please help in deleting multiple rows from a table.
home.php
<form action="del.php" method="get" enctype="multipart/form-data">
<?php
while($row=mysql_fetch_array($rs))
{
?>
<tr>
<td align="center" bgcolor="#FFFFFF"><input name="need_delete[<?php echo $row['id']; ?>]" type="checkbox" id="checkbox[<?php echo $row['id']; ?>]" value="<?php echo $row['id']; ?>"></td>
<td><?php echo $row['listingtype'];?></td>
<td><?php echo $row['propertyname'];?></td>
<td><?php echo $row['price'];?></td>
<td><?php echo $row['listdate'];?></td>
</tr>
<?php
}
?>
</table>
<tr>
<td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td>
</tr></form>
del.php
<?php
include "include/db.php";
$tbl_name='propertylistingbasicinfo';
// Check if delete button active, start this
if ( ! empty($_POST['delete'])) {
foreach ($_POST['need_delete'] as $id => $value) {
$sql = 'DELETE FROM `'.$tbl_name.'` WHERE `id`='.(int)$id;
mysql_query($sql);
}
header('Location: home.php');
}
?>
Error : When i click on delete button, blank screen come.
And url looks like this : http://localhost/realestate/del.php?need_delete%5B2%5D=2&delete=Delete
your mixing up GET with POST, change form method to post
You need something similar to this in your form
<input type="checkbox" name="record[]" value="<?php echo $id ?>">
then you can use implode() function to concatenate ids and remove them
$deleted = implode(',',$_POST['record']);
$query = mysql_query("delete from table where id in ('$deleted') ");
Not tested but this the idea.
The problem is that you are submitting the form with method="get" and in del.php, you are accessing values from $_POST. Change method="get" to method="post" on home.php
I would change it to the following...
home.php:
<form action="del.php" method="post" enctype="multipart/form-data">
<table>
<?php while($row=mysql_fetch_array($rs)) { ?>
<tr>
<td align="center" bgcolor="#FFFFFF">
<input name="need_delete[]" value="<?php echo $row['id']; ?>" type="checkbox" id="checkbox[<?php echo $row['id']; ?>]" />
</td>
<td><?php echo $row['listingtype'];?></td>
<td><?php echo $row['propertyname'];?></td>
<td><?php echo $row['price'];?></td>
<td><?php echo $row['listdate'];?></td>
</tr>
<?php } ?>
<tr>
<td colspan="5" align="center" bgcolor="#FFFFFF">
<input name="delete" type="submit" id="delete" value="Delete" />
</td>
</tr>
</table>
del.php:
<?php
//Get the db-file and set the table name
include "include/db.php";
$tbl_name='propertylistingbasicinfo';
// Check if delete button active, start this
if ( !empty($_POST['delete'])) {
//Let's sanitize it
$sanitized_post_ids = array();
foreach($_POST['need_delete'] as $id ) $sanitized_post_ids[] = intval($id);
//Get the ids and add a trailing ",", but remove the last one
$in_str = substr(implode(',', $sanitized_post_ids), 0, -1);
//Build the sql and execute it
$sql = 'DELETE FROM ' . $tbl_name ' WHERE id IN (' . $in_str . ')';
mysql_query($sql);
//Redirect!
header('Location: home.php');
}
?>
Hope this works out for you (and that I didn't manage to add a typo or similar misshaps)!
Related
//Deleting is working. However, I can't delete the specified row in the table. It always deletes the last row. I hope you could help me. Thank you! This is my code for displaying data from database:
<form action="deleteCart.php" method = "post" role="form">
<?php
while ($row = mysqli_fetch_array($result2)) {
?>
<tr style="text-align: center;">
<td> <img src="images/<?php echo $row["ImageProduct1"]; ?>"/>
<td><?php echo $row['NameProduct1']; ?> </td>
<td>#<?php echo $row['OrderID']; ?></td>
<td><?php echo $row['OrderQuantity']; ?></td>
<td><input type="submit" name="cancelOrder" value = "Cancel" ></td>
<td><input type="hidden" name="hiddenID" value="<?php echo $row['OrderID']; ?>"></td>
</tr>
<?php
}
?>
</form>
//This is my code for deleting:
if(isset($_POST['cancelOrder'])){
orderID = $_POST['hiddenID'];
mysqli_query($con, "DELETE FROM OrderTable WHERE OrderID=$_POST[hiddenID];");
header('location: deleteCart.php');
}
Delete only the last record because you submitting form whole table record. you should try this code. it will work fine.
this will submit separate record.
<?php
while ($row = mysqli_fetch_array($result2)) {
?>
<form action="deleteCart.php" method = "post" role="form">
<tr style="text-align: center;">
<td><img src="images/<?php echo $row["ImageProduct1"]; ?>"/>
<td><?php echo $row['NameProduct1']; ?> </td>
<td>#<?php echo $row['OrderID']; ?></td>
<td><?php echo $row['OrderQuantity']; ?></td>
<td>
<input type="hidden" name="hiddenID" value="<?php echo $row['OrderID']; ?>">
<input type="submit" name="cancelOrder" value = "Cancel" >
</td>
</tr>
</form>
<?php
}
?>
Im new in php. this problem stuck me for two days. ergh. I want to display a table that contain input field so that user can insert the data and update it into database. User can change all the data in the table. I want to update multiple rows at a time, but it ends up updating only 1 row (the last row). Anyone please help me for this. Thnks.
This are the form.
This are the following code.
[<table>
<thead>
<tr>
<td><b>Item Code</b></td>
<td><b>Item Barcode</b></td>
<td><b>Item</b></td>
<td><b>QOH</b></td>
<td><b>Quantity</br>Checked</b></td>
<td><b>Quantity</br>Order</b></td>
</tr>
</thead>
<?php
$Barcode=$_SESSION\["Barcode"\];
$code=$_SESSION\["Code"\];
$itemcode=$_SESSION\["Itemcode"\];
$guid=$_SESSION\["guid"\];
$sql = "SELECT itemmastersupcode.*, itembarcode.*, stock_count_item.*, stock_count.*, po_ex_c.*, d.itemlink_total_qty
FROM itemmastersupcode
WHERE stock_count.SupCode = '$code' and stock_count_item.TRANS_GUID = '$guid'
GROUP BY itemmastersupcode.Itemcode";
$result=mysqli_query($conn2,$sql);
$rowcount = mysqli_num_rows($result);
while($row = mysqli_fetch_assoc($result))
{
?>
<tbody>
<tr>
<td><?php echo $row\["Itemcode"\]; ?></td>
<td><?php echo $row\["Barcode"\]; ?></td>
<td><?php echo $row\["Description"\]; ?></td>
<td><?php echo $row\["itemlink_total_qty"\]; ?></td>
<td><?php echo $row\["qty"\]; ?></td>
<form class="form-inline" role="form" method="POST" id="myForm">
<td><input type="number" name="qty" value=""/></td>
</tr>
</tbody>
<input type="hidden" name="itemcode" value="<?php echo $row\["itemcode"\]; ?>"/>
<input type="hidden" name="supcode" value="<?php echo $_SESSION\["Code"\] ?>"/>
<input type="hidden" name="guid" value="<?php echo $_SESSION\["guid"\] ?>"/>
<?php
}
?>
</table>
<button name="save" type="submit" ><b>SUBMIT</b></button>
</form>
<?php
if (isset($_POST\["save"\]))
{
$itemcode=$_POST\['itemcode'\];
$qty=$_POST\['qty'\];
$supcode=$_POST\['supcode'\];
$guid=$_POST\['guid'\];
$sql = "UPDATE stock_count, stock_count_item SET stock_count.posted = '1', stock_count_item.qty_order = '$qty'
WHERE stock_count.TRANS_GUID = '$guid' AND stock_count_item.Itemcode ='$itemcode'
and stock_count_item.TRANS_GUID = '$guid' ";][1]
An UPDATE query will update all records that are filtered by the WHERE clause. If no WHERE is given, all records are updated:
UPDATE table1 SET field1='value1';
will set the field1 column of all records to value1.
UPDATE table1 SET field1='value1' WHERE field2='value2';
will set the field1 column to value1 or all records where field2 is equal to value2.
So, in your case, the records that are found through the WHERE clause are updated. This is all basic SQL stuff by the way, so I advise you to read up on SQL.
Finally, also use prepared statements in your code to prevent SQL injection.
<table>
<thead>
<tr>
<td><b>Item Code</b></td>
<td><b>Item Barcode</b></td>
<td><b>Item</b></td>
<td><b>QOH</b></td>
<td><b>Quantity</br>Checked</b></td>
<td><b>Quantity</br>Order</b></td>
</tr>
</thead>
<?php
$Barcode=$_SESSION["Barcode"];
$code=$_SESSION["Code"];
$itemcode=$_SESSION["Itemcode"];
$guid=$_SESSION["guid"];
$sql = "SELECT itemmastersupcode.*, itembarcode.*, stock_count_item.*, stock_count.*, po_ex_c.*, d.itemlink_total_qty
FROM itemmastersupcode
WHERE stock_count.SupCode = '$code' and stock_count_item.TRANS_GUID = '$guid'
GROUP BY itemmastersupcode.Itemcode";
$result=mysqli_query($conn2,$sql);
$rowcount = mysqli_num_rows($result);
while($row = mysqli_fetch_assoc($result))
{
?>
<tbody>
<tr>
<td><?php echo $row["Itemcode"]; ?></td>
<td><?php echo $row["Barcode"]; ?></td>
<td><?php echo $row["Description"]; ?></td>
<td><?php echo $row["itemlink_total_qty"]; ?></td>
<td><?php echo $row["qty"]; ?></td>
<form class="form-inline" role="form" method="POST" id="myForm">
<td><input type="number" name="itemcode[<?php echo $row["itemcode"]; ?>][qty]" value=""/></td> //update here
</tr>
</tbody>
<?php
}
?>
</table>
<input type="hidden" name="supcode" value="<?php echo $_SESSION["Code"] ?>"/> //update here
<input type="hidden" name="guid" value="<?php echo $_SESSION["guid"] ?>"/>//update here
<button name="save" type="submit" ><b>SUBMIT</b></button>
</form>
Php content
<?php
if (isset($_POST["save"]))
{
$itemcodes=$_POST['itemcode'];
$qty=$_POST['qty'];
$supcode=$_POST['supcode'];
$guid=$_POST['guid'];
$sql = "UPDATE stock_count, stock_count_item SET
stock_count.posted = '1',
stock_count_item.qty_order = CASE stock_count_item.Itemcode";
foreach( $itemcodes as $itmcode=>$qty)
{
$sql.=" WHEN ".$itmcode." THEN ".$qty
}
$sql.=" END WHERE stock_count.TRANS_GUID =$guid AND stock_count_item.TRANS_GUID=$guid AND stock_count_item.Itemcode IN (".implode(",",array_keys( $itemcodes)).") ";
?>
Hope it will help
Im actually trying to add only a specific row from the table product to the table product_add but the last row is being inserted in the table product_add. What i want is that when I click on the button ADD that specific row is being inserted in the table product_add. I think that the code is not considering the if (isset($_REQUEST['submit'])) part.
<?php
include'connect.php';
$image = isset($_GET['image']) ? $_GET['image'] : "";
$id = isset($_GET['id']) ? $_GET['id'] : "";
$name = isset($_GET['name']) ? $_GET['name'] : "";
$price= isset($_GET['price']) ? $_GET['price'] : "";
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0){
?>
<form method="POST" id="form" name="form">
<table border='1'>
<tr>
<th>Id</th>
<th>Image</th>
<th>Name</th>
<th>Price MUR</th>
</tr>
<?php
while ($row = mysql_fetch_array($result)){
extract($row);
?>
<tr>
<td><?php echo ($row['id']); ?></td>
<td><img src=<?php echo $row['image'] ?> width='120' height='100'/></td>
<td><?php echo htmlspecialchars($row['name']); ?></td>
<td><?php echo htmlspecialchars($row['price']); ?></td>
<td>
<input id="submit" type="submit" name="submit" value='ADD'/>
</td>
</tr>
<?php
}
?>
</table>
</form>
<?php
}
if (isset($_REQUEST['submit']))
{
$insert = "INSERT INTO product_add(id, name, price) VALUES ('$id', '$name','$price')";
$insertQuery=mysql_query($insert);
}
?>
basically it a general coding issue
type submit and also name submit is conflicting
first add an attribute in form tag enctype="multipart/form-data" for image or video upload
then
creat a hidden field named 'something'
like
<input type="hidden" name="something" />
and after that use this
isset($_REQUEST['something']
add from in each while
like this updated code
<?php
include'connect.php';
$image = isset($_REQUEST['image']) ? $_REQUEST['image'] : "";
$id = isset($_REQUEST['id']) ? $_REQUEST['id'] : "";
$name = isset($_REQUEST['name']) ? $_REQUEST['name'] : "";
$price= isset($_REQUEST['price']) ? $_REQUEST['price'] : "";
$sql="SELECT * FROM product";
$result = mysql_query($sql);
if($result>0){
?>
<table border='1'>
<tr>
<th>Id</th>
<th>Image</th>
<th>Name</th>
<th>Price MUR</th>
</tr>
<?php
while ($row = mysql_fetch_array($result)){
?>
<tr>
<td><?php echo ($row['id']); ?></td>
<td><img src=<?php echo $row['image'] ?> width='120' height='100'/></td>
<td><?php echo htmlspecialchars($row['name']); ?></td>
<td><?php echo htmlspecialchars($row['price']); ?></td>
<td>
<form method="POST" action="" >
<input type="hidden" name="id" value="<?php echo $row['id']; ?>" />
<input type="hidden" name="name" value="<?php echo $row['name']; ?>" />
<input type="hidden" name="image" value="<?php echo $row['image']; ?>" />
<input type="hidden" name="price" value="<?php echo $row['price']; ?>" />
<input id="submit" type="submit" name="submit" value='ADD'/>
</form>
</td>
</tr>
<?php
}
?>
</table>
<?php
}
if (isset($_REQUEST['submit']))
{
$insert = "INSERT INTO product_add(id, name, price) VALUES ('$id', '$name','$price')";
$insertQuery=mysql_query($insert);
}
?>
NOTE: mysql_* is deprecated use mysqli_* or PDO
I have a table called "project_name" in my database called "encrypt_decrypt". The table contains only 1 column called "name" which contains different values of name (ex : p1, p2, p3...). I have to retrieve this values(p1,p2,p3..) from my database and display it on a registration form with each value displaying one below the other having a checkbox with it so that user can select any of the name while registering! How do i do this in php ???
Thanks in advance!
<html>
<body>
<form name="reg" action="code_exec2.php" onsubmit="return validateForm()" method="post">
<table width="274" border="0" align="center" cellpadding="2" cellspacing="0">
<tr>
<td><div align="right" style="white-space:nowrap" >Please select the project:</td>
</tr>
<tr>
<td><div align="right"><input type="checkbox" name="project[]" ></div></td>
<td><?php
session_start();
include('connection2.php');
$row=mysql_query("select * from project_name");
$array= array();
$output = mysql_fetch_assoc($row);
while($output){
$array[] = $output;
}
print_r($array);
?></td>
</tr>
<tr>
<td><div align="right"><input type="checkbox" name="Select all"
value="select all" onclick="toggle(this)"></div></td>
<td>Select all</td>
</tr>
<tr>
<td><div align="right"></div></td>
<td><input name="submit" type="submit" value="Submit" /></td>
</tr>
</table>
</form>
</body>
Try this.
$result=mysql_query("select * from project_name");
$checkboxes=array();
while($r=mysql_fetch_assoc($result)){
$checkboxes[]='<input type="checkbox" name="names[]" value="'.$r['name'].'">'.$r['name'].'<br />';
}
Then echo below wherever you want the checkboxes to appear.
echo implode("\n",$checkboxes);
Assuming, that your connection to db is correct, you need to change the way you display results:
<?php
session_start();
include('connection2.php');
$row=mysql_query("select * from project_name");
$array= array();
while($output = mysql_fetch_assoc($row)){
//now you have row with name, and you need to display each name with new tr:
?>
<tr>
<td><div align="right"><input type="checkbox" name="project[]" value="<?php echo $output['name'] ?>"></div></td>
<td><?php echo $output['name'] ?></td>
</tr>
<?php } // closing while loop
?>
Note that I added value to checkbox - if you want to do something with checked project, you have to know which one it was.
And remember taht mysql_ functions are depreated! You should use PDO or mysqli_ instead
i tried this and i got: any ways thanks for all your help :)
<?php
include('connection.php');
$r=mysql_query("select distinct name from project_name");
$ProdArray=array();
while ($row = mysql_fetch_object($r)) {
array_push($ProdArray,$row->name);
}
foreach($ProdArray as $p) {
echo "<tr>";
echo "<td><div align='right'>";
echo "<input type='checkbox' name='project[]' value=" .$p. " />";
echo "</div></td>";
echo "<td>$p</td>";
echo "</tr>";
}
?>
Good day. I'm a newbie in php.
What I'm trying to do is i want to get the id of the specific data row from my database. And update some column on my table.
What I did is this..
<td style="width:50px;"><input type="checkbox" id="chkPending" name="chkPending[]" value="<?php echo $row['RequestNumber']; ?>"/></td>
<td><span class="label label-success">View Details</span></td>
<td style="width:100px;"><?php echo $row['RequestNumber']; ?></td>
<td style="width:100px;"><?php echo $row['Requestor']; ?></td>
<td style="width:100px;"><?php echo $row['Department']; ?></td>
<td style="width:50px;"><?php echo $row['category']; ?></td>
<td style="width:100px;"><?php echo $row['AssignedTo']; ?></td>
<td style="width:100px;"><?php echo $row['status']; ?></td>
<td style="width:100px;"><?php echo $row['DateRequested']; ?></td>
<td style="width:100px;"><?php echo $row['TimeRequested']; ?></td>
PHP CODE
<?php
$RequestNumber = $POST_['chkPending'];
$sql = "UPDATE tblrequest SET Assignedto = 'personnel', status = 'Assigned' WHERE RequestNumber = '$RequestNumber'";
if (isset($_POST['submit'])) {
$success = mysql_query($sql) or die(mysql_error());
mysql_close();
}
if ($success == TRUE) {
?>
<script>
alert('You have successfully update account.');
</script>
<?php
}
?>
I would appreciate any help. Thank you in advance.
This is my whole code:**
Change your input name by this:
<input type="checkbox" id="chkPending" name="chkPending[<?= $row['RequestNumber']; ?>]" />
In your PHP code do this:
<?php
if (isset($_POST['submit'])) {
foreach($_POST['chkPending'] as $RequestNumber=>$value)
{
$sql = "UPDATE tblrequest SET Assignedto = 'personnel', status = 'Assigned' WHERE RequestNumber = '".$RequestNumber."'";
$success = mysql_query($sql) or die(mysql_error());
}
mysql_close();
}
if ($success == TRUE) {
?>
<?php
<script>
alert('You have successfully update account.');
</script>
<?php
}
?>
You can use this code to compare it. This code is working and will print 2,4.
<form action="#" method="POST">
<input name="test[1]" type="checkbox" />
<input name="test[2]" checked type="checkbox" />
<input name="test[3]" type="checkbox" />
<input name="test[4]" checked type="checkbox" />
<input type="submit" />
</form>
<?php
if($_POST)
{
foreach($_POST['test'] as $id => $value)
{
echo $id.'<br />';
}
}
?>