I found a script in Web Designer magazine that enables you to gather Album Data from a Facebook Fan Page, and put it on your site.
The script utilizes PHP's file_get_contents() function, which works great on my personal server, but is not allowed on the Network Solutions hosting.
In looking through their documentation, they recommended that you use a cURL session to gather the data. I have never used cURL sessions before, and so this is something of a mystery to me. Any help would be appreciated.
The code I "was" using looked like this:
<?php
$FBid = '239319006081415';
$FBpage = file_get_contents('https://graph.facebook.com/'.$FBid.'/albums');
$photoData = json_decode($FBpage);
$albumID = $photoData->data[0]->id;
$albumURL = "https://graph.facebook.com/".$albumID."/photos";
$rawAlbumData = file_get_contents("https://graph.facebook.com/".$albumID."/photos");
$photoData2 = json_decode($rawAlbumData);
$a = 0;
foreach($photoData2->data as $data) {
$photoArray[$a]["source"] = $data->source;
$photoArray[$a]["width"] = $data->width;
$photoArray[$a]["height"] = $data->height;
$a++;
}
?>
The code that I am attempting to use now looks like this:
<?php
$FBid = '239319006081415';
$FBUrl = "https://graph.facebook.com/".$FBid."/albums";
$ch = curl_init($FBUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
$contents = curl_exec($ch);
curl_close($ch);
$photoData = json_decode($contents);
?>
When I try to echo or manipulate the contents of $photoData however, it's clear that it is empty.
Any thoughts?
Try removing curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1); I'm not exactly sure what that does but I'm not using it and my code otherwise looks very similar. I'd also use:
json_decode($contents,true); This should put the results in an array instead of an object. I've had better luck with this approach.
Put it in the works for me category.
Try this it could work
$ch = curl_init($FBUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE);
$contents = curl_exec($ch);
$pageData = json_decode($contents);
//object to array
$objtoarr = get_object_vars($pageData);
curl_close($ch);
Use jquery get Json instead This tips is from FB Album downloader GreaseMonkey script
Related
I am working with a API. the link shows in the class like this
private $apiPath = "http://www.website.com/api/v1/users/username";
now if the username part is tom and i put it in the browser like so.
private $apiPath = "http://www.website.com/api/v1/users/tom";
it will display all toms stats in text format.
I am trying to figure out how to display it in HTML rendered format
using php so i can display it on my site. I was told its in an array.
so I am assuming using variables i can get it to display what and where I want. I am just really unclear.
I have the class but unsure what to do. do i include it?
This will allow you to grab the username from db and compare
function stats(){
$user_id = $_GET['uid'];
$sql = "SELECT * FROM users WHERE uid = $user_id ";
$result = query($sql);
$row = mysqli_fetch_object($result);
$username = $row->username);
$url = ('"http://www.website.com/api/v1/users/'.$username);
$rCURL = curl_init();
curl_setopt($rCURL, CURLOPT_URL, $url);
curl_setopt($rCURL, CURLOPT_HEADER, 0);
curl_setopt($rCURL, CURLOPT_RETURNTRANSFER, 1);
$aData = curl_exec($rCURL);
curl_close($rCURL);
$response = json_decode($aData, true);
}
If you just want the data that the API is returning, that class would tell me that it is returning JSON which is a data interchange format. You could use PHP's cURL function to get the data from the API and then decode it into a PHP array using json_decode and then you could do what you like with the data.
For example:
$apiUrl = "http://www.website.com/api/v1/users/$username";
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$apiURL);
$result=curl_exec($ch);
curl_close($ch);
$userArray = json_decode($result, true);
If you need to use the class as you need to process the data into the form it does, you will need to include the class and use it.
import 'myclass.php';
$userData = new statsProfile('name');
Then you can use the other methods of the class as you need.
how to replace php function 'file' using curl?
$ego_quote = file($egoUrl); nicely put into an array.
$ego_quote[0] = error=OK
$ego_quote[1] = eta=Overnight
$ego_quote[2] = price=56.44
how can i achieve this when i'm using CURL?
Reason, function 'fopen' which is related to function 'file' not available on our production server.
Thank you
Thanks to Crayon Violent in this post.
$ego_quote = explode("\n",$ego_quote);
Which will give you the same result as function file
$ego_quote[0] = error=OK
$ego_quote[1] = eta=Overnight
$ego_quote[2] = price=56.44
You could do something like this:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $egoUrl);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
curl_close($ch);
echo $output;
I am using an API that returns JSON from a GET request
Eg.
https://api.domain.com/v1/Account/{auth_id}/Call/{call_uuid}
Returns
{
"call_duration": 4,
"total_amount": "0.00400"
}
How can I call this page from within a script and save call_duation and total_amount as separate variables?
Something like the following?:
$call_duration =
$_GET[https://api.domain.com/v1/Account/{auth_id}/Call/{call_uuid}, 'call_duration'];
$_GET[] contains the get parameters that are passed to your code - they don't generate a GET request.
You could use curl to make your request:
$ch = curl_init("https://api.domain.com/v1/Account/{auth_id}/Call/{call_uuid}");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$output = curl_exec($ch);
curl_close($ch);
$result = json_decode($output);
If PHP has allow_url_fopen enabled you can simply do
json_decode(file_get_contents('https://api.domain.com/v1/Account/{auth_id}/Call/{call_uuid}'))
Otherwise you'll have to resort to using something like Curl to get the request going. $_GET is a superglobal array which doesn't actually do anything. It only contains what the script was started with. It does not make any requests itself.
Use curl to get the JSON, then json_decode to decode it into PHP variables
$auth_id = 'your auth id here';
$call_uuid = 'your call_uuid here';
// initialise curl, set URL and options
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"https://api.domain.com/v1/Account/{$auth_id}/Call/{$call_uuid}");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_HEADER, 0);
// get the response and decode it
$response = curl_exec($ch);
curl_close($ch);
$response = json_decode($response);
$call_duration = $response['call_duration'];
$total_amount = $response['total_amount'];
Please take a look at this sample code:
function http_response($url)
{
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, TRUE);
curl_setopt($ch, CURLOPT_NOBODY, TRUE); // remove body
curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
$head = curl_exec($ch);
$httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
echo $httpCode ;
}
this code will print the httpCode of the given url. I have couple of questions:
Can I get rid of some setopt() lines here and still getting httpCode?
What about if I want to check multiple urls at the same time? Can I modify the code to do that?
Can I do the same functionality in a simpler way using libraries different than cURL?
Thanks :)
You should be able to remove CURLOPT_HEADER and CURLOPT_NOBODY and still get the same result.
You could do that like this:
$urls = array(
'http://google.com',
'http://facebook.com'
);
$status = array();
foreach($urls as $url){
$status[$url] = http_response($url);
}
Try print_r($status); after this and you'll see the result.
You could do this with file_get_contents and $http_response_header, to learn more: http://www.php.net/manual/en/reserved.variables.httpresponseheader.php I would however recommend using cURL anyway.
*2. to check multiple urls you have to use this function in a loop, in any programming language 1 response from a server = 1 connection to that server. If you want to use 1 function to get responses from multiple servers you can always pass an array to the function and do the loop inside the function
*3. you can try this way:
function get_contents() {
file_get_contents("http://example.com");
var_dump($http_response_header);
}
get_contents();
I want to bypass the ajax same-origin policy by having a php page on my site that basically acts like a JSON proxy. Eg i make an ajax request like this:
mysite.com/myproxy.php?url=blah.com/api.json&a=1&b=2
It then makes a request to:
blah.com/api.json?a=1&b=2
And returns the JSON (or whatever) result to the original requester.
Now i assume i'd be stupidly reinventing the wheel if i wrote this php code (plus i don't know php!) - is there some pre-existing code to do this? I'm sure i'm not the only one who's butted my head up against the same-origin policy before.
Oh yeah JSONP isn't an option for this particular api.
Thanks all
Okay, here's something -
Slap this into a php script, call it like this
script.php?url=blah
post the contents you want posted to the server.
<?php
$curlPost = http_build_query($_POST);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $_GET['url']);
curl_setopt($ch, CURLOPT_HEADER, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $curlPost);
$data = curl_exec($ch);
curl_close($ch);
echo json_encode($data);
?>
Now this script is a bit too open for my liking, so to increase security I would recommend that you add a list of domains to a white list.
So add this to the top:
$whitelist = array('http://www.google.com','http://www.ajax.com');
$list = array();
foreach($whitelist as $w)
$list[] = parse_url($w,PHP_URL_HOST);
$url = $_GET['url'];
$url = pathinfo($url,PHP_URL_HOST);
if(!in_array($url, $list)) die('no access to that domain');