OK, this is an amateur question but I am having the most trouble displaying the values of my database. I want to display the entire 'phone' column so my mysql query is this:
$result = mysql_query('SELECT phone FROM contactList WHERE phone != 1') or die(mysql_error());
$row = mysql_fetch_array($result)
My PHP script is as this:
while(isset($rows))
{
echo $rows['phone'] . "html break tag";
}
It looks like though I'm only getting the first result instead of looping through the entire column.
Do I need to increment the ID in my loop and get value via ID? The only problem with that is my auto-incremental ID column starts # 130 and skips some numbers here and there.
try this instead
While($row = mysql_fetch_array($result))
echo $row['phone'];
That should help you looping through the whole array.
Related
I have echoed the first row value of a column with success. Now I was thinking if there is a way to echo the second and the third values separately .
Here is the working code
...
sql="SELECT `semester` FROM `$course`";
$retval=mysqli_query($link,$sql) ;
$row=mysqli_fetch_array($retval) ;
echo $row[0];
....
I tried to index the mysql array so that I can echo with indices but its not working.
Just want to echo the values separately for js manipulation
Guys I found the solution.
Just define a new variable and access the $result with
MYSQLI_FETCH_ROW which always returns the next row in the query. Thanks and all the best
If you want to access each row separately using an index you need to first fetch all rows into PHP array.
$sql = "SELECT `semester` FROM `table`";
$retval = $link->query($sql);
$rows = $retval->fetch_all(MYSQLI_BOTH);
echo $rows[0]['semester']; // value from first row
echo $rows[2]['semester']; // value from third row
$search = htmlspecialchars($_GET["s"]);
if(isset($_GET['s'])) {
// id index exists
$wordarray = explode(" ",$search);
$stringsearch = implode('%',$wordarray);
echo $stringsearch;
echo ",";
$result = mysqli_fetch_array($conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%';"));
if (!empty($result)) {
echo sizeof($result);
echo ",";
Database has 3 rows with titles test,pest,nest with corresponding id's 1,2,3. when i request domain.com/?s=est
it echos something like this
est,2,
Now when i checked $result[0] and $result[1], $result[0] echoed 1 and $result[1] didn't echo anything. When I use foreach function, it is taking only value of $result[0]
and $result should be array of all the three indexes.
I cannot find any mistake,
when i type the same command in sql console it works, somebody help me, thanks in advance.
The problem is, if you're expecting multiple rows, then don't do this:
$result = mysqli_fetch_array($conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%';"));
This only fetches the first row, you need to loop it to advance the next pointer and get the next following row set:
$result = $conn->query("SELECT ID FROM table WHERE title LIKE '%$stringsearch%' ");
while($row = $result->fetch_array()) {
echo $row[0] . '<br/>';
// or $row['ID'];
}
Sidenote: Consider using prepared statements instead, since mysqli already supports this.
Just wondering if anyone can help me with this problem...
I want to be able to check if a certain ID (user for example is logged on) The ID's of these users will be pulled from a table, and then fed into an array and then checked if it is in there.
However when I pull the data the if inarray() no longer works as it would if I just typed it in straight within the code instead of pulling it.
I want to pull approved ID's through so they can access a certain link essentially!
Any help would be appreciated! Thanks!
<?php
mssql_select_db("$ins", $con);
$result = mssql_query("SELECT ID FROM Event WHERE EventPublic LIKE 'Yes' AND EventDate >= GETDATE() -1 ORDER BY EventDate ASC ");
while($row = mssql_fetch_array($result))
{
$test = "". $row['ID'] .",";
}
$tests = explode(',', $test);
if (in_array("2, 48", $tests)) {
echo "WOO";
}
else
{
echo "BOO";
}
mssql_close($con);
?>
in array should be an actual array
in_array(array('2', '48'), $tests)
also, it would be better to put
$tests = array();
before the while loop, then change the code inside the loop to read
$tests[] = $row['ID'];
then you can do away with the '$tests = explode(...' line.
Your having the issue with your in_array test because you are comparing an array and with a string in the following line:
if (in_array("2, 48", $tests))
The above line checks if the string "2, 48" exist in the array. But the array will have 2 as one element and 48 as a separate element. To fix this you can search for each element individually with something like:
if(in_array('2',$tests) || in_array('48',$tests))
I'm probably missing something easy, but I seem to be blocked here... I have a MySQL database with two tables and each table has several rows. So the goal is to query the database and display the results in a table, so I start like so:
$query = "SELECT name, email, phone FROM users";
Then I have this PHP code:
$result = mysql_query($query);
Then, I use this to get array:
$row = mysql_fetch_array($result);
At this point, I thought I could simply loop through the $row array and display results in a table. I already have a function to do the looping and displaying of the table, but unfortunately the array seems to be incomplete before it even gets to the function.
To troubleshoot this I use this:
for ($i = 0; $i < count($row); $i++) {
echo $row[$i] . " ";
}
At this point, I only get the first row in the database, and there are 3 others that aren't displaying. Any assistance is much appreciated.
You need to use the following because if you call mysql_fetch_array outside of the loop, you're only returning an array of all the elements in the first row. By setting row to a new row returned by mysql_fetch_array each time the loop goes through, you will iterate through each row instead of whats actually inside the row.
while($row = mysql_fetch_array($result))
{
// This will loop through each row, now use your loop here
}
But the good way is to iterate through each row, as you have only three columns
while($row = mysql_fetch_assoc($result))
{
echo $row['name']." ";
echo $row['email']." ";
}
One common way to loop through results is something like this:
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
print_r($row);
// do stuff with $row
}
Check out the examples and comments on PHP.net. You can find everything you need to know there.
I have a small problem and since I am very new to all this stuff, I was not successful on googling it, because I dont know the exact definitions for what I am looking for.
I have got a very simple database and I am getting all rows by this:
while($row = mysql_fetch_array($result)){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
Now, my question is: how do I filter the 2nd result? I thought something like this could work, but it doesnt:
$name2= $row['name'][2];
Is it even possible? Or do I have to write another mysql query (something like SELECT .. WHERE id = "2") to get the name value in the second row?
What I am trying to is following:
-get all data from the database (with the "while loop"), but than individually display certain results on my page. For instance echo("name in second row") and echo("id of first row") and so on.
If you would rather work with a full set of results instead of looping through them only once, you can put the whole result set to an array:
$row = array();
while( $row[] = mysql_fetch_array( $result ) );
Now you can access individual records using the first index, for example the name field of the second row is in $row[ 2 ][ 'name' ].
$result = mysql_query("SELECT * FROM ... WHERE 1=1");
while($row = mysql_fetch_array($result)){
/*This will loop arround all the Table*/
if($row['id'] == 2){
/*You can filtere here*/
}
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
$counter = 0;
while($row = mysql_fetch_array($result)){
$counter++;
if($counter == 2){
echo $row['id']. " - ". $row['name'];
echo "<br />";
}
}
This While loop will automatically fetch all the records from the database.If you want to get any other field then you will only need to use for this.
Depends on what you want to do. mysql_fetch_array() fetches the current row to which the resource pointer is pointing right now. This means that you don't have $row['name'][2]; at all. On each iteration of the while loop you have all the columns from your query in the $row array, you don't get all rows from the query in the array at once. If you need just this one row, then yes - add a WHERE clause to the query, don't retrieve the other rows if you don't need them. If you need all rows, but you wanna do something special when you get the second row, then you have to add a counter that checks which row you are currently working with. I.e.:
$count = 0;
while($row = mysql_fetch_array($result)){
if(++$count == 2)
{
//do stuff
}
}
Yes, ideally you have to write another sql query to filter your results. If you had :
SELECT * FROM Employes
then you can filter it with :
SELECT * FROM Employes WHERE Name="Paul";
if you want every names that start with a P, you can achieve this with :
SELECT * FROM Employes WHERE Name LIKE "P%";
The main reason to use a sql query to filter your data is that the database manager systems like MySQL/MSSQL/Oracle/etc are highly optimized and they're way faster than a server-side condition block in PHP.
If you want to be able to use 2 consecutive results in one loop, you can store the results of the first loop, and then loop through.
$initial = true;
$storedId = '';
while($row = mysql_fetch_array($result)) {
$storedId = $row['id'];
if($initial) {
$initial = false;
continue;
}
echo $storedId . $row['name'];
}
This only works for consecutive things though.Please excuse the syntax errors, i haven't programmed in PHP for a very long time...
If you always want the second row, no matter how many rows you have in the database you should modify your query thus:
SELECT * FROM theTable LIMIT 1, 1;
See: http://dev.mysql.com/doc/refman/5.5/en/select.html
I used the code from the answer and slightly modified it. Thought I would share.
$result = mysql_query( "SELECT name FROM category;", db_connect() );
$myrow = array();
while ($myrow[] = mysql_fetch_array( $result, MYSQLI_ASSOC )) {}
$num = mysql_num_rows($result);
Example usage
echo "You're viewing " . $myrow[$view_cat]['name'] . "from a total of " . $num;