How to amend my php function to add extra text? - php

Note that I used this with wordpress.
I added this function to functions.php:
function string_limit_words($string, $word_limit)
{
$words = explode(' ', $string, ($word_limit + 1));
if(count($words) > $word_limit)
array_pop($words);
return implode(' ', $words);
}
I added this to my html:
<?php if ( $woo_options['woo_post_content_home'] == "true" ) the_content(); else $excerpt = get_the_excerpt(); echo string_limit_words($excerpt,38); ?>
What this does is shortens the text to the number of words specified (in this sample its 38). What I want to do is add [...] after those 38 words. Any suggestions on how I can do this?
Regards,

Change it to
function string_limit_words($string, $word_limit)
{
$words = explode(' ', $string, ($word_limit + 1));
if(count($words) > $word_limit)
{
array_pop($words);
$words[] = '[...]';
}
return implode(' ', $words);
}

Uh...
function string_limit_words($string, $word_limit)
{
$words = explode(' ', $string, ($word_limit + 1));
if(count($words) > $word_limit)
array_pop($words);
return implode(' ', $words) . '...';
}

Just
echo string_limit_words($excerpt,38) . " ...";
should suffice.

You can modify the function like this so it will add the ellipses only when shorten the phrase.
function string_limit_words($string, $word_limit)
{
$ellipses = '';
$words = explode(' ', $string, ($word_limit + 1));
if(count($words) > $word_limit) {
array_pop($words);
$ellipses = ' ...';
}
$newString = implode(' ', $words) + $ellipses;
return $newString
}

Related

Extract Keywords from text php

I am trying to extract relative keywords from description input which use Wysiwyg, with multi language english/arabic… using the following function but its not doing the task I want. Have a look the function I am using:
function extractKeyWords($string) {
mb_internal_encoding('UTF-8');
$stopwords = array();
$string = preg_replace('/[\pP]/u', '', trim(preg_replace('/\s\s+/iu', '', mb_strtolower($string))));
$matchWords = array_filter(explode(' ',$string) , function ($item) use ($stopwords) { return !($item == '' || in_array($item, $stopwords)
|| mb_strlen($item) <= 2 || is_numeric($item));});
$wordCountArr = array_count_values($matchWords);
// <p><p>
arsort($wordCountArr);
return array_keys(array_slice($wordCountArr, 0, 10)); }
figured it out ! Thanks
function generateKeywords($str)
{
$min_word_length = 3;
$avoid = ['the','to','i','am','is','are','he','she','a','an','and','here','there','can','could','were','has','have','had','been','welcome','of','home',' ','“','words','into','this','there'];
$strip_arr = ["," ,"." ,";" ,":", "\"", "'", "“","”","(",")", "!","?"];
$str_clean = str_replace( $strip_arr, "", $str);
$str_arr = explode(' ', $str_clean);
$clean_arr = [];
foreach($str_arr as $word)
{
if(strlen($word) > $min_word_length)
{
$word = strtolower($word);
if(!in_array($word, $avoid)) {
$clean_arr[] = $word;
}
}
}
return implode(',', $clean_arr);
}
This one seems very nice and comprehensive https://www.beliefmedia.com.au/create-keywords
Just make sure to change this line
$string = preg_replace('/[^\p{L}0-9 ]/', ' ', $string);
to
$string = preg_replace('/[^\p{L}0-9 ]/u', ' ', $string);
To support other langages (e.g Arabic)
And also better to use mb_strlen
If the string is in html format you can add the
strip_tags($str);
Before
$min_word_length = 3;

PHP: How can I cut the word and add "..."

How can I cut the words and add "..." after reaching 4 or 5 words?
The code below states I did the character-based word cuttingb but I need it now to be by word.
Currently I have this kind of code:
if(strlen($post->post_title) > 35 )
{
$titlep = substr($post->post_title, 0, 35).'...';
}
else
{
$titlep = $post->post_title;
}
and this is the output of title:
if ( $params['show_title'] === 'true' ) {
$title = '<h3 class="wp-posts-carousel-title">';
$title.= '' . $titlep . '';
$title.= '</h3>';
}
Typically, I'll explode the body and pull out the first x characters.
$split = explode(' ', $string);
$new = array_slice ( $split, 0 ,5);
$newstring = implode( ' ', $new) . '...';
Just know, this method is slow.
Variant #1
function crop_str_word($text, $max_words = 50, $sep = ' ')
{
$words = split($sep, $text);
if ( count($words) > $max_words )
{
$text = join($sep, array_slice($words, 0, $max_words));
$text .=' ...';
}
return $text;
}
Variant #2
function crop_str_word($text, $max_words, $append = ' …')
{
$max_words = $max_words+1;
$words = explode(' ', $text, $max_words);
array_pop($words);
$text = implode(' ', $words) . $append;
return $text;
}
Variant #3
function crop_str_word($text, $max_words)
{
$words = explode(' ',$text);
if(count($words) > $max_words && $max_words > 0)
{
$text = implode(' ',array_slice($words, 0, $max_words)).'...';
}
return $text;
}
via
You should use str_replace function of PHP.
str_replace('your word', '...', $variable);
read that article: http://php.net/manual/en/function.str-replace.php
In WordPress this functionality is done by wp_trim_words() function.
<?php
if(strlen($post->post_title) > 35 )
{
$titlep = wp_trim_words( $post->post_title, 35, '...' );
}
else
{
$titlep = $post->post_title;
}
?>
If you do this functionality using PHP then write code as below:
<?php
$titlep = strlen($post->post_title) > 35 ? substr($post->post_title, 0, 35).'...' : $post->post_title;
?>

replacing word in string that has length of 40 or more

I have the following code:
$caption = $picture->getCaption();
$words = explode(" ", $caption);
foreach ($words as $word) {
$string_length = strlen($word);
if ($string_length > 40) {
str_replace($word, '', $caption);
$picture->setCaption($caption);
}
}
However, why doesn't this replace the caption with the trimmed word removed?
You need to do like this:
$caption = $picture->getCaption();
$words = explode(" ", $caption);
foreach ($words as $word)
{
$string_length = strlen($word);
if ($string_length > 40) {
$picture->setCaption(str_replace($word, '', $caption));
}
}
You need to assign the replacement made:
$caption = str_replace($word, '', $caption);
I think this is much better:
$caption = $picture->getCaption();
// explode them by spaces, filter it out
// get all elements thats just inside 40 char limit
// them put them back together again with implode
$caption = implode(' ', array_filter(explode(' ', $caption), function($piece){
return mb_strlen($piece) <= 40;
}));
$picture->setCaption($caption);
You have to do it like that :
$caption = $picture->getCaption();
$words = explode(" ", $caption);
foreach ($words as $word)
{
$string_length = strlen($word);
if ($string_length > 40) {
$replaced = str_replace($word, '', $caption);
$picture->setCaption($replaced);
}
}

PHP string find and replace until last instance

I have a string in a DB table which is separated by a comma i.e. this,is,the,first,sting
What I would like to do and don't know how is to have the string outputted like:
this, is, the, first and string
Note the spaces and the last comma is replaced by the word 'and'.
This can be your solution:
$str = 'this,is,the,first,string';
$str = str_replace(',', ', ', $str);
echo preg_replace('/(.*),/', '$1 and', $str);
First use, the function provided in this answer: PHP Replace last occurrence of a String in a String?
function str_lreplace($search, $replace, $subject)
{
$pos = strrpos($subject, $search);
if($pos === false)
{
return $subject;
}
else
{
return substr_replace($subject, $replace, $pos, strlen($search));
}
}
Then, you should perform a common str_replace on text to replace all other commas:
$string = str_lreplace(',', 'and ', $string);
str_replace(',',', ',$string);
$words = explode( ',', $string );
$output_string = '';
for( $x = 0; $x < count($words); x++ ){
if( $x == 0 ){
$output = $words[$x];
}else if( $x == (count($words) - 1) ){
$output .= ', and ' . $words[$x];
}else{
$output .= ', ' . $words[$x];
}
}

Php substr entire words

How can i substr 20 chars from $xbio and get only complete words?
$xbio = 'word1 ord2 word3 word4 and so on';
echo ''.substr($xbio, 0, 20).'...';
TY
Found this searching stackoverflow - tell me what do you think please:
<? $xbio = preg_replace('/\s+?(\S+)?$/', '', substr($xbio, 0, 50)); ?>
This is the function i always use:
# advanced substr
function gen_string($string,$min) {
$text = trim(strip_tags($string));
if(strlen($text)>$min) {
$blank = strpos($text,' ');
if($blank) {
# limit plus last word
$extra = strpos(substr($text,$min),' ');
$max = $min+$extra;
$r = substr($text,0,$max);
if(strlen($text)>=$max) $r=trim($r,'.').'...';
} else {
# if there are no spaces
$r = substr($text,0,$min).'...';
}
} else {
# if original length is lower than limit
$r = $text;
}
return $r;
}
preg_match('/^([a-zA-Z0-9 ]{1,20})\\b/', $xbio, $matches);
echo $matches[1];
This is a function that i use for this kind of task:
function truncate($str, $maxLength, $append = '...') {
if (strlen($str) > $maxLength) {
$str = substr($str, 0, $maxLength);
$str = preg_replace('/\s+.*?$/', '', $str); // this line is important for you
$str = trim($str);
$str .= $append:
}
return $str;
}

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