) "user1"
[1]=>
string(5) "user2"
}
}
Note that it's a 2-level array. A top level single-element array at index [0]. That element at 0 contains ANOTHER array, which contains your two usernames.
You should have this instead:
$arrayDirectory = array('user1', 'user2');
$res = array();
foreach($arrayDirectory as $user) {
$res[] = $obj->obtainID($user);
}

Answer 2

first of all you are wrong with your function, you forgot to add the ending ')' for sizeof function,also arrays aren't defined with { } you should use array( ) instead.
and finally you are doing a bad practice over there;
you should not call a function in a loop (sizeof()), like this every time the loop goes through it will initiate sizeof() function and it will take some resource, since sizeof($object) won't change while using the loop, you should save it in a variable
$sizeofobject = sizeof($object);
and use that variable in your loop instead