i got a problem.
i want to log in a website with CURL, but the page generates a key, which is in a hidden field. So I have to grab the value of the hidden field... after that i have to submit the password, the email AND the the grabbed key.
Is that possible?
hope you understand
Thanks
----edit----
if the page reload, there's a new key in the hidden field.. and the old one do not work
Yes, it's possible. The basic steps would be:
1. Fetch form
2. Run returned data through DOMdocument to extract the hidden form field's value
3. Post login data, including the key value from step #2
4. ???
5. Profit
Yes, it is.
Load the page contents into a variable (eg. $contents = file_get_contents(...);).
Now, parse it so you can get the hidden key (eg. $matches = preg_match(..., ...); $key = $matches[1];).
Now, post the request using the hidden key (eg. $context = streamcontextcreate(...); $data = file_get_contents(..., false, $context);).
Yes, it is possible.
You can even grab the page with
$source = htmlspecialchars(file_get_contents($url));
Then use strpos, substr and so on to get information of that field (that's the easiest way)
Then just POST it with this function
$urltopost = $url
$datatopost = array ($name => $value);
$ch = curl_init ($urltopost);
curl_setopt ($ch, CURLOPT_POST, true);
curl_setopt ($ch, CURLOPT_POSTFIELDS, $datatopost);
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, true);
$returndata = htmlspecialchars(curl_exec ($ch));
Related
I am trying to update my API with an update curl function but am struggling to work out why it isn't working
The areas where it may be wrong is key($id) I want it to
extract the ID column based on the key value for the ID array.
$URL I want to create the URL based on the const variables plus the resource name plus the value of the ID array that has been passed through rawurlencode.
So far this is my update code, but am wondering what area is wrong.
I can provide more info if needed and appreciate any help, thanks
<?php
function update(array $id,array $vaules, $resourcename)
$jsonData = json_encode($vaules);
key($id);
$url = DOMAIN.FOLDER.APIPATH.$resourcename.rawurlencode("/".$id);
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,array ('content-type: application/json'));
curl_setopt($ch, CURLOPT_CUSTOMREQUEST,PUT);
curl_setopt($ch,CURLOPT_POSTFIELDS,$jsonData);
curl_exec($ch);
curl_getinfo(CURLINFO_HTTP_CODE);
}
The function key() returns the current key in an array (according to the internet pointer). Right now you're not doing anything with it, you're calling the function and not assigning it anywhere.
Did you mean to write: rawurlencode("/".key($id).$vaules);?
As your code is right now, assuming $id is an array, you're trying to convert an array into a string, which I doubt is what you want.
I want to get information about a channel, is it online at the moment or not:
$stream_list = ...;
$mycurl = curl_init();
curl_setopt ($mycurl, CURLOPT_HEADER, 0);
curl_setopt ($mycurl, CURLOPT_RETURNTRANSFER, 1);
//Build the URL
$url = "http://api.justin.tv/api/stream/list.json?channel=" . $stream_list;
curl_setopt ($mycurl, CURLOPT_URL, $url);
$web_response = curl_exec($mycurl);
but thats always return with an empty array. I saw many example based on it - mine wont work, what am I doing wrong?
An empty array probably means nothing was found with the stream list you provided.
I used http://api.justin.tv/api/stream/list.json?channel=beyondthesummit,towelliee and was able to get an array from the API, and then I used http://api.justin.tv/api/stream/list.json?channel=foobar and got an empty JSON array back.
I'd make sure $stream_list has the value you expect. And if it does, try removing the channel filter completely to see if you get results.
It returns an empty array if the channel is not live.
Is it bad practice or will it be slower if I use curl within a foreach loop?
I'm planning on having an autocomplete input field, and the query in the input would be sent to an API call.
I'm getting an id from a certain link (ie: http://api.linke1.com/names)
foreach($json as j){
$id = $j->id; //from http://api.linke1.com/names
$url = "https://api.site/{$id}/photos";
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$output = curl_exec($ch);
curl_close($ch);
$jsonDecode = json_decode($output);
$results = $jsonDecode->results;
foreach($results as $result)
{
$photoURL= $result->photo->url; //from https://api.site/{$id}/photos
}
}
So every time I type in a name, it will go into the foreach searching for an id from http://api.linke1.com/names, and then it will look for the photo url from the other link. I wanted to output a list of an array, so eventually i'll have a list of data to output showing information such as name, photo, etc...
Will this slow down dramatically because each letter typed in the input field it will run through this foreach loop. Would there be an easier way?
Thanks!
Initialize the curl and the things that doesn't change before the loop and close it afterwards.
That will speed up the thing a little bit.
and you can use curl_multi_*, which can fetch several URLs in parallel.
http://se2.php.net/manual/en/ref.curl.php
Can i send for example a string or another piece of information to another .php file without it being exposed [thus not by GET but by POST conform to what i know] without using a form?
If you don't want your data to be seen by the user, use a PHP session.
Data in a post request is still accessible (and manipulable) by the user.
Checkout this tutorial on PHP Sessions.
You could use AJAX to send a POST request if you don't want forms.
Using jquery $.post method it is pretty simple:
$.post('/foo.php', { key1: 'value1', key2: 'value2' }, function(result) {
alert('successfully posted key1=value1&key2=value2 to foo.php');
});
Send your data with SESSION rather than post.
session_start();
$_SESSION['foo'] = "bar";
On the page where you recieve the request, if you absolutely need POST data (some weird logic), you can do this somwhere at the beginning:
$_POST['foo'] = $_SESSION['foo'];
The post data will be valid just the same as if it was sent with POST.
Then destroy the session (or just unset the fields if you need the session for other purposes).
It is important to destroy a session or unset the fields, because unlike POST, SESSION will remain valid until you explicitely destroy it or until the end of browser session. If you don't do it, you can observe some strange results. For example: you use sesson for filtering some data. The user switches the filter on and gets filtered data. After a while, he returns to the page and expects the filter to be reset, but it's not: he still sees filtered data.
Simply use: file_get_contents()
// building array of variables
$content = http_build_query(array(
'username' => 'value',
'password' => 'value'
));
// creating the context change POST to GET if that is relevant
$context = stream_context_create(array(
'http' => array(
'method' => 'POST',
'content' => $content, )));
$result = file_get_contents('http://www.example.com/page.php', null, $context);
//dumping the reuslt
var_dump($result);
Reference: my answer to a similar question:
have a look at the php documentation for theese functions you can send post reqeust using them.
fsockopen()
fputs()
or simply use a class like Zend_Http_Client which is also based on socket-conenctions.
also found a neat example using google...
function redir(data) {
document.getElementById('redirect').innerHTML = '<form style="display:none;" position="absolute" method="post" action="location.php"><input id="redirbtn" type="submit" name="value" value=' + data + '></form>';
document.getElementById('redirbtn').click();
}
<button onclick="redir('dataToBeSent');">Next Page</button>
<div id="redirect"></div>
You can use this method which creates a new hidden form whose "data" is sent by "post" to "location.php" when a button[Next Page] is clicked.
I would highly recommend using curl in such situation, file_get_content() does work but not at all times, and it could be troublesome to use it in some applications.
Though curl comes in different variations depending on what you want to send and in what method, here is the most common method of posting your data without HTML form using curl.
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://example.com/request_uri');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
$post = array(
'data1' => 'value1',
'data2' => $value2
);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
$result = curl_exec($ch);
if (curl_errno($ch)) {
echo 'Error:' . curl_error($ch);
}
curl_close($ch);
//do what you want with the responce
var_dump($result)
How can I query a particular website with some fields and get the results to my webpage using php?
let say website xyz.com will give you the name of the city if you give them the zipcode. How can I acehive this easliy in php? any code snap shot will be great.
If I understand what you mean (You want to submit a query to a site and get the result back for processing and such?), you can use cURL.
Here is an example:
<?php
// create curl resource
$ch = curl_init();
// set url
curl_setopt($ch, CURLOPT_URL, "example.com");
//return the transfer as a string
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
// $output contains the output string
$output = curl_exec($ch);
// close curl resource to free up system resources
curl_close($ch);
?>
You can grab the Lat/Long from this site with some regexp like this:
if ( preg_match_all( "#<td>\s+-?(\d+\.\d+)\s+</td>#", $output, $coords ) ) {
list( $lat, $long ) = $coords[1];
echo "Latitude: $lat\nLongitude: $long\n";
}
Just put that after the curl_close() function.
That will return something like this (numbers changed):
Latitude: 53.5100
Longitude: 60.2200
You can use file_get_contents (and other similar fopen-class functions) to do this:
$result = file_get_contents("http://other-site.com/query?variable=value");
Do you mean something like:
include 'http://www.google.com?q=myquery'; ? or which fields do you want to get?
Can you be a bit more specific pls :)
If you want to import the html to your page and analyze it, you probably want to use cURL.
You have to have the extensions loaded to your page (it's usually part of PHP _ I think it has to be compiled in? The manual can answer that)
Here is a curl function. Set up your url like
$param='fribby';
$param2='snips';
$url="www.example.com?data=$param&data2=$param2";
function curl_page($url)
{
$response =false;
$ch = curl_init($url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,true);
curl_setopt($ch,CURLOPT_FAILONERROR,true);
curl_setopt($ch,CURLOPT_FOLLOWLOCATION,1);
curl_setopt($ch,CURLOPT_TIMEOUT,30);
$response = curl_exec($ch);
curl_close($ch);
return $response;
}
$page_data=curl_page($url);
Then, you can get data out of the page using the DOM parsing or grep/sed/awk type stuff.