Displaying results as hyperlinks to an additional query? - php

I've been looking for a way to display MySQL results as hyperlinks that will perform another query when clicked.
Say I have a 2 tables in my database linked by ALTER TABLE topics ADD FOREIGN KEY(topic_cat) REFERENCES categories(cat_id) ON DELETE CASCADE ON UPDATE CASCADE;
categories:
+-----------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+--------------+------+-----+---------+----------------+
| cat_id | int(8) | NO | PRI | NULL | auto_increment |
| cat_name | varchar(255) | NO | UNI | NULL | |
| cat_description | varchar(255) | NO | | NULL | |
+-----------------+--------------+------+-----+---------+----------------+
topics:
+---------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------------+--------------+------+-----+---------+----------------+
| topic_id | int(8) | NO | PRI | NULL | auto_increment |
| topic_subject | varchar(255) | NO | | NULL | |
| topic_date | datetime | NO | | NULL | |
| topic_cat | int(8) | NO | MUL | NULL | |
| topic_by | int(8) | NO | MUL | NULL | |
+---------------+--------------+------+-----+---------+----------------+
I also have a PHP search form that queries the table "categories":
$var = #$_GET['search'] ;
$trimmed = trim($var);
$query = "select * from categories where cat_name like \"%$trimmed%\"
order by cat_name";
I want to be able to display the results of the above query as hyperlinks and when clicked, I want to display results that are linked to "cat_name" by "topic_cat" and "cat_id". I can't seem to find an example of this anywhere online. Any suggestions?

When you output results, do
print ("<a href='show_category_topics.php?id=".$row["cat_id"]."'>".$row["cat_name"]."</a>");
On a new page (show_category_topics.php) run the query
$query = "SELECT * FROM topics WHERE topic_cat ='".mysql_real_escape_string($_GET["id"])."'"; and print results.
You can also use ajax calls to php pages.

Related

How to display a "foreign key" value in an array in PHP?

I have a current problem, I tried to search in the documentations and the answers already given in the same site, but none of the answers helped me.
In fact I have a database, and two tables.
-> gpscoordonnee
MariaDB [leguideduflaneur]> DESCRIBE gpscoordonnee;
+--------------+----------+------+-----+---------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------------+----------+------+-----+---------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| Nom_Commerce | int(11) | NO | MUL | NULL | |
| date | datetime | NO | | current_timestamp() | |
+--------------+----------+------+-----+---------------------+----------------+
3 rows in set (0.017 sec)
-> marchantpart
MariaDB [leguideduflaneur]> DESCRIBE marchantpart;
+---------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| Nom | varchar(200) | NO | | NULL | |
| Adresse | varchar(300) | NO | | NULL | |
| Tel | int(11) | NO | | NULL | |
| Email | varchar(100) | NO | | NULL | |
+---------+--------------+------+-----+---------+----------------+
5 rows in set (0.016 sec)
In the gpscoordonnee table, the Nom_Commerce field is a foreign Keys of Name of the marchantpart table.
I want by displaying the Nom_Commerce that it displays the contents of Nom
AND NOT 1
I have already tried all these methods but nothing is displayed, not even an error :
SELECT n.Nom
from gpscoordonnee us
LEFT JOIN marchantpart ON us.NID = n.Nom
OR
SELECT gpscoordonnee, marchantpart.Nom AS Nom_Commerce
FROM gpscoordonnee
JOIN marchantpart ON marchantpart.Nom=gpscoordonnee.Nom_Commerce
I don't want this :
Result that displays integers instead of names
But i want this :
Result with names
I find my error.
I use SELECT Nom FROM gpscoordonnee t1 INNER JOIN marchantpart t2 ON t1.Nom_Commerce=t2.id and my result is this
RESULT
Thanks for all the people who help me.

How to display information from Two sql tables on my blog using php and html

I am trying to display information from my SQL tables on my web blog. I have two tables blog_posts and blog_members which look like
Blog_members
+----------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------+------------------+------+-----+---------+----------------+
| memberID | int(11) unsigned | NO | PRI | NULL | auto_increment |
| username | varchar(255) | YES | | NULL | |
| password | varchar(255) | YES | | NULL | |
| email | varchar(255) | YES | | NULL | |
+----------+------------------+------+-----+---------+----------------+
and
blog_posts
+-----------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+------------------+------+-----+---------+----------------+
| postID | int(11) unsigned | NO | PRI | NULL | auto_increment |
| postTitle | varchar(255) | YES | | NULL | |
| postDesc | text | YES | | NULL | |
| postCont | text | YES | | NULL | |
| postDate | datetime | YES | | NULL | |
+-----------+------------------+------+-----+---------+----------------+
I am able to add the information from one table but I want to display memeberID when I post an article do I need additional columns in the blog_posts table if so how would I go about this would I need to use a join?
I am displaying the information on my blog using the PHP below.
$stmt = $db->query('SELECT postID, postTitle, postDesc, postDate FROM blog_posts ORDER BY postID DESC');
// $stmt = $db->query('SELECT memberID FROM blog_members');
while($row = $stmt->fetch()){
echo '<div>';
echo '<h1>'.$row['postTitle'].'</h1>';
echo '<p>Posted on '.date('jS M Y H:i:s', strtotime($row['postDate'])).'</p>';
// echo '<p> by'.$row['memberID'].'</p>';
echo '<p>'.$row['postDesc'].'</p>';
echo '<p1>Read More</p1>';
echo '</div>';
echo '<hr />';
that displays the posts but not the memberID I would like a post to have the member that created it aswell.
Think about a row in your posts table. How do you know which member that row belongs to? As mentioned in the comments, you can add a memberId to your posts table so that you can join the two tables and find both the member that belongs to a post, as well as the posts for a particular member. One convention for these columns is to prefix them with something like fk (foreign key) to indicate their role on the table. The table might look like this:
+-------------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+------------------+------+-----+---------+----------------+
| postID | int(11) unsigned | NO | PRI | NULL | auto_increment |
| postTitle | varchar(255) | YES | | NULL | |
| postDesc | text | YES | | NULL | |
| postCont | text | YES | | NULL | |
| postDate | datetime | YES | | NULL | |
| fkMemberID | int(11) unsigned | NO | | NULL | |
+-------------+------------------+------+-----+---------+----------------+
Then after you have retrieved a post, you will have the memberId that is the owner of that post, and you can retrieve the member details using that id.
(You would also create a separate foreign key object in the database which maintains the integrity of the foreign key columns. i.e. it makes sure you don't put a memberId of say 53 into the posts table fkMemberId column unless there is a memberId of 53 in the member table. You probably already know that but just thought to mention. :) )

Multi table deletion MySQL through PHP

I am making a simple database to use as a mock example for an E-Commerce website. One things that I am required to do it delete records from the database using PHP. I can delete a user name or a order or etc.. But when I try to do them all at once I am screwing something up. What I want to happen is delete all the information about a user. Example : User info, Shipping Info, Billing Info, Credit Card Info, and anything else to do with the specific user. My tables are as followed.
mysql> SHOW columns FROM shirt_billing_addresses;
+----------------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------------------+--------------+------+-----+---------+----------------+
| shirt_billing_addresses_id | mediumint(9) | NO | PRI | NULL | auto_increment |
| house | mediumint(9) | NO | | NULL | |
| street | varchar(100) | NO | | NULL | |
| city | varchar(100) | NO | | NULL | |
| state | char(2) | NO | | NULL | |
| zip | char(5) | NO | | NULL | |
+----------------------------+--------------+------+-----+---------+----------------+
6 rows in set (0.01 sec)
mysql> SHOW columns FROM shirt_credit_cards;
+-----------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------------+--------------+------+-----+---------+----------------+
| shirt_credit_cards_id | mediumint(9) | NO | PRI | NULL | auto_increment |
| shirt_users_id | mediumint(9) | NO | MUL | NULL | |
| type | varchar(30) | NO | | NULL | |
| no | char(16) | NO | | NULL | |
| security_code | char(3) | NO | | NULL | |
+-----------------------+--------------+------+-----+---------+----------------+
5 rows in set (0.04 sec)
mysql> SHOW columns FROM shirt_orders;
+-----------------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------------------+--------------+------+-----+---------+----------------+
| shirt_orders_id | int(11) | NO | PRI | NULL | auto_increment
| order_total | double(6,2) | NO | | NULL | |
| payment_date | datetime | NO | | NULL | |
| shirt_credit_cards_id | mediumint(9) | NO | MUL | NULL | |
| shirt_shipping_addresses_id | mediumint(9) | NO | MUL | NULL
| shirt_billing_addresses_id | mediumint(9) | NO | MUL | NULL |
| shirt_shipping_methods_id | tinyint(4) | NO | MUL | NULL |
+-----------------------------+--------------+------+-----+---------+----------------+
7 rows in set (0.02 sec)
mysql> SHOW columns FROM shirt_shipping_addresses;
+-----------------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------------------+--------------+------+-----+---------+----------------+
| shirt_shipping_addresses_id | mediumint(9) | NO | PRI | NULL | auto_increment
| house | mediumint(9) | NO | | NULL | |
| street | varchar(100) | NO | | NULL | |
| city | varchar(100) | NO | | NULL | |
| state | char(2) | NO | | NULL | |
| zip | char(5) | NO | | NULL | |
+-----------------------------+--------------+------+-----+---------+----------------+
6 rows in set (0.03 sec)
mysql> SHOW columns FROM shirt_users;
+----------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------+--------------+------+-----+---------+----------------+
| shirt_users_id | mediumint(9) | NO | PRI | NULL | auto_increment |
| first_name | varchar(30) | NO | | NULL | |
| last_name | varchar(30) | NO | | NULL | |
| email | varchar(30) | NO | | NULL | |
| user_id | varchar(30) | NO | | NULL | |
| password | char(40) | NO | | NULL | |
+----------------+--------------+------+-----+---------+----------------+
6 rows in set (0.03 sec)
mysql> SHOW columns FROM shirt_users_types;
+----------------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------------+--------------+------+-----+---------+----------------+
| shirt_users_types_id | int(11) | NO | PRI | NULL | auto_increment |
| shirt_users_id | mediumint(9) | NO | MUL | NULL | |
| shirt_types_id | smallint(6) | NO | MUL | NULL | |
| shirt_orders_id | int(11) | NO | MUL | NULL | |
| type_quantity | smallint(6) | NO | | NULL | |
| type_total | double(6,2) | NO | | NULL | |
+----------------------+--------------+------+-----+---------+----------------+
6 rows in set (0.03 sec)
The PHP code I have is as follows:
#mysqli_query($link, "SET AUTOCOMMIT=0");
$select_sui = "SELECT
shirt_users.shirt_users_id,
shirt_users_types.shirt_users_types_id,
shirt_orders.shirt_orders_id,
shirt_shipping_addresses.shirt_shipping_addresses_id,
shirt_billing_addresses.shirt_billing_addresses_id,
shirt_credit_cards.shirt_credit_cards_id
from
shirt_users,
shirt_users_types,
shirt_orders,
shirt_shipping_addresses,
shirt_billing_addresses,
shirt_credit_cards
where
shirt_users.shirt_users_id = shirt_users_types.shirt_users_id and
shirt_users_types.shirt_orders_id = shirt_orders.shirt_orders_id and
shirt_orders.shirt_shipping_addresses_id = shirt_shipping_addresses.shirt_shipping_addresses_id and
shirt_orders.shirt_billing_addresses_id = shirt_billing_addresses.shirt_billing_addresses_id and
shirt_orders.shirt_credit_cards_id = shirt_credit_cards.shirt_credit_cards_id and
shirt_users.shirt_users_id = $shirt_users_id";
The only problem is that this query will return an empty set unless all the tables have the correct information in it. This is a problem because if a user has not ordered any items yet but I want to delete them from the database, It will not allow me. Any help on this matter would be greatly appreciated.
You have to use LEFT JOIN to link your tables (MySQL doc).
SELECT [...]
FROM shirt_users
LEFT JOIN shirt_users_types ON shirt_users.shirt_users_id = shirt_users_types.shirt_users_id
LEFT JOIN shirt_orders ON shirt_users_types.shirt_orders_id = shirt_orders.shirt_orders_id
LEFT JOIN shirt_shipping_addresses ON shirt_orders.shirt_shipping_addresses_id = shirt_shipping_addresses.shirt_shipping_addresses_id
LEFT JOIN shirt_billing_addresses ON shirt_orders.shirt_billing_addresses_id = shirt_billing_addresses.shirt_billing_addresses_id
LEFT JOIN shirt_credit_cards ON shirt_orders.shirt_credit_cards_id = shirt_credit_cards.shirt_credit_cards_id
WHERE
shirt_users.shirt_users_id = $shirt_users_id
With this you'll be able to load shirt_users even if there is no linked record in other tables.
EDIT for Delete records
If you want to delete in all your tables in only one request, you must use as syntax which is fairly the same as your first try (by replacing the SELECT statement by DELETE). ANd you will get the same problem (it will only delete records which have a linked record in each table and not null).
Method 1 :
NB : Your DB must support foreign keys (for example, MyISAM doesn't support it but InnoDB does).
You can use this method, if you always need in your app to delete all linked records.
The most beautiful way to achieve this is to add a ON DELETE CASCADE constraint on your relations :
-- Drop the old constraint ("fk_test" must be replace by your constraint name)
ALTER TABLE shirt_users_types DROP FOREIGN KEY `fk_test`;
-- Create the new with ON DELETE
ALTER TABLE shirt_users_types
ADD CONSTRAINT `fk_test`
FOREIGN KEY (`shirt_users_id` )
REFERENCES `shirt_users` (`shirt_users_id` )
ON DELETE CASCADE;
When you will delete a shirt_users entry, all linked records in shirt_users_types.
In a few words, with ON DELETE CASCADE, each time you will delete a parent element (the One side of the relation), all the children (the Many side of the relation or the table wich contains the column <related_record>_id) will be automatically deleted too.
Method 2 :
If your relation can be nullable (for example if shirt_users_types.shirt_orders_id can be null) or if your DB schema not permits to delete all needed records with ON DELETE CASCADE.
You can delete your records with several DELETE using relations to shirt_users in order to retrieve records in each linked table. (For correct syntax of DELETE with relations see MySQL docs).
In your code your unique identifier is $shirt_users_id, so you have to start by deleting in the tables which are not directly linked to shirt_users and by reaching back your relations to finish by the table shirt_users.
If you don't delete records in the correct order, you will not be able to delete all you need.
For example, with schema described in your question, if you delete records in shirt_orders before shirt_shipping_addresses, you will no longer can retrieve shipping addresses with $shirt_users_id because shirt_shipping_addresses is linked to shirt_users due to its relation with shirt_orders.
So the correct order for your current schema is (there is no need to have an order for table on the same line the list above) :
shirt_shipping_addresses / shirt_billing_addresses
shirt_orders / shirt_credit_cards / shirt_users_types
shirt_users
You can have a contraint fails error due to foreign keys. In this case you can make your delete in a TRANSACTION (it's a best practice) or disable foreign key checks for your queries.
SET foreign_key_checks = 0;

Get profile posts from friends

I'm making a small CMS, where you can have friends, and post on their walls. I'm making a page where you can view all the posts your friends have posted (on their profiles) however, I cannot get it to properly function.
Table: friends
+---------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------------+---------+------+-----+---------+----------------+
| friend_id | int(10) | NO | PRI | NULL | auto_increment |
| user1_id | int(10) | NO | | NULL | |
| user2_id | int(10) | NO | | NULL | |
| friends_since | int(10) | NO | | NULL | |
+---------------+---------+------+-----+---------+----------------+
Table: profile_posts
+----------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------------+---------+------+-----+---------+----------------+
| post_id | int(12) | NO | PRI | NULL | auto_increment |
| posted_user_id | int(12) | YES | | NULL | |
| user_id | int(12) | YES | | NULL | |
| date_posted | int(11) | YES | | NULL | |
| total_likes | int(12) | YES | | NULL | |
| users_liked | text | YES | | NULL | |
| total_dislikes | int(12) | YES | | NULL | |
| users_dislikes | text | YES | | NULL | |
| message | text | YES | | NULL | |
+----------------+---------+------+-----+---------+----------------+
Basically, if I want to determine if a user has posted on their profile as a status, the posted_user_id and user_id columns in the table profile_posts have to match (posted_user_id is the user's id of the post being posted on, and user_id is the user_id is the id of the person who posted that message).
However, I've tried multiple times to get friend's statuses.
SELECT *
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON `pp`.posted_user_id = `pp`.user_id
WHERE
`f`.user1_id != 2 OR
`f`.user2_id != 2
ORDER BY `pp`.`date_posted` DESC
LIMIT 0,15;
(Hurray for not working! :D)
SELECT `f`.*,`pp`.*,
IF(`f`.user1_id=2, `f`.user2_id, `f`.user1_id) AS `uid`
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON `pp`.posted_user_id =`uid`
WHERE
`f`.user1_id = `uid` OR
`f`.user2_id = `uid`
ORDER BY `pp`.`date_posted` DESC
LIMIT 0,15;
I'm not sure how to do this honestly, It's starting to make me rage as I cannot figure how to do this. :/
Never mind, figured out how to do it. :D
EDIT:
SELECT
`f`.*,
`pp`.*,
`ai`.`name`,
`ai`.`lastname`
FROM `friends` AS `f`
LEFT JOIN `profile_posts` AS `pp`
ON
`pp`.`posted_user_id` = `pp`.`user_id` AND
`pp`.`user_id` = `f`.user1_id OR
`pp`.`user_id` = `f`.user2_id
LEFT JOIN `account_info` AS `ai`
ON `ai`.`u_id` = `pp`.`user_id`
WHERE
`pp`.`user_id` = `pp`.`posted_user_id` AND
`f`.user1_id = 1 OR
`f`.user2_id = 1 AND
`pp`.`user_id` = `pp`.`posted_user_id`
GROUP BY `pp`.post_id
ORDER BY `pp`.date_posted DESC
LIMIT 0,20;
Selects the current user's friends, then it grabs all profile posts of their friends and then joins the account information table to get the name, and other information.
I'm trying to see if I can make this smaller, if not better..

Mysql one to many relationship. Order by number of rows in second table

I have created a voting system in php and mysql. When a user votes on an id, a record is inserted in "votes" referencing the FK media_id. When I then display the entries I use this query to get the number of votes for each entry:
$sql = "SELECT COUNT(*) FROM insta_votes WHERE media_id ='".$mediaid."'";
if ($res = $db->query($sql)) {
return $res->fetchColumn();
}
return 0;
This works fine, but I want to be able to sort the results by the number of votes they have. Preferably using just one query. How can I achieve this?
The tables are structured like this:
votes table
+-----------+--------------+------+-----+-------------------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+-------------------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| media_id | varchar(255) | NO | | NULL | |
| ip | varchar(20) | NO | | NULL | |
| c_time | timestamp | NO | | CURRENT_TIMESTAMP | |
| sessionid | varchar(30) | NO | | NULL | |
+-----------+--------------+------+-----+-------------------+----------------+
entries table
+---------------+--------------+------+-----+-------------------+-------+
| Field | Type | Null | Key | Default | Extra |
+---------------+--------------+------+-----+-------------------+-------+
| page_id | int(11) | NO | MUL | NULL | |
| media_id | varchar(255) | NO | PRI | NULL | |
| url | varchar(255) | NO | | NULL | |
| c_time | datetime | NO | | NULL | |
| likes | int(11) | YES | | NULL | |
| deleted | tinyint(1) | NO | | 0 | |
| inserted_time | timestamp | YES | | CURRENT_TIMESTAMP | |
| numReports | int(11) | NO | | 0 | |
+---------------+--------------+------+-----+-------------------+-------+
Thank you!
If I understand the tables correctly (and I may not), each entries row may reference multiple votes rows. In that case, the query you need will go something like this:
SELECT
entries.page_id,
COUNT(*) AS VoteCount
FROM entries
INNER JOIN votes ON entries.media_id = votes.media_id
GROUP BY entries.page_id
ORDER BY VoteCount
If you add additional entries columns to the SELECT list, be sure to add them to the GROUP BY list as well.
Addendum: #JuanPabloCalifano pointed out, correctly, that this query won't include entries with zero votes. Here's how to include them:
SELECT
entries.page_id,
COALESCE(COUNT(votes.id), 0) AS VoteCount
FROM entries
LEFT JOIN votes ON entries.media_id = votes.media_id
GROUP BY entries.page_id
ORDER BY VoteCount
SELECT COUNT(*) as CNT, `media_id` FROM `insta_votes` GROUP BY `media_id` order by 1;
SELECT COUNT(*), media_id FROM insta_votes
GROUP BY media_id
ORDER BY COUNT(*);"

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