I have the following code:
$referrals = inputFilter($_POST['referralsIds']);
$array =explode(",",$referrals);
foreach($array as $key=>$value):
/
$s=mysql_query("SELECT * FROM users WHERE upline='".$userdata['id']."' AND id='$value'");
$num_rows=mysql_num_rows($s);
if($num_rows==0)
return 2;
// No error found and the update was succesful - Return success!
mysql_query("UPDATE users SET upline='' WHERE id='$value'");
mysql_query("UPDATE users SET rbalance=rbalance-".$sdata['direct_delete_fee'].", direct_referrals=direct_referrals-1 WHERE username='".$userdata['username']."'");
return 100;
endforeach;
The $referrals variable is posting two values (10,11).But when I put it in a foreach loop, it will only run the query with the first value (10). How to do so it run through ALL values submitted?
Thanks.
You have a return 100 inside your for loop. It's terminating the loop on its first iteration.
return statements terminate the enclosing function. If you need to return multiple results, consider pushing them onto an array and then returning the array once you're done.
You have code returning before the end of your for each
return 100; //HERE
endforeach;
You probably want:
endforeach;
return 100;
So you have two values, then you explode it ? :O But i think you meant $array.
You have return 100 which will return from the function, and as well from foreach.
You are returning 100 from whatever function you're in on the first iteration of the loop. returning will cause the loop to stop immediately.
Related
I'm working on in_array() method. If the value read is already in the array it should be skipped and proceed to the next value. If the current value is not on the array yet, it should be pushed to the array.
here's my code:
while ($Result_Data_2 = mysqli_fetch_array($Result)){ //130 rows from database
$Res_Array = array();
$SQL_Result_Time = $Result_Data_2['Interpretation_Time'];
/* Some statements here */
if(in_array($SQL_Result_Time, $Res_Array, true)){
break;
}
else{
array_push($Res_Array, $Number, $SQL_Questionnaire_ID, $SQL_User_ID, $SQL_Psychology_FirstName, $SQL_Psychology_LastName, $SQL_Result_Date, $SQL_Result_Time);
}
echo "<pre>";print_r($Res_Array);echo "</pre>";
}
Problem: It seems that it ignores my condition which is if(in_array($SQL_Result_Time, $Res_Array, true)){break; } and still inserts the value into the array. It still duplicates data
Question:
How to prevent the duplication data where if the current value was found inside the array it would just skip the statement and proceed to another value for checking the array and so on?
Is my logic on checking the value on the array is right?
You are re-initialising your array on every iteration of the while loop. You should declare it outside of the loop:
$Res_Array = array();
while ($Result_Data_2 = mysqli_fetch_array($Result)){ //130 rows from database
$SQL_Result_Time = $Result_Data_2['Interpretation_Time'];
/* Some statements here */
if(in_array($SQL_Result_Time, $Res_Array, true)){
break;
}
else{
array_push($Res_Array, $Number, $SQL_Questionnaire_ID, $SQL_User_ID, $SQL_Psychology_FirstName, $SQL_Psychology_LastName, $SQL_Result_Date, $SQL_Result_Time);
}
echo "<pre>";print_r($Res_Array);echo "</pre>";
}
Also, as mentioned by Marvin Fischer in his answer, your break statement will terminate the while loop on the first duplicated value. You should instead use continue
while ($Result_Data_2 = mysqli_fetch_array($Result)){ //130 rows from database
...
if(in_array($SQL_Result_Time, $Res_Array, true)){
continue;
}
....
}
This question should clarify any issues you have with break and continue statements
First of all, inside of a loop you should use continue, otherwise you cancel the whole loop, secondly you empty $Res_Array at the beginning of every loop purging the old data, inserting the new one and echoing it again
i've a array problem couldn't just solve it:
here's the code that is already in a foreach loop. i'm getting the $row->class_id value from this loop. it works fine and get me the total students row within an array and i preserved it in $total_student_of_this_class variable. i used another foreach loop for storing the result of first loop and then second loop and so on. but this loop gives only first loop result.
i need to combine the all array of total iteration of the loop.
$total_student_of_this_class =
$this->db->select('student_id')->where('class_id',
$row->class_id)->get('student')->result_array();
echo count($total_student_of_this_class);
// prints 2 in the first row of the output table and 5 in the second
row for me.
$total_student = array();
foreach ($total_student_of_this_class as $tt)
{
$total_student[] = $tt;
}
echo '<pre>';
print_r($total_student_of_this_class);
echo '</pre>'
echo count($total_student);
// prints only 2 outside the loop (not 7)
pls someone help me.
The problem here is seems to be with $total_student = array();: initializing array inside an other loop it always starts it from zero values array, so you get only results from one iteration inside it and doesn't collect all datas.
You can also look at array_merge php function.
<?php
public function fetchAll($sql){
$result = mysqli_query($connection,$sql);
$out=array();
while($row=mysqli_fetch_assoc($result)){
$out[] = $row;
}
return $out;
}
Here array() has no initial size. can u tell me how this works without any size
2.in while statement we are saving arrays in a non declared variable, without any size too.how this statement works. how long this loop will work.
The code:
$out=array();
only initializes the $out-variable as an array, that is initially empty.
$out[]=$row;
will ADD an item/element into the array, increasing it's size by one on each cycle of the loop. Loop will run as many times as there are rows in your sql-result. Please read array_push documentation to fully understand this shorthand.
I need to get all the elements from a textarea in a HTML form and insert them into the MySQL database using PHP. I managed to get them into an array and also find the number of elements in the array as well. However when I try to execute it in a while loop it continues displaying the word "execution" (inside the loop) over a 1000 times in the page.
I cannot figure out what would be the issue, because the while loop is the only applicable one for this instance
$sent = $_REQUEST['EmpEmergencyNumbers'];
$data_array = explode("\n", $sent);
print_r($data_array);
$array_length = count($data_array);
echo $array_length;
while(count($data_array)){
echo "execution "; // This would be replaced by the SQL insert statement
}
you should use
foreach($data_array as $array)
{
//sql
}
When you access the submitted data in your php, it will be available in either $_GET or $_POST arrays, depending upon the method(GET/POST) in which you have submitted it. Avoid using the $_REQUEST array. Instead use, $_GET / $_POST (depending upon the method used).
To loop through each element in an array, you could use a foreach loop.
Example:
//...
foreach($data_array as $d)
{
// now $d will contain the array element
echo $d; // use $d to insert it into the db or do something
}
Use foreach for the array or decrement the count, your while loop
is a infinite loop if count is >0
Why is this not possible? Is there some way I can make the resolut not to be empty?
$sqlAllInfo = "SELECT item1, item2 FROM example";
$resAllInfo = mysql_query($sqlAllInfo);
while($rowAllInfo = mysql_fetch_assoc($resAllInfo)){
echo $rowAllInfo['item1'];
}
$rowAllInfo = mysql_fetch_assoc($resAllInfo);
echo $rowAllinfo['item2'];
Thanks for your time
No, the result will always be empty after your while loop, because the while loop extracts all value from the result resource..the while loop continues looping while there is still information to extract, and will finish when it is empty or when an error occurs
if you ment to get the last entry
$rowAllInfo still contains the last entry ;)
You are looping through the result set using while until there are no more results left. The while loop exits when mysql_fetch_assoc returns false, because there are no more results. Calling mysql_fetch_assoc again still means that there are no more results.
This line:
while($rowAllInfo = mysql_fetch_assoc($resAllInfo)){
assigns a new value to rowAllInfo and afterwards checks whether it is still "true"-ish (as "true" as PHP can be ;-) )
Now, after the last row is fetched, mysql_fetch_assoc() will return false, which is then assigned to $rowAllInfo. As $rowAllInfo is now "false", the loop will not execute anymore, but - look - it's too late! You Variable already has the value false assigned to it.
Even after that, you call mysql_fetch_assoc() once again. But, as you have already fetched all rows within your loop, no more rows are left, and once again $rowAllInfo is set to "false".
So, whatever you are trying to do - this is probably not your way. A common way to achieve what I understand you are trying to do is the following:
$allRows = array();
while( $row = mysql_fetch_assoc($res) ) {
$allRows[] = $row;
}
// show the array we just created...
echo print_r( $arrRows, 1 );